If the length of a rice field is increased by 20% and the breadth is reduced by 20%, the area of the field will be 192 sq. m. What is the area of the original field? (a) 184 sq. m. (b) 196 sq. m. (c) 204 sq. m. (d) 225 sq. m. (e) None of these

If the length of a rice field is increased by 20% and the breadth is reduced by 20%, the  area of the field will be 192 sq. m. What is the area of the original field? (a) 184 sq. m.
(b) 196 sq. m.
(c) 204 sq. m.
(d) 225 sq. m.
(e) None of these
by

1 Answer

Answer :

(e) None of these
by

Related questions

A rectangular park has a concrete footpath running in the middle of the park parallel to the length of the park. The rest of the park is used as a playing ground, which has an area of 253 sq. m. If the width of the path is 4m and the length of the park is greater than its breadth by 8 m. What is the area of the park? (in sq. m.) (a) 896 (b) 345 (c) 432

Description : A rectangular park has a concrete footpath running in the middle of the park parallel to the length of the park. The rest of the park is used as a playing ground, which has an area of 253 sq. m. If the width of the path ... m. What is the area of the park? (in sq. m.) (a) 896 (b) 345 (c) 432

Last Answer : (b) 345

Meeta purchased 35 rings at the rate of Rs. 160 per ring. At what rate per ring should she sell it so that profit earned is 20%? (a) Rs. 180 (b) Rs. 186 (c) Rs. 192 (d) Rs. 194 (e) Rs. 200

Description : Meeta purchased 35 rings at the rate of Rs. 160 per ring. At what rate per ring should she sell it so that profit earned is 20%? (a) Rs. 180 (b) Rs. 186 (c) Rs. 192 (d) Rs. 194 (e) Rs. 200

Last Answer : (c) Rs. 192

The width of a rectangular park is 10/21 of its length. If the area of the park is 3360 sq m, then what is the difference between the length and the width of the park? a) 40m b) 44m c) 48m d) 52m e) 56m

Description : The width of a rectangular park is 10/21 of its length. If the area of the park is 3360 sq m, then what is the difference between the length and the width of the park? a) 40m b) 44m c) 48m d) 52m e) 56m

Last Answer : Let the length of the park be x metres. Width = x × 10 / 21 = 10x / 21 Area = x × 10x / 21 = 3360 or, x^2 = 3360 × 21 / 10 = 7056 or, x = 84 Hence, length = x = 84m and width = 84 × 10 / 21 = 40 metres Difference = 84 – 40 = 44 metres Answer: b)

If the length of a rectangle is decreased by 3 units and breadth increased by 4 unit, then the area will increase by 9 sq. units. Represent this situation as a linear equation in two variables. -Maths 9th

Description : If the length of a rectangle is decreased by 3 units and breadth increased by 4 unit, then the area will increase by 9 sq. units. Represent this situation as a linear equation in two variables. -Maths 9th

Last Answer : Solution :-

Area of a rectangle is equal to the area of circle whose radius is 14 cms. If the breadth of the rectangle is 22 cms. What is its length? a) 27 cms b) 28 cms c) 25 cms. d) 29 cms e) None of these

Description : Area of a rectangle is equal to the area of circle whose radius is 14 cms. If the breadth of the rectangle is 22 cms. What is its length? a) 27 cms b) 28 cms c) 25 cms. d) 29 cms e) None of these

Last Answer : According to question, l×b = ¶r2 l ×22 = 22/7 ×14 × 14 l = 22/7 ×14 × 14/22 cms = 28 cms. Answer: b)

A rectangular plot has a concrete path running inner side of the plot is used as a lawn, which has an area of 432 sq.m. If the width of the path is 4 m and the length of the plot is greater than its breadth by 2m, what is the area of the rectangular plot? 1) 980 m^2 2) 975 m^2 3) 984 m^2 4) 960 m^2 5) 965 m^2

Description : A rectangular plot has a concrete path running inner side of the plot is used as a lawn, which has an area of 432 sq.m. If the width of the path is 4 m and the length of the plot is greater than its breadth by 2m, what is ... plot? 1) 980 m^2 2) 975 m^2 3) 984 m^2 4) 960 m^2 5) 965 m^2

Last Answer : 4) 960 m^2

Two concentric circles have radii of 23 cm and 9 cm. A rectangle has an area equal to the annular space between the above two circles. If the breadth of the rectangle is 22 cm then find its length. 1 : 32 cm 2 : 48 cm 3 : 76 cm 4 : 64 cm 5 : None of these

