Any number with an exponent of one is equal to 128) A) two. B) itself. C) zero. D) on

Any number with an exponent of one is equal to 128) A) two. B) itself. C) zero. D) on
by

1 Answer

Answer :

B) itself.
by

Related questions

Any number with an exponent of zero is equal to 2) A) itself. B) ten. C) zero. D) one.

Description : Any number with an exponent of zero is equal to 2) A) itself. B) ten. C) zero. D) one.

Last Answer : D) one.

Convert decimal 12 to octal. 75) A) 168 B) 128 C) 108 D) 148

Description : Convert decimal 12 to octal. 75) A) 168 B) 128 C) 108 D) 148

Last Answer : D) 148

What is the decimal value of 26? 56) A) 128 B) 36 C) 32 D) 64

Description : What is the decimal value of 26? A) 128 B) 36 C) 32 D) 64

Last Answer : D) 64

The hexadecimal equivalent of decimal 128 is ________. 41) A) 8216 B) 8016 C) 8516 D) 9016

Description : The hexadecimal equivalent of decimal 128 is ________. 41) A) 8216 B) 8016 C) 8516 D) 9016

Last Answer : B) 8016

In a positive logic system, logic state 1 corresponds to (A) positive voltage (B) higher voltage level (C) zero voltage level (D) lower voltage level

Description : In a positive logic system, logic state 1 corresponds to (A) positive voltage (B) higher voltage level (C) zero voltage level (D) lower voltage level

Last Answer : (B) higher voltage level We decide two voltages levels for positive digital logic. Higher voltage represents logic 1 & a lower voltage represents logic 0.

When signed numbers are used in binary arithmetic, then which one of the following notations would have unique representation for zero. (A) Sign-magnitude. (B) 1’s complement. (C) 2’s complement. (D) 9’s complement.

Description : When signed numbers are used in binary arithmetic, then which one of the following notations would have unique representation for zero. (A) Sign-magnitude. (B) 1’s complement. (C) 2’s complement. (D) 9’s complement.

Last Answer : (A) Sign-magnitude.

Why does any number raised to an exponent of zero equal 1?

Description : Why does any number raised to an exponent of zero equal 1?

Last Answer : answer:I can't remember the math proving it, but I sort of remember when I questioned it myself when doing A-levels maths that I realised that it equals the number being divided by itself, which is ... negative numbers, so please let me know as I do not have any proper calculator to do this with.

In successive-approximation A/D converter, offset voltage equal to 1/2 LSB is added to the D/A converter’s output. This is done to (A) Improve the speed of operation. (B) Reduce the maximum quantization error. (C) Increase the number of bits at the output. (D) Increase the range of input voltage that can be converted

Description : In successive-approximation A/D converter, offset voltage equal to 1/2 LSB is added to the D/A converter's output. This is done to (A) Improve the speed of operation. (B) Reduce the maximum ... Increase the number of bits at the output. (D) Increase the range of input voltage that can be converted

Last Answer : (B) Reduce the maximum quantization error.

-8 is equal to signed binary number (A) 10001000 (B) 00001000 (C) 10000000 (D) 11000000

Description : -8 is equal to signed binary number (A) 10001000 (B) 00001000 (C) 10000000 (D) 11000000

Last Answer : (A) 10001000

CMOS circuits consume power (A) Equal to TTL (B) Less than TTL (C) Twice of TTL (D) Thrice of TTL

Description : CMOS circuits consume power (A) Equal to TTL (B) Less than TTL (C) Twice of TTL (D) Thrice of TTL

Last Answer : Ans: B As in CMOS one device is ON & one is Always OFF so power consumption is low.

How many different symbols are used in the octal number system? 108) A) ten B) two C) seven D) eight

Description : How many different symbols are used in the octal number system? 108) A) ten B) two C) seven D) eight

Last Answer : D) eight

Convert the decimal number 3.375 to binary. 132) A) 0101.1100 B) 0011.1010 C) 0011.0011 D) 0011.01

Description : Convert the decimal number 3.375 to binary. 132) A) 0101.1100 B) 0011.1010 C) 0011.0011 D) 0011.01

Last Answer : D) 0011.01

Convert the binary number 0001.0010 to decimal. 121) A) 1.20 B) 1.40 C) 1.125 D)

