What is wavelength (λ)?

What is wavelength (λ)?
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1 Answer

Answer :

The space occupied by one cycle of a radio wave at any given  instant.
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At separation between a node and antinode, wavelength becomes A. λ B. λ⁄2 C. λ⁄4 D. 2λ

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The region where the Lyman series contains the wavelength 1∕ λ = RH [1/ 12 – 1/ n2 ] is a) visible region b) infrared region c) ultraviolet region d ) none of these

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To observe interference in thin films with a light of wavelength λ, the thickness of the film (a) Should be much smaller than λ (b) Should be a few thousand times of λ (c) Should be of the order of λ (d) Should be of the order of nanometer

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Last Answer : Higher.

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Last Answer : Ultraviolet absorption region (below 400 nm) and infrared absorption region (above 2000 nm).

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Last Answer : (c) a, b, c are in H.P. only for all m As the points A(a, ma), B[b, (m + 1)b] and C[c, (m + 2)c] are collinear. Area of Δ ABC should be equal to zero.⇒ \(rac{1}{2}\)[x1(y2 - y3) + x2(y3 - y1) + ... - bc = 0 ⇒ ab + bc = 2ac ⇒ b = \(rac{2ac}{a+c}\)∴ a, b, c are harmonic progression (H.P.) for all m.

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A fuzzy set A on R is ................. iff A(λx1 + (1 – λ)x2) ≥ min [A(x1), A(x2)] for all x1, x2 ∈ R and all λ ∈ [0, 1], where min denotes the minimum operator. (A) Support (B) α-cut (C) Convex (D) Concave

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Last Answer : (C) Convex 

A pushdown automation M = (Q, Σ, Γ, δ, q0, z, F) is set to be deterministic subject to which of the following condition(s), for every q ∈ Q, a ∈ Σ ∪ {λ} and b ∈ Γ (s1) δ(q, a, b) contains at most one element (s2) if δ(q, λ, b) is not empty then δ(q, c, b) must be empty for every c ∈ Σ (A) only s1 (B) only s2 (C) both s1 and s2 (D) neither s1 nor s2

Description : A pushdown automation M = (Q, Σ, Γ, δ, q0, z, F) is set to be deterministic subject to which of the following condition(s), for every q ∈ Q, a ∈ Σ ∪ {λ} and b ∈ Γ (s1) δ(q, a, b) contains at most one ... ) must be empty for every c ∈ Σ (A) only s1 (B) only s2 (C) both s1 and s2 (D) neither s1 nor s2

Last Answer : (C) both s1 and s2

The grammar with production rules S → aSb |SS|λ generates language L given by: (A) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≥ nb(v) where v is any prefix of w} (B) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≤ nb(v) where v is any prefix of w} (C) L = {w∈{a, b}* | na(w) ≠ nb(w) and na(v) ≥ nb(v) where v is any prefix of w} (D) L = {w∈{a, b}* | na(w) ≠ nb(w) and na(v) ≤ nb(v) where v is any prefix of w}

Description : The grammar with production rules S → aSb |SS|λ generates language L given by: (A) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≥ nb(v) where v is any prefix of w} (B) L = {w∈{a, b}* | na(w) = nb(w) and na(v ... (D) L = {w∈{a, b}* | na(w) ≠ nb(w) and na(v) ≤ nb(v) where v is any prefix of w}

Last Answer : (A) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≥ nb(v) where v is any prefix of w} 

The equivalent production rules corresponding to the production rules S→Sα1|Sα2|β1|β2 is (A) S→β1 | β2, A→α1A | α2A | λ (B) S→β1 | β2 | β1A | β2A, A→α1A | α2A (C) S→β1 | β2, A→α1A | α2A (D) S→β1 | β2 | β1A | β2A, A→α1A | α2A | λ

Description : The equivalent production rules corresponding to the production rules S→Sα1|Sα2|β1|β2 is (A) S→β1 | β2, A→α1A | α2A | λ (B) S→β1 | β2 | β1A | β2A,  A→α1A | α2A (C) S→β1 | β2, A→α1A | α2A (D) S→β1 | β2 | β1A | β2A,  A→α1A | α2A | λ

Last Answer : (D) S→β1 | β2 | β1A | β2A,  A→α1A | α2A | λ

Given the production rules of a grammar G1 as S1→AB | aaB A→a | Aa B→b and the production rules of a grammar G2 as S2→aS2bS2 | bS2aS2 | λ Which of the following is correct statement? (A) G1 is ambiguous and G2 is not ambiguous. (B) G1 is ambiguous and G2 is ambiguous. (C) G1 is not ambiguous and G2 is ambiguous. (D) G1 is not ambiguous and G2 is not ambiguous.