Description : Two concentric circles have radii of 23 cm and 9 cm. A rectangle has an area equal to the annular space between the above two circles. If the breadth of the rectangle is 22 cm then find its length. 1 : 32 cm 2 : 48 cm 3 : 76 cm 4 : 64 cm 5 : None of these

Last Answer : 4 : 64 cm

Rohit sold his bicycle at 4 % profit. If he sold it for Rs.204 less, he would have made a 30% loss. What was his cost price(in Rs.)? a)630 b)640 c)600 d)560

Description : Rohit sold his bicycle at 4 % profit. If he sold it for Rs.204 less, he would have made a 30% loss. What was his cost price(in Rs.)? a)630 b)640 c)600 d)560

Last Answer : c)600 

If the axial length of a drainage basin is 35 km and its form factor is 0.2, the total area of the basin is (A) 205 sq. km. (B) 215 sq. km. (C) 225 sq. km. (D) 245 sq. km.

Description : If the axial length of a drainage basin is 35 km and its form factor is 0.2, the total area of the basin is (A) 205 sq. km. (B) 215 sq. km. (C) 225 sq. km. (D) 245 sq. km.

Last Answer : Answer: Option D

A reduction of 20% in the price of sugar enables a person to get 7.8 kg more sugar for Rs.3.90. The original price of sugar per kg is a) Rs. 10 b) Rs.11.50 c) Rs. 12.5 d) Rs. 15 , e) Rs. 10.5

Description : A reduction of 20% in the price of sugar enables a person to get 7.8 kg more sugar for Rs.3.90. The original price of sugar per kg is a) Rs. 10 b) Rs.11.50 c) Rs. 12.5 d) Rs. 15 , e) Rs. 10.5

Last Answer : d) Rs. 15 ,

The owner of a TV shop charges his customer 20% more than the CP. If a customer paid Rs. 10800 for a TV, then find its original price? (a) Rs. 9300 (b) Rs. 8600 (c) Rs. 9800 (d) Rs. 7600 (e) None of the above

Description : The owner of a TV shop charges his customer 20% more than the CP. If a customer paid Rs. 10800 for a TV, then find its original price? (a) Rs. 9300 (b) Rs. 8600 (c) Rs. 9800 (d) Rs. 7600 (e) None of the above

Last Answer : (e) None of the above

I. 3x^2 – 47x + 184 = 0 II. 3y^2 – 38y + 119 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Description : I. 3x^2 – 47x + 184 = 0 II. 3y^2 – 38y + 119 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Last Answer : 3 : if x > y

A wall have length 24m and breadth 16m. What will be total cost of painting it from both sides if rate of painting is Rs 8 per square metre? 1) Rs 5696 2) Rs 5856 3) Rs 6032 4) Rs 6144 5) Rs 6272

Description : A wall have length 24m and breadth 16m. What will be total cost of painting it from both sides if rate of painting is Rs 8 per square metre? 1) Rs 5696 2) Rs 5856 3) Rs 6032 4) Rs 6144 5) Rs 6272

Last Answer : 4) Rs 6144

5287 – 176.22 – 78.584 = ? a) 5023.196 b) 5032.196 c) 5302.196 d) 5203.196 e) None of these

Description : 5287 – 176.22 – 78.584 = ? a) 5023.196 b) 5032.196 c) 5302.196 d) 5203.196 e) None of these

Last Answer : 5287 – 176.22 – 78.584 = 5032.196 Answer: b)

676, 400, 196, 64, 4, ? a) 4 b) 36 c) 16 d) -4 e) -16

Description : 676, 400, 196, 64, 4, ? a) 4 b) 36 c) 16 d) -4 e) -16

Last Answer : Answer: c)

√1369 ×√1444 +√?=1420 a) 14 b) 196 c) 198 d) 194 e) 16

Description : √1369 ×√1444 +√?=1420 a) 14 b) 196 c) 198 d) 194 e) 16

Last Answer : √1369 ×√1444 - √? =1420 Or, √(37)2 ×√(38)2×√? = 1420 Or,37 × 38 ×√? = 1420 Or,1406 + √? =1420 Or, √? = 1420 -1406 =14 ? = 196 Answer: b)

The external length, breadth and height of a closed box are 10cm, 9cm and 7cm respectively. The total inner surface area of the box is 262 sq.cm. If the walls of the box are of uniform thickness “t” cm, then “t” equals a) 1cm b) 23/3 cm c) 28/9 cm d) 42.5 cm

