Description : How many address bits are required to represent 4K memory (A) 5 bits. (B) 12 bits. (C) 8 bits. (D) 10 bits.
Last Answer : (B) 12 bits.
Description : How many address bits are required to represent a 32 K memory (A) 10 bits. (B) 12 bits. (C) 14 bits. (D) 16 bits.
Last Answer : (D) 16 bits.
Description : Which of the following memories stores the most number of bits (A) a 5M×8 memory. (B) a 1M × 16 memory. (C) a 5M × 4 memory. (D) a 1M ×12 memory.
Last Answer : Ans: A 5Mx8 = 5 x 220 x 8 = 40M (max)
Description : In successive-approximation A/D converter, offset voltage equal to 1/2 LSB is added to the D/A converter's output. This is done to (A) Improve the speed of operation. (B) Reduce the maximum ... Increase the number of bits at the output. (D) Increase the range of input voltage that can be converted
Last Answer : (B) Reduce the maximum quantization error.
Description : The A/D converter whose conversion time is independent of the number of bits is (A) Dual slope (B) Counter type (C) Parallel conversion (D) Successive approximation.
Last Answer : Ans: C The A/D converter whose conversion time is independent of the Number of bits is Parallel conversion. (This type uses an array of comparators connected in parallel and comparators compare the input voltage at a particular ratio of the reference voltage).
Description : The number of control lines for a 8 – to – 1 multiplexer is (A) 2 (B) 3 (C) 4 (D) 5
Last Answer : Ans: B The number of control lines for an 8 to 1 Multiplexer is 3 (The control signals are used to steer any one of the 8 inputs to the output)
Description : A weighted resistor digital to analog converter using N bits requires a total of (A) N precision resistors. (B) 2N precision resistors. (C) N + 1 precision resistors. (D) N – 1 precision resistors.
Last Answer : (A) N precision resistors.
Description : How many select lines will a 32:1 multiplexer will have (A) 5. (B) 8. (C) 9. (D) 11.
Last Answer : (A) 5.
Description : The information in ROM is stored (A) By the user any number of times. (B) By the manufacturer during fabrication of the device. (C) By the user using ultraviolet light. (D) By the user once and only once.
Last Answer : (B) By the manufacturer during fabrication of the device.
Description : In a RAM, information can be stored (A) By the user, number of times. (B) By the user, only once. (C) By the manufacturer, a number of times. (D) By the manufacturer only once.
Last Answer : Ans: A RAM is used by the user, number of times.
Description : The number of control lines for 32 to 1 multiplexer is (A) 4. (B) 5. (C) 16. (D) 6.
Last Answer : Ans: B The number of control lines for 32 (2^5) and to select one input among them total 5 select lines are required.
Description : The number of control lines for 16 to 1 multiplexer is (A) 2. (B) 4. (C) 3. (D) 5.
Last Answer : (B) 4.
Description : How many flip-flops are required to construct mod 30 counter (A) 5 (B) 6 (C) 4 (D) 8
Last Answer : (A) 5
Description : How many select lines will a 16 to 1 multiplexer will have (A) 4 (B) 3 (C) 5 (D) 1
Last Answer : (A) 4
Description : Which of the memory is volatile memory (A) ROM (B) RAM (C) PROM (D) EEPROM
Last Answer : Ans: B RAM is a volatile memory (Volatile memory means the contents of the RAM get erased as soon as the power goes off.)
Description : For the 8-bit word 00111001, the check bits stored with it would be 0111. Suppose when the word is read from memory, the check bits are calculated to be 1101. What is the data word that was read from memory? (A) 10011001 (B) 00011001 (C) 00111000 (D) 11000110
Last Answer : (B) 00011001
Description : How many two input AND gates and two input OR gates are required to realize Y = BD+CE+AB (A) 1, 1 (B) 4, 2 (C) 3, 2 (D) 2, 3
Last Answer : Ans: A There are three product terms, so three AND gates of two inputs are required. As only two input OR gates are available, so two OR gates are required to get the logical sum of three product terms.
Description : How many two-input AND and OR gates are required to realize Y=CD+EF+G (A) 2,2. (B) 2,3. (C) 3,3. (D) none of these.
Last Answer : Ans: A Y=CD+EF+G Number of two input AND gates=2 Number of two input OR gates = 2 One OR gate to OR CD and EF and next to OR of G & output of first OR gate.
Description : How many flip flops are required to construct a decade counter (A) 10 (B) 3 (C) 4 (D) 2
Last Answer : Ans: C Decade counter counts 10 states from 0 to 9 ( i.e. from 0000 to 1001 ) Thus four FlipFlop's are required.
Description : How many AND gates are required to realize Y = CD+EF+G (A) 4 (B) 5 (C) 3 (D) 2
Last Answer : 2
Description : A 4-bit synchronous counter uses flip-flops with propagation delay times of 15 ns each. The maximum possible time required for change of state will be (A) 15 ns. (B) 30 ns. (C) 45 ns. (D) 60 ns.
