Description : A train travelling at 20 m s-1 accelerates at 0.5 m s-2 for 30 s, the distance travelled by train is A. 825 m B. 700 m C. 650 m D. 600 m
Last Answer : 825 m
Description : A locomotive of weight 100 tonnes is attached to train of wagons weighing 1000 tonnes. The locomotive pulls the wagons with a constant velocity of 36 km/hour. When the coupling between the train and wagons breaks, the wagons roll on 95 m in ... would be a.0.36 m b.0.44 m c.0.77 m. d.0.5 m e.0.66 m
Last Answer : d. 0.5 m
Description : A rocket is fired vertically from the ground with a resultant vertical acceleration of 10 m/sec the fuel is finished in one minute and it continues to move up. The maximum height reached will be a.2 km b.20 km c.36 km d.10 km e.80 km
Last Answer : a. 2 km
Description : A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km
Last Answer : 3) 840 km
Description : The maximum speed of a train is 90 km/h. It takes 10 hours to cover a distance of 500 km. Find the ratio of its average speed to maximum speed? -Science
Last Answer : Average speed=total distancetime=50010=50Average speed=total distancetime=50010=50 km/hr Ratio of average speed to maximum speed= 50:90=5:9
Description : It takes 60 sec for a train running at 162 km/hr to cross a bridge. And it takes 36 sec for the same speed to cross a boy walking at the rate of 18km/hr in the same direction in which the train is ... the train and length of the platform. A) 1440 &1260m B) 1220 &60m C) 1000 & 1460m D) 1260 &1450m
Last Answer : ANSWER: A Explanation: Relative speed of the train to man = (162 - 18) = 144km/hr Convert km/hr into m/s 144km/hr = (144 * 5 /18) m/s = 40 m/s When the train passes ... of bridge = 2700 length of bridge = 1260 m the length of the bridge & train are 1260 and 1440m
Description : A wheel accelerates from rest with an acceleration of 6 rad/sec2. How many revolutions are experienced in 4 seconds? a.12.36 b.25.6 c.9.82 d.107 dynes e.7.64
Last Answer : e. 7.64
Description : A train travels between two stations 15 km apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform retardation, the maximum speed attained by the train during the journey will by a.125 km/hr b.107 dynes c.80 km/hr d.100 km/hr e.60 km/hr
Last Answer : d. 100 km/hr
Description : A train travels between two stations 15 km, apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform relardation, the maximum speed attained by the train, during, the journey, will be a.60 km/hr b.80 km/hr c.125 km/hr d.100 km/hr e.107 dynes
Description : The distance travelled per turn of α-helix in nm is (A) 0.34 (B) 0.44 (C) 0.54 (D) 0.64
Last Answer : Answer : C
Description : Anil after travelling 6 km towards East from his house realized that he has travelled in a wrong direction, lie turned and travelled 12 km towards West, turned right and travelled 8 km to reach his office. The straight distance of the office from his house is: (A) 20 km (B) 14 km (C) 12 km (D) 10 km
Last Answer : Answer: D
Description : Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds -Physics 9th
Last Answer : Uniform acceleration in the interval between 4th and 5th seconds = = (5u + 1/2 * a * 5^2) - (4u + 1/2 * a * 4^2) = 5u + 1/2 *a * 25 - 4u + 1/2 * a * 16 = u + 1/2 * a * (25-16) = u + 1/2 * a * 9 = u + 9/2 * a If it starts from rest then the displacement will be 9/2a. hope this helps!
Description : Distance travelled by a body in time ‘t’ is A. instantaneous speed B. average velocity C. average acceleration D. instantaneous acceleration
Last Answer : average velocity
Description : How much distance was traveled by first train of India? (a) 33 km (b) 36 km (c) 34 km (d) 46 km
Last Answer : (c) 34 km
Description : Horizontal distance travelled by a ball if it's thrown with initial velocity of 20 m s-1 at an angle of 30° is A. 24 m B. 56 m C. 35.3 m D. 36.3 m
Last Answer : 35.3 m
Description : In certain city the Taxi charges comprise of a fixed charge and the charge of the distance travelled. A person paid Rs.156 for a journey of 16 km and another person paid Rs.204 for the journey of 24 km. The amount paid by a passenger who has travelled 30 km is (A) 236 (B) 240 (C) 248 (D) 256
Last Answer : Answer: B
Description : 2 bus start from A & B respectively and travel towards each other at a speed of 150 km/hr and 120 km/hr respectively. By the time they meet, the first bus has travelled by 300km more than the second. The distance between A & B is a) 2700 b) 2800 c) 2750 d) 2457
Last Answer : A At the time of meeting, Let the distance travelled by the second bus be xkm Then distance covered by the 1st bus is (x+300)km x/120= (x+300) /150 150x = 120(x+300) 150x = 120x +36000 30x = ... X=36000/30 X=1200 So the distance covered between A & B =(x+x+300) =(1200+1200+300) =2700km.
