State Euclid's first postulate. -Maths 9th

1 Answer

Answer :

Solution   :- A straight may be drawn from any point to any other point.

Related questions

Description : Does Euclid's fifth postulate imply the existence of parallel lines?Explain. -Maths 9th

Last Answer : Solution :-

Description : State Euclid's fifth axiom (as per order given in the textbook for class IX). -Maths 9th

Last Answer : Solution :- A straight line may be drawn from any point to any other point

Description : To which country does Euclids belong? -Maths 9th

Last Answer : Solution :- Greece

Description : It is known that if x+y =10, then x+y+z = 10+z.Which axiom of Euclids does this statement illustrate? -Maths 9th

Last Answer : Solution :- Second axiom.

Description : In Fig.5.7, AC = XD, c is the mid-point of AB and D is the mid-point of XY. Using a Euclid's axiom,show that AB=XY. -Maths 9th

Last Answer : Solution :-

Description : Introduction to Euclid's Geometry Class 9th Formulas -Maths 9th

Last Answer : An algebraic expression is the combination of constants and variable connected by the four basic operations (+, -, , ). For example : 2x , x2y , xy/3, 3 etc. Types of Algebraic expression : Polynomial in one variable : An ... b2) (x) a3 + b3 + c3 - 3abc = (a+b+c)(a2+b2+c2-ab - bc - ca)

Description : NCERT Solutions for class 9 Maths Chapter 5 Introduction to Euclid’s Geometry Exercise 5.2 -Maths 9th

Last Answer : 1. How would you rewrite Euclid's fifth postulate so that it would be easier to understand ? We can have: Two distinct intersecting lines cannot be parallel to the same line. 2. Does Euclid's fifth postulate imply ... other side also. ∴ The lines m' and n' never meet, i.e., they are parallel.

Description : Cbqs (case base study ) of chapter 5 Introduction to Euclid's Geometry of maths class 9th -Maths 9th

Last Answer : answer:

Description : Use Euclid’s division algorithm to find the HCF of: i. 135 and 225 ii. 196 and 38220 iii. 867 and 225 -Maths 10th

Last Answer : 135 and 225 As you can see, from the question 225 is greater than 135. Therefore, by Euclid's division algorithm, we have, 225 = 135 1 + 90 Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get, ... (867,225) = HCF(225,102) = HCF(102,51) = 51. Hence, the HCF of 867 and 225 is 51

Description : Use Euclid’s Division Lemma to show that the cube of any positive integer is either of the form 9m, 9m + 1 or 9m + 8 -Maths 10th

Last Answer : Let us consider a and b where a be any positive number and b is equal to 3. According to Euclid's Division Lemma a = bq + r where r is greater than or equal to zero and less than b (0 ≤ r < b) a = 3q + r so ... 8 Where m = (3q3 + 6q2 + 4q)therefore a can be any of the form 9m or 9m + 1 or, 9m + 8.

Description : Use Euclid’s division algorithm to find the HCF of : (i) 135 and 225 (ii) 196 and 38220 (iii) 867 and 255 -Maths 10th

Last Answer : (i) Given numbers are 135 and 225. On applying Euclid's division algorithm, we have 225 = 135 x 1 + 90 Since the remainder 90 ≠ 0, so again we apply Euclid's division algorithm to 135 and 90, to get 135 = 90 x ... division lemma, to a =867 and b=255 to find q and r such that 867 = 255q + r, 0 ≤ r

Description : “The state of a simple compressible system is completely specified by two independent, intensive properties”. This is known as ______.  A. Equilibrium postulate  B. State postulate  C. Environment postulate  D. Compressible system postulate

Last Answer : State postulate

Description : Can you use euclids formula to generate integers 9, 12, andv15?

Last Answer : im not sure how to answer it

Description : what- the image of a triangle after a translation is shown. fill in the blank with a congruence postulate. use SSS?

Last Answer : SSS

Description : which congruence postulate or theorem would you use to prove MEX?

Last Answer : HL congruence theorem

Description : what- Complete the Angle-Side-Angle Congruence Postulate. The same words go in each blank.If _____ and the included side of one triangle are congruent to _____ and the included side of another triangle, then the triangles are congruent?