Description : Given the production rules of a grammar G1 as S1→AB | aaB A→a | Aa B→b and the production rules of a grammar G2 as S2→aS2bS2 | bS2aS2 | λ Which of the following is correct statement? ( ... G1 is not ambiguous and G2 is ambiguous. (D) G1 is not ambiguous and G2 is not ambiguous.

Last Answer : (B) G1 is ambiguous and G2 is ambiguous.

The Greibach normal form grammar for the language L={an bn+1|n≥0} is (A) S→a SB, B→bB|λ (B) S→a SB, B→bB|b (C) S→a SB|b, B→b (D) S→a Sb|b

Description : The Greibach normal form grammar for the language L={an bn+1|n≥0} is (A) S→a SB, B→bB|λ (B) S→a SB, B→bB|b (C) S→a SB|b, B→b (D) S→a Sb|b

Last Answer : (C) S→a SB|b, B→b 

Given the following statements: S1 : The grammars S→asb | bsa | ss | a and S→asb | bsa | a are not equivalent. S2: The grammars S→ss | sss | asb | bsa | λ and S→ss | asb | bsa | λ are equivalent. Which of the following is true? (A) S1 is correct and S2 is not correct. (B) Both S1 and S2 are correct (C) S1 is not correct and S2 is correct (D) Both S1 and S2 are not correct.

Description : Given the following statements: S1 : The grammars S→asb | bsa | ss | a and S→asb | bsa | a are not equivalent. S2: The grammars S→ss | sss | asb | bsa | λ and S→ss | asb | bsa | λ are equivalent. ... and S2 are correct (C) S1 is not correct and S2 is correct (D) Both S1 and S2 are not correct.

Last Answer : (A) S1 is correct and S2 is not correct.

The context free grammar for the language L = {an bm | n≤m+3, n≥0, m≥0} is (A) S→aaaA; A→aAb|B, B→Bb|λ (B) S→aaaA|λ, A→aAb|B, B→Bb|λ (C) S→aaaA|aaA|λ, A→aAb|B, B→Bb|λ (D) S→aaaA|aaA|aA|λ, A→aAb|B, B→Bb|λ

Description : The context free grammar for the language L = {an bm | n≤m+3, n≥0, m≥0} is (A) S→aaaA; A→aAb|B, B→Bb|λ (B) S→aaaA|λ, A→aAb|B, B→Bb|λ (C) S→aaaA|aaA|λ, A→aAb|B, B→Bb|λ (D) S→aaaA|aaA|aA|λ, A→aAb|B, B→Bb|λ

Last Answer : (D) S→aaaA|aaA|aA|λ, A→aAb|B, B→Bb|λ

The regular expression for the complement of the language L = {anbm|n≥4, m≤3} is: (A) (λ + a + aa + aaa)b* + a*bbbb* + (a + b)*ba(a + b)* (B) (λ + a + aa + aaa)b* + a*bbbbb* + (a + b)*ab(a + b)* (C) (λ + a + aa + aaa) + a*bbbbb* + (a + b)*ab(a + b)* (D) (λ + a + aa + aaa)b* + a*bbbbb* + (a + b)*ba(a + b)*

Description : The regular expression for the complement of the language L = {anbm|n≥4, m≤3} is: (A) (λ + a + aa + aaa)b* + a*bbbb* + (a + b)*ba(a + b)* (B) (λ + a + aa + aaa)b* + a*bbbbb* + (a + b)*ab(a + b)* (C) (λ + a ... *bbbbb* + (a + b)*ab(a + b)* (D) (λ + a + aa + aaa)b* + a*bbbbb* + (a + b)*ba(a + b)*

Last Answer : (D) (λ + a + aa + aaa)b* + a*bbbbb* + (a + b)*ba(a + b)*

The phase angle corresponding to λ/4 in a standing– wave pattern is:

Description : The phase angle corresponding to λ/4 in a standing– wave pattern is: (1) 30° (2) 90° (3) 135° (4) 180°

Last Answer : The phase angle corresponding to λ/4 in a standing– wave pattern is: 90°