136% of 105 – 84% of 165 = ? a) 4.2 b) 5.7 c) 6.4 d) 7.8 e) 8.6

136% of 105 – 84% of 165 = ?
a) 4.2
b) 5.7
c) 6.4
d) 7.8
e) 8.6
by

1 Answer

Answer :

a) 4.2
by

Related questions

The ratio between two number is 3:4 ,if each number be increased by 9, the ratio becomes 18:23 find the sum of the number a) 135 b) 105 c) 155 d) 165 e) None of these

Description : The ratio between two number is 3:4 ,if each number be increased by 9, the ratio becomes 18:23 find the sum of the number a) 135 b) 105 c) 155 d) 165 e) None of these

Last Answer : Let the two numbers be 3x and 4x. When they are increased by 9 they become 3x + 9 and 4x + 9. It is given that the ratio is 18:23 Thus, 3x + 9/4x + 9 = 18:23 23(3x + 9) = 18(4x + 9) 69x + 207 = 72x ... = -45 X = 15 Thus two numbers are 3x15 = 45 and 4 x 15 = 60 And the sum is 60+45 = 105 Answer: b)

A Mixture contain 88% of sulphur,another mixture contain 70% of sulphur.In order to get 84% of sulphur,in what ratio these two must be mixed. A) 2:7 B)7:2 C)7:4 D)4:5

Description : A Mixture contain 88% of sulphur,another mixture contain 70% of sulphur.In order to get 84% of sulphur,in what ratio these two must be mixed. A) 2:7 B)7:2 C)7:4 D)4:5

Last Answer : B)7:2

63251 × 82 = ? × 42105 a) 101 b) 123 c) 147 d) 165 e) 189

Description : 63251 × 82 = ? × 42105 a) 101 b) 123 c) 147 d) 165 e) 189

Last Answer : Answer: b)

63251 * 82 = ? * 42l05 1) 101 2) 123 3) 147 4) 165 5) 8885

Description : 63251 * 82 = ? * 42l05 1) 101 2) 123 3) 147 4) 165 5) 8885

Last Answer : 4) 165

In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage of water in the final mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Description : In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage ... mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Last Answer : 2) 28. 57%

Find the electric field when the velocity of the field is 12m/s and the flux density is 8.75 units. a) 510 b) 105 c) 150 d) 165

Description : Find the electric field when the velocity of the field is 12m/s and the flux density is 8.75 units. a) 510 b) 105 c) 150 d) 165

Last Answer : b) 105

187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these

Description : 187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these

Last Answer : The pattern is -5.5, -11, -16.5, -22 and so on. Answer: c)

Vinoth could get equal number of Rs. 55, Rs. 85 and Rs. 105 ticket for a Zoo. He spend Rs. 3920 for all the tickets. How many of each did he buy? a) 15 b) 18 c) 16 d) 26 e) None of these

Description : Vinoth could get equal number of Rs. 55, Rs. 85 and Rs. 105 ticket for a Zoo. He spend Rs. 3920 for all the tickets. How many of each did he buy? a) 15 b) 18 c) 16 d) 26 e) None of these

Last Answer : Total money = 55x + 85x + 105x = 3920 245x = 3920 x = 16 Answer: c)

2 9 30 105 ? 2195 a) 432 b) 426 c) 440 d) 436 e) None of these

Description : 2 9 30 105 ? 2195 a) 432 b) 426 c) 440 d) 436 e) None of these

Last Answer : The series is ×1 + 1 × 7, ×2 + 2 × 6, ×3 + 3 × 5... Answer: d)

2 9 ? 105 436 2195 13182 a) 32 b) 45 c) 40 d) 30 e) 25

Description : 2 9 ? 105 436 2195 13182 a) 32 b) 45 c) 40 d) 30 e) 25

Last Answer : The series is (2 + 7) × 1 = 9; (9 + 6) × 2 = 30; (30 + 5) × 3 = 105; (105 + 4) × 4 = 436; (436 + 3) × 5 = 2195; (2195 + 2) × 6 = 13182 Answer: d)

Find: (i) 32% of 425 (ii) 1623% of 16 (iii) 6.5% of 400 (iv) 136% of 70 (v) 2.8% of 35 (vi) 0.6% of 45 -Maths

Description : Find: (i) 32% of 425 (ii) 1623% of 16 (iii) 6.5% of 400 (iv) 136% of 70 (v) 2.8% of 35 (vi) 0.6% of 45 -Maths