Last Answer : two angles

Description : Is this statement true or falseIf two sides and one angle of one triangle are congruent to two sides and one angle of another triangle, then the triangles are congruent by the Side-Angle-Side Postulate?

Last Answer : Answers is the place to go to get the answers you need and to ask the questions you want

Description : what postulate or theorem guarantees that line L and line N are parallel?

Last Answer : converse of the corresponding angles postulate

Description : what- A crossbar connects two wooden columns. Which statement is true, by the Converse of the Corresponding Angles Postulate?

Last Answer : A+

Description : Which statement is true, by the Converse of the Corresponding Angles Postulate?

Last Answer : if

Description : Which is a true statement that can be proven diagram hypothesis theorem postulate?

Last Answer : theorem

Description : Is qrs congruent tuv if so name the postulate that applies?

Last Answer : Might not be congruent

Description : In right triangle JKL mK 44. In right triangle PQR mQ 44. Which similarity postulate or theorem proves that JKL and PQR are similar?

Last Answer : The answer will be AA which is short for (Angle Angle). Hope this helped.

Description : Name the scientist who modified cell the- ory by giving the postulate “Omnis cellula-e- cellula”?

Last Answer : Rudolf Virchow He states that all cells arise  from pre-existing cells through cell division.

Description : Certain fundamental beliefs called "postulates" underlie auditing theory. Which of the following is not a postulate of auditing? a. Economic assertions can be verified. b. The auditor acts exclusively ... long-term conflict exists between the auditor and the management of the entity under audit

Last Answer : An audit has a benefit only to the owners

Description : A hypothesis is a (A) law (B) canon (C) postulate (D) supposition

Last Answer : (D) supposition

Description : Which of the following expressions are polynomials in one variable and which are not? State reasons for your answer. (i) 4x2–3x+7 -Maths 9th

Last Answer : Solution: The equation 4x2–3x+7 can be written as 4x2–3x1+7x0 Since x is the only variable in the given equation and the powers of x (i.e., 2, 1 and 0) are whole numbers, we can say that the expression 4x2–3x+7 is a polynomial in one variable

Description : State and prove-line joining the midpoint of any two sides of a triangle is parallel to throw side and is equal to 1/2 of it -Maths 9th

Last Answer : Here, In △△ ABC, D and E are the midpoints of sides AB and AC respectively. D and E are joined. Given: AD = DB and AE = EC. To Prove: DE ∥∥ BC and DE = 1212 BC. Construction: Extend line segment DE to ... we have DF ∥∥ BC and DF = BC DE ∥∥ BC and DE = 1212BC (DE = EF by construction) Hence proved.

Description : State whether the following statements are true or false ? Justify your answer. -Maths 9th

Last Answer : (i) False, here √2 is an irrational number and 3 is a rational number, we know that when we divide irrational number by non-zero rational number it will always give an irrational number. (ii) False, ... in the form p/q, q ≠0. p,q both are integers and these numbers are called irrational numbers.

Description : state and prove angle sum property of triangle -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : State and prove-line joining the midpoint of any two sides of a triangle is parallel to throw side and is equal to 1/2 of it -Maths 9th

Last Answer : Here, In △△ ABC, D and E are the midpoints of sides AB and AC respectively. D and E are joined. Given: AD = DB and AE = EC. To Prove: DE ∥∥ BC and DE = 1212 BC. Construction: Extend line segment DE to ... we have DF ∥∥ BC and DF = BC DE ∥∥ BC and DE = 1212BC (DE = EF by construction) Hence proved.

Description : State whether the following statements are true or false ? Justify your answer. -Maths 9th

Last Answer : (i) False, here √2 is an irrational number and 3 is a rational number, we know that when we divide irrational number by non-zero rational number it will always give an irrational number. (ii) False, ... in the form p/q, q ≠0. p,q both are integers and these numbers are called irrational numbers.

