Number of girls enrolled in only Dancing classes is what per cent of the boys enrolled in the same? (Rounded off to two digits after decimal) (1) 38•67 (2) 35•71 (3) 41•83 (4) 28•62 (5) None of these

Number of girls enrolled in only Dancing classes is what per cent of the boys enrolled in  the same? (Rounded off to two digits after decimal)
(1) 38•67
(2) 35•71
(3) 41•83
(4) 28•62
(5) None of these
by

1 Answer

Answer :

(2) 35•71
by

Related questions

Total number of girls enrolled in Singing is approximately what per cent of the total number of students in the school ? (1) 22 (2) 38 (3) 64

Description : Total number of girls enrolled in Singing is approximately what per cent of the total number of students in the school ? (1) 22 (2) 38 (3) 64

Last Answer : 3) 64

What is the per cent increase in the number of products manufactured by the company in the year 2006 from the previous year ? (Rounded off to two digits after decimal) (1) 19·25 (2) 33·33 (3) 10·45 (4) 42·66 (5) None of these

Description : What is the per cent increase in the number of products manufactured by the company in the year 2006 from the previous year ? (Rounded off to two digits after decimal) (1) 19·25 (2) 33·33 (3) 10·45 (4) 42·66 (5) None of these

Last Answer : (5) None of these

The number of products sold by the company in the year 2004 is what per cent of the number of products manufactured by it in that year ? (Rounded off to two digits after decimal) (1) 71·43 (2) 67·51 (3) 81·67 (4) 56·29 (5) None of these

Description : The number of products sold by the company in the year 2004 is what per cent of the number of products manufactured by it in that year ? (Rounded off to two digits after decimal) (1) 71·43 (2) 67·51 (3) 81·67 (4) 56·29 (5) None of these

Last Answer : 1) 71·43 v

What is the respective ratio of the number of girls enrolled in only Painting classes to the number of boys enrolled in the same ? (1) 77 : 26 (2) 21 : 73 (3) 26 : 77 (4) 73 : 21 (5) None of these

Description : What is the respective ratio of the number of girls enrolled in only Painting classes to the number of boys enrolled in the same ? (1) 77 : 26 (2) 21 : 73 (3) 26 : 77 (4) 73 : 21 (5) None of these

Last Answer : (3) 26 : 77

What is the total number of boys who are enrolled in Dancing ? (1) 636 (2) 728 (3) 584 (4) 868 (5) None of these

Description : What is the total number of boys who are enrolled in Dancing ? (1) 636 (2) 728 (3) 584 (4) 868 (5) None of these

Last Answer : (4) 868

(331/30)+( 661/60) +(704/11) -35.013 + 36.026 =? a) 69 b) 67 c) 83 d) 89 e) 85

Description : (331/30)+( 661/60) +(704/11) -35.013 + 36.026 =? a) 69 b) 67 c) 83 d) 89 e) 85

Last Answer : ?=331/30 + 661/60 + 704/11 – 35.013 + 36.026 =11 + 11 + 64 -1.013 =86-1 ≈ 85 Answer: e)

What percent of the total number of girls in the college do not know Hindi? (rounded off to nearest integer) (1) 38 (2) 46 (3) 48 (4) 36 (5) 43

Description : What percent of the total number of girls in the college do not know Hindi? (rounded off to nearest integer) (1) 38 (2) 46 (3) 48 (4) 36 (5) 43

Last Answer : (5) 43

The average weight of a group of 75 women was calculated as 47 kg. It was later discovered that the weight of one of the women was read as 45 kg, whereas her actual weight was 25kg. What is the actual average weight of the group of 75 women? (rounded off to two digits after decimal) (a) 46.73 kg (b) 46.64 kg (c) 45.96 kg (d) Cannot be determined (e) None of these

Description : The average weight of a group of 75 women was calculated as 47 kg. It was later discovered that the weight of one of the women was read as 45 kg, whereas her actual weight was 25kg. What is the actual average weight ... kg (b) 46.64 kg (c) 45.96 kg (d) Cannot be determined (e) None of these

Last Answer : (a) 46.73 kg

The average age of the whole class is 12.05 years. The average age of all girls is 12.5 years and the average age of boys is 11.75 years. If the total number of boys is 45 then what is the total number of girls in the class? a) 20 b) 25 c) 30 d) 35 e) 40