Description : The external length, breadth and height of a closed box are 10cm, 9cm and 7cm respectively. The total inner surface area of the box is 262 sq.cm. If the walls of the box are of uniform thickness “t” cm, then “t” equals a) 1cm b) 23/3 cm c) 28/9 cm d) 42.5 cm

Last Answer : a) 1cm

196, 200, 209, 234, 283, 404, 573, _____ 1 : 872 2 : 840 3 : 884 4 : 878 5 : 862

Description : 196, 200, 209, 234, 283, 404, 573, _____ 1 : 872 2 : 840 3 : 884 4 : 878 5 : 862

Last Answer : Answer-5 (862) Explanation- add square of prime no. in each step 4,9,25,49,121,so on

A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Description : A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Last Answer : Length of the wire = circumference of the circle 2 × (22/7) × 56 = 2 × 22 × 8 = 352 cm side of square = 352/4 = 88cm area of square = 88 × 88 = 7744 sq.cm Answer: c)

A copper wire is bent to form an equilateral triangle of area 16√3 sq.cm. What will be the area (in sq.cm) if the same copper wire was bent to form a square? a) 16 b) 24 c) 32 d) 40 e) None of the above

Description : A copper wire is bent to form an equilateral triangle of area 16√3 sq.cm. What will be the area (in sq.cm) if the same copper wire was bent to form a square? a) 16 b) 24 c) 32 d) 40 e) None of the above

Last Answer : Area of equilateral triangle = 16√3 = √3 (side)2 /4 Or side2 = 16×4 = 64 So each side = 8cm Perimeter = 8×3 = 24 cm Since perimeter of the square is 24 cm, each side = 6cm So area = 6×6 = 36 sq cm Answer: e)

The area of a circle is 154 sq cm. Its circumference is a) 44cm b) 88cm c) 154cm d) 176cm e) 164 cm

Description : The area of a circle is 154 sq cm. Its circumference is a) 44cm b) 88cm c) 154cm d) 176cm e) 164 cm

Last Answer : a) 44cm

A rectangular grassy plot 110 m by 65 m has a gravel path 2.5 m wide all round it on the inside. Find the cost of gravelling the path at 80 paise per sq. Meter 1).Rs.680 2).Rs.860 3).Rs.608 4).None.

Description : A rectangular grassy plot 110 m by 65 m has a gravel path 2.5 m wide all round it on the inside. Find the cost of gravelling the path at 80 paise per sq. Meter 1).Rs.680 2).Rs.860 3).Rs.608 4).None.

Last Answer : 1).Rs.680 Exp: overall area of the grassy plot is 110 x 65 =7150 sq. meters.The area of the grassy plot after applying the gravel path is 105 x 60=6300 sq. meters.Area of the gravel path is 7150 – 6300 = 850 sq.mtrs.Hence x 0.80=Rs.680 .

The shares of A, B and C are in the ratio 4 : 5 : 8. If each of the shares is increased by 75%, 20% and 25% respectively, what will be the ratio of their new shares? 1 : 5 : 3 : 5 2 : 7 : 6 : 9 3 : 7 : 6 : 10 4 : 5 : 6 : 10 5 : None of these

Description : The shares of A, B and C are in the ratio 4 : 5 : 8. If each of the shares is increased by 75%, 20% and 25% respectively, what will be the ratio of their new shares? 1 : 5 : 3 : 5 2 : 7 : 6 : 9 3 : 7 : 6 : 10 4 : 5 : 6 : 10 5 : None of these

Last Answer : 3 : 7 : 6 : 10

The price of oil is increased by 20%,as a result a family decrease consumption by 25%.The expenditure of the family on oil will be 1).90%increase 2).10%incraese 3).90%decrease 4).10%increase.

Description : The price of oil is increased by 20%,as a result a family decrease consumption by 25%.The expenditure of the family on oil will be 1).90%increase 2).10%incraese 3).90%decrease 4).10%increase.