Last Answer : answer:

Evaluate: (4 + 4×18 – 6 - 8) / (123×6 - 146×5) a) 7.5 b) 7.75 c) 8 d) 8.25 e) 8.5

Description : Evaluate: (4 + 4×18 – 6 - 8) / (123×6 - 146×5) a) 7.5 b) 7.75 c) 8 d) 8.25 e) 8.5

Last Answer : Numerator = 4 + 72 – 14 = 62 Denominator = 738 – 730 = 8 Required value = 62/8 = 7.75 Answer: b)

A man can row 15 km/hr in still water. It takes him twice as long to row upstream as to row downstream. Find the rate of stream? a) 5 km/hr b) 10 km/hr c) 7.5 km/hr d) 6 km/hr e) 8 km/hr

Description : A man can row 15 km/hr in still water. It takes him twice as long to row upstream as to row downstream. Find the rate of stream? a) 5 km/hr b) 10 km/hr c) 7.5 km/hr d) 6 km/hr e) 8 km/hr

Last Answer : Let the man’s upstream speed be x km/hour and downstream speed will be 2x km/hour Speed in still water = 1/2 (2x + x) = 3x/2 km/hour 3x/2 = 15 X = 10 Hence, his downstream speed = 20km/hour Rate of stream = 1/2 (20-10) = 5km/hour Answer: a)

19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Description : 19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Last Answer : 240 1 180 = 4/3 12 4 (240 1 180) = 3 (4/3) = 4 101 + 98 7 - 113 = 101 + 14 - 113 = 2 19 + (12 4 (240 1 180)) 6 (101 + 98 7 - 113) = 19 + 4 6 2 = 19 + 4 3 = 31 7 2 ... 180)) 6 (101 + 98 7 - 113) - (7 2 + 14 - 3.5 - 9 8.5) 4 = 31 - (-250) = 281 Answer: e)

7^3 * √7 * 3√7 * ÷ 7 ÷ 3√(√7) = (7)^? a) 5/6 b) 5/3 c) 7/6 d) 8/3 e) 7/3

Description : 7^3 * √7 * 3√7 * ÷ 7 ÷ 3√(√7) = (7)^? a) 5/6 b) 5/3 c) 7/6 d) 8/3 e) 7/3

Last Answer : e) 7/3

A and B enter into a partnership. A contributes Rs. 16,000 and B Rs. 12,000. At the end of 6 months C joins them with a capital of Rs. 20,000. In what ratio should they divide their annual profit? a) 8:6:5 b) 4 :3 :5 c) 5:6:8 d) 5:3:4 e) 5:7:8

Description : A and B enter into a partnership. A contributes Rs. 16,000 and B Rs. 12,000. At the end of 6 months C joins them with a capital of Rs. 20,000. In what ratio should they divide their annual profit? a) 8:6:5 b) 4 :3 :5 c) 5:6:8 d) 5:3:4 e) 5:7:8

Last Answer : a) 8:6:5

Pipe A can fill a water tank in 8 hours, Pipe B can fill the same tank in 12 hours and Pipe C can empty the tank in 24 hours. If all three pipes are opened together, in how many hours will the tank be completely filled or empty? a) 4.8 hours b) 5 hours c) 5.4 hours d) 6 hours e) 7.2 hours

Description : Pipe A can fill a water tank in 8 hours, Pipe B can fill the same tank in 12 hours and Pipe C can empty the tank in 24 hours. If all three pipes are opened together, in how many hours will the tank be completely filled or empty? a) 4.8 hours b) 5 hours c) 5.4 hours d) 6 hours e) 7.2 hours

Last Answer : If all the three pipes are opened together, in one hour they will fill 1/8 + 1/12 – 1/24 = (3+2-1)/24 = 1/6 part of tank. So, to fill it completely it will take 6 hours. Answer is: d)

Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. What is the proportion of the solution Y in the liquid in the tank after 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Description : Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. ... 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Last Answer : a Part of the tank filled by pipe P in 1 minute = 1 / 40 Part of the tank filled by pipe Q in 1 minute = 1 / 15 Part of the tank filled by pipe R in 1 minute = 1/ 30 Here we have to find the proportion of ... together in 5 minute = 5 1/8 = 5/ 8 Required proportion = (1/3) / ( 5/8) = 8 / 15