Description : The average age of the whole class is 12.05 years. The average age of all girls is 12.5 years and the average age of boys is 11.75 years. If the total number of boys is 45 then what is the total number of girls in the class? a) 20 b) 25 c) 30 d) 35 e) 40

Last Answer : Let the number of girls be x. The number of boys is 45. :. Total age of boys and girls in the class = (x+45) × 12.05 or, (x+45) × 12.05 = 45 × 11.75 + x × 12.5 or, 12.05x + 542.25 = 528.75 + 12.5x or, 13.5 = 0.45x or, x = 13.5/0.45 = 30 Answer is: c)

Sum of Rs.118 was shared among 50 boys and girls,each girl receive Rs.2.60 and boy receive Rs.1.80.Find the number of girls. A) 15 B)25 C)30 D)35

Description : Sum of Rs.118 was shared among 50 boys and girls,each girl receive Rs.2.60 and boy receive Rs.1.80.Find the number of girls. A) 15 B)25 C)30 D)35

Last Answer : D)35

What is the total number of students enrolled in all the three classes together ? (1) 150 (2) 125 (3) 140 (4) 160 (5) None of these

Description : What is the total number of students enrolled in all the three classes together ? (1) 150 (2) 125 (3) 140 (4) 160 (5) None of these

Last Answer : (5) None of these

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

67,74,78,?,92,94 a) 86 b) 85 c) 83 d) 84 e) 88

Description : 67,74,78,?,92,94 a) 86 b) 85 c) 83 d) 84 e) 88

Last Answer : The next term is obtained by adding the unit’s digit to the number. Hence the missing number =78+8=86 Answer: a)

Total literate population of city E is what percentage of total population of city D? 1) 67.5% 2) 71.5% 3) 74.5% 4) 77.5% 5) 82.5%

Description : Total literate population of city E is what percentage of total population of city D? 1) 67.5% 2) 71.5% 3) 74.5% 4) 77.5% 5) 82.5%

Last Answer : 2) 71.5%

The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Description : The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Last Answer : Answer – B (15110) Explanation – Here (48 – 38) = 10, (60 – 50) = 10, (72 – 62) = 10, (108 – 98) = 10 & (140 – 130) = 10. Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10 = 15120 – 10 = 15110

The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Description : The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Last Answer : Answer: B boys = 4x and girls = 5x. Required ratio = [(130/100)*4x]/ [(140/100)*5x] 26/35

Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys? A) 62.5% B) 54.8% C) 52.6% D) 55.8% E) 53.5%

Description : Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys? A) 62.5% B) 54.8% C) 52.6% D) 55.8% E) 53.5%

Last Answer : Answer: B Total students in both = 6x+11x = 17x Boys in class 4 = (60/100)*6x = 360x/100 Boys in class 5 = (52/100)*11x = 572x/100 So total boys = 360x/100 + 572x/100 = 932x/100 = 9.32x % of boys = [9.32x/17x] * 100=54.8%

√730 + √840 - √960 + √1090 - √290 = ? a) 41 b) 33 c) 20 d) 28 e) 55

Description : √730 + √840 - √960 + √1090 - √290 = ? a) 41 b) 33 c) 20 d) 28 e) 55

Last Answer : ? = 27 + 29 – 31 + 33 – 17 = 41 Answer: a)

3.25 × 16 + 7.25 × 8 = ? + 75 a) 83 b) 75 c) 61 d) 53 e) 35

Description : 3.25 × 16 + 7.25 × 8 = ? + 75 a) 83 b) 75 c) 61 d) 53 e) 35

Last Answer : ? + 75 = 52 + 58 = 110 ? = 110 – 75 = 35 Answer: e)

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Description : A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Last Answer : Total time taken = (160/64) + (160/80) = 9/2 hrs. Avg Speed – 320 × (2/9) km/hr = 71.11km/hr Answer: c)

(37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Description : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Last Answer : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? Sol: 27.75 x 1764 ÷ 64 – 2 = 8 x ? 27.75 x 27.5625 – 2 = 8 x ? 762.859/8=? ? = 95.357 Answer: a)

49/55 of 365/517 of 5111 = ? (Take 4 digits after the decimal point) a) 3015.6001 b) 3148.8123 c) 3214.2379 d) 3348.6179 e) 3358.6279

Description : 49/55 of 365/517 of 5111 = ? (Take 4 digits after the decimal point) a) 3015.6001 b) 3148.8123 c) 3214.2379 d) 3348.6179 e) 3358.6279