Last Answer : 4).10%increase. Exp: (120/100)×(75/100)×100=90. 100-90=10%(should be decrease)

3 4 12 45 ? 1005 a) 152 b) 198 c) 144 d) 192 e) None of these

Description : 3 4 12 45 ? 1005 a) 152 b) 198 c) 144 d) 192 e) None of these

Last Answer : Answer: e)

When the integers from 1 to 999 are written on a paper, the number of zeros used in writing it is: a) 192 b) 189 c) 200 d) 203 e) 216

Description : When the integers from 1 to 999 are written on a paper, the number of zeros used in writing it is: a) 192 b) 189 c) 200 d) 203 e) 216

Last Answer : From 1 to 10 : 1 zero From 11-100 : 10 zeros (100 has 2 zeros) From 101 – 900 : 8×20 = 160 zeros From 901-999 : we have 18 zeros Total = 1+10+160+18 = 189 zeros Answer: b)

256 128 ? 192 96 240 80 a) 64 b) 156 c) 96 d) 128 e) 176

Description : 256 128 ? 192 96 240 80 a) 64 b) 156 c) 96 d) 128 e) 176

Last Answer : The series is ×0.5, ÷1, ×1.5, ÷2, ×2.5.... Answer: d)

Number of appeared candidates increased by 20% from 2002 to 2006. If 25% of the appeared candidates qualified in 2006, what was the number of qualified candidates in 2006? A. 205 B. 225 C. 245 D. 240 E. 230

Description : Number of appeared candidates increased by 20% from 2002 to 2006. If 25% of the appeared candidates qualified in 2006, what was the number of qualified candidates in 2006? A. 205 B. 225 C. 245 D. 240 E. 230

Last Answer : B. 225

The LCM of two numbers is 45 times their HCF. If one of the numbers is 125 and the sum of HCF and LCM is 1150, then the other number is? a) 100 b) 125 c) 250 d) 225 e) 180

Description : The LCM of two numbers is 45 times their HCF. If one of the numbers is 125 and the sum of HCF and LCM is 1150, then the other number is? a) 100 b) 125 c) 250 d) 225 e) 180

Last Answer : LCM = 45× HCF LCM + HCF = 46× HCF = 1150 HCF = 25, LCM =1125. product of 2 numbers = LCM×HCF required number = (25× 1125) / 125 = 225. Answer: d)

6000 ÷ 15 × 225 – 70000 = ? a) 20000 b) 18000 c) 16000 d) 14000 e) 15000

Description : 6000 ÷ 15 × 225 – 70000 = ? a) 20000 b) 18000 c) 16000 d) 14000 e) 15000

Last Answer : ? = 6000 – 225 / 15 - 70000 = 90000 – 70000 = 20000 Answer: a)

0 1 9 36 99 225 441 a) 9 b) 36 c) 99 d) 225 e) 441

Description : 0 1 9 36 99 225 441 a) 9 b) 36 c) 99 d) 225 e) 441

Last Answer : Answer: c)

104 153 189 214 ? a) 239 b) 225 c) 264 d) 235 e) None of these

Description : 104 153 189 214 ? a) 239 b) 225 c) 264 d) 235 e) None of these

Last Answer : Answer: e)

4 32 ? 2048 16348 a) 250 b) 286 c) 256 d) 225 e) None of these

Description : 4 32 ? 2048 16348 a) 250 b) 286 c) 256 d) 225 e) None of these

Last Answer : Multiply by 8. Answer: c)

Use Euclid’s division algorithm to find the HCF of: i. 135 and 225 ii. 196 and 38220 iii. 867 and 225 -Maths 10th

Description : Use Euclid’s division algorithm to find the HCF of: i. 135 and 225 ii. 196 and 38220 iii. 867 and 225 -Maths 10th

Last Answer : 135 and 225 As you can see, from the question 225 is greater than 135. Therefore, by Euclid's division algorithm, we have, 225 = 135 1 + 90 Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get, ... (867,225) = HCF(225,102) = HCF(102,51) = 51. Hence, the HCF of 867 and 225 is 51

Use Euclid’s division algorithm to find the HCF of : (i) 135 and 225 (ii) 196 and 38220 (iii) 867 and 255 -Maths 10th

Description : Use Euclid’s division algorithm to find the HCF of : (i) 135 and 225 (ii) 196 and 38220 (iii) 867 and 255 -Maths 10th

Last Answer : (i) Given numbers are 135 and 225. On applying Euclid's division algorithm, we have 225 = 135 x 1 + 90 Since the remainder 90 ≠ 0, so again we apply Euclid's division algorithm to 135 and 90, to get 135 = 90 x ... division lemma, to a =867 and b=255 to find q and r such that 867 = 255q + r, 0 ≤ r

If the numerator of a fraction is increased by 25% and the denominator is doubled, the fraction thus obtained is 5/9. What is the original fraction? a) 3/4 b) 7/8 c) 8/9 d) Cannot be determined e) None of these

