The point at which the two coordinate axes meet is called the -Maths 9th

The point at which the two coordinate axes meet is called the -Maths 9th
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(c) The point at which the two coordinate axes meet is called the origin.
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The point at which the two coordinate axes meet is called the -Maths 9th

Description : The point at which the two coordinate axes meet is called the -Maths 9th

Last Answer : (c) The point at which the two coordinate axes meet is called the origin.

What is the equation of the straight line passing through the point (4, 3) and making intercepts on the co-ordinates axes whose sum is –1 ? -Maths 9th

Description : What is the equation of the straight line passing through the point (4, 3) and making intercepts on the co-ordinates axes whose sum is –1 ? -Maths 9th

Last Answer : Diagonals of a rhombus bisect each other at right angles ⇒ Co-ordinates of mid-points of AC and BD are equal∴ 0 = \(\bigg(rac{4+(-2)}{2},rac{-5+(-1)}{2}\bigg)\) = (1, -3)Slope of BD = \(rac{-5+1}{4+2}\) = \(rac{-4}{6}\) ... (rac{3}{2}\) isy + 3 = \(rac{3}{2}\) (x - 1)⇒ 2y + 6 = 3x - 3 ⇒ 2y = 3x - 9.

A line passes through the point of intersection of the lines 100x + 50y – 1 = 0 and 75x + 25y + 3 = 0 and makes equal intercepts on the axes. -Maths 9th

Description : A line passes through the point of intersection of the lines 100x + 50y – 1 = 0 and 75x + 25y + 3 = 0 and makes equal intercepts on the axes. -Maths 9th

Last Answer : (d) x + 2y = 2Let the required equation make intercept on x-axis = 2a ⇒ intercept made on y-axis = a ∴ Eqn of the given line in the intercept from:\(rac{x}{2a}+rac{y}{a}=1\) ...(i)Since the line ... 1 ⇒ a = 1.∴ Required equation of line : \(rac{x}{2 imes1}+rac{y}{1}=1\) ⇒ x + 2y = 2.

Coordinate of â–¡ABCD is WCS are: lowermost corner A(2,2) & diagonal corner are C(8,6). W.r.t MCS. The coordinates of origin of WCS system are (5,4). If the axes of WCS are at 600 in CCW w.r.t. the axes of MCS. Find new vertices of point A in MCS. a.(4.268, 6.732) b.(5.268, 6.732) c.(4.268, 4.732) d.(6.268, 4.732)

Description : Coordinate of â- ABCD is WCS are: lowermost corner A(2,2) & diagonal corner are C(8,6). W.r.t MCS. The coordinates of origin of WCS system are (5,4). If the axes of WCS are at 600 in CCW w.r.t. the axes of MCS. Find new ... in MCS. a.(4.268, 6.732) b.(5.268, 6.732) c.(4.268, 4.732) d.(6.268, 4.732)

Last Answer : a.(4.268, 6.732)

If y-coordinate of a point is zero, then this point always lies -Maths 9th

Description : If y-coordinate of a point is zero, then this point always lies -Maths 9th

Last Answer : (c) If y-coordinate of a point is zero, then this point always lies on X-axis. Because perpendicular distance of the point from X-axis measured along Y-axis is zero.

If y-coordinate of a point is zero, then this point always lies -Maths 9th

Description : If y-coordinate of a point is zero, then this point always lies -Maths 9th

Last Answer : (c) If y-coordinate of a point is zero, then this point always lies on X-axis. Because perpendicular distance of the point from X-axis measured along Y-axis is zero.

If y-coordinate of a point is zero, then where will this point lie in the coordinate plane? On the x-axis. -Maths 9th

Description : If y-coordinate of a point is zero, then where will this point lie in the coordinate plane? On the x-axis. -Maths 9th

Last Answer : Solution :- On the x-axis.

