In moment distribution method the effect of applies moment on adjacent joints are a. neglected b. carried over c. multiplied by a factor before applying d. distributed over the span

In moment distribution method the effect of applies moment on adjacent joints are a. neglected
b. carried over
c. multiplied by a factor before applying
d. distributed over the span
by

1 Answer

Answer :

b. carried over
by

Related questions

In moment distribution method any unbalanced moment at a joint is a. neglected b. multiplied by a factor to solve c. distributed in the spans d.considered infinite

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Last Answer : c. distributed in the spans

A continuous beam is simply supported on its one or both the end supports the fixing moment on simply supported beam end is a. zero b. infinite c. neglected in calculation d. multiplied by a cross over factor in calculation

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Effect of applied moment at a joint on the other joints is known as the a.carry in factor b. carry over factor c.carry up factor d.carry down factor

Description : Effect of applied moment at a joint on the other joints is known as the a.carry in factor b. carry over factor c.carry up factor d.carry down factor

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In a fixed beam the total change of slope along the span is a. Zero b.infinite c. neglected d.assumed to be unit value

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In continuous beam if it is end is fixed supported the bending moment will be a. zero b. neglected c. infinite

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In continuous beam if it is end simply supported the bending moment will be a. zero b. neglected c. infinite

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A beam of uniform rectangular section 200 mm wide and 300mm deep is simply supported at its ends.It carries a uniformly distributed load of 9KN/m run over the entire span of 5m.If E=1×104 N/mm2, what is the maximum deflection? a.14.26 mm b.17.28 mm c.18.53 mm d.16.27 mm.

Description : A beam of uniform rectangular section 200 mm wide and 300mm deep is simply supported at its ends.It carries a uniformly distributed load of 9KN/m run over the entire span of 5m.If E=1×104 N/mm2, what is the maximum deflection? a.14.26 mm b.17.28 mm c.18.53 mm d.16.27 mm.

Last Answer : d.16.27 mm.

A simply supported beam carries a uniformly distributed load over the whole span.The deflection at the centre is y.If the distributed load per unit length is doubled and also depth of beam is doubled ,then the deflection at the centre would be a.2y b.4y c.y/2 d.y/4.

Description : A simply supported beam carries a uniformly distributed load over the whole span.The deflection at the centre is y.If the distributed load per unit length is doubled and also depth of beam is doubled ,then the deflection at the centre would be a.2y b.4y c.y/2 d.y/4.

Last Answer : d.y/4.

A simply supported beam is of rectangular section.It carries a uniformly distributed load over the whole span.The deflection at the centre is y.If the depth of beam is doubled ,the deflection at the centre would be a.2y b.4y c.y/2 d.y/8.

Description : A simply supported beam is of rectangular section.It carries a uniformly distributed load over the whole span.The deflection at the centre is y.If the depth of beam is doubled ,the deflection at the centre would be a.2y b.4y c.y/2 d.y/8.

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In a simply supported beam carrying a uniformly distributed load over the left half span, the point of contraflexure will occur in (a) Left half span of the beam (b) Right half span of the beam. (c) Quarter points of the beam (d) Does not exist

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The shear force at the centre of a simply supported beam of span l carrying a uniformly distributed load of w per unit length over the whole span is (a) wl (b) wl/2 (c) wl/4 (d) Zero

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In the three moment equation method a. imaginary span unit span is assumed b. imaginary span zero span is assumed c. no imaginary span assumed d.twice the imaginary span is assumed

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In the theorem of three moments a.both end sinking are considered b.one end sinking is considered c.sinking is neglected d.sinking is modified by a factor

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In a simply supported beam subjected to uniformly distributed load (w) over the entire length (l), total load=W, maximum Bending moment is (a) Wl/8 or wl2/8 at the mid-point (b) Wl/8 or wl2/8 at the end (c) Wl/4 or wl2/4 (d) Wl/2

Description : In a simply supported beam subjected to uniformly distributed load (w) over the entire length (l), total load=W, maximum Bending moment is (a) Wl/8 or wl2/8 at the mid-point (b) Wl/8 or wl2/8 at the end (c) Wl/4 or wl2/4 (d) Wl/2

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The bending moment diagram for a cantilever with U.D.L. over the whole span will be (a) Triangle (b) Rectangle (c) Parabola (d) Ellipse

Description : The bending moment diagram for a cantilever with U.D.L. over the whole span will be (a) Triangle (b) Rectangle (c) Parabola (d) Ellipse