8 men and 4 women-together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men left and 4 new women joined, in how many more days will the work be completed? a) 7 days b) 6 days c) 5 days d) 8 days e) 4 days

Description : 8 men and 4 women-together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men ... more days will the work be completed? a) 7 days b) 6 days c) 5 days d) 8 days e) 4 days 

Last Answer : 1 man = 2 women 8 men + 4 women = 20 women 2 day's work of 20 women = 20 × 6/1 = 20 × 2/x x =1/3 Remaining work = 1 – 1/3 = 2/3 Total number of females = 16 20 × 6/1 = 16 × x ÷2/ 3 x = 5 days Short Cut M1D1=M2D2+M3D3 10x6 =10x2 + 8 x 60-20= 8x x= 5 days Answer: c)

The ratio between the present ages of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years? A.5 : 7 B.7 : 8 C.8 : 7 D.Data inadequate E.None of these

Description : The ratio between the present ages of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years? A.5 : 7 B.7 : 8 C.8 : 7 D.Data inadequate E.None of these

Last Answer : Answer – B (7 : 8) Explanation – Let A’s age and B’s age be 6X years and 7X years respectively Then, 7X – 6X = 4 X = 4 Required ratio = (6X + 4) : (7X + 4) = (6*4+4) : (7*4 +4) =28 : 32 = 7 : 8

6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days. a) 4 days b) 6 days c) 2 days d) 8 days e) 7 days

Description : 6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days. a) 4 days b) 6 days c) 2 days d) 8 days e) 7 days

Last Answer : Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b Work done by 6 men and 8 women in 1 day = 1/10 => 6m + 8b = 1/10 => 60m + 80b = 1 --- (1) Work done by 26 men and 48 ... 1 day = 15/100 + 20/200 =1/4 => Time taken by 15 men and 20 women in doing the work = 4 days Answer: a)

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

(1024 − 263 − 233) ÷ (986 − 764 − 156) = ? a) 9 b) 6 c) 7 d) 8 e) None of these

Description : (1024 − 263 − 233) ÷ (986 − 764 − 156) = ? a) 9 b) 6 c) 7 d) 8 e) None of these

Last Answer : Answer: d) 

Value of 1/ {2 + [1 / (2 +1/[ 2 – 1/2 ])]} a) 6/19 b) 7/19 c) 8/19 d) 9/19 e) None of these

Description : Value of 1/ {2 + [1 / (2 +1/[ 2 – 1/2 ])]} a) 6/19 b) 7/19 c) 8/19 d) 9/19 e) None of these

Last Answer : Answer: c) 

A sum of money is divided among Suresh, Ganesh, Vignesh and Mahesh in the ratio of 3 : 4 : 9 : 10 respectively. If the share of Vignesh is Rs.2,580/-more than the share of Ganesh, then what is the total amount of money of Suresh and Mahesh together ? a) Rs. 6,985/- b) Rs. 6,487/- c) Rs. 6,708/- d) Rs. 7,156/- e) Rs. 8,457/-

Description : A sum of money is divided among Suresh, Ganesh, Vignesh and Mahesh in the ratio of 3 : 4 : 9 : 10 respectively. If the share of Vignesh is Rs.2,580/-more than the share of Ganesh, then what is the total amount of money of Suresh ... ,985/- b) Rs. 6,487/- c) Rs. 6,708/- d) Rs. 7,156/- e) Rs. 8,457/-

Last Answer : According to the question, difference of ratio of Ganesh and Vignesh is 5 so, 1 ratio = 2580/5 = 516 Now, total ratio of Suresh + Mahesh = 13 So, total money = 13 × 516 = Rs. 6708 Answer: c)

The shares of A, B and C are in the ratio 4 : 5 : 8. If each of the shares is increased by 75%, 20% and 25% respectively, what will be the ratio of their new shares? 1 : 5 : 3 : 5 2 : 7 : 6 : 9 3 : 7 : 6 : 10 4 : 5 : 6 : 10 5 : None of these

Description : The shares of A, B and C are in the ratio 4 : 5 : 8. If each of the shares is increased by 75%, 20% and 25% respectively, what will be the ratio of their new shares? 1 : 5 : 3 : 5 2 : 7 : 6 : 9 3 : 7 : 6 : 10 4 : 5 : 6 : 10 5 : None of these

Last Answer : 3 : 7 : 6 : 10

In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Description : In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Last Answer : A)11:77:7

An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Description : An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Last Answer : Answer: a)

