A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train? A.59 km/hr B.65 km/hr C.70 km/hr D.81 km/hr E. None of these

1 Answer

Answer :

Answer-D (81 km/hr)

Explanation4.5 km/hr =(4.5 x 5/18)m/sec =5m/4sec = 1.25 m/sec, and

5.4 km/hr =(5.4 x 5/18)m/sec =3m/2sec = 1.5 m/sec.

Let the speed of the train be x m/sec.

Then, (x – 1.25) x 8.4 = (x – 1.5) x 8.5

=> 8.4x – 10.5 = 8.5x – 12.75

=> 0.1x = 2.25

=> x = 22.5

Therefore Speed of the train =(22.5 x18 /5)km/hr = 81 km/hr.

Related questions

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Last Answer : ANSWER:B Explanation:  First girl speed = 9km/hr  = 9 * 5 / 18 m/s  = 5/2 m/s  = 2.5 m/s  second girl speed = 10.8 km/hr  = 10.8 * 5/18 m/s  = 54/18  = 3 m/s  Let the speed of the train ... x - 3) * 17  16.8x - 42 = 17x - 51  0.2x = 9  x = 45  Therefore the speed of the train is 45 m/s

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Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

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Description : A train 330 m long passes a man, running at 18 km/hr in the direction opposite to that of the train in 18 seconds. The speed of the train is. A) 38 km/hr B) 29km/hr C) 48km/hr D) 44km/hr

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Description : A train 200m in length, travels at 120 km/hr. In what time it will pass a boy who is walking at 12km an hour. a) against(opposite) it: b) in the same direction? A) 5.4,6.66 B) 7.2,5.2 C) 3.5,6 D) 12,16

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Description : Two passenger trains are running in the same direction on parallel tracks at 210km/hr and 150km/hr respectively. The faster train passes a man 81 sec faster than the slower train. Find the length of the faster train. A) 1250m B) 1150m C) 1350m D) 1450m

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Last Answer : (a) Rs. 75,000/-

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Last Answer : ANSWER:A Explanation:  Speed of the person = 8 kmph  = (8*5/18)m/s  = 20/9 m/s  Then relative speed of train = (x-20/9)m/s  As train takes 50 sec to cross the person  Therefore 50 =250/(x-20/ ... 20,000 m  = 20 km Thus time taken by the person to cover the distance of 20km= 20/8 hr=2 ½ hr

Description : A father runs after his son, who is 1000 meters ahead. The father runs at a speed of 1 kilometre every 8 minutes, and the son runs at a speed of 1 kilometer every 12 minutes. How much distance has ... father overtakes him? a) 2500 meters b) 2000 meters c) 1500 meters d) 1000 meters e) 1200 meters

Last Answer : Time taken is same for both father and son Let x be the distance son travelled before being overtaken by his father Time taken by son = x/5 km/hour Time taken by father = (1000 + x) / 7.5 km/hr Since, time taken is same x/5 = (1000 + x) / 7.5 or x = 2000m Answer: b)

Description : Two trains, both 50m long, moving in opposite directions cross each other in 4 seconds. If one is moving thrice as fast the other, then the speed of the faster train is. A) 45km/hr B) 19 km/hr C) 95 km/hr D) 67.5 km/hr

Last Answer : ANSWER:D Explanation:  Let the speed of the slower train be x' m/sec  The speed of the sfaster train = 3x m/s  Relative speed = (x +3x)m/sec  = 4x m/sec  50 + 50 / 4 = 4x  100 / 4 = 4x  100 = 16x  x = 100 ... the faster train = 3 * 25 / 4  = 75 / 4 m/s = (75/4 *18 /5)km/hr  = 67.5 km/hr

Description : A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Last Answer : Answer – C (7) Explanation – Relative speed = (2 + 3) = 5 rounds per hourSo, they cross each other 5 times in an hour and 2 times in half an hourHence, they cross each other 7 times before 9.30 a.m.

Description : 4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these 

Last Answer : Answer: a)