Description : Convert the binary number 0001.0010 to decimal. 121) A) 1.20 B) 1.40 C) 1.125 D)

Last Answer : C) 1.125

Convert the binary number 10010.0100 to decimal. 103) A) 16.25 B) 18.25 C) 18.40 D) 24.50

Description : Convert the binary number 10010.0100 to decimal. 103) A) 16.25 B) 18.25 C) 18.40 D) 24.50

Last Answer : B) 18.25

Convert the decimal number 0.0625 to binary. 100) A) 0000.0111 B) 0000.1110 C) 0000.0011 D) 0000.0001

Description : Convert the decimal number 0.0625 to binary. 100) A) 0000.0111 B) 0000.1110 C) 0000.0011 D) 0000.0001

Last Answer : D) 0000.0001

Which numbering formats are really codes rather than true number systems? 96) A) hexadecimal and octal B) binary and octal C) decimal and binary D) BCD and ASCII

Description : Which numbering formats are really codes rather than true number systems? 96) A) hexadecimal and octal B) binary and octal C) decimal and binary D) BCD and ASCII

Last Answer : Which numbering formats are really codes rather than true number systems?

Convert the decimal number 10.5 to binary. 92) A) 1100.1000 B) 1010.0101 C) 1010.1000 D) 1011.1000

Description : Convert the decimal number 10.5 to binary. 92) A) 1100.1000 B) 1010.0101 C) 1010.1000 D) 1011.1000

Last Answer : C) 1010.1000

Convert the decimal number 14.875 to binary. 87) A) 1110.0111 B) 1110.1110 C) 1111.1011 D) 1100.1100

Description : Convert the decimal number 14.875 to binary. 87) A) 1110.0111 B) 1110.1110 C) 1111.1011 D) 1100.1100

Last Answer : B) 1110.1110

What numeric symbols are used in the binary number system? 58) A) 0 through 8 B) 0, 1, 2 C) 1, 2 D) 0, 1

Description : What numeric symbols are used in the binary number system? 58) A) 0 through 8 B) 0, 1, 2 C) 1, 2 D) 0, 1

Last Answer : D) 0, 1

How many unique numeric symbols are used in the decimal number system? 47) A) unlimited B) nine C) one D) ten

Description : How many unique numeric symbols are used in the decimal number system? 47) A) unlimited B) nine C) one D) ten

Last Answer : D) ten

How many symbols are used in the hexadecimal number system? 15) A) sixteen B) six C) ten D) twelve

Description : How many symbols are used in the hexadecimal number system? 15) A) sixteen B) six C) ten D) twelve

Last Answer : A) sixteen

Convert the decimal number 6.75 to binary. 14) A) 0110.1100 B) 0111.1100 C) 0110.0110 D) 0110.1010

Description : Convert the decimal number 6.75 to binary. 14) A) 0110.1100 B) 0111.1100 C) 0110.0110 D) 0110.1010

Last Answer : A) 0110.1100

Convert the decimal number 12.125 to binary. 12) A) 1100.0110 B) 1110.0010 C) 1100.0010 D) 1010.1100

Description : Convert the decimal number 12.125 to binary. 12) A) 1100.0110 B) 1110.0010 C) 1100.0010 D) 1010.1100

Last Answer : C) 1100.0010

Convert the binary number 0000.1010 to decimal. 6) A) 0.10 B) 0.55 C) 0.50 D) 0.625

Description : Convert the binary number 0000.1010 to decimal. 6) A) 0.10 B) 0.55 C) 0.50 D) 0.625

Last Answer : D) 0.625

The decimal equivalent of Binary number 10101 is (A) 21 (B) 31 (C) 26 (D) 28

Description : The decimal equivalent of Binary number 10101 is (A) 21 (B) 31 (C) 26 (D) 28

Last Answer : (A) 21

The 2’s complement of the number 1101110 is (A) 0010001. (B) 0010001. (C) 0010010. (D) None.

Description : The 2’s complement of the number 1101110 is (A) 0010001. (B) 0010001. (C) 0010010. (D) None.

Last Answer : Ans: C 1’s complement of 1101110 is = 0010001 Thus 2’s complement of 1101110 is = 0010001 + 1 = 0010010

The information in ROM is stored (A) By the user any number of times. (B) By the manufacturer during fabrication of the device. (C) By the user using ultraviolet light. (D) By the user once and only once.