3 1/7 + 4 2/5 - ? = -2 3/5 a) a) 10 1/7 b) b) 7 1/10 c) c) 8 8/7 d) d) 9 8/7 e) None of these

Description : 3 1/7 + 4 2/5 - ? = -2 3/5 a) a) 10 1/7 b) b) 7 1/10 c) c) 8 8/7 d) d) 9 8/7 e) None of these

Last Answer : 3 1/7 + 4 2/5 - ? = -2 3/5 22/7 + 22/5 + 13/5 = 355/35 = 71/7 = 10 1/7 Answer: a)

Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a total simple interest of 19,550 at the end of 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Description : Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a ... 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Last Answer : Let the amount borrowed be Rs P Total amount of simple interest = (P×3×4)/100 + (p×2×8)/100 + (p×2×9)/100 = 19550 0.12P + 0.16P + 0.18P = 19550 0.46p= 19550 P = Rs. 42500 Answer: b)

Ajay reads at an average rate of 30 pages per hour, while Vikram reads at an average rate of 40 pages per hour. If Ajay starts reading a novel at 4:30 PM and Vikram begins reading an identical copy of the same book at 5:20 PM, at what time will they be reading the same page? a) 7:50 PM b) 8:15 PM c) 8:40 PM d) 9:00 PM e) 9:25 PM

Description : Ajay reads at an average rate of 30 pages per hour, while Vikram reads at an average rate of 40 pages per hour. If Ajay starts reading a novel at 4:30 PM and Vikram begins reading an identical copy of the same book at 5:20 PM, at ... same page? a) 7:50 PM b) 8:15 PM c) 8:40 PM d) 9:00 PM e) 9:25 PM

Last Answer : Ajay reads at average rate of 30 pages per hour ie. 1 page in every two minutes. Therefore, by 5:20 PM, he would have covered 25 pages By 6:20 PM, Ajay would have read 25+30 pages and Vikram would have ... and he will also finish 100 pages Hence, both of them will be on same page at 7:50 Answer: a)

The sum of 5 natural numbers A, B, C, D, E is 126. It is known that A:B = 7:8, B:C = 2:3, C:D = 4:5, D:E = 5:7.What is the difference between A and E? a) 14 b) 22 c) 24 d) 28 e) 32

Description : The sum of 5 natural numbers A, B, C, D, E is 126. It is known that A:B = 7:8, B:C = 2:3, C:D = 4:5, D:E = 5:7.What is the difference between A and E? a) 14 b) 22 c) 24 d) 28 e) 32

Last Answer : A:B = 7:8 B:C = 2:3 = 8:12 SO, A:B:C = 7:8:12 C:D = 4:5 = 12:15 A:B:C:D = 7:8:12:15 D:E = 5:7 = 15:21 SO, A:B:C:D:E = 7:8:12:15:21 given x(7+8+12+15+21) = 126 or 63x = 126 or x =2 E – A = 21X – 7X = 14X = 28 Answer: d)

Busses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? a) 3 km/hr b) 4 km/hr c) 5 km/hr d) 7 km/hr e) None of these

Description : Busses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? a) 3 km/hr b) 4 km/hr c) 5 km/hr d) 7 km/hr e) None of these

Last Answer : Distance covered in 10 minutes at 20 kmph = distance covered in 8 minutes at (20+x) kmph 20× 10/60=8/60(20+x) 200 = 160 + 8x 8x = 40 x=40/8=5 kmph Answer: c)

A reduction of 20% in the price of sugar enables a person to get 7.8 kg more sugar for Rs.3.90. The original price of sugar per kg is a) Rs. 10 b) Rs.11.50 c) Rs. 12.5 d) Rs. 15 , e) Rs. 10.5

Description : A reduction of 20% in the price of sugar enables a person to get 7.8 kg more sugar for Rs.3.90. The original price of sugar per kg is a) Rs. 10 b) Rs.11.50 c) Rs. 12.5 d) Rs. 15 , e) Rs. 10.5

Last Answer : d) Rs. 15 ,

The ages of A and B are in the ratio 8 : 5. If the sum of their ages is 39 years, what will be the ratio of their ages after 9 years? a) 3 : 2 b) 8 : 7 c) 10: 7 d) 11 : 8 e) None of these

Description : The ages of A and B are in the ratio 8 : 5. If the sum of their ages is 39 years, what will be the ratio of their ages after 9 years? a) 3 : 2 b) 8 : 7 c) 10: 7 d) 11 : 8 e) None of these

