(d) x = yThe equations of the given lines are: 4x + 3y = 12 ...(i) 3x + 4y = 12 ...(ii) Solving the simultaneous equations (i) and (ii), we get\(x\) = \(rac{12}{7}\), y = \(rac{12}{7}\)∴ Point of the intersection of the given lines is \(\bigg(\)\(rac{12}{7}\), \(rac{12}{7}\)\(\bigg)\)Now equation of the line passing through (0, 0) and\(\bigg(\)\(rac{12}{7}\), \(rac{12}{7}\)\(\bigg)\)isy - 0 = \(\bigg(rac{rac{12}{7}-0}{rac{12}{7}-0}\bigg)\) (x – 0), i.e., y = x.