Description : Mr.Aneesh left for city 1 from city 2 at 3.00 pm. He travelled at the speed of 60km/hr for 1 and half hours. After that the speed was reduced to 15 km/hr. If the distance between two cities is 120 kms, at what time did Mr.Aneesh reach city 1 ? a) 6.30 pm. b) 5.30 pm. c) 7.30 pm. d) 8.30 pm.
Last Answer : A Mr.Aneesh travelled 60 km/hr for 1 1/2 hours (3/2 hours). Distance covered in 3/2 hours = 60 x 3/2 = 90 km. Therefore, remaining distance = 120 -90 = 30 km After 3/2 hours, the speed was ... village 2 at 3.00 pm + 3 hours 30 minutes = 6.30pm Hence the required answer is 6.30 pm.
Description : The speed of a van increases by 5 kmph after every one hour. If the distance travelled in the first one hour was 55 km, what was the total distance travelled in 8 hours? a) 580km b) 116km c) 147km d) 240km
Last Answer : A Distance travelled in 1ST hour =55 km Speed of the van increases by 5 kmph after every one hour. Hence, distance travelled in 2nd hour =60 km distance travelled in 3rd hour =65 km and so on Total distance travelled =(55+60+……..+(8 terms)) =8/2(2*55+(8-1)5) =4(110+35) =580km
Description : X and y are two trains of length 500m and 400m run on parallel lines. When they run in the same direction it will take 60 sec to cross each other. When they run in opposite direction, it will take 20 sec to cross each ... ) A) 116 and 42 km/hr B) 54 and 78km/hr C) 104 and 60km/hr D) 108 and 54km/hr
Last Answer : ANSWER : D Explanation: Let the speed of 2 trains be a1 and a2 Total distance covered to cross each other = (500 + 400)m = 900m When they run in the same direction, Relative speed = a1 - a2 = 900 /60 ... hr a 2= (15 * 18 / 5)m/s = 54km/hr Speed of two trains are 108 and 54 km/hr
Description : A train covers the first half of the distance between two stations with a speed of 40 km/h and the other half with 60 km/h. Then its average speed is
Last Answer : A train covers the first half of the distance between two stations with a speed of 40 km/h and the other half with ... 48 km/h C. 52 km/h D. 100 km/h
Description : A train leaves Mumbai for chennai at 6 : 45 a.m. and goes at the rate of 100 km/h. Another train leaves Chennai for Mumbai at 4.30a.m. and goes at the rate of 120 km/h. If the distance between both is 1240 km, at what distance from Mumbai will the two trains meet? A) 210km B) 324km C) 115km D) 440km
Last Answer : ANSWER: D Explanation: Given speed of the first train = 100kmph speed of the second train = 120kmph The second train leaving Chennai starts its journey earlier and it travels = 120 *(6.45a.m. ... train covers 4.40 *100 = 440 km Therefore the first train meet to the second train at 440km
Description : The distance between two stations ooty and chennai is 615km. A train with speed of 75 km/h leaves ooty at 8:00 am towards chennai. Another train with speed of 105 km/h leaves Chennai at 9 : 00 am towards ooty . Then, at what time both trains meet? A) 6 B) 12 C) 18 D) 24
Last Answer : ANSWER:B Explanation: First train leaves at 8.00am and second leaves at 9.00am So,first train that is , from ooty to Chennai has covered 75 km distance in 1 hr. So , distance left by between the station = ... the trains will meet , 3 hr after second train left i.e., 9.00 am +3 = 12.00 pm
Description : Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these
Last Answer : Answer – C (48 sec) Explanation – Relative speed = all lengths/time [60+90] = [1.10 +0.9 ]/time [ PLUS when opposite direction] time=2/150 = 1/75 h 1 hour______3600 sec 1/75 hr______? ?= 3600/75=48 sec
Description : A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 112 minutes, the length ... is : a) 560 metres b) 620 metres c) 700 meres d) 750 metres e) 720 meters
Last Answer : Answer: c)
Description : The speed of a motor car changes from 18 km/h to 72 km/h in 5 s. Its acceleration is (a) 6 m/s2 (b) 5 m/s2 (c) 4 m/s2 (d) 3 m/s2
Last Answer : Ans:(d)
Description : A car is travelling at 15 m s-1, the distance it will travel in 1 hour is A. 54 km B. 55 km C. 56 km D. 57 km
Last Answer : 54 km
Description : A certain thing is thrown twice from a place with the gap of 45 minutes between the two shots. A girl approaching this point in a train heard the second shot 44 minutes after she heard the first shot. What is the speed of train ... travels at 660 m/s? a) 62 km/hr b) 54 km/hr c) 48 km/hr d) 27 km/hr