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In moment distribution method initially all the members of the beam as assumed to be a.free b.fixed c.partially free d.partially fixed

Description : In moment distribution method initially all the members of the beam as assumed to be a.free b.fixed c.partially free d.partially fixed

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While calculating bending stress in the following welded joints which of the welds moment of inertia can be neglected? a) 1 b) None of the listed c) Both 1 & 3 d) Both 2 & 4

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In a cantilever subjected to a combination of concentrated load, uniformly distributed load and uniformly varying load, Maximum bending moment is (a) Where shear force=0 (b) At the free end (c) At the fixed end (d) At the mid-point

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A sudden jump anywhere on the Bending moment diagram of a beam is caused by (a) Couple acting at that point (b) Couple acting at some other point (c) Concentrated load at the point (d) Uniformly distributed load or Uniformly varying load on the beam

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For any part of a beam subjected to uniformly distributed load, bending moment diagram is (a) Horizontal straight line (b) Vertical straight line (c) Line inclined to x-axis (d) Parabola

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In a simply supported beam, bending moment at the end (a) Is always zero if it does not carry couple at the end (b) Is zero, if the beam has uniformly distributed load only (c) Is zero if the beam has concentrated loads only (d) May or may not be zero

Description : In a simply supported beam, bending moment at the end (a) Is always zero if it does not carry couple at the end (b) Is zero, if the beam has uniformly distributed load only (c) Is zero if the beam has concentrated loads only (d) May or may not be zero

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In continuous beam with couple , the couple will cause a. negative moment in one part and positive moment in other part of the span b. negative moment in both part of the span c. no moment d. positive moment in both part of the span

Description : In continuous beam with couple , the couple will cause a. negative moment in one part and positive moment in other part of the span b. negative moment in both part of the span c. no moment d. positive moment in both part of the span

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In comparison with a simply supported beam of same span and load , a continuous beam has a.less maximum bending moment b. same bending moment c. higher maximum bending moment d. twice the bending moment

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For the same span and loads fixed beam in comparison with simply supported beams has a. lesser value of maximum bending moment b. more value of maximum bending moment c.twice the value of maximum bending moment d.same value of maximum bending moment

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A concentrated load P acts on a simply supported beam of span L at a distance L/3 from the left support. The bending moment at the point of application of the load is given by (a) PL/3 (b) 2PL/3 (c) PL/9 (d) 2PL/9

Description : A concentrated load P acts on a simply supported beam of span L at a distance L/3 from the left support. The bending moment at the point of application of the load is given by (a) PL/3 (b) 2PL/3 (c) PL/9 (d) 2PL/9

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If a continuous beam is fixed on the right then the imaginary span is taken a.before the right end b. after the right end c. before the left end d. after the left end

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A cantilever of length 3m carries a uniformly distributed load of 15KN/m over a length of 2m from the free end.If I= 108 mm4 and E= 2×105 N/mm2,find the slope at the free end? a.0.00326 rad b.0.00578 rad c.0.00677 rad d.0.00786 rad

Description : A cantilever of length 3m carries a uniformly distributed load of 15KN/m over a length of 2m from the free end.If I= 108 mm4 and E= 2×105 N/mm2,find the slope at the free end? a.0.00326 rad b.0.00578 rad c.0.00677 rad d.0.00786 rad

Last Answer : a.0.00326 rad

A cantilever of length 3 m carries a uniformly distributed load over the entire length.If the deflection at the free end is 40 mm,find the slope at the free end. a.0.0115 rad b.0.01777 rad c.0.001566 rad d.0.00144 rad

Description : A cantilever of length 3 m carries a uniformly distributed load over the entire length.If the deflection at the free end is 40 mm,find the slope at the free end. a.0.0115 rad b.0.01777 rad c.0.001566 rad d.0.00144 rad

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The slope at the free end of a cantilever of length 1m is 10 .If the cantilever carries a uniformly distributed load over the whole length ,then the deflection at the free end will be a.1cm b.1.309 cm c.2.618 cm. d.3.927cm.

Description : The slope at the free end of a cantilever of length 1m is 10 .If the cantilever carries a uniformly distributed load over the whole length ,then the deflection at the free end will be a.1cm b.1.309 cm c.2.618 cm. d.3.927cm.

