A copper wire is bent to form an equilateral triangle of area 16√3 sq.cm. What will be the area (in sq.cm) if the same copper wire was bent to form a square?
a) 16
b) 24
c) 32
d) 40
e) None of the above
Area of equilateral triangle = 16√3 = √3 (side)2 /4
Or side2 = 16×4 = 64
So each side = 8cm
Perimeter = 8×3 = 24 cm
Since perimeter of the square is 24 cm, each side = 6cm
So area = 6×6 = 36 sq cm
Answer: e)