Last Answer : Sum of ratios = 8 +5 = 13. Sum of ages = 39 years 13 ratio = 39 years  1 ratio = 3 years 9 years = 3 ratio new ratio = (8+3) : (5+3) = 11 : 8 Answer: d)

If the numerator of a fraction is increased by 25% and the denominator is doubled, the fraction thus obtained is 5/9. What is the original fraction? a) 3/4 b) 7/8 c) 8/9 d) Cannot be determined e) None of these

Description : If the numerator of a fraction is increased by 25% and the denominator is doubled, the fraction thus obtained is 5/9. What is the original fraction? a) 3/4 b) 7/8 c) 8/9 d) Cannot be determined e) None of these

Last Answer : Let the numerator & denominator of a fraction be n & d. According to questions, = n × 5 / d × 8 = 5/9 = n/d = 8 × 5 / 5 × 9 = n/d = 8/9 Answer: c)

If the compound interest accrued on an amount of Rs.15,000/- in two years is Rs.2,496/-.What is the rate of interest p.c.p.a.? a) 8 b) 12 c) 7.5 d) Cannot be determined e) None of these

Description : If the compound interest accrued on an amount of Rs.15,000/- in two years is Rs.2,496/-.What is the rate of interest p.c.p.a.? a) 8 b) 12 c) 7.5 d) Cannot be determined e) None of these

Last Answer : Let the rate of interest p.c.p.a. be x. 2496 =15000 * x /100 x = 16.64 16.64 is the rate of interest compounded for two year & for one year = 8% 8% C.I. table for two year. I year = 8% II year = 8.64 Total =16.64% Answer: a)

The compound interest accrued on an amount of Rs. 25,500 at the end of three years is Rs. 8,440.5.What would be the simple interest accrued on the same amount at the same rate in the same period? a) Rs. 5,450/- b) Rs. 8,750/- c) Rs. 4,350/- d) Rs. 3,650/- e) Rs. 7,650/-

Description : The compound interest accrued on an amount of Rs. 25,500 at the end of three years is Rs. 8,440.5.What would be the simple interest accrued on the same amount at the same rate in the same period? a) Rs. 5,450/- b) Rs. 8,750/- c) Rs. 4,350/- d) Rs. 3,650/- e) Rs. 7,650/- 

Last Answer : A = P + Interest = 25500 + 8440.5 = 33940.5 A = P + 1 + (R/100)^3 33940.5 = 25500 a + R/100)^3 a + R/100)^3 = 33940.5 / 25500 a + R/100)^3 = 1.331 a + R/100)^3 = ... R = 10% Simple Interest = Principle Rate Time / 100 = 25500 10 3/100 = 7650 Answer: e)

1/8 × 3/5 × 4/7 x 7897 = ? a) 310 b) 325 c) 375 d) 275 e) 338

Description : 1/8 × 3/5 × 4/7 x 7897 = ? a) 310 b) 325 c) 375 d) 275 e) 338

Last Answer : ? = 7897 × 4 × 3 / 8 × 5 × 7 = 338.31 = 338 (approx.) Answer: e)

11 6 7 12 26 67.5 ? a) 205.5 b) 195.5 c) 216.5 d) 200.5 e) 222.5

Description : 11 6 7 12 26 67.5 ? a) 205.5 b) 195.5 c) 216.5 d) 200.5 e) 222.5

Last Answer : The series is: 11 × 0.5 + 0.5 = 6; 6 × 1 + 1 = 7; 7 × 1.5 + 1.5 = 12; 12 × 2 + 2 = 26; 26 × 2.5 + 2.5 = 67.5; 67.5 × 3 + 3 = 205.5. Answer: a)

13 6 7 9 20 47.5 ? a) 149.5 b) 140.5 c) 150.5 d) 147.5 e) 145.5

Description : 13 6 7 9 20 47.5 ? a) 149.5 b) 140.5 c) 150.5 d) 147.5 e) 145.5

Last Answer : The series is × 0.5 – 0.5, × 1 + 1, ×1.5 – 1.5, ×2 + 2, ... Answer: e)

In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is? a) 5 kmph b) 6 kmph c) 6.25 kmph d) 7.5 kmph e) None of these

Description : In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is? a) 5 kmph b) 6 kmph c) 6.25 kmph d) 7.5 kmph e) None of these

