63251 * 82 = ? * 42l05 1) 101 2) 123 3) 147 4) 165 5) 8885

63251 * 82 = ? * 42l05
1) 101
2) 123
3) 147
4) 165
5) 8885
by

1 Answer

Answer :

4) 165
by

Related questions

63251 × 82 = ? × 42105 a) 101 b) 123 c) 147 d) 165 e) 189

Description : 63251 × 82 = ? × 42105 a) 101 b) 123 c) 147 d) 165 e) 189

Last Answer : Answer: b)

(562 % of 816) + 1449 = ? 1) 4145 2) 5675 3) 6035 4) 7325 5) 8885

Description : (562 % of 816) + 1449 = ? 1) 4145 2) 5675 3) 6035 4) 7325 5) 8885

Last Answer : 3) 6035

13 6 7 9 20 47.5 ? a) 149.5 b) 140.5 c) 150.5 d) 147.5 e) 145.5

Description : 13 6 7 9 20 47.5 ? a) 149.5 b) 140.5 c) 150.5 d) 147.5 e) 145.5

Last Answer : The series is × 0.5 – 0.5, × 1 + 1, ×1.5 – 1.5, ×2 + 2, ... Answer: e)

Total literate population of City F is approximately what percentage of total illiterate population of City A ? 1) 137.5% 2) 142.5% 3) 147.5% 4) 152.5% 5) 157.5%

Description : Total literate population of City F is approximately what percentage of total illiterate population of City A ? 1) 137.5% 2) 142.5% 3) 147.5% 4) 152.5% 5) 157.5%

Last Answer : 4) 152.5%

136% of 105 – 84% of 165 = ? a) 4.2 b) 5.7 c) 6.4 d) 7.8 e) 8.6

Description : 136% of 105 – 84% of 165 = ? a) 4.2 b) 5.7 c) 6.4 d) 7.8 e) 8.6

Last Answer : a) 4.2

In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage of water in the final mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Description : In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage ... mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Last Answer : 2) 28. 57%

The average domestic investment in the year 2011 is what percent of the average investment in Transport during the given four years? a) 201% b) 65.34% c) 125.45% d) 147.97% e) 167.23%

Description : The average domestic investment in the year 2011 is what percent of the average investment in Transport during the given four years? a) 201% b) 65.34% c) 125.45% d) 147.97% e) 167.23%

Last Answer : b) 65.34%

The ratio between two number is 3:4 ,if each number be increased by 9, the ratio becomes 18:23 find the sum of the number a) 135 b) 105 c) 155 d) 165 e) None of these

Description : The ratio between two number is 3:4 ,if each number be increased by 9, the ratio becomes 18:23 find the sum of the number a) 135 b) 105 c) 155 d) 165 e) None of these

Last Answer : Let the two numbers be 3x and 4x. When they are increased by 9 they become 3x + 9 and 4x + 9. It is given that the ratio is 18:23 Thus, 3x + 9/4x + 9 = 18:23 23(3x + 9) = 18(4x + 9) 69x + 207 = 72x ... = -45 X = 15 Thus two numbers are 3x15 = 45 and 4 x 15 = 60 And the sum is 60+45 = 105 Answer: b)

Evaluate: (4 + 4×18 – 6 - 8) / (123×6 - 146×5) a) 7.5 b) 7.75 c) 8 d) 8.25 e) 8.5

Description : Evaluate: (4 + 4×18 – 6 - 8) / (123×6 - 146×5) a) 7.5 b) 7.75 c) 8 d) 8.25 e) 8.5

Last Answer : Numerator = 4 + 72 – 14 = 62 Denominator = 738 – 730 = 8 Required value = 62/8 = 7.75 Answer: b)

Dhivya, Dinesh and Deepi enter into a partnership and their shares are in the ratio 1/3 :1/4 :1/5. After 2 months, dhivya withdraws half of her capital and after 10 months, a profit of Rs. 462 is divided among them, what is Deepi’s share? A) 123.56 B) 165.45 C) 143.3 D) 146.43

Description : Dhivya, Dinesh and Deepi enter into a partnership and their shares are in the ratio 1/3 :1/4 :1/5. After 2 months, dhivya withdraws half of her capital and after 10 months, a profit of Rs. 462 is divided among them, what is Deepi’s share? A) 123.56 B) 165.45 C) 143.3 D) 146.43

