Aniline is prepared by (a) the reaction of benzene with ammonia (b) the reduction of nitrobenzene with Sn/HCl (c) the dehydrogenation of nitrobenzene (d) the reaction of nitrobenzene with I2/NaOH

Aniline is prepared by
(a) the reaction of benzene with ammonia
(b) the reduction of nitrobenzene with Sn/HCl
(c) the dehydrogenation of nitrobenzene
(d) the reaction of nitrobenzene with I2/NaOH
by

1 Answer

Answer :

the reduction of nitrobenzene with Sn/HCl
by

Related questions

Which of the following statements is False/Incorrect about nitrobenzene? (a) is formed by nitration of benzene at temperatures below 60°C. (b) can be further nitrated to give m-dinitrobenzene. (c) can be oxidized with KMnO4 to give benzoic acid. (d) can be reduced with Sn/HCl to give aniline.

Description : Which of the following statements is False/Incorrect about nitrobenzene? (a) is formed by nitration of benzene at temperatures below 60°C. (b) can be further nitrated to give m-dinitrobenzene. (c) can be oxidized with KMnO4 to give benzoic acid. (d) can be reduced with Sn/HCl to give aniline.

Last Answer : can be oxidized with KMnO4 to give benzoic acid

Which of the following statements is false about aniline? (a) It is a primary aromatic amine. (b) It is a weak base which forms salts with acids. (c) It liberates nitrogen on treatment with ice-cold nitrous acid. (d) It can be prepared by the reduction of nitrobenzene with tin and HCl

Description : Which of the following statements is false about aniline? (a) It is a primary aromatic amine. (b) It is a weak base which forms salts with acids. (c) It liberates nitrogen on treatment with ice-cold nitrous acid. (d) It can be prepared by the reduction of nitrobenzene with tin and HCl

Last Answer : It liberates nitrogen on treatment with ice-cold nitrous acid

Iodobenzene can be prepared by (a) treating chlorobenzene with I2 using FeCl3 catalyst. (b) treating phenol with I2 in NaOH solution. (c) treating benzenediazonium chloride with KI (d) treating benzene with CH3I using AlCl3 catalyst

Description : Iodobenzene can be prepared by (a) treating chlorobenzene with I2 using FeCl3 catalyst. (b) treating phenol with I2 in NaOH solution. (c) treating benzenediazonium chloride with KI (d) treating benzene with CH3I using AlCl3 catalyst

Last Answer : treating benzenediazonium chloride with KI

Nitrobenzene undergoes reduction with zinc and KOH to give (a) Aniline (b) Hydrazobenzene (c) Azobenzene (d) None of these

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Last Answer : Hydrazobenzene

Which of the following give aniline by reduction of nitrobenzene?

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Last Answer : Which of the following give aniline by reduction of nitrobenzene? A. `H_(2)//Pd-C` B. `Sn+HCI` C. `Cu+HCI` D. `(NH_(4))_(2)S`

Which of the following reagents is used to prepare benzenediazoniumchloride from aniline?(a) NaNO2 + HCl(b) LiAlH4(c) NH2NH2 + KOH(d) NaOH

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Last Answer : NaNO2 + HCl

When aniline is heated with glycerol in the presence of sulfuric acid and nitrobenzene, it gives quinoline. This reaction in called (a) Fischer synthesis (b) Skraup synthesis (c) Diazotization (d) Corey-House synthesis

Description : When aniline is heated with glycerol in the presence of sulfuric acid and nitrobenzene, it gives quinoline. This reaction in called (a) Fischer synthesis (b) Skraup synthesis (c) Diazotization (d) Corey-House synthesis

Last Answer : Skraup synthesis

Reduction of p-nitrotoluene with Sn + HCl gives : (a) p-methylaniline (b) Toluene (c) m-methylaniline (d) N-Methylaniline

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Last Answer : p-methylaniline

Benzoic acid and diphenyl ketone are both solids insoluble in water. A mixture of these compounds can be separated if we (a) add the mixture to a solution of NaOH in water, and filter. (b) add the mixture to a solution of HCl in water, and filter. (c) dissolve the mixture in benzene and boil off the benzene. (d) It is impossible to separate a mixture of two solids when both are insoluble in water.

Description : Benzoic acid and diphenyl ketone are both solids insoluble in water. A mixture of these compounds can be separated if we (a) add the mixture to a solution of NaOH in water, and filter. (b) add ... benzene. (d) It is impossible to separate a mixture of two solids when both are insoluble in water.

Last Answer : add the mixture to a solution of NaOH in water, and filter

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Benzene reacts with concentrated HNO3 in the presence of concentrated H2SO4 to give nitrobenzene. This reaction is an example of (a) Electrophilic addition (b) Nucleophilic addition (c) Electrophilic substitution (d) Nucleophilic substitution

Description : Benzene reacts with concentrated HNO3 in the presence of concentrated H2SO4 to give nitrobenzene. This reaction is an example of (a) Electrophilic addition (b) Nucleophilic addition (c) Electrophilic substitution (d) Nucleophilic substitution

Last Answer : Electrophilic substitution

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Description : Compound (A) when reacted with PCl5 and then with ammonia gave (B). Compound (B) when treated with bromine and NaOH, produced (C). Compound (C) on treatment with NaNO2/HCl at 0°C and then boiling with H2O ... Compound (A) is (a) o-Toluic acid (b) o-Chlorotoluene (c) m-Toluic acid (d) o-Bromotoluene

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Last Answer : Aniline

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Which of the following compounds does not give iodoform test on treatment with I2/NaOH?(a) Ethanol (b) Propanone (c) 2-Propanol (d) Butanone

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Last Answer : mitigation reaction.

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Last Answer : Nitrous acid then CuBr