Last Answer : B Actual time between the two shots being fired = 45 minutes. If a girl was stationary she would have heard the shots after 44 minutes. But since the train was moving towards the source, she heard the second shot after ... = (15 *18/5) km/hr =54 km/hr Hence the speed of the train is 54 km/hr
Description : Numerical Questions and answers on Motion for Class 9 physics a. What is the distance travelled by the SUV is first 2 seconds? b. What is the braking force at the end of 5 seconds to bring the SUV to a stop within one seconds? -Science
Last Answer : a. The distance travelled by the SUV is first 2 seconds = Area of ΔABEΔABE =12 AE BE=12 AE BE =12 2 15=15m=12 2 15=15m b. Acceleration will be given by the slope of the line CD a=0−156−5= ... =−15m/s2 Now mass of the SUV =1000 Kg Braking Force will be F=ma=1000 −15=−15000NF=ma=1000 −15=−15000N
Description : A scooter travelling at 10 m/s speed up to 20 m/s in 4 sec. Find the acceleration of scooter. -Science
Last Answer : Acceleration is given by a=ΔvΔta=ΔvΔt a=20−104=104=2.5a=20−104=104=2.5 So a=2.5 m/s
Description : Two metro train 360 meters and 360 meters in length respectively and running in same directions, one at the rate of 116 km and other at the rate of 100 km an hours. What time will they be cross of each other? A) 100 sec B) 162sec C) 132sec D) 126sec
Last Answer : ANSWER: B Explanation: Length of the 1st metro train = 360m Length of the 2nd metro train = 360m Total length of the both metro train = 360 + 360 = 720 m speed of the 1st metro train = 116 km/hr ... Required time = distance / speed = (720/(40/9))sec = 720 * 9 /40 = 162sec.
Description : Two trains A and B are moving in opposite directions at 180 km/hr and 270 km/hr. their lengths are 3.30 km and 2.7 km respectively. The time taken by the slower train to cross the faster train in second is. A) 48sec B) 13 sec C) 38sec D) 24sec
Last Answer : ANSWER: A Explanation: Speed of 1st train = 180 km/hr Speed of 2nd train = 270 km/hr Relative speed = (180 + 270)km/hr = 450 km/hr = (450 * 5 / 180)m/s = (2250 / 18)m/s =125 m/s Distance covered = (3.30 + 2.70)km = 6km = 6000m Required time = 6000 / 125 = 48sec
Description : A goods train 110m long is running with the speed of 30 km/hr. in what time will it pass a boy who is running at 3.5 km/hr in the direction opposite to that in which the train is going. A) 9 sec B) 10sec C) 12sec D) 13sec
Last Answer : ANSWER : C Explanation: Length of the train = 110 m Speed of the train = 30 km/hr Speed of the boy = 3.5 km/hr Speed of the train relative to man = (30 + 3.5) km/hr = 33.5 km/hr Convert km/ ... cover 110 m at 9.30 m/s = 110 / 9.30 = 11.8 seconds = 12 sec(approx.).
Description : A passenger train 165 m long which is running at a speed of 30km/hr. In what time will it pass a man who is running at a speed of 3 km/hr in the opposite direction. In which the train is moving. A)14 sec B) 17sec C)16sec D)18sec
Last Answer : ANSWER: D Explanation: Speed of the train = 30 km/hr Speed of man = 3 km/hr Length of the train = 165m If direction is given in opposite direction then we add both speed. That is (30 + 3 )= 33 km/hr ... can easily get the distance of m/s So it cover 165 m i.e., 165 * 6 /55 = 18 sec.
Description : The rajdhani express of 400m runs at a speed of 124 km/hr and a person runs on the platform at a speed of 40km/hr in the direction opposite to that of the train. Find the time taken by the train to cross the running person? A) 7 sec B) 8.78sec C) 7.78sec D) 8 sec
Last Answer : ANSWER : B Explanation: Length of the train = 400m Speed of train = 124 km/hr Speed of person = 40 km/hr Relative speed (speed of trai relative to man) = (124 + 40) km/hr = 164 km/hr [As the ... train to cover 400m at a relative of 45.55 m/s = 400 / 45.55 = 8.78 sec.
Description : A train 170 m long is running at a speed of 22.5 km/hr. what time will it take to cross a 80m long bridge? A) 20 sec B) 40 sec C) 15 sec D) 30sec
Last Answer : ANSWER:B Explanation: Length of the train = 170 m Length of the bridge = 80 m Therefore, length of the train + length of the bridge = (170 + 80) m = 250m Speed of the train = 22.5 km/hr Speed ... .25m/sec Therefore, time taken by the train to cross the bridge = 250 m/6.25 m/sec. = 40 seconds.