Where does the point (–2, 4) lie in the coordinate plane? -Maths 9th

Description : Where does the point (–2, 4) lie in the coordinate plane? -Maths 9th

Last Answer : Solution :- II quadrant

The position of a boy on the coordinate plane is given by the point (4,6) . What is the perpendicular distance from the x-axis and the y-axis ? -Maths 9th

Description : The position of a boy on the coordinate plane is given by the point (4,6) . What is the perpendicular distance from the x-axis and the y-axis ? -Maths 9th

Last Answer : answer:

Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Description : Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Last Answer : circle of radius a touches both axis in 1st quadrant so its centre will be (a,a). ∴ Required equation ⇒(x−a)2+(y−a)2=a2 ⇒x2+a2−2ax+y2+a2−2ay=a2 ⇒x2+y2−2ax−2ay+2a2−a2=0 ⇒x2−y2−2ax−2ay+a2=0.

Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Description : Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Last Answer : Given that the circle of radius ‘a’ touches both axis. So, its centre is (a, a) So, the equation of required circles is : (x-a)2 + (y-a)2 = a2 ⇒ x2 - 2ax + a2+y2 - 2ay + a2 = a2 ⇒ x2 + y2 - 2ax - 2ay + a2 = 0

Draw the graph of the equation 3x + 4y = 12 and find the co-ordinates of the points of intersection of the equation with the co-ordinate axes. -Maths 9th

Description : Draw the graph of the equation 3x + 4y = 12 and find the co-ordinates of the points of intersection of the equation with the co-ordinate axes. -Maths 9th

Last Answer : Solution :-

What do you mean by Rectangular Axes? -Maths 9th

Description : What do you mean by Rectangular Axes? -Maths 9th

Last Answer : (c) \(rac{19}{90}\)In the words ASSISTANT' and STATISTICS', N' and C' are the uncommon letters. The same letters are A, I, S and T whose numbers in both the words are as follows:AISTASSISTANT\( ightarrow\)2132STATISTICS\( ightarrow\ ... 1}{45}\) + \(rac{1}{10}\) + \(rac{1}{15}\) = \(rac{19}{90}\).

Find the ratio in which the x-axes divides the line joining the points (–2, 5) and (1, –9) ? -Maths 9th

Description : Find the ratio in which the x-axes divides the line joining the points (–2, 5) and (1, –9) ? -Maths 9th

Last Answer : Let the co-ordinates of the point of internal division A be (x, y). Then,\(x\) = \(rac{2 imes(-7)+3 imes8}{2+3}\) = \(rac{-14+24}{5}\) = \(rac{10}{5}\) = 2y = \(rac{2 imes4+3 imes9}{2+3}\) = \(rac{8+27}{5}\) = \(rac{35}{5}\) = 7∴ Co-ordinates of the point for internal division are (2, 7).

If (–5, 4) divides the line segment between the co-ordinate axes in the ratio 1 : 2, then what is its equation ? -Maths 9th

Description : If (–5, 4) divides the line segment between the co-ordinate axes in the ratio 1 : 2, then what is its equation ? -Maths 9th

Last Answer : (d) x = yThe equations of the given lines are: 4x + 3y = 12 ...(i) 3x + 4y = 12 ...(ii) Solving the simultaneous equations (i) and (ii), we get\(x\) = \(rac{12}{7}\), y = \(rac{12}{7}\)∴ Point of the ... )isy - 0 = \(\bigg(rac{rac{12}{7}-0}{rac{12}{7}-0}\bigg)\) (x - 0), i.e., y = x.

The line through the points (4, 3) and (2, 5) cuts off intercepts of lengths λ and μ on the axes. Which one of the following is correct ? -Maths 9th

Description : The line through the points (4, 3) and (2, 5) cuts off intercepts of lengths λ and μ on the axes. Which one of the following is correct ? -Maths 9th

Last Answer : (c) a, b, c are in H.P. only for all m As the points A(a, ma), B[b, (m + 1)b] and C[c, (m + 2)c] are collinear. Area of Δ ABC should be equal to zero.⇒ \(rac{1}{2}\)[x1(y2 - y3) + x2(y3 - y1) + ... - bc = 0 ⇒ ab + bc = 2ac ⇒ b = \(rac{2ac}{a+c}\)∴ a, b, c are harmonic progression (H.P.) for all m.