Description : If the numerator of a fraction is increased by 25% and the denominator is doubled, the fraction thus obtained is 5/9. What is the original fraction? a) 3/4 b) 7/8 c) 8/9 d) Cannot be determined e) None of these

Last Answer : Let the numerator & denominator of a fraction be n & d. According to questions, = n × 5 / d × 8 = 5/9 = n/d = 8 × 5 / 5 × 9 = n/d = 8/9 Answer: c)

If the numerator of a fraction is increased by 300% and the denominator of the fraction is increased by 150%, the resultant fraction is 3/5. What is the original fraction? a) 7/5 b) 3/7 c) 7/15 d) 1/6 e) None of these

Description : If the numerator of a fraction is increased by 300% and the denominator of the fraction is increased by 150%, the resultant fraction is 3/5. What is the original fraction? a) 7/5 b) 3/7 c) 7/15 d) 1/6 e) None of these

Last Answer : x + 300% of x / y +150% of y = 3/5 400x/250y = 3/5 x/y = 3 × 250 /5 × 400 x/y = 3/8 Answer: e)

Each side of an equilateral triand 12 is \( 24 cm \) the mid - point of its sides are joined to form another tranpla this brress is doins centinuously infinite46. The perimeter of 7 th triangle is \( ( \) in \( cm ) \)a) \( \frac{3}{4} \)b) \( \frac{5}{8} \)c) \( \frac{9}{8} \)d) \( \frac{7}{8} \)47. The sum of perimeter of all triangle is (in \( cm \) )a) 144b) 625c) 400d) 16948. The area of all the triangle is (in sq cm)a) 576b) \( 144 \sqrt{3} \)c) \( 169 \sqrt{3} \)d) \( 192 \sqrt{3} \)49. The sum of perimeter of first 6 triangle is (in \( cm \) )a) 120b) \( \frac{567}{4} \)c) \( \frac{569}{4} \)d) 14450. The side of the 5th triangle is (in \( cm \) )a) 6b) \( 1.5 \)c) \( 0.75 \)d) 3

Description : Each side of an equilateral triand 12 is \( 24 cm \) the mid - point of its sides are joined to form another tranpla this brress is doins centinuously infinite46. The perimeter of 7 th triangle is \( ( \) in \( cm ) \)a) \( \ ... of the 5th triangle is (in \( cm \) )a) 6b) \( 1.5 \)c) \( 0.75 \)d) 3

Last Answer : Each side of an equilateral triand 12 is \( 24 cm \) the mid - point of its sides are joined to form another tranpla ... ( 1.5 \) c) \( 0.75 \) d) 3

The loss made by selling 16 m of a cloth equals the selling price of 4 m of that cloth. Find the loss percentage a)15% b)20% c)33 1/3% d)25%

Description : The loss made by selling 16 m of a cloth equals the selling price of 4 m of that cloth. Find the loss percentage a)15% b)20% c)33 1/3% d)25%

Last Answer : b)20%

The profit made by selling 25 m of a cloth equals the selling price of 5 m of that cloth. find the profit percentage? a)25% b)20% c)16 2/3% d)30%

Description : The profit made by selling 25 m of a cloth equals the selling price of 5 m of that cloth. find the profit percentage? a)25% b)20% c)16 2/3% d)30%

Last Answer : a)25%

The profit made by selling 30 m of a cloth equals the cost price of 6 m of that cloth. find the profit percentage a)25% b)20% c)16 2/3% d)30%

Description : The profit made by selling 30 m of a cloth equals the cost price of 6 m of that cloth. find the profit percentage a)25% b)20% c)16 2/3% d)30%

Last Answer : b)20% 

The loss made by selling 20 m of a cloth equals the cost price of 5 m of that cloth. Find the loss percentage a)33 1/3% b)25% c)20% d)40%

Description : The loss made by selling 20 m of a cloth equals the cost price of 5 m of that cloth. Find the loss percentage a)33 1/3% b)25% c)20% d)40%

Last Answer : b)25%

You are working with three networks that have the network IDs 192.168.5.0, 192.168.6.0, and192.168.7.0. What subnet mask can you use to combine these addresses intoone? A. 255.255.252.0 B. 225.255.254.0 C. 255.255.255.240 D. 255.255.255.252

Description : You are working with three networks that have the network IDs 192.168.5.0, 192.168.6.0, and192.168.7.0. What subnet mask can you use to combine these addresses intoone? A. 255.255.252.0 B. 225.255.254.0 C. 255.255.255.240 D. 255.255.255.252

