In the above problem, compute for the mass. (Formula: m = p1V1 / RT1)  a. 0.2148 lb  b. 0.2134 lb  c. 0.1248 lb  d. None of the above

In the above problem, compute for
the mass.
(Formula: m = p1V1 / RT1)
 a. 0.2148 lb
 b. 0.2134 lb
 c. 0.1248 lb
 d. None of the above
by

1 Answer

Answer :

0.2148 lb
by

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Description : A certain gas, with cp = 0.529Btu/ lb. °Rand R = 96.2ft.lb/lb. °R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5psia. Compute for T2.  a.1520°R  b. 1620°R  c. 1720°R  d. 1820°R formula: T2= T1V2/V1

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Last Answer : 12 kJ

A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 x10^6 kJ  D. 2 x10^6 kJ Formula: fromthe steamtable vƒ = 0.001043 m^3 / kg vg = 1.6940 m^3 / kg u ƒ= 417.3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

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Last Answer : 2 x10^6 kJ

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Last Answer : 4474.23 N

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Description : Helium ( R= 0.4698 BTU/lbm-˚R ) is compressed isothermally from 14.7 psia and 68 ˚F. The compression ratio is 1:4. Calculate the work done by the gas.  A. –1454 BTU/lbm  B. -364 BTU/lbm  C.-187BTU/lbm  D.46.7 BTU/lbm Formula: W = RT ln (V2/V1)

Last Answer : -364 BTU/lbm

Water (specific heat cv= 4.2 kJ/ kg ∙ K ) is being heated by a 1500 W h eater. What is the rate of change in temperature of 1kg of the water?  A. 0.043 K/s  B. 0.179 K/s  C. 0.357 K/s  D. 1.50 K/s Formula: Q = mcv ( T)

Description : Water (specific heat cv= 4.2 kJ/ kg ∙ K ) is being heated by a 1500 W h eater. What is the rate of change in temperature of 1kg of the water?  A. 0.043 K/s  B. 0.179 K/s  C. 0.357 K/s  D. 1.50 K/s Formula: Q = mcv ( T)

Last Answer : 0.179 K/s

Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Description : Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Last Answer : 1.1577 BTU/lbm-˚R

3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Description : 3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Last Answer : 24.9 ft^3

What is the formula to convert °F to °C?  a) °C = °F + 273  b) °C = 5/9 (°F - 32)  c) °C = 9/5 (°F)+32  d) None of the above

Description : What is the formula to convert °F to °C?  a) °C = °F + 273  b) °C = 5/9 (°F - 32)  c) °C = 9/5 (°F)+32  d) None of the above

Last Answer : °C = 5/9 (°F - 32)

What is the formula to convert °C to °F?  a) °F = °C + 273  b) °F = 5/9 (°C - 32)  c) °F = 9/5 (°C)+32  d) None of the above

Description : What is the formula to convert °C to °F?  a) °F = °C + 273  b) °F = 5/9 (°C - 32)  c) °F = 9/5 (°C)+32  d) None of the above

Last Answer : momentum

How many Newton’s (N) in 900,000 dynes?  a) 8 Newton’s  b) 9 Newton’s  c) 7 Newton’s  d) 6 Newton’s Formula: 1Newton (N)=100,000dynes

Description : How many Newton’s (N) in 900,000 dynes?  a) 8 Newton’s  b) 9 Newton’s  c) 7 Newton’s  d) 6 Newton’s Formula: 1Newton (N)=100,000dynes

Last Answer : 9 Newton’s

3 horsepower (hp) = _____________watts?  a) 1492 watts  b) 2238 watts  c) 746 watts  d) 2238 kilowatts Formula: 1hp= 746 watts

Description : 3 horsepower (hp) = _____________watts?  a) 1492 watts  b) 2238 watts  c) 746 watts  d) 2238 kilowatts Formula: 1hp= 746 watts

Last Answer : 2238 watts

Two thick slices of bread, when completely oxidized by the body, can supply 200,000 cal of heat. How much work is this equivalent to?  a) 4,190,000 joules  b) 8,390,000 joules  c) 839,000 joules  d) 419 000 joules Formula: J =Work/Heat J = mechanical equivalent of heat whose value is 4.19 joules/calorie

Description : Two thick slices of bread, when completely oxidized by the body, can supply 200,000 cal of heat. How much work is this equivalent to?  a) 4,190,000 joules  b) 8,390,000 joules  c) 839, ... d) 419 000 joules Formula: J =Work/Heat J = mechanical equivalent of heat whose value is 4.19 joules/calorie

Last Answer : 419 000 joules

How many joules of work is the equivalent of 15000 cal of heat?  a) 62850 joules  b) 3579.95 joules  c) 14995.81 joules  d) 15004.19 joules Formula: J =Work/Heat J = mechanical equivalent of heat whose value is 4.19 joules/calorie

Description : How many joules of work is the equivalent of 15000 cal of heat?  a) 62850 joules  b) 3579.95 joules  c) 14995.81 joules  d) 15004.19 joules Formula: J =Work/Heat J = mechanical equivalent of heat whose value is 4.19 joules/calorie

Last Answer : 62850 joules