A straight line passes through the points (a, 0) and (0, b). The length of the line segment contained between the axes is 13 and the product of -Maths 9th

Description : A straight line passes through the points (a, 0) and (0, b). The length of the line segment contained between the axes is 13 and the product of -Maths 9th

Last Answer : (d) \(rac{23}{\sqrt{17}}\)The given lines are:L : \(rac{x}{5}+rac{y}{b}=1\) ....(i)K : \(rac{x}{c}+rac{y}{3}=1.\) ...(ii)Since line L passes through (13, 32),\(rac{13}{ ... between parallel lines ax + by + c1 = 0 and ax + by c2 = 0 is d = \(rac{|c_2-c_1|}{\sqrt{a^2+b^2}}\bigg)\)

The straight line ax + by + c = 0 and the co-ordinate axes form an isosceles triangle under which of the following conditions ? -Maths 9th

Description : The straight line ax + by + c = 0 and the co-ordinate axes form an isosceles triangle under which of the following conditions ? -Maths 9th

Last Answer : (a) | a | = | b | The equation of line AB, i.e., ax + by + c = 0 in intercept form is ax + by = - c⇒ \(rac{x}{\big(-rac{c}{a}\big)}\) + \(rac{x}{\big(-rac{c}{b}\big)}\) = 1Δ AOB is isosceles Δ if OA = OB, i.e., ... \(rac{-c}{a}\) = \(rac{-c}{a}\) ⇒ \(rac{1}{a}\) = \(rac{1}{a}\) ⇒ | a | = | b |.

The ellipse `x^2+""4y^2=""4` is inscribed in a rectangle aligned with the coordinate axes, which in turn is inscribed in another ellipse that passes t

Description : The ellipse `x^2+""4y^2=""4` is inscribed in a rectangle aligned with the coordinate axes, which in turn is inscribed in another ellipse that passes t

Last Answer : The ellipse `x^2+""4y^2=""4` is inscribed in a rectangle aligned with the coordinate axes, which in turn is ... 4x^2+48y^2=48` D. `4x^2+64y^2=48`

Notes of coordinate geometry -Maths 9th

Description : Notes of coordinate geometry -Maths 9th

Last Answer : NEED ANSWER

Notes of coordinate geometry -Maths 9th

Description : Notes of coordinate geometry -Maths 9th

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Find the coordinate where the linear equation 3x -4y = 11 meets at x-axis. -Maths 9th

Description : Find the coordinate where the linear equation 3x -4y = 11 meets at x-axis. -Maths 9th

Last Answer : hope it helps

Find the coordinate where the linear equation 4x - 23 y = 7 meets at y-axis. -Maths 9th

Description : Find the coordinate where the linear equation 4x - 23 y = 7 meets at y-axis. -Maths 9th

Last Answer : 4x-2=-7*3y 4x+21y=2 The equation meets y axis when x=0 4.0+21y=2 y=21/2 Hence , the equation meets y-axis at (0,21/2)

Coordinate Geometry Class 9th Formula -Maths 9th

Description : Coordinate Geometry Class 9th Formula -Maths 9th

Last Answer : Here, the traingle ABC is isosceles So,Angle A willbe 90°.And AB=BC therefore their angles will be equal So..90+x+x=180° 2x=90° X=45° Then angle B and angle C = 45°

NCERT Solutions for class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.2 -Maths 9th

