An electron moving with a velocity of 5 × 10 3 m / s enters into a uniform electric field and acquires a uniform acceleration of 10 3 m / s 2 in the direction of initial velocity. i. Find out the time in which electron velocity will be doubled.? ii. How much distance electron would cover in this time.? -Science

An electron moving with a velocity of 5 × 10 3 m / s enters into a uniform electric field and acquires a uniform acceleration of 10 3 m / s 2 in the direction of initial velocity. i. Find out the time in which electron velocity will be doubled.? ii. How much distance electron would cover in this time.? -Science
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Answer :

Given u=5×103m/su=5×103m/s , a=103m/s2a=103m/s2, v=2u=104v=2u=104 m/s i.Using v=u+atv=u+at 104=5×103+103t104=5×103+103t or t=5 sec ii. Using s=ut+12at2s=ut+12at2 s=5×103×5+12×103×52s=5×103×5+12×103×52 =37.5×103m=37.5×103m
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