Last Answer : 255.255.252.0

If a Company require 60 hosts then What is the best possible subnet mask? a. 255.255.255.0 b. 255.255.255.192 c. 255.255.225.224 d. 225.225.255.240

Description : If a Company require 60 hosts then What is the best possible subnet mask? a. 255.255.255.0 b. 255.255.255.192 c. 255.255.225.224 d. 225.225.255.240

Last Answer : b. 255.255.255.192

The dimensions of a rectangular settling tank are: length 24 m, width 6 m and depth 3 m. If 2 hour detention period for tanks is recommended, the rate of flow of sewage per hour, is A. 204 cu.m B. 208 cu.m C. 212 cu.m D. 216 cu.m

Description : The dimensions of a rectangular settling tank are: length 24 m, width 6 m and depth 3 m. If 2 hour detention period for tanks is recommended, the rate of flow of sewage per hour, is A. 204 cu.m B. 208 cu.m C. 212 cu.m D. 216 cu.m

Last Answer : ANS: D

Nithish bought two purses which together cost him Rs.440. He sold one of the purse at a loss of 20% and the other one at a gain of 40%. The selling price of both purse are same. Then find out the cost price of both purse. a) Rs.150 and Rs.290 b) Rs.140 and Rs.300 c) Rs.170 and Rs.270 d) Rs.160 and Rs.280 e) None of the Above

Description : Nithish bought two purses which together cost him Rs.440. He sold one of the purse at a loss of 20% and the other one at a gain of 40%. The selling price of both purse are same. Then find out the cost price of both ... Rs.140 and Rs.300 c) Rs.170 and Rs.270 d) Rs.160 and Rs.280 e) None of the Above

Last Answer : 80/100 * x = 140/100 * y x = 7/4y x + y = 440 7/4 y + y = 440 y = 160 ; x = 280 Answer: d)

A merchant dealer gives successive discounts of 10% and 20% in that order and makes a profit of 20%. what will be the profit if he offers a single flat discount of 30%? a) 20% b) 16.67% c) 18% d) 14% e) None of these

Description : A merchant dealer gives successive discounts of 10% and 20% in that order and makes a profit of 20%. what will be the profit if he offers a single flat discount of 30%? a) 20% b) 16.67% c) 18% d) 14% e) None of these

Last Answer : let marked price be 100. SP with 10%, 20% = 80% of (90% of 100) = 72. profit = 20% so CP = 72/1.20 = Rs. 60 by offering a flat discount of 30%, sales price = 70% of 100 = 70 profit = (70 - 60) ×100 / 60 = 16.67% Answer: b)

Which of the following series of discounts is the best for a customer? (A) Successive discounts of 10% ,20%,30% (B) Successive discounts of 20%,20%,20% (C) Successive discounts of 15%,15%,15%,15% (D) Successive discounts of 20%,40% a) A b) B c) C d) D e) A and B

Description : Which of the following series of discounts is the best for a customer? (A) Successive discounts of 10% ,20%,30% (B) Successive discounts of 20%,20%,20% (C) Successive discounts of 15%,15%,15%,15% (D) Successive discounts of 20%,40% a) A b) B c) C d) D e) A and B

Last Answer : consider the price as 100 A = 100 × 0.9 × 0.8 × 0.7 =50.4 B = 100 × 0.8 × 0.8 × 0.8=51.2 C = 100 × 0.85 × 0.85 × 0.85 ×0.85 ~ =52.2 D = 100 × 0.8 × 0.6 =48 We see that the maximum discount of 52% (100-48) is on D, which is the best for a customer. Answer : d

Which of the following series of discounts is the best for a customer? (A) Successive discounts of 10% ,20%,30% (B) Successive discounts of 20%,20%,20% (C) Successive discounts of 15%,15%,15%,15% (D) Successive discounts of 20%,40% a) A b) B c) C d) D e) A and B

Description : Which of the following series of discounts is the best for a customer? (A) Successive discounts of 10% ,20%,30% (B) Successive discounts of 20%,20%,20% (C) Successive discounts of 15%,15%,15%,15% (D) Successive discounts of 20%,40% a) A b) B c) C d) D e) A and B

Last Answer : consider the price as 100 A = 100 × 0.9 × 0.8 × 0.7 =50.4 B = 100 × 0.8 × 0.8 × 0.8=51.2 C = 100 × 0.85 × 0.85 × 0.85 ×0.85 ~ =52.2 D = 100 × 0.8 × 0.6 =48 We see that the maximum discount of 52% (100-48) is on D, which is the best for a customer. Answer : d