Last Answer : For x + 1 = 0, we have x = -1. ∴ The zero of x + 1 is -1. (i) p(x) = x3 + x2 + x + 1 ∴ p(-1) = (-1)3 + (-1)2 + (-1) + 1 = -1 + 1 - 1 + 1 = 0 i.e. when p(x) is divided by (x + 1), then the remainder is zero. ∴ ... ] = (y - 1)[2y(y + 1) + 1(y + 1)] = (y - 1)[(y + 1)(2y + 1)] = (y - 1)(y + 1)(2y + 1)

NCERT Solutions for class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.1 -Maths 9th

Last Answer : 1. Find the value of the polynomial 5x - 4x2 + 3 at (i) x = 0 (ii) x = -1 (iii) x = 2 (i) ∵ p(x) = 5x - 4x2 + 3 = 5(x) - 4(x)2 + 3 ∴ p(0) = 5(0) - 4(0) + 3 = 0 - 0 + 3 = 3 Thus, the value of 5x - 4x2 ... p(x) = cx + d ∴ p(x) = 0 ⇒ cx + d = 0 or c x = -d or x = - dc Thus, a zero of cx + d is - dc.

MCQ Questions for Class 9 Maths Chapter 3 Coordinate Geometry with answers -Maths 9th

Description : MCQ Questions for Class 9 Maths Chapter 3 Coordinate Geometry with answers -Maths 9th

Last Answer : Below you will find MCQ Questions of Chapter 3 Coordinate Geometry Class 9 Maths Free PDF Download that will help you in gaining good marks in the examinations and also cracking competitive exams ... Coordinate Geometry MCQ Questions will help you in practising more and more questions in less time.

Cbqs (case base study ) of chapter 3 Coordinate Geometry of maths class 9th -Maths 9th

Description : Cbqs (case base study ) of chapter 3 Coordinate Geometry of maths class 9th -Maths 9th

Last Answer : answer:

At what point does the graph of the linear equation 2x + 3y = 9 meet a line which is parallel to the y-axis, at a distance of 4 units from the origin and on the right of the y-axis? -Maths 9th

Description : At what point does the graph of the linear equation 2x + 3y = 9 meet a line which is parallel to the y-axis, at a distance of 4 units from the origin and on the right of the y-axis? -Maths 9th

Last Answer : hope its clear

Spiral gear are used for transmitting power between two shaft Inclined at a. Right angle to each other and axes can intersect b. Right angle to each other and axes cannot intersect c. At angle slightly lesser or greater than 90 of axles can meet d. None of the above

Description : Spiral gear are used for transmitting power between two shaft Inclined at a. Right angle to each other and axes can intersect b. Right angle to each other and axes cannot intersect c. At angle slightly lesser or greater than 90 of axles can meet d. None of the above

Last Answer : c. At angle slightly lesser or greater than 90 of axles can meet

PQ and RS are two equal and parallel line segments.Any points M not lying on PQ or RS is joined to Q and S and lines through P parallel to SM meet at N.Prove that line segments MN and PQ are equal and parallel to each other. -Maths 9th

Description : PQ and RS are two equal and parallel line segments.Any points M not lying on PQ or RS is joined to Q and S and lines through P parallel to SM meet at N.Prove that line segments MN and PQ are equal and parallel to each other. -Maths 9th

Last Answer : hope its clear

In the figure, ABCD is a rhombus, whose diagonals meet at 0. Find the values of x and y. -Maths 9th

Description : In the figure, ABCD is a rhombus, whose diagonals meet at 0. Find the values of x and y. -Maths 9th

Last Answer : Since diagonals of a rhombus bisect each other at right angle . ∴ In △AOB , we have ∠OAB + ∠x + 90° = 180° ∠x = 180° - 90° - 35° [∵ ∠ OAB = 35°] = 55° Also, ∠DAO = ∠BAO = 35° ∴ ∠y + ∠DAO + ∠BAO + ∠x ... 180° ⇒ ∠y = 180° - 125° = 55° Hence the values of x and y are x = 55°, y = 55°.