Last Answer : Answer: C) Ratio of initial investments = 1/3 : 1/4 : 1/5 = 20 :15 :12 Let their initial investments be 20x, 15x and 12x respectively Dhivya: Dinesh :Deepi = (20x *2 +10x *10) : (15x *12) : (12x*12) =140x : ... 70:90:72 = 35 : 45 :36 Deepi s share = Rs.462 * 36/116 = Rs(16632/116) =Rs.143.3

4×(√3 + √4)2 + 6(√5 +√6)2 -3(√2 + √3)2 =? a) 167 b) 123 c) 157 d) 153 e) 149

Description : 4×(√3 + √4)2 + 6(√5 +√6)2 -3(√2 + √3)2 =? a) 167 b) 123 c) 157 d) 153 e) 149

Last Answer : ? =4(3+4+2√12) + 6(5+6+2√30)-3(2+3+2√6) =4(7+2√12)+6(11+2√30)-3(5+2√6) =28 + 8√12 + 66 + 12√30 – 15 - 6√6 =(28+66-15) + (8√12+12√30-6√6) =79 + (8√4 × 3 + 12√30 - 6√6) =79+16√3 + 12√30 - 6√6 =79 + 16 ×1.7 + 12 × 5.4 – 6 ×2.4 =79+27.2 + 64.8-14.4 = 156.6 = 157 Answer: c)

987.67 × 123.35 ÷ 9 = ? a) 13411 b) 13621 c) 13489 d) 13551 e) 13721

Description : 987.67 × 123.35 ÷ 9 = ? a) 13411 b) 13621 c) 13489 d) 13551 e) 13721

Last Answer : ? = (987 × 123) / 9 = 13489 Answer: c)

√6889+√3721+√1024-√2401=? a) 129 b) 128 c) 127 d) 124 e) 123

Description : √6889+√3721+√1024-√2401=? a) 129 b) 128 c) 127 d) 124 e) 123

Last Answer : √6889 + √3721 +√1024 - √2401 = ? Or,?= √(83)2 + √(61)2 + √(32)2 - √(49)2 =83+61+32 – 49 =127 Answer: c)

Reshma purchased 120 chairs at price of Rs. 110 per chair. He sold 30 chairsat a profit of Rs. 12 per chair and 75 chairs at profit of Rs. 14 per chairs. The remaining chairs were sold at a loss of Rs. 7 per chairs. What is the average profit per table? A. Rs 10.56 B. Rs 10.87 C. Rs 12.123 D. Rs 12.67

Description : Reshma purchased 120 chairs at price of Rs. 110 per chair. He sold 30 chairsat a profit of Rs. 12 per chair and 75 chairs at profit of Rs. 14 per chairs. The remaining chairs were sold at a loss of Rs. 7 per chairs ... the average profit per table? A. Rs 10.56 B. Rs 10.87 C. Rs 12.123 D. Rs 12.67 

Last Answer : Answer – B (Rs 10.875) Explanation – Total C.P = Rs. (120 x 110) =Rs. 13200. Total S.P = Rs.[(30 x 110 + 30 x 12) + (75 x 110 + 75 x 14) + (15 x 110 – 15 x 7) =Rs..14505 Average profit = Rs. (14505 – 13200) /120 = Rs. 1305/120= 10.875

. What is the ratio of the total investment in Metals to that in Machinery? a) 135 : 302 b) 24 : 49 c) 2 : 4 d) 197 : 226 e) 123 : 233

Description : . What is the ratio of the total investment in Metals to that in Machinery? a) 135 : 302 b) 24 : 49 c) 2 : 4 d) 197 : 226 e) 123 : 233

Last Answer : d) 197 : 226

19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Description : 19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Last Answer : 240 1 180 = 4/3 12 4 (240 1 180) = 3 (4/3) = 4 101 + 98 7 - 113 = 101 + 14 - 113 = 2 19 + (12 4 (240 1 180)) 6 (101 + 98 7 - 113) = 19 + 4 6 2 = 19 + 4 3 = 31 7 2 ... 180)) 6 (101 + 98 7 - 113) - (7 2 + 14 - 3.5 - 9 8.5) 4 = 31 - (-250) = 281 Answer: e)