Last Answer : Ans: A 15 ns because in synchronous counter all the flip-flops change state at the same time.
Description : The gates required to build a half adder are (A) EX-OR gate and NOR gate (B) EX-OR gate and OR gate (C) EX-OR gate and AND gate (D) Four NAND gates.
Last Answer : (C) EX-OR gate and AND gate
Description : How many Flip-Flops are required for mod–16 counter? (A) 5 (B) 6 (C) 3 (D) 4
Last Answer : (D) 4
Description : What numeric symbols are used in the binary number system? 58) A) 0 through 8 B) 0, 1, 2 C) 1, 2 D) 0, 1
Last Answer : D) 0, 1
Description : 1’s complement representation of decimal number of -17 by using 8 bit representation is (A) 1110 1110 (B) 1101 1101 (C) 1100 1100 (D) 0001 0001
Last Answer : (A) 1110 1110
Description : -8 is equal to signed binary number (A) 10001000 (B) 00001000 (C) 10000000 (D) 11000000
Last Answer : (A) 10001000
Description : If the number of address bits in a memory is reduced by 2 and the addressability is doubled, the size of the memory (i.e., the number of bits stored in the memory) a. doubles b. remains unchanged c. halves d. increases by 2^(address bits)/addressability
Last Answer : c. halves
Description : What is the decimal value of 2-3? 74) A) 0.25 B) 0.75 C) 0.125 D) 0.8
Last Answer : C) 0.125
Description : What is the decimal value of 23? 27) A) 4 B) 8 C) 2 D) 6
Last Answer : A) 00010000
Description : The decimal equivalent of binary 1010000 is ________. 8) A) 9610 B) 8010 C) 7810 D) 8410
Last Answer : A) 9610
Description : The commercially available 8-input multiplexer integrated circuit in the TTL family is (A) 7495. (B) 74153. (C) 74154. (D) 74151.
Last Answer : Ans: B MUX integrated circuit in TTL is 74153.
Description : A stack pointer is a. a 16-bit register in the microprocessor that indicate the beginning of the stack memory. b. a register that decodes and executes 16-bit arithmetic expression. c. The first memory location where a subroutine address is stored. d. a register in which flag bits are stored
Last Answer : a. a 16-bit register in the microprocessor that indicate the beginning of the stack memory.
Description : Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ... ...... (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps
Last Answer : Answer: Marks given to all
Description : The process of entering data into a ROM is called (A) burning in the ROM (B) programming the ROM (C) changing the ROM (D) charging the ROM
Last Answer : Ans: B The process of entering data into ROM is known as programming the ROM.
Description : Convert the decimal number 3.375 to binary. 132) A) 0101.1100 B) 0011.1010 C) 0011.0011 D) 0011.01
Last Answer : D) 0011.01
Description : Any number with an exponent of one is equal to 128) A) two. B) itself. C) zero. D) on
Last Answer : B) itself.
Description : Convert the binary number 0001.0010 to decimal. 121) A) 1.20 B) 1.40 C) 1.125 D)
Last Answer : C) 1.125
Description : How many different symbols are used in the octal number system? 108) A) ten B) two C) seven D) eight
Last Answer : D) eight
Description : Convert the binary number 10010.0100 to decimal. 103) A) 16.25 B) 18.25 C) 18.40 D) 24.50
Last Answer : B) 18.25
Description : Convert the decimal number 0.0625 to binary. 100) A) 0000.0111 B) 0000.1110 C) 0000.0011 D) 0000.0001
Last Answer : D) 0000.0001
Description : Which numbering formats are really codes rather than true number systems? 96) A) hexadecimal and octal B) binary and octal C) decimal and binary D) BCD and ASCII
Last Answer : Which numbering formats are really codes rather than true number systems?
Description : Convert the decimal number 10.5 to binary. 92) A) 1100.1000 B) 1010.0101 C) 1010.1000 D) 1011.1000
Last Answer : C) 1010.1000
Description : Convert the decimal number 14.875 to binary. 87) A) 1110.0111 B) 1110.1110 C) 1111.1011 D) 1100.1100
Last Answer : B) 1110.1110
Description : How many unique numeric symbols are used in the decimal number system? 47) A) unlimited B) nine C) one D) ten
Last Answer : D) ten
Description : How many symbols are used in the hexadecimal number system? 15) A) sixteen B) six C) ten D) twelve
Last Answer : A) sixteen
Description : Convert the decimal number 6.75 to binary. 14) A) 0110.1100 B) 0111.1100 C) 0110.0110 D) 0110.1010
Last Answer : A) 0110.1100
Description : Convert the decimal number 12.125 to binary. 12) A) 1100.0110 B) 1110.0010 C) 1100.0010 D) 1010.1100
Last Answer : C) 1100.0010
Description : Convert the binary number 0000.1010 to decimal. 6) A) 0.10 B) 0.55 C) 0.50 D) 0.625
Last Answer : D) 0.625
Description : Any number with an exponent of zero is equal to 2) A) itself. B) ten. C) zero. D) one.
Last Answer : D) one.