Description : The information in ROM is stored (A) By the user any number of times. (B) By the manufacturer during fabrication of the device. (C) By the user using ultraviolet light. (D) By the user once and only once.

Last Answer : (B) By the manufacturer during fabrication of the device.

The result of adding hexadecimal number A6 to 3A is (A) DD. (B) E0. (C) F0. (D) EF.

Description : The result of adding hexadecimal number A6 to 3A is (A) DD. (B) E0. (C) F0. (D) EF.

Last Answer : (B) E0.

The number of control lines for 32 to 1 multiplexer is (A) 4. (B) 5. (C) 16. (D) 6.

Description : The number of control lines for 32 to 1 multiplexer is (A) 4. (B) 5. (C) 16. (D) 6.

Last Answer : Ans: B The number of control lines for 32 (2^5) and to select one input among them total 5 select lines are required.

The number of flip flops contained in IC 7490 is (A) 2. (B) 3. (C) 4. (D) 10.

Description : The number of flip flops contained in IC 7490 is (A) 2. (B) 3. (C) 4. (D) 10.

Last Answer : (A) 2.

The number of control lines for 16 to 1 multiplexer is (A) 2. (B) 4. (C) 3. (D) 5.

Description : The number of control lines for 16 to 1 multiplexer is (A) 2. (B) 4. (C) 3. (D) 5.

Last Answer : (B) 4.

Which of the following memories stores the most number of bits (A) a 5M×8 memory. (B) a 1M × 16 memory. (C) a 5M × 4 memory. (D) a 1M ×12 memory.

Description : Which of the following memories stores the most number of bits (A) a 5M×8 memory. (B) a 1M × 16 memory. (C) a 5M × 4 memory. (D) a 1M ×12 memory.

Last Answer : Ans: A 5Mx8 = 5 x 220 x 8 = 40M (max)

In a RAM, information can be stored (A) By the user, number of times. (B) By the user, only once. (C) By the manufacturer, a number of times. (D) By the manufacturer only once.

Description : In a RAM, information can be stored (A) By the user, number of times. (B) By the user, only once. (C) By the manufacturer, a number of times. (D) By the manufacturer only once.

Last Answer : Ans: A RAM is used by the user, number of times.

The excess 3 code of decimal number 26 is (A) 0100 1001 (B) 01011001 (C) 1000 1001 (D) 01001101

Description : The excess 3 code of decimal number 26 is (A) 0100 1001 (B) 01011001 (C) 1000 1001 (D) 01001101

Last Answer : Ans: B (26)10 in BCD is ( 00100110 ) BCD Add 011 to each BCD 01011001 for excess – 3

1’s complement representation of decimal number of -17 by using 8 bit representation is (A) 1110 1110 (B) 1101 1101 (C) 1100 1100 (D) 0001 0001

Description : 1’s complement representation of decimal number of -17 by using 8 bit representation is (A) 1110 1110 (B) 1101 1101 (C) 1100 1100 (D) 0001 0001

Last Answer : (A) 1110 1110

The decimal equivalent of Binary number 11010 is (A) 26. (B) 36. (C) 16. (D) 23.

Description : The decimal equivalent of Binary number 11010 is (A) 26. (B) 36. (C) 16. (D) 23.

Last Answer : (A) 26.

Words having 8-bits are to be stored into computer memory. The number of lines required for writing into memory are (A) 1. (B) 2. (C) 4. (D) 8.

Description : Words having 8-bits are to be stored into computer memory. The number of lines required for writing into memory are (A) 1. (B) 2. (C) 4. (D) 8.

Last Answer : Ans: D Because 8-bit words required 8 bit data lines.

The A/D converter whose conversion time is independent of the number of bits is (A) Dual slope (B) Counter type (C) Parallel conversion (D) Successive approximation.

Description : The A/D converter whose conversion time is independent of the number of bits is (A) Dual slope (B) Counter type (C) Parallel conversion (D) Successive approximation.

Last Answer : Ans: C The A/D converter whose conversion time is independent of the Number of bits is Parallel conversion. (This type uses an array of comparators connected in parallel and comparators compare the input voltage at a particular ratio of the reference voltage).

The code where all successive numbers differ from their preceding number by single bit is (A) Binary code. (B) BCD. (C) Excess – 3. (D) Gray.