Last Answer : Let Abhay's speed be x km/hr. Then, 30/x-30/2x= 3 6x = 30 x = 5 km/hr. Answer: a)

189 2/9 +189 3/9+189 5/9+189 6/9+189 7/9 =? a) 1138 b) 1037 c) 1237 d) 1238 e) 1137

Description : 189 2/9 +189 3/9+189 5/9+189 6/9+189 7/9 =? a) 1138 b) 1037 c) 1237 d) 1238 e) 1137

Last Answer : ? = 189 2/9 + 189 3/9 +189 4/9 +189 5/9 + 189 6/9 + 189 7/9 =(189 × 6) +(2/9 + 3/9 +4/9+5/9+6/9+7/9 ) =1134 + (2+3+4+5+6+7)/9 =113 + (27/9) =1134 + 3=1137 Answer: e)

Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these

Description : Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these

Last Answer : Present ratio of Deepa&Subha = 5 : 6 Six year hence ratio of Deepa&Subha = 6 : 7 Difference between ratio = 1 Difference in ages between present & future = 6 year. 1 ratio=6 yrs & SUBHA's age = 6 6 =36 year 5 year ago ... = 7 6 = 42 year B's age 5 year ago = 42-6-5 = 42-11 = 31 year Answer: d)

12.28× 1.5 -36÷ 2.4 = ? a) 3.24 b) 7.325 c) 6.42 d) 4.32 e) None of these

Description : 12.28× 1.5 -36÷ 2.4 = ? a) 3.24 b) 7.325 c) 6.42 d) 4.32 e) None of these

Last Answer : 12.28 × 1.5 - 15 = ? 18.42 - 15 = ? ? = 3.42 Answer: e)

If the numerator of a fraction is increased by 300% and the denominator of the fraction is increased by 150%, the resultant fraction is 3/5. What is the original fraction? a) 7/5 b) 3/7 c) 7/15 d) 1/6 e) None of these

Description : If the numerator of a fraction is increased by 300% and the denominator of the fraction is increased by 150%, the resultant fraction is 3/5. What is the original fraction? a) 7/5 b) 3/7 c) 7/15 d) 1/6 e) None of these

Last Answer : x + 300% of x / y +150% of y = 3/5 400x/250y = 3/5 x/y = 3 × 250 /5 × 400 x/y = 3/8 Answer: e)

A shopkeeper declares that he sells rice at the cost price. However he uses a weight of 425 grams. Instead of 500 grams, what is his percentage of profit? a) a) 16 5/6 b) 15 c) c) 20 7/23 d) 25 e) None of these

Description : A shopkeeper declares that he sells rice at the cost price. However he uses a weight of 425 grams. Instead of 500 grams, what is his percentage of profit? a) a) 16 5/6 b) 15 c) c) 20 7/23 d) 25 e) None of these

Last Answer : % profit = Loss/Actual Weight x 100 = 500 – 425/500 × 100 = 75/500 x 100 = 15% Answer: b)

A train travelling at a speed of 75 mph enters a tunnel 7/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges? A.1 min B.3 min C.5 min D.6 min E.None of these

Description : A train travelling at a speed of 75 mph enters a tunnel 7/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges? A.1 min B.3 min C.5 min D.6 min E.None of these

Last Answer : Answer – B (3 min) Explanation – Actually train is covering length of tunnel + its own length here so total distance = 7/2 + 1/4= 15/4 miles time= distance /speed time= (15/4) / 75 = 1/20 hour (1/20)x60 = 3 min

Mr. Xavier invested a certain amount in Debit and Equity funds in the ratio of 4 : 5 respectively. At the end of one year, he earned a total dividend of 30% on his investment. After one year he reinvested the amount including dividend in the ratio of 6 : 7 in Debt and Equity Funds. If the amount reinvested in Equity Funds was Rs. 94,500/-, what was the original amount invested in Equity Funds? (a) Rs. 75,000/- (b) Rs. 81,000/- (c) Rs. 60,000/- (d) Rs. 65,000/- (e) None of these

Description : Mr. Xavier invested a certain amount in Debit and Equity funds in the ratio of 4 : 5 respectively. At the end of one year, he earned a total dividend of 30% on his investment. After one year he reinvested the amount including ... . 81,000/- (c) Rs. 60,000/- (d) Rs. 65,000/- (e) None of these

Last Answer : (a) Rs. 75,000/-