A box contains 15bolts of which 5 are defective. If 5 bolts are selected at random from the box, what is the probability that at least one of them is defective? a) 91/143 b) 101/143 c) 111/143 d) 121/143 e) 131/143

Description : A box contains 15bolts of which 5 are defective. If 5 bolts are selected at random from the box, what is the probability that at least one of them is defective? a) 91/143 b) 101/143 c) 111/143 d) 121/143 e) 131/143

Last Answer : Probability that at least one is defective = 1 – probability that none is defective Probability that none is defective = 10C5 / 15C5 = 12/143 Required Probability = 1-12/143 = 131/143 Answer: e)

501/58 * 291/101 ÷ 31/155 = ? a) 140 b) 125 c) 95 d) 85 e) 110

Description : 501/58 * 291/101 ÷ 31/155 = ? a) 140 b) 125 c) 95 d) 85 e) 110

Last Answer : Answer: b)

Total literate population of city E is what percentage of total population of city D? 1) 67.5% 2) 71.5% 3) 74.5% 4) 77.5% 5) 82.5%

Description : Total literate population of city E is what percentage of total population of city D? 1) 67.5% 2) 71.5% 3) 74.5% 4) 77.5% 5) 82.5%

Last Answer : 2) 71.5%

A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? a) 79 b) 80 c) 81 d) 82 e) 83

Description : A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? a) 79 b) 80 c) 81 d) 82 e) 83

Last Answer : work finished by 33 days = 33 117 8 = 30888 man hours 4/7th of the job is finished. remaining work = 1-(4/7) = 3/7 if 4/7th of the work is 30888 hours, then 3/7th of the work = [30888 ... 9 number of men = 198 since, 117 men are already working, additional men required = 198 - 117 = 81 Answer: c)

What is the average domestic investment in the year 2014? (You are not expected to calculate the exact value? a) Rs.2814.28 Crore b) Rs.2519.75 Crore c) Rs.2234.82 Crore d) Rs.3151.51 Crore e) Rs.3329.79 Crore

Description : What is the average domestic investment in the year 2014? (You are not expected to calculate the exact value? a) Rs.2814.28 Crore b) Rs.2519.75 Crore c) Rs.2234.82 Crore d) Rs.3151.51 Crore e) Rs.3329.79 Crore

Last Answer : a) Rs.2814.28 Crore

A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is a) 177.7 km b) 154.2 km c) 163.5 km d) 147.3 km

Description : A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is a) 177.7 km b) 154.2 km c) 163.5 km d) 147.3 km

Last Answer : A Let the distance between bus stop and destination be X. The total time taken by the bus to cover X = 4 hours Since X/2 by 40km/hr and remaining X/2 by 50km/hr Then by Time = distance/speed, we have ... = 1600 9X = 1600 X = 1600/9 = 177.7 Hence 177.7 km is the required answer.

187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these

Description : 187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these

Last Answer : The pattern is -5.5, -11, -16.5, -22 and so on. Answer: c)

In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Description : In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Last Answer : Let current age of Ram and his son be R,S (R + 10) = 3(S + 10) [2 times older = 3 times the age] R = 3S + 20 (R - 5) = 9(S - 5) 3S + 20 – 5= 9S – 45 3S + 15 = 9S – 45 or S = 10., R = 50 sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66. Answer: b)

An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Description : An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Last Answer : Answer: a)

A man who makes a profit of 25 percent by selling sugar at Rs. 4.25/kg., lowers his price so as to gain only 5 paise per Kg. In what ratio must his sales be increased so that his total profit may be the same as before? a) 1 : 5 b) 1 : 11 c) 1 : 13 d) 1 : 17 e) 1 : 21

Description : A man who makes a profit of 25 percent by selling sugar at Rs. 4.25/kg., lowers his price so as to gain only 5 paise per Kg. In what ratio must his sales be increased so that his total profit may be the same as before? a) 1 : 5 b) 1 : 11 c) 1 : 13 d) 1 : 17 e) 1 : 21

