Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a total simple interest of 19,550 at the end of 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a total simple interest of 19,550 at the end of 7 years, how much money did he borrow?
a) 39,500
b) 42,500
c) 41,900
d) 43,000
e) None of these
by

1 Answer

Answer :

Let the amount borrowed be Rs P
Total amount of simple interest = (P×3×4)/100 + (p×2×8)/100 + (p×2×9)/100 = 19550
0.12P + 0.16P + 0.18P = 19550
0.46p= 19550
P = Rs. 42500
Answer: b)
by

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Last Answer : A = P + Interest = 25500 + 8440.5 = 33940.5 A = P + 1 + (R/100)^3 33940.5 = 25500 a + R/100)^3 a + R/100)^3 = 33940.5 / 25500 a + R/100)^3 = 1.331 a + R/100)^3 = ... R = 10% Simple Interest = Principle Rate Time / 100 = 25500 10 3/100 = 7650 Answer: e)

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Last Answer : Let the sum be S, time be ‘n’ years for 6%. n+2 years for 5% 2400 = S + S ×n × 6/100 2400 = S + S × (n+2) × 5/100 So, 6n = 5(n+2) or n = 10 years. 2400 = S + S × 10 × 6/100 = 1.6S S = 2400/1.6 = 1500 Answer: a)

Jagdeep bought a refrigerator with 20% discount on the labeled price. Had he bought at it with 30% discount, he would have saved Rs. 500 more. At what price did he buy the refrigerator? A. Rs 5000 B. Rs 10,000 C. Rs 12,500 D. Rs 15,000

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Last Answer : Answer – A. Rs 5,000 Explanation – Let the labelled price be Rs.x Then, (80% of x)- (70% of x) = 500 10% of x =500 10%………..500 100%…………? ?= (500 x 100/10) = 5000=x

A sum of money is divided among Suresh, Ganesh, Vignesh and Mahesh in the ratio of 3 : 4 : 9 : 10 respectively. If the share of Vignesh is Rs.2,580/-more than the share of Ganesh, then what is the total amount of money of Suresh and Mahesh together ? a) Rs. 6,985/- b) Rs. 6,487/- c) Rs. 6,708/- d) Rs. 7,156/- e) Rs. 8,457/-

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Last Answer : According to the question, difference of ratio of Ganesh and Vignesh is 5 so, 1 ratio = 2580/5 = 516 Now, total ratio of Suresh + Mahesh = 13 So, total money = 13 × 516 = Rs. 6708 Answer: c)

A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km

Description : A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km

Last Answer : 3) 840 km

What is the average score in an exam taken by 500 students where the minimum score is 200? a. Half the students scored above 700. b. Half the students scored below 700. c. The maximum score in the exam was 850, scored by exactly 42 students.

Description : What is the average score in an exam taken by 500 students where the minimum score is 200? a. Half the students scored above 700. b. Half the students scored below 700. c. The maximum score in the ... . e) If the data in statement a, b and c together are not sufficient to answer the question.

Last Answer : The fact that half scored above 700, and other half less than 700 does not tell the actual distribution of scores to calculate the average. Statement (c) also does not help us determine the average. Answer: e)

A man plays 100 games with cards. He gets Rs.5 if he wins and pays Rs.2 if he loses. If he wins Rs.3 on the whole, in how many games did he win? a) 25 b) 28 c) 29 d) 32 e) None of these

Description : A man plays 100 games with cards. He gets Rs.5 if he wins and pays Rs.2 if he loses. If he wins Rs.3 on the whole, in how many games did he win? a) 25 b) 28 c) 29 d) 32 e) None of these

Last Answer : Suppose he wins the first game and loses the second. Then his gain =Rs 5- Rs 2 = Rs 3 out of remaining 98 games, amount won =amount lost =>Games won : Games lost 2 : 5 In last 98 Games, he wins =2/7 × 98 =28 games =>Total games he won =28 + 1 =29 Answer: c)

A started a business with Rs. 21,000 and is joined afterwars by B with Rs. 36,000. After how many months did B join if the profits at the end of the year are divided equally? A.8 months B.2 months C.5 months D.7 months

Description : A started a business with Rs. 21,000 and is joined afterwars by B with Rs. 36,000. After how many months did B join if the profits at the end of the year are divided equally? A.8 months B.2 months C.5 months D.7 months

Last Answer : Answer – C (5 months) Explanation – let B joined after x months Then, 21000 x 12 = 36000 x (12 – x)36 = 180x = 5Hence, B joined after 5 months

A and B started a business jointly. A’s investment was thrice the investment of B and the period of his investment was two times the period of investment of B. If B received Rs.4000 as profit, then their total profit is : a) Rs.16,000 b) Rs.20,000 c) Rs.24,000 d) Rs.28,000 e) None of these

Description : A and B started a business jointly. A’s investment was thrice the investment of B and the period of his investment was two times the period of investment of B. If B received Rs.4000 as profit, then their total profit is : a) Rs.16,000 b) Rs.20,000 c) Rs.24,000 d) Rs.28,000 e) None of these

Last Answer : Suppose B invested Rs. x for y months. Then, A invested Rs.3x for 2y months. So, A : B = (3x × 2y) : (x × y) = 6xy : xy = 6 : 1 So, B’s profit : total profit = 1 : 7 Let the total profit be Rs. x. Then, 1 / 7 = 40000 / x Or x = 28000. Answer: d)

2 3 5 8 14 23 41 69 a) 5 b) 8 c) 14 d) 41 e) 69

Description : 2 3 5 8 14 23 41 69 a) 5 b) 8 c) 14 d) 41 e) 69

Last Answer : The series is an alternate series, having S 1 = 2 5 14 41; ×3 – 1 in each term S 2 = 3 8 23 69; ×3 – 1 in each term Answer: e)

Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Description : Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Last Answer : Arranging the data in ascending order, we have 25, 31, 32, 37, 39, 42, 43, 45, 46 Here, number of observations = 9 (odd) Median = value of (9+1 / 2)th Observation = Value of 5th Observation = 39

Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Description : Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Last Answer : Arranging the data in ascending order, we have 25, 31, 32, 37, 39, 42, 43, 45, 46 Here, number of observations = 9 (odd) Median = value of (9+1 / 2)th Observation = Value of 5th Observation = 39