Last Answer : 49/55 of 365/517 of 5111 = ? Sol: 0.8909 x 0.7059 x 5111 = ? 0.62888631 x 5111 =? ? = 3214.2379 Answer: c)

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

Calculate the shaft diameter on rigidity basis if torsional moment is 196000N-mm, length of shaft is 1000mm. Permissible angle of twist per meter is 0.5’ and take G=79300N/mm2. a) None of the listed b) 41.2mm c) 35.8mm d) 38.8mm

Description : Calculate the shaft diameter on rigidity basis if torsional moment is 196000N-mm, length of shaft is 1000mm. Permissible angle of twist per meter is 0.5’ and take G=79300N/mm2. a) None of the listed b) 41.2mm c) 35.8mm d) 38.8mm

Last Answer : b) 41.2mm

Calculate the shaft diameter on rigidity basis if torsional moment is 196000N-mm, length of shaft is 1000mm. Permissible angle of twist per meter is 0.5’ and take G=79300N/mm². a) None of the listed b) 41.2mm c) 35.8mm d) 38.8mm

Description : Calculate the shaft diameter on rigidity basis if torsional moment is 196000N-mm, length of shaft is 1000mm. Permissible angle of twist per meter is 0.5’ and take G=79300N/mm². a) None of the listed b) 41.2mm c) 35.8mm d) 38.8mm

Last Answer : b) 41.2mm

3 7 6 28 9 112 12 ? a) 112 b) 448 c) 28 d) 38 e) None of these

Description : 3 7 6 28 9 112 12 ? a) 112 b) 448 c) 28 d) 38 e) None of these

Last Answer : First series: 3, 6, 9 (increased by 3) Second Series: 7, 28, 112, 448 (multiplied by 4) Answer: d)

60% loss on cost price is what percent loss on selling price? A. 28 B. 38 % C. 40 D. 150%

Description : 60% loss on cost price is what percent loss on selling price? A. 28 B. 38 % C. 40 D. 150%

Last Answer : Answer – D (150 %) Explanation – Loss = 60% on CP i.e., 0.6CP ⇒ SP = 0.4CP Loss % on SP = loss/SP x 100 = 0.6CP/0.4CP x 100 = 150%.

987.67 × 123.35 ÷ 9 = ? a) 13411 b) 13621 c) 13489 d) 13551 e) 13721

Description : 987.67 × 123.35 ÷ 9 = ? a) 13411 b) 13621 c) 13489 d) 13551 e) 13721

Last Answer : ? = (987 × 123) / 9 = 13489 Answer: c)

Nishu is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the speed of the train? A.35 kmph B.54 kmph C.62 kmph D.70 kmph E.None of these

Description : Nishu is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the speed of the train? A.35 kmph B.54 kmph C.62 kmph D.70 kmph E.None of these

Last Answer : Answer - B (54 kmph) Explanation - Let the length of the train be x metres. Then, the train covers x metres in 8 seconds (train is actually covering itself because length of man is very less compartable to train)and (x + ... /8]m/sec (convert to km/hr i.e x 18/5) =[120/8] x 18/5kmph = 54 kmph.

Out of the students studying Homeopathy, what is the ratio between number of boys knowing English and the number of girls knowing Hindi respectively? (1) 3 : 5 (2) 2 : 3 (3) 9 : 11

Description : Out of the students studying Homeopathy, what is the ratio between number of boys knowing English and the number of girls knowing Hindi respectively? (1) 3 : 5 (2) 2 : 3 (3) 9 : 11

Last Answer : (2) 2 : 3

25,?,45,58,73,90,109 a) 33 b) 34 c) 35 d) 38 e) 36

Description : 25,?,45,58,73,90,109 a) 33 b) 34 c) 35 d) 38 e) 36

Last Answer : The series is 3×5+10=25,4×6+10=34,5×7+10=45,6×8+10=58,7×9+10=73,8× 10+10=90,9×11+10=109 Hence missing term=34 Answer: b)

The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of the number of boys to the number of girls in the class is: A. 1 : 4 B. 2 : 3 C. 3 : 4 D. 4 : 2 E. None of these

Description : The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of the number of boys to the number of girls in the class is: A. 1 : 4 B. 2 : 3 C. 3 : 4 D. 4 : 2 E. None of these

Last Answer : Answer – B (2 : 3) Explanation – Let the ratio be k:1 Then, k x 16.4 + 1 x 15.4 = (k + 1) x 15.8 (16.4 – 15.8) k = (15.8 – 15.4) k=2/3

67.28 rounded to 1 decimal place?