Description : state and prove angle sum property of triangle -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : State whether the following statements are True or false. Justify your answers. -Maths 9th

Last Answer : Solution :-

Description : Solve the equation u-5 =15 and state the axiom that you use here. -Maths 9th

Last Answer : Solution :-

Description : If the corresponding angles of two triangles are equal, then they are always. State true or false and justify your answer. -Maths 9th

Last Answer : Solution :- False, because two equilateral triangles with sides 3 cm and 6 cm respectively have all angles equal, but the triangles are not congruent.

Description : State which of the following formulae is/are incorrect and justify your statement. -Maths 9th

Last Answer : (ii) V = ab + c, is incorrect As volume is three - dimensional, so each term in the formula must have a product of three letter terms.

Description : find the mean of first five multiples of 10 -Maths 9th

Last Answer : This is the correct one...

Description : Determine the mean of first 10 natural numbers. -Maths 9th

Last Answer : Mean = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 / 10 = 55 / 10 = 5.5

Description : By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial x4 + 1 and x-1. -Maths 9th

Last Answer : Actual division method

Description : find the mean of first five multiples of 10 -Maths 9th

Last Answer : This is the correct one...

Description : Determine the mean of first 10 natural numbers. -Maths 9th

Last Answer : Mean = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 / 10 = 55 / 10 = 5.5

Description : By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial x4 + 1 and x-1. -Maths 9th

Last Answer : Actual division method

Description : The sides of a quadrilateral ABCD are 6 cm, 8 cm, 12 cm and 14 cm (taken in order), respectively and the angle between the first two sides is a right angle. -Maths 9th

Last Answer : Given ABCD is a quadrilateral having sides AB=6cm, BC=8cm, CD=12cm and DA=14 cm. Now. Join AC. We have, ABC is a right angled triangle at B. Now, AC2=AB2+BC2 [by Pythagoras theorem]Now, AC2=AB2+BC2 ... =24(1+6-√)cm2=24+246=24(1+6)cm2 Hence, the area of quadrilateral is 241+6-√−−−−−−√cm2241+6cm2 .

Description : The mean of 25 observations is 36. Out of these observations, if the mean of first 13 observations is 32 and that of the last 13 observations is 40, the 13th observation is -Maths 9th

Last Answer : NEED ANSWER

Description : Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Last Answer : circle of radius a touches both axis in 1st quadrant so its centre will be (a,a). ∴ Required equation ⇒(x−a)2+(y−a)2=a2 ⇒x2+a2−2ax+y2+a2−2ay=a2 ⇒x2+y2−2ax−2ay+2a2−a2=0 ⇒x2−y2−2ax−2ay+a2=0.

Description : The sides of a quadrilateral ABCD are 6 cm, 8 cm, 12 cm and 14 cm (taken in order), respectively and the angle between the first two sides is a right angle. -Maths 9th

Last Answer : Given ABCD is a quadrilateral having sides AB = 6 cm, BC = 8 cm, CD = 12 cm and DA = 14 cm. Now, join AC.

Description : The mean of 25 observations is 36. Out of these observations, if the mean of first 13 observations is 32 and that of the last 13 observations is 40, the 13th observation is -Maths 9th

Last Answer : (b) Given, mean of 25 observations = 36 ∴ Sum of 25 observations = 36 x 25 = 900 Now, the mean of first 13 observations = 32 ∴ Sum of first 13 observations = 13 x 32 = 416 and the mean of last 13 ... - (Sum of 25 observations) = (520 + 416)-900 = 936 - 900 = 36 Hence, the 13th observation is 36.

Description : Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Last Answer : Given that the circle of radius ‘a’ touches both axis. So, its centre is (a, a) So, the equation of required circles is : (x-a)2 + (y-a)2 = a2 ⇒ x2 - 2ax + a2+y2 - 2ay + a2 = a2 ⇒ x2 + y2 - 2ax - 2ay + a2 = 0

Description : he auto-rickshaw fare in a city is charged as ₹10 for the first kilometre and @ ₹4 per kilometre for subsequent distance covered. Write the linear equation to express the above statement. Draw the graph of linear equation. -Maths 9th

Last Answer : Solution :- Fig. 3.12 represents the graph of the linear equation y = 4x+6.