If an angle of a parallelogram is two - third of its adjacent angle , then find the smallest angle of the parallelogram . -Maths 9th

If an angle of a parallelogram is two - third of its adjacent angle , then find the smallest angle of the parallelogram . -Maths 9th
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In a parallelogram ABCD, Let ∠A  be x and ∠B be 2x / 3  ∴ ∠A + ∠B = 180° ⇒ x + 2x / 3 = 180° ⇒ 5x / 3 = 180°  ⇒ x° = 180° × 3 / 5 = 108°  ∠A = 108° , ∠B = 2 / 3  ×  108° = 72°  
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If an angle of a parallelogram is two - third of its adjacent angle , then find the smallest angle of the parallelogram . -Maths 9th

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If A = i + 2j + 3k and B = 3i - 2j + k, then the area of parallelogram formed from these vectors as the adjacent sides will be

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The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm, is -Maths 9th

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