Description : The code where all successive numbers differ from their preceding number by single bit is (A) Binary code. (B) BCD. (C) Excess – 3. (D) Gray.

Last Answer : Ans: D The code where all successive numbers differ from their preceding number by single bit is Gray Code. (It is an unweighted code. The most important characteristic of this code is that only a single bit change occurs when going from one code number to next.)

The 2’s complement of the number 1101101 is (A) 0101110 (B) 0111110 (C) 0110010 (D) 0010011

Description : The 2’s complement of the number 1101101 is (A) 0101110 (B) 0111110 (C) 0110010 (D) 0010011

Last Answer : (D) 0010011 Ans: D The 2’s complement of the number 1101101 is 0010011 (1’s complement of the number 1101101 is 0010010 2’s complement of the number 1101101is 0010010 + 1 =0010011)

The Gray code for decimal number 6 is equivalent to (A) 1100 (B) 1001 (C) 0101 (D) 0110

Description : The Gray code for decimal number 6 is equivalent to (A) 1100 (B) 1001 (C) 0101 (D) 0110

Last Answer : (C) 0101

The hexadecimal number ‘A0’ has the decimal value equivalent to (A) 80 (B) 256 (C) 100 (D) 160

Description : The hexadecimal number ‘A0’ has the decimal value equivalent to (A) 80 (B) 256 (C) 100 (D) 160

Last Answer : (D) 160

The number of control lines for a 8 – to – 1 multiplexer is (A) 2 (B) 3 (C) 4 (D) 5

Description : The number of control lines for a 8 – to – 1 multiplexer is (A) 2 (B) 3 (C) 4 (D) 5

Last Answer : Ans: B The number of control lines for an 8 to 1 Multiplexer is 3 (The control signals are used to steer any one of the 8 inputs to the output)

The decimal equivalent of hex number 1A53 is (A) 6793 (B) 6739 (C) 6973 (D) 6379

Description : The decimal equivalent of hex number 1A53 is (A) 6793 (B) 6739 (C) 6973 (D) 6379

Last Answer : (B) 6739

What is the binary equivalent of the decimal number 368 (A) 101110000 (B) 110110000 (C) 111010000 (D) 111100000

Description : What is the binary equivalent of the decimal number 368 (A) 101110000 (B) 110110000 (C) 111010000 (D) 111100000

Last Answer : (A) 101110000

The base of the octal system is 71) A) eight. B) two. C) ten. D) seven.

Description : The base of the octal system is 71) A) eight. B) two. C) ten. D) seven.

Last Answer : A) eight.

How many two input AND gates and two input OR gates are required to realize Y = BD+CE+AB (A) 1, 1 (B) 4, 2 (C) 3, 2 (D) 2, 3

Description : How many two input AND gates and two input OR gates are required to realize Y = BD+CE+AB (A) 1, 1 (B) 4, 2 (C) 3, 2 (D) 2, 3

Last Answer : Ans: A There are three product terms, so three AND gates of two inputs are required. As only two input OR gates are available, so two OR gates are required to get the logical sum of three product terms.

A full adder logic circuit will have (A) Two inputs and one output. (B) Three inputs and three outputs. (C) Two inputs and two outputs. (D) Three inputs and two outputs.

Description : A full adder logic circuit will have (A) Two inputs and one output. (B) Three inputs and three outputs. (C) Two inputs and two outputs. (D) Three inputs and two outputs.

Last Answer : Ans: D A full adder circuit will add two bits and it will also accounts the carry input generated in the previous stage. Thus three inputs and two outputs (Sum and Carry) are there.

How many two-input AND and OR gates are required to realize Y=CD+EF+G (A) 2,2. (B) 2,3. (C) 3,3. (D) none of these.

Description : How many two-input AND and OR gates are required to realize Y=CD+EF+G (A) 2,2. (B) 2,3. (C) 3,3. (D) none of these.

Last Answer : Ans: A Y=CD+EF+G Number of two input AND gates=2 Number of two input OR gates = 2 One OR gate to OR CD and EF and next to OR of G & output of first OR gate.

Shifting a register content to left by one bit position is equivalent to (A) division by two. (B) addition by two. (C) multiplication by two. (D) subtraction by two

Description : Shifting a register content to left by one bit position is equivalent to (A) division by two. (B) addition by two. (C) multiplication by two. (D) subtraction by two

Last Answer : (C) multiplication by two.