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A simply supported beam carries uniformly distributed load of 20 kN/m over the length of 5 m. If flexural rigidity is 30000 kN.m2, what is the maximum deflection in the beam? a. 5.4 mm b. 1.08 mm c. 6.2 mm d. 8.6 mm

Description : A simply supported beam carries uniformly distributed load of 20 kN/m over the length of 5 m. If flexural rigidity is 30000 kN.m2, what is the maximum deflection in the beam? a. 5.4 mm b. 1.08 mm c. 6.2 mm d. 8.6 mm

Last Answer : a. 5.4 mm

In continuous over the mid span, the deflection is a. concave up b. concave down c. convex up d. convex down

Description : In continuous over the mid span, the deflection is a. concave up b. concave down c. convex up d. convex down

Last Answer : a. concave up

Maximum deflection in a S.S beam with UDL w over the entire span will be a. at the left hand support. b.at the right support. c. at the centre. d.none.

Description : Maximum deflection in a S.S beam with UDL w over the entire span will be a. at the left hand support. b.at the right support. c. at the centre. d.none.

Last Answer : c. at the centre.

Maximum deflection in a S.S beam with UDL w over the entire span will be a. 3wl4 /584EI. b. 5wl4/384EI. C. 7wl4/384EI. d. None.

Description : Maximum deflection in a S.S beam with UDL w over the entire span will be a. 3wl4 /584EI. b. 5wl4/384EI. C. 7wl4/384EI. d. None.

Last Answer : b. 5wl4/384EI.

A cantilever beam of length of 2m carries a U.D.L. of 150 N/m over its whole span. The maximum shear force in the beam will be (a) 150 N (b) 300 N (c) 150 N-m (d) 600 N-m

Description : A cantilever beam of length of 2m carries a U.D.L. of 150 N/m over its whole span. The maximum shear force in the beam will be (a) 150 N (b) 300 N (c) 150 N-m (d) 600 N-m

Last Answer : (b) 300 N

For a simply supported beam of span L, loaded with U.D.L. w/m over the whole span, the maximum B.M will be (a) wL/4 (b) wL2 /8 (c) wL2 /4 (d) WwL2 /2

Description : For a simply supported beam of span L, loaded with U.D.L. w/m over the whole span, the maximum B.M will be (a) wL/4 (b) wL2 /8 (c) wL2 /4 (d) WwL2 /2

Last Answer : (b) wL2

In which condition the axial distance between two adjacent coils is called as pitch? a. Compressed condition b. Uncompressed condition c. Both a. and b. d. None of the above

Description : In which condition the axial distance between two adjacent coils is called as pitch? a. Compressed condition b. Uncompressed condition c. Both a. and b. d. None of the above

Last Answer : b. Uncompressed condition

The property of a material by which it can be drawn to a smaller section by applying a tensile load is called (a) Elasticity (b) Plasticity (c) Ductility (d) Malleability

Description : The property of a material by which it can be drawn to a smaller section by applying a tensile load is called (a) Elasticity (b) Plasticity (c) Ductility (d) Malleabilityy

Last Answer : (c) Ductility

The number of moment equation in Clapeyron’s method is a.2 b.3 c.4 d.5

Description : The number of moment equation in Clapeyron’s method is a.2 b.3 c.4 d.5

Last Answer : b.3

Deflection is found out by moment area method by using a. First moment of area. b. Second moment of area. c. Third moment of area. d.None.

Description : Deflection is found out by moment area method by using a. First moment of area. b. Second moment of area. c. Third moment of area. d.None.

Last Answer : a. First moment of area.

Differences in deflections between two points A and B by the moment area method is given by a.(Area of BMD diagram between A and B ).XB/2EI. b.(Area of BMD diagram between A and B).XB/3EI c.(Area of BMD diagram between A and B) .XB/EI d.None.

Description : Differences in deflections between two points A and B by the moment area method is given by a.(Area of BMD diagram between A and B ).XB/2EI. b.(Area of BMD diagram between A and B).XB/3EI c.(Area of BMD diagram between A and B) .XB/EI d.None.

Last Answer : c.(Area of BMD diagram between A and B) .XB/EI

.Differences in slopes between two points A and B by the moment area method is given by a.Area of BMD diagram between A and B /2EI. b.Area of BMD diagram between A and B /3EI. C.Area of BMD diagram between A and B /EI d.None.

Description : .Differences in slopes between two points A and B by the moment area method is given by a.Area of BMD diagram between A and B /2EI. b.Area of BMD diagram between A and B /3EI. C.Area of BMD diagram between A and B /EI d.None.