Last Answer : 125% C.P. of sugar per kg = Rs. 4.25 C.P of the sugar per kg = [4.25×100] / 125 = Rs. 3.40. thus, the profit on 1 kg 85 paise by reducing price to 5 paise, to make same profit he must sell, 85/5 = 17kg so required ratio = 1 : 17. Answer: d)

3 1/7 + 4 2/5 - ? = -2 3/5 a) a) 10 1/7 b) b) 7 1/10 c) c) 8 8/7 d) d) 9 8/7 e) None of these

Description : 3 1/7 + 4 2/5 - ? = -2 3/5 a) a) 10 1/7 b) b) 7 1/10 c) c) 8 8/7 d) d) 9 8/7 e) None of these

Last Answer : 3 1/7 + 4 2/5 - ? = -2 3/5 22/7 + 22/5 + 13/5 = 355/35 = 71/7 = 10 1/7 Answer: a)

Evaluate: (0.625 × 0.0729 × 28.9)/(0.0081 × 0.025 × 1.7) a) 382.5 b) 3725 c) 3625 d) 3825 e) None of these

Description : Evaluate: (0.625 × 0.0729 × 28.9)/(0.0081 × 0.025 × 1.7) a) 382.5 b) 3725 c) 3625 d) 3825 e) None of these

Last Answer : (0.625×0.0729×28.9) / (0.0081×0.025×1.7) = (625/25) × (729/81) × (289/17) = 25×9× 17 = 3825. Answer: d)

Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a total simple interest of 19,550 at the end of 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Description : Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a ... 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Last Answer : Let the amount borrowed be Rs P Total amount of simple interest = (P×3×4)/100 + (p×2×8)/100 + (p×2×9)/100 = 19550 0.12P + 0.16P + 0.18P = 19550 0.46p= 19550 P = Rs. 42500 Answer: b)

Ajay reads at an average rate of 30 pages per hour, while Vikram reads at an average rate of 40 pages per hour. If Ajay starts reading a novel at 4:30 PM and Vikram begins reading an identical copy of the same book at 5:20 PM, at what time will they be reading the same page? a) 7:50 PM b) 8:15 PM c) 8:40 PM d) 9:00 PM e) 9:25 PM

Description : Ajay reads at an average rate of 30 pages per hour, while Vikram reads at an average rate of 40 pages per hour. If Ajay starts reading a novel at 4:30 PM and Vikram begins reading an identical copy of the same book at 5:20 PM, at ... same page? a) 7:50 PM b) 8:15 PM c) 8:40 PM d) 9:00 PM e) 9:25 PM

Last Answer : Ajay reads at average rate of 30 pages per hour ie. 1 page in every two minutes. Therefore, by 5:20 PM, he would have covered 25 pages By 6:20 PM, Ajay would have read 25+30 pages and Vikram would have ... and he will also finish 100 pages Hence, both of them will be on same page at 7:50 Answer: a)

A committee of 5 members is to be formed from 8 men and 5 women. How many committees can be formed if at least 2 women and 1 man have to present in the committee? a) 800 b) 840 c) 880 d) 920 e) 996

Description : A committee of 5 members is to be formed from 8 men and 5 women. How many committees can be formed if at least 2 women and 1 man have to present in the committee? a) 800 b) 840 c) 880 d) 920 e) 996

Last Answer : The various possible cases are: i. 2 women and 3 men = 5C2 × 8C3 = 10 × 56 = 560 ii. 3 women and 2 men = 5C3 × 8C2 = 10 × 28 = 280 iii. 4 women and 1 men = 5C4 × 8C1 = 5 × 8 = 40 Total = 560 + 280 + 40 = 880 Answer: c)

What is the size of the longest pencil that can fit in a box with dimensions 12 cm× 10 cm× 8cm? a) 15 b) 15.5 c) 17 d) 17.5 e) 18

Description : What is the size of the longest pencil that can fit in a box with dimensions 12 cm× 10 cm× 8cm? a) 15 b) 15.5 c) 17 d) 17.5 e) 18

Last Answer : Answer: d)

The average monthly expenditure of a family was Rs. 2200 during the first 3 months; Rs. 2250 during the next 4 months and Rs. 3120 during the last 5 months of a year. If the total savings during the year were Rs. 1260, then the average monthly income was: a) Rs. 2605 b) Rs. 2680 c) Rs. 2705 d) Rs. 2745 e) Rs. 2595