Description : 67.28 rounded to 1 decimal place?

Last Answer : 67.3

In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Description : In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Last Answer : 2 boys, 1 gi(Prl = (15c2×10c1) / 25c3 = 1050/2300 1 boy, 2 girls = (15c1×10c2) / 25c3 = 675/2300 Difference = (1050 - 675)/2300 = 375/2300 = 15/92 Answer: c)

Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Description : Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Last Answer : Answer – B (24) Explanation – Let the present ages of Simmi and Anu be 5x years and 4x years respectively Then, [5X + 3] / [4X + 3] =11/9 x=6 Anu’s present age = 4X = 24 years

In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Description : In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Last Answer : A)11:77:7

My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then what was the age my father when my brother was born? a) 35 years b) 34 years c) 33 years d) 32 years e) 30 years

Description : My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, ... father when my brother was born? a) 35 years b) 34 years c) 33 years d) 32 years e) 30 years

Last Answer : Let my age = x Then My brother's age = x + 3 My mother's age = x + 26 My sister's age = (x + 3) + 4 = x + 7 My Father's age = (x + 7) + 28 = x + 35 => age my father when my brother was born = x + 35 – (x + 3) = 32. Answer: d)

A man sells two houses at the rate of Rs.1.995 lakh each. On one he gains 5% and on the other he loses 5%. His gain or loss per cent in the whole transaction is a) 0.25% loss b) 0.25% gain c) 2.5% loss d) 2.5% gain e) 1.25% loss

Description : A man sells two houses at the rate of Rs.1.995 lakh each. On one he gains 5% and on the other he loses 5%. His gain or loss per cent in the whole transaction is a) 0.25% loss b) 0.25% gain c) 2.5% loss d) 2.5% gain e) 1.25% loss

Last Answer : a) 0.25% loss

Rajesh loses 20% by selling a radio for Rs. 768. What per cent will he gain by selling it for Rs. 1080? (a) 6.25% (b) 8.25% (c) 10.25% (d) 4.25% (e) None of these

Description : Rajesh loses 20% by selling a radio for Rs. 768. What per cent will he gain by selling it for Rs. 1080? (a) 6.25% (b) 8.25% (c) 10.25% (d) 4.25% (e) None of these

Last Answer : (e) None of these

On an IQ test consisting of 250 questions, Jasvinder answered 40% of the first 125 questions correctly. What per cent of the other 125 questions does he need to answer correctly for his grade on the entire exam to be 60%? (a) 75% (b) 80% (c) 60% (d) Cannot be determined (e) None of these

Description : On an IQ test consisting of 250 questions, Jasvinder answered 40% of the first 125 questions correctly. What per cent of the other 125 questions does he need to answer correctly for his grade on the entire exam to be 60%? (a) 75% (b) 80% (c) 60% (d) Cannot be determined (e) None of these

Last Answer : (b) 80%

A number consists of two digits whose sum is 8. If 8 is subtracted from the number, the digits interchange their places. The number is (1) 44 (2) 35 (3) 62 (4) 33

Description : A number consists of two digits whose sum is 8. If 8 is subtracted from the number, the digits interchange their places. The number is (1) 44 (2) 35 (3) 62 (4) 33

Last Answer : (4) 33

A grocer bought two kinds of rice at Rs. 38 and Rs. 32 per kg respectively. In what ratio should these two be mixed, so that by selling the mixture at Rs.42.5 per kg, 25% may be gained? a) 2:1 b) 3:2 c) 3:4 d) 1:2

Description : A grocer bought two kinds of rice at Rs. 38 and Rs. 32 per kg respectively. In what ratio should these two be mixed, so that by selling the mixture at Rs.42.5 per kg, 25% may be gained? a) 2:1 b) 3:2 c) 3:4 d) 1:2

Last Answer : d) 1:2

Reshma purchased 120 chairs at price of Rs. 110 per chair. He sold 30 chairsat a profit of Rs. 12 per chair and 75 chairs at profit of Rs. 14 per chairs. The remaining chairs were sold at a loss of Rs. 7 per chairs. What is the average profit per table? A. Rs 10.56 B. Rs 10.87 C. Rs 12.123 D. Rs 12.67