X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Description : X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Last Answer : Here, △XZM and △XZL are on the same base (XZ) and lie between the same parallels (XZ || LM). ∴ ar(△XZL) = ar( △XZM) Adding ar(△XZY) on both sides , we have ar(△XZL) + ar(△XZY) = ar(△XZM) + ar(△XZY) ⇒ ar(△LZY) = ar(quad.MZYX)

In the figure, chord AB of circle with centre O, is produced to C such that BC = OB. CO is joined and produced to meet the circle in D. -Maths 9th

Description : In the figure, chord AB of circle with centre O, is produced to C such that BC = OB. CO is joined and produced to meet the circle in D. -Maths 9th

Last Answer : In △OBC, OB = BC ⇒ ∠BOC = ∠BCO = y ...[angles opp. to equal sides are equal] ∠OBA is the exterior angle of △BOC So, ∠ABO = 2y ...[ext. angle is equal to the sum of int. opp. angles] Similarly, ∠AOD is the exterior angle of △AOC ∴ x = 2y + y = 3y

In the figure, ABCD is a rhombus, whose diagonals meet at 0. Find the values of x and y. -Maths 9th

Description : In the figure, ABCD is a rhombus, whose diagonals meet at 0. Find the values of x and y. -Maths 9th

Last Answer : Since diagonals of a rhombus bisect each other at right angle . ∴ In △AOB , we have ∠OAB + ∠x + 90° = 180° ∠x = 180° - 90° - 35° [∵ ∠ OAB = 35°] = 55° Also, ∠DAO = ∠BAO = 35° ∴ ∠y + ∠DAO + ∠BAO + ∠x ... 180° ⇒ ∠y = 180° - 125° = 55° Hence the values of x and y are x = 55°, y = 55°.

X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Description : X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Last Answer : Here, △XZM and △XZL are on the same base (XZ) and lie between the same parallels (XZ || LM). ∴ ar(△XZL) = ar( △XZM) Adding ar(△XZY) on both sides , we have ar(△XZL) + ar(△XZY) = ar(△XZM) + ar(△XZY) ⇒ ar(△LZY) = ar(quad.MZYX)

In the figure, chord AB of circle with centre O, is produced to C such that BC = OB. CO is joined and produced to meet the circle in D. -Maths 9th

Description : In the figure, chord AB of circle with centre O, is produced to C such that BC = OB. CO is joined and produced to meet the circle in D. -Maths 9th

Last Answer : In △OBC, OB = BC ⇒ ∠BOC = ∠BCO = y ...[angles opp. to equal sides are equal] ∠OBA is the exterior angle of △BOC So, ∠ABO = 2y ...[ext. angle is equal to the sum of int. opp. angles] Similarly, ∠AOD is the exterior angle of △AOC ∴ x = 2y + y = 3y

The bisectors of the angles of a triangle ABC meet BC, CA and AB at X, Y and Z respectively. -Maths 9th

Description : The bisectors of the angles of a triangle ABC meet BC, CA and AB at X, Y and Z respectively. -Maths 9th

Last Answer : answer:

ABCD is a cyclic quadrilateral such that AC ⊥ BD. AC meet BD at E. Prove that EA^2 + EB^2 + EC^2 + ED^2 = 4R^2, -Maths 9th

Description : ABCD is a cyclic quadrilateral such that AC ⊥ BD. AC meet BD at E. Prove that EA^2 + EB^2 + EC^2 + ED^2 = 4R^2, -Maths 9th

Last Answer : answer:

The moment of a force a.Occurs about a point b.Measures the capacity to do useful work c.Occurs only when bodies are in motion d.Measures the ability to produce turning or twisting about an axes e.None of the above

Description : The moment of a force a.Occurs about a point b.Measures the capacity to do useful work c.Occurs only when bodies are in motion d.Measures the ability to produce turning or twisting about an axes e.None of the above

Last Answer : d. Measures the ability to produce turning or twisting about an axes

Find the point on the curve `9y^2=x^3,` where the normal to the curve makes equal intercepts on the axes.