Description : The average monthly expenditure of a family was Rs. 2200 during the first 3 months; Rs. 2250 during the next 4 months and Rs. 3120 during the last 5 months of a year. If the total savings during the year were Rs. 1260 ... income was: a) Rs. 2605 b) Rs. 2680 c) Rs. 2705 d) Rs. 2745 e) Rs. 2595

Last Answer : Total expenditure for first 3 months = 2200 3 = Rs 6600 Total expenditure for next 4 months = 2250 4 = Rs9000 Total expenditure for last 5 months = 3120 5 = Rs 15600 Total expenditure = 6600 + ... + savings = 31200 + 1260 = Rs 324060 Average monthly income = 32460/12 = Rs 2705 Answer: c)

Two equal sums are lent at the same time at 6% and 5 % simple interest respectively. The former is recovered 24 months earlier than the latter. And the amount in each case is Rs. 2400. Find the sum of money lent initially. a) 1500 b) 2000 c) 2400 d) 3000 e) 3600

Description : Two equal sums are lent at the same time at 6% and 5 % simple interest respectively. The former is recovered 24 months earlier than the latter. And the amount in each case is Rs. 2400. Find the sum of money lent initially. a) 1500 b) 2000 c) 2400 d) 3000 e) 3600

Last Answer : Let the sum be S, time be ‘n’ years for 6%. n+2 years for 5% 2400 = S + S ×n × 6/100 2400 = S + S × (n+2) × 5/100 So, 6n = 5(n+2) or n = 10 years. 2400 = S + S × 10 × 6/100 = 1.6S S = 2400/1.6 = 1500 Answer: a)

The monthly incomes of two persons are in the ratio 5 : 4 and their monthly expenditures are in the ratio 9 : 7. If each person saves Rs. 500 per month, then what are their monthly incomes? a) Rs 8000 and Rs 10000 b) Rs 3750 and Rs 3000 c) Rs 5000 and Rs 4000 d) Rs 4500 and Rs 4000 e) None of the above

Description : The monthly incomes of two persons are in the ratio 5 : 4 and their monthly expenditures are in the ratio 9 : 7. If each person saves Rs. 500 per month, then what are their monthly incomes? a) Rs 8000 and Rs ... Rs 3750 and Rs 3000 c) Rs 5000 and Rs 4000 d) Rs 4500 and Rs 4000 e) None of the above

Last Answer : Let the incomes of two persons be 5x and 4x let the expenditures of them be 9y and 7y Each person saves Rs. 500 Therefore, 5x - 9y = 500 4x - 7y = 500 Solving the above equations, 20x - 36y = 2000 20x - ... = 500 + 9(500) = 5000 X = 1000 Hence, their salaries are Rs. 5000 and Rs. 4000 Answer: c)

A man can row 15 km/hr in still water. It takes him twice as long to row upstream as to row downstream. Find the rate of stream? a) 5 km/hr b) 10 km/hr c) 7.5 km/hr d) 6 km/hr e) 8 km/hr

Description : A man can row 15 km/hr in still water. It takes him twice as long to row upstream as to row downstream. Find the rate of stream? a) 5 km/hr b) 10 km/hr c) 7.5 km/hr d) 6 km/hr e) 8 km/hr

Last Answer : Let the man’s upstream speed be x km/hour and downstream speed will be 2x km/hour Speed in still water = 1/2 (2x + x) = 3x/2 km/hour 3x/2 = 15 X = 10 Hence, his downstream speed = 20km/hour Rate of stream = 1/2 (20-10) = 5km/hour Answer: a)

5 ? 4 7.5 17 45 a) 3.5 b) 3 c) 2.5 d) 2 e) None of these

Description : 5 ? 4 7.5 17 45 a) 3.5 b) 3 c) 2.5 d) 2 e) None of these

Last Answer : The series is ×0.5 + 0.5, ×1 + 1, ×1.5 + 1.5, ... Answer: b)

5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Description : 5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Last Answer : Each term in the series is the addition of successive prime numbers. Like Prime numbers are2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and so on. So first term is addition of (2 + 3). Ie 5, then second term is (3 + 5) ie ... +17)ie. 30, then (17+19)ie.36, then (19+23)ie., 42, then (23+29)i.e. 52. Answer: a)