Description : Reshma purchased 120 chairs at price of Rs. 110 per chair. He sold 30 chairsat a profit of Rs. 12 per chair and 75 chairs at profit of Rs. 14 per chairs. The remaining chairs were sold at a loss of Rs. 7 per chairs ... the average profit per table? A. Rs 10.56 B. Rs 10.87 C. Rs 12.123 D. Rs 12.67 

Last Answer : Answer – B (Rs 10.875) Explanation – Total C.P = Rs. (120 x 110) =Rs. 13200. Total S.P = Rs.[(30 x 110 + 30 x 12) + (75 x 110 + 75 x 14) + (15 x 110 – 15 x 7) =Rs..14505 Average profit = Rs. (14505 – 13200) /120 = Rs. 1305/120= 10.875

At what height must top rails be fitted above working platform? a. Between 90 cm (35 inches) and 110 cm (43 inches) b. Between 100 cm (39 inches) and 120 cm (47 inches) c. Between 95 cm (38 inches) and 115 cm ( 45 inches) d. Between 105 cm (41 inches)and 125 cm (49 inches)

Description : At what height must top rails be fitted above working platform? a. Between 90 cm (35 inches) and 110 cm (43 inches) b. Between 100 cm (39 inches) and 120 cm (47 inches) c. Between 95 cm (38 inches) and 115 cm ( 45 inches) d. Between 105 cm (41 inches)and 125 cm (49 inches)

Last Answer : c. Between 95 cm (38 inches) and 115 cm ( 45 inches)

A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Description : A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is  subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Last Answer : Answer- 3(65) Explanation:- let the number be written as xy x-ten’s place y units place x+y=11…………………1 (10x+y)-(10y+x)=9 10x+y-10y-x=9 9x-9y=9 x-y=1………………….2 Add (1) & (2) 2x=12 x=6 y=5 the number is 65

The profit made by David in selling his calculator for Rs.400 would be the same as the loss he would have made in selling it at a 25% loss. If he sold his calculator after offering a discount of Rs.100, find the percentage at which he marked it above the cost price. a)56.25% b)62.5% c)60% d)50%

Description : The profit made by David in selling his calculator for Rs.400 would be the same as the loss he would have made in selling it at a 25% loss. If he sold his calculator after offering a discount of Rs.100, find the percentage at which he marked it above the cost price. a)56.25% b)62.5% c)60% d)50%

Last Answer : a)56.25%

A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? a) 79 b) 80 c) 81 d) 82 e) 83

Description : A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? a) 79 b) 80 c) 81 d) 82 e) 83

Last Answer : work finished by 33 days = 33 117 8 = 30888 man hours 4/7th of the job is finished. remaining work = 1-(4/7) = 3/7 if 4/7th of the work is 30888 hours, then 3/7th of the work = [30888 ... 9 number of men = 198 since, 117 men are already working, additional men required = 198 - 117 = 81 Answer: c)

Evaluate: 48×52 + 61×59 + 77×83 a) 12486 b) 10996 c) 13406 d) 13206 e) None of these

Description : Evaluate: 48×52 + 61×59 + 77×83 a) 12486 b) 10996 c) 13406 d) 13206 e) None of these

Last Answer : 48×52 = (50 - 2) × (50 + 2) = 502 – 22 = 2496 61 × 59 = (60 + 1) × (60 - 1) = 602 – 12 = 3599 77 × 83 = (80 - 3) × (80 + 3) = 802 – 32 = 6391 Sum = 2496 + 3599 + 6391 = 12486 Answer: a)

If the digits of a two digit number are interchanged, the number formed is greater than the original number by 45. If the difference between the digits is 5.What is the original number?

Description : If the digits of a two digit number are interchanged, the number formed is greater than the original number by 45. If the difference between the digits is 5.What is the original number? a) 18 b) 25 c) 36 d) Cannot be determined e) None of these

Last Answer : According to question both statements gives some equation which have two variable and it is not possible to find out two variable by single eg. Answer: d)

The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number? 1. 63 2. 48 3. 96 4. 69 5. 66

Description : The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number? 1. 63 2. 48 3. 96 4. 69 5. 66

Last Answer : Answer- 4 (69) Explanation:- lets digit at tens and ones place be 2x and 3x So,number is 2x*10 + 3x After interchanging number will be 3x*10 +2x so, [3x*10 +2x] – [2x*10 + 3x]27 we get,x=3 so number =69