Simplifying by combining similar terms : -Maths 9th

1 Answer

Answer :

Reducing into simplest form : √45 = √32 × 5 = 3√5 √20 = √22 × 5 = 2√5     ∴ √45 -3√20 + 4√5 =  3√5 - 3 × 2√5 + 4√5   = 3√5 - 6√5 + 4√5   = √5      

Related questions

Description : Simplifying by combining similar terms: -Maths 9th

Last Answer : Reducing into simplest form

Description : Simplifying by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form : √45 = √32 × 5 = 3√5 √20 = √22 × 5 = 2√5 ∴ √45 -3√20 + 4√5 = 3√5 - 3 × 2√5 + 4√5 = 3√5 - 6√5 + 4√5 = √5

Description : Simplifying by combining similar terms: -Maths 9th

Last Answer : Reducing into simplest form

Description : Simplify by combining similar terms: -Maths 9th

Last Answer : 5√2 + 20√2 = (5+20)√2 = 25√2

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form √12 = √22 × 3 = 2√3 √75 = √3 × 52 = 5√3 Therefore 4√3 - 3√12 + 2√75 = 4√3 - 3 × 2√3 + 2 × 5√3 = 4√3 - 6√3 + 10√3 = (4 - 6 + 10) √3 = 8√3

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form √8 = √(22× 2) = 2 × √2 √32 = √(22 × 22 × 2) = 2 × 2√2 = 4√2 ∴ √8 + √32 - √2 = 2√2 + 4√2 - √2 = (2 + 4 -1) √2 = 5√2 .

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : √12 = √(22 × 3) = 2√3 √50 = √(2 × 52) = (5 √2) √48 = √(22 × 22 × 3) = (2 × 2√3)= 4√3 ∴ 4√12 - √50 - 7 √48 = 4 × 2√3 - 5√2 - 7 × 4√3 = 8√3 - 5√2 - 28√3 = (8 -28)√3 - 5√2 = -20√3 - 5√2

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form

Description : Simplify by combining similar terms: -Maths 9th

Last Answer : 5√2 + 20√2 = (5+20)√2 = 25√2

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form √12 = √22 × 3 = 2√3 √75 = √3 × 52 = 5√3 Therefore 4√3 - 3√12 + 2√75 = 4√3 - 3 × 2√3 + 2 × 5√3 = 4√3 - 6√3 + 10√3 = (4 - 6 + 10) √3 = 8√3

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form √8 = √(22× 2) = 2 × √2 √32 = √(22 × 22 × 2) = 2 × 2√2 = 4√2 ∴ √8 + √32 - √2 = 2√2 + 4√2 - √2 = (2 + 4 -1) √2 = 5√2 .

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : √12 = √(22 × 3) = 2√3 √50 = √(2 × 52) = (5 √2) √48 = √(22 × 22 × 3) = (2 × 2√3)= 4√3 ∴ 4√12 - √50 - 7 √48 = 4 × 2√3 - 5√2 - 7 × 4√3 = 8√3 - 5√2 - 28√3 = (8 -28)√3 - 5√2 = -20√3 - 5√2

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form

Description : Aman was facing some difficulties in simplifying -Maths 9th

Last Answer : Solution:- 1/( √7 - √3) = 1/(√7 - √3) x √7 + √3/√7 + √3 = √7 + √3/(√7)2 - (√3)2 = (√7 + √3)/4 Helpfulness, cooperativeness, knowledge.

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Description : Find the ratio by mass of the combining elements in the following compounds. -Maths 9th

Last Answer : (a) CaCOg → Ca: C :0 = 40:12 : 48= 10 : 3:12 (b) MgCI2 → Mg : Cl = 24 : 2 x 35.5 = 24 : 71 (c) H2SO4 → H : S : O = 2 x 1 : 32 : 4 x 16 = 2 : 32 : 64= 1:16: 32 (d) C2H5OH → C : H : 0 = 2 x 12 : 6 x 1 ... N : H = 14 : 3 x 1=14: 3 (f) Ca (OH)2 → Ca : 0 : H = 40 : 2 x 16 : 2 x 1= 40: 32 :2 = 20 :16:1

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Description : Let R be a relation defined on the set A of all triangles such that R = {(T1, T2) : T1 is similar to T2}. Then R is -Maths 9th

Last Answer : (d) An equivalence relation.Every triangle is similar to itself, so (T1, T1) ∈ R ⇒ R is reflexive. (T1, T2) ∈ R ⇒ T1 ~ T2 ⇒T2 ~ T1, ⇒ (T2, T1) ∈ R ⇒ R is symmetrictransitive. ∴ R is an equivalence relation.

Description : Inside a triangular park, there is a flower bed forming a similar triangle. Around the flower bed runs a uniform path of such a width that the -Maths 9th

Last Answer : (d) 3 : 1Let ABC be the triangular flower bed of side lengths a, b and c respectively. Then Area of ΔABC = \(\sqrt{s(s-a)(s-b)(s-c)}\)where s = \(rac{a+b+c}{2}\)Now according to the given condition,ΔPQR ... of ΔABC - Area of ΔABC= 3 (Area of ΔABC)∴ Reqd. Ratio = Area of Path : Area of ΔABC = 3 : 1.

Description : Draw an equiliateral triangle of height 3.6 cm. Draw another triangle similar to it such that its side is of the side of the first. -Maths 9th

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Description : Express x in terms of y for the linear equation 23x +4y = -7. -Maths 9th

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Description : If a, b, c be the p^th, q^th, r^th terms of a GP, then the value of (q – r) log a + (r – p) -Maths 9th

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Description : What is the sum, of 'n' terms in the series : log m + log -Maths 9th

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Description : The sum of n terms of the series -Maths 9th

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Description : G is the centroid of ΔABC with height h units. If a line DE parallel to BC cuts ΔABC at a height h/4 from BC, find the distance GG' in terms of AG -Maths 9th

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Description : What is bronze made by combining with copper ?

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