2 3 5 8 14 23 41 69 a) 5 b) 8 c) 14 d) 41 e) 69

Description : 2 3 5 8 14 23 41 69 a) 5 b) 8 c) 14 d) 41 e) 69

Last Answer : The series is an alternate series, having S 1 = 2 5 14 41; ×3 – 1 in each term S 2 = 3 8 23 69; ×3 – 1 in each term Answer: e)

3 7.5 15 37.5 75 167.5 375 a) 167.5 b) 75 c) 37.5 d) 15 e) 7.5

Description : 3 7.5 15 37.5 75 167.5 375 a) 167.5 b) 75 c) 37.5 d) 15 e) 7.5

Last Answer : The series is ×2.5, ×2 alternately Answer: a)

5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

Description : 5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

Last Answer : The series is +5, +7, +9, +11, .... Answer: c)

[(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35

Description : [(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35

Last Answer : ? = [(64+9) / 24] – [(81+16)/36] = (73/24) – (97/36) = (219 - 194)/72 = 25/72 = 0.347 = 0.35 Answer: e)

The incomes of A of B are in the ratio 3:2 and their expenditure are in the ratio 5:3 if each saves rupees 2000, what is their income? a) 32000 b) 20000 c) 1190 d) 8000 e) None of these

Description : The incomes of A of B are in the ratio 3:2 and their expenditure are in the ratio 5:3 if each saves rupees 2000, what is their income? a) 32000 b) 20000 c) 1190 d) 8000 e) None of these

Last Answer : Let the income be 3x and 2x. It is given that the saving of each is Rs. 2000. Then, their expenditures are 3x - 2000 and 2x - 2000 Again, (3x - 2000)/(2x - 2000) = 5/3 => 3(3x - 2000) = 5(2x - ... -x = -4000 => x = 4000 Therefore, their salaries are 3 x 4000 = 12000 and 2 x 4000 = 8000 Answer: d)

A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Description : A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Last Answer : Work done by A in one day = 1/5 and work done by B in one day = 1/7 They are working alternately. Therefore, Work done in first two day = (1/5 + 1/7) = 12/35 Work done in first four day = 24/35 Work done in ... = 4/35/1/7 = 4/5 of the day. Therefore Total days taken = 5 + 4/5 = 29/5 days Answer: b)

1/9, 4/9, 1 7/9, 7 1/9, 28 4/9, ? a) 112(1/9) b) 113(7/9) c) 115(4/9) d) 140(5/9) e) 142(2/9)

Description : 1/9, 4/9, 1 7/9, 7 1/9, 28 4/9, ? a) 112(1/9) b) 113(7/9) c) 115(4/9) d) 140(5/9) e) 142(2/9)

Last Answer : The pattern is 1/9,4/9,16/9,64/9,256/9,1024/9. 1024/9 = 113 7/9 Answer: b)

Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 units of labour. There is a no other constraint on production. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 ... both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : from statement I : Let the price of product Q be P' Then the price of product R is 4P From Statement II: Cost of product Q =2 Cost of product R=5 Therefore, Profit percentage of product ... )=80P-100 Hence, product R is more profitable. Both statements are required to answer the question Answer :c

Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

A man distributed 43 chocolates to his children. How many of his children are more than five years old? I. A child older than five years gets 5 chocolates II. A child 5 years or younger in age gets 6 chocolates. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : A man distributed 43 chocolates to his children. How many of his children are more than five years old? I. A child older than five years gets 5 chocolates II. A child 5 years or younger ... the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : From both statement I and II: Let the number of chocolates received by child older than 5 years be x and that of for child than 5 years or younger be y Therefore, 5x + 6 y = 43 Since x and y has to ... for the above equation will be x=5 and y=3 Hence, 5 children are older than 5 years Answer : c

Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 units of labour. There is a no other constraint on production. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 ... both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : from statement I : Let the price of product Q be P' Then the price of product R is 4P From Statement II: Cost of product Q =2 Cost of product R=5 Therefore, Profit percentage of product ... )=80P-100 Hence, product R is more profitable. Both statements are required to answer the question Answer :c