Last Answer : C.Area of BMD diagram between A and B /EI

When a uniformly distributed load, shorter than the span of the girder, moves from left to right, then the conditions for maximum bending moment at a section is that (A) The head of the load reaches the section (B) The tail of the load reaches the section (C) The load position should be such that the section divides it equally on both sides (D) The load position should be such that the section divides the load in the same ratio as it divides the span

Description : When a uniformly distributed load, shorter than the span of the girder, moves from left to right, then the conditions for maximum bending moment at a section is that (A) The head of the load ... position should be such that the section divides the load in the same ratio as it divides the span

Last Answer : (D) The load position should be such that the section divides the load in the same ratio as it divides the span

When a uniformly distributed load, longer than the span of the girder, moves from left to right, then the maximum bending moment at mid section of span occurs when the uniformly distributed load occupies (A) Less than the left half span (B) Whole of left half span (C) More than the left half span (D) Whole span

Description : When a uniformly distributed load, longer than the span of the girder, moves from left to right, then the maximum bending moment at mid section of span occurs when the uniformly distributed load occupies (A) Less ... (B) Whole of left half span (C) More than the left half span (D) Whole span

Last Answer : (D) Whole span

A simply supported beam of span carries a uniformly distributed load . The maximum bending moment is (A) WL/2 (B) WL/4 (C) WL/8 (D) WL/12

Description : A simply supported beam of span carries a uniformly distributed load . The maximum bending moment is (A) WL/2 (B) WL/4 (C) WL/8 (D) WL/12

Last Answer : (C) WL/8

If a three hinged parabolic arch carries a uniformly distributed load on its entire span, every section of the arch resists. (A) Compressive force (B) Tensile force (C) Shear force (D) Bending moment

Description : If a three hinged parabolic arch carries a uniformly distributed load on its entire span, every section of the arch resists. (A) Compressive force (B) Tensile force (C) Shear force (D) Bending moment

Last Answer : (A) Compressive force

A uniformly distributed load (w) of length shorter than the span crosses a girder. The bending moment at a section in the girder will be maximum when (a) Head of the load is at the section (b) Tail of the load is at the section (c) Section divides the load in the same ratio as it divides the span (d) Section divides the load in two equal lengths.

Description : A uniformly distributed load (w) of length shorter than the span crosses a girder. The bending moment at a section in the girder will be maximum when (a) Head of the load is at the section (b) Tail ... load in the same ratio as it divides the span (d) Section divides the load in two equal lengths.

Last Answer : (c) Section divides the load in the same ratio as it divides the span

Find the correct statement from the followings. (a) For a cantilever slab, the ratio of span to overall depth should not 12. (b) One way slab which carry uniformly distributed load should be designed to resist a sagging bending moment near mid-span. (c) When the slab is built into a brick or masonry wall the slab should be designed to resist a hogging moment at the face of the support. (d) All of the above.

Description : Find the correct statement from the followings. (a) For a cantilever slab, the ratio of span to overall depth should not 12. (b) One way slab which carry uniformly distributed load should be designed to ... be designed to resist a hogging moment at the face of the support. (d) All of the above.

Last Answer : (d) All of the above.

A uniformly distributed load of 20 kN/m acts on a simply supported beam of rectangular cross section of width 20 mm and depth 60 mm. What is the maximum bending stress acting on the beam of 5m? a. 5030 Mpa b. 5208 Mpa c. 6600 Mpa d. Insufficient data

Description : A uniformly distributed load of 20 kN/m acts on a simply supported beam of rectangular cross section of width 20 mm and depth 60 mm. What is the maximum bending stress acting on the beam of 5m? a. 5030 Mpa b. 5208 Mpa c. 6600 Mpa d. Insufficient data

Last Answer : b. 5208 Mpa

For any part of a beam subjected to uniformly distributed load, Shear force diagram is (a) Horizontal straight line (b) Vertical straight line (c) Line inclined to x-axis (d) Parabola

Description : For any part of a beam subjected to uniformly distributed load, Shear force diagram is (a) Horizontal straight line (b) Vertical straight line (c) Line inclined to x-axis (d) Parabola

Last Answer : (c) Line inclined to x-axis

Corresponding to Fig. (3), the loading on the portion AD of the beam will be (a) Uniformly distributed load (b) Uniformly varying load (c) Point loads (d) Cannot be said

Description : Corresponding to Fig. (3), the loading on the portion AD of the beam will be (a) Uniformly distributed load (b) Uniformly varying load (c) Point loads (d) Cannot be said

Last Answer : (a) Uniformly distributed load