If G is the specific gravity of particles of diameter d, the velocity of settlement V in still water at T°C, according to Stoke's law, is (A) V = 418 (G - 1) d² [(3T + 70)/100] (B) V = 418 (G - 1) d [(3T - 70)/100] (C) V = 418 (G - 1) d² [(2T + 70)/100] (D) V = 418 (G - 1) d 4 [(3T + 70)/100]

If G is the specific gravity of particles of diameter d, the velocity of settlement V in still water 

at T°C, according to Stoke's law, is 

(A) V = 418 (G - 1) d² [(3T + 70)/100] 

(B) V = 418 (G - 1) d [(3T - 70)/100] 

(C) V = 418 (G - 1) d² [(2T + 70)/100] 

(D) V = 418 (G - 1) d

4

 [(3T + 70)/100] 

by

1 Answer

Answer :

(A) V = 418 (G - 1) d² [(3T + 70)/100] 

by

Related questions

The settling velocity of a spherical particle of diameter less than 0.1 mm as per Stock’s law, is A. Vs = 418 (Gs – Gw) d [(3T + 70)/100] B. Vs = 418 (Gs – Gw)d² [(3T + 70)/100] C. Vs = 218 (Gs – Gw)d² [(3T + 70)/100] D. Vs = 218 (Gs – Gw)d [(3T + 70)/100]

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