Description : Find the point on the curve `9y^2=x^3,` where the normal to the curve makes equal intercepts on the axes.

Last Answer : Find the point on the curve `9y^2=x^3,` where the normal to the curve makes equal intercepts on the axes. A. `(3, ... `(3, pm 8/3)` D. `(4, pm 3/8)`

Find the point on the curve `9y^2=x^3,` where the normal to the curve makes equal intercepts on the axes.

Description : Find the point on the curve `9y^2=x^3,` where the normal to the curve makes equal intercepts on the axes.

Last Answer : Find the point on the curve `9y^2=x^3,` where the normal to the curve makes equal intercepts on the axes.

The reaction step that has its transition state at the highest point on the reaction coordinate is the called the __________. (a) rate-determining step (b) activation energy (c) transition step (d) product favored step

Description : The reaction step that has its transition state at the highest point on the reaction coordinate is the called the __________. (a) rate-determining step (b) activation energy (c) transition step (d) product favored step

Last Answer : rate-determining step

In homogenous coordinate system (x, y, z) the points with z = 0 are called (A) Cartesian points (B) Parallel points (C) Origin point (D) Point at infinity

Description : In homogenous coordinate system (x, y, z) the points with z = 0 are called (A) Cartesian points (B) Parallel points (C) Origin point (D) Point at infinity

Last Answer : (D) Point at infinity

If two chords of a circle with a common end-point are inclined equally to the diameter through this common end-point, then prove that chords are equal. -Maths 9th

Description : If two chords of a circle with a common end-point are inclined equally to the diameter through this common end-point, then prove that chords are equal. -Maths 9th

Last Answer : Let AB and AC be two chords and AD be the diameter of the circle . Draw OL ⊥ AB and OM ⊥ AC . In ΔOLA and ΔOMA ∠ OLA = ∠ OMA = 90° OA = OA [common sides] ∠ OAL = ∠ OAM [given] . OLA ≅ OMA [by ASA congruency] OL =OM (by CPCT) Chords AM and AC are equidistant from O. ∴ AB = AC Hence proved.

In figure, AB and CD are two chords of a circle intersecting each other at point E. -Maths 9th

Description : In figure, AB and CD are two chords of a circle intersecting each other at point E. -Maths 9th

Last Answer : Given In a figure, two chords AB and CD intersecting each other at point E.

Two equal chords AB and CD of a circle when produced intersect at a point P. Prove that PB = PD. -Maths 9th

Description : Two equal chords AB and CD of a circle when produced intersect at a point P. Prove that PB = PD. -Maths 9th

Last Answer : According to question prove that PB = PD.

If two chords of a circle with a common end-point are inclined equally to the diameter through this common end-point, then prove that chords are equal. -Maths 9th

Description : If two chords of a circle with a common end-point are inclined equally to the diameter through this common end-point, then prove that chords are equal. -Maths 9th

Last Answer : Let AB and AC be two chords and AD be the diameter of the circle . Draw OL ⊥ AB and OM ⊥ AC . In ΔOLA and ΔOMA ∠ OLA = ∠ OMA = 90° OA = OA [common sides] ∠ OAL = ∠ OAM [given] . OLA ≅ OMA [by ASA congruency] OL =OM (by CPCT) Chords AM and AC are equidistant from O. ∴ AB = AC Hence proved.

In figure, AB and CD are two chords of a circle intersecting each other at point E. -Maths 9th

Description : In figure, AB and CD are two chords of a circle intersecting each other at point E. -Maths 9th

Last Answer : Given In a figure, two chords AB and CD intersecting each other at point E.

Two equal chords AB and CD of a circle when produced intersect at a point P. Prove that PB = PD. -Maths 9th

Description : Two equal chords AB and CD of a circle when produced intersect at a point P. Prove that PB = PD. -Maths 9th

Last Answer : According to question prove that PB = PD.