Description : An electron moving with a velocity of 5 10 3 m / s enters into a uniform electric field and acquires a uniform acceleration of 10 3 m / s 2 in the direction of initial velocity. i. ... which electron velocity will be doubled.? ii. How much distance electron would cover in this time.? -Science
Last Answer : Given u=5×103m/su=5×103m/s , a=103m/s2a=103m/s2, v=2u=104v=2u=104 m/s i.Using v=u+atv=u+at 104=5×103+103t104=5×103+103t or t=5 sec ii. Using s=ut+12at2s=ut+12at2 s=5×103×5+12×103×52s=5×103×5+12×103×52 =37.5×103m=37.5×103m
Description : When ball having a projectile motion is rising up, it A. decelerates B. accelerates C. rises up with constant acceleration D. acceleration becomes zero
Last Answer : decelerates
Description : Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: A.40 m B.55 m C.65 m D.50 m E.None of these
Last Answer : Answer- D (50) Explanation – Relative speed= total lengths/time (46-36) x 5/18 = [L + L ] / 36 10 x (5/18) x36 x (1/2)= L L=50 m
Description : Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these
Last Answer : Answer – C (36 kmph) Explanation – Let the speed of each train be x m/sec. Then, relative speed of the two trains = 2x m/sec. So, 2x = (120 + 120)/12 ⇔ 2x = 20 ⇔ x = 10. ∴ Speed of each train = 10 m/sec = [10 x 18/5] km/hr = 36 km/hr
Description : The average speed of a train is 1 3/7 times the average speed of a car. The car covers a distance of 616 km in 8 hours. How much distance will the train cover in 13 hours? a) 1340 km b) 1423 km c) 1430 km d) 1936 km e) None of these
Last Answer : speed of the car = 616/8 = 77km/hr speed of the train = 10/7 × 77 = 110 km/hr Distance covered by train = 110 × 13 = 1430 km. Answer: c)
Description : Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77
Last Answer : D Total distance = (400+250+50+600)km =1300 km Total time taken = (400/70 + 600/80+250/60+50/40) hrs =(40/7 +60/8+25/6+5/4) =(24*40)+(21*60)+(28*25)+(42*5) / 168 =960+1260+700+210 / 168 =(3130 / 168) Average speed =(1300*168 / 3130) km/hr =218400/3130 =69.77 km/hr
Description : A body moves, from rest with a constant acceleration of 5 m per sec. The distance covered in 5 sec is most nearly (A) 38 m (B) 62.5 m (C) 96 m (D) 124 m
Last Answer : (B) 62.5 m
Description : Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64
Last Answer : C Total time taken = 4 hours; Time of stoppage = 1 hour, that is, actual time taken = 4 hours - 1 hours = 3 hours Speed = Distance/Time = 216/3 = 72 km/hr Average speed = Total Distance/ Total Time = 216/4 = 54 km/hr
Description : A car travelled south-west for 200 miles depicts A. distance B. speed C. velocity D. displacement
Last Answer : displacement
Description : The speed of a car increases by 2 kms after every one hour. If the distance travelled in the first one hour was 35 kms, what was the total distance traveled in 12 hours? A.456 kms B.482 kms C.552 kms D.556 kms E.None of these
Last Answer : Answer – C (552 kms) Explanation – Total distance travelled in 12 hours = (35 + 37 + 39 + …… upto 12 terms) This is an A.P. with first term, a = 35, number of terms, n = 12, common difference, d =2. Required distance =12/2 (2 x 35 + (12 – 1) x 2) = 6(70 + 22) = 552 kms
Description : The velocity-time graph shows the motion of a cyclist. Find (i) its acceleration (ii) its velocity (iii) the distance covered by the cyclist in 15 seconds Numerical Questions and answers on Motion for Class 9 physics -Science
Last Answer : (i) We can see from the graph that velocity is not changing So,acceleration is equal to zero. (ii) By Reading the graph, velocity = 20 m/s (iii) Distance covered in 15 seconds, s=u×t=20×15=300s=u×t=20×15=300 m
Description : The distance between two cities A and B is 330km. A train starts from A at 8 (a)m. and travels towards B at 60 km/hr. Another train starts from B at 9 (a)m. and travels towards A at 75 km/hr. At what time do they meet? a) 10 am. b) 10 : 30 am. c) 11 am. d) 11 : 30 am. e) None of these
Last Answer : Distance travelled by first train in one hour = 60 x 1 = 60 km Therefore, distance between two train at 9 a.m. = 330 – 60 = 270 km Now, Relative speed of two trains = 60 + 75 = 135 km/hr Time of meeting of two trains =270/135=2 hrs. Therefore, both the trains will meet at 9 + 2 = 11 A.M. Answer: c)
Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these
Last Answer : Answer – C (11 am) Explanation – Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330 60x + 75(x – 1) = 330 x = 3 So, they meet at (8 + 3), i.e. 11 a.m