The octal equivalent of 111010 is a. 81 b. 72 c. 71 d. None of above

The octal equivalent of 111010 is
a. 81
b. 72
c. 71
d. None of above
by

1 Answer

Answer :

72
by

Related questions

The octal equivalent of 111010 is a. 81 b. 72 c. 71

Description : The octal equivalent of 111010 is a. 81 b. 72 c. 71

Last Answer : b. 72

The octal equivalence of 111010 is A) 81 B) 72 C) 71 D) None of above

Description : The octal equivalence of 111010 is A) 81 B) 72 C) 71 D) None of above

Last Answer : Answer : B

The octal equivalence of 111010 is a. 81 b. 72 c. 71 d. None of above

Description : The octal equivalence of 111010 is a. 81 b. 72 c. 71 d. None of above

Last Answer : b. 72

The octal equivalence of 111010 is a. 81 b. 72 c. 71 d. None of above

Description : The octal equivalence of 111010 is a. 81 b. 72 c. 71 d. None of above

Last Answer : b. 72

The base of the octal system is 71) A) eight. B) two. C) ten. D) seven.

Description : The base of the octal system is 71) A) eight. B) two. C) ten. D) seven.

Last Answer : A) eight.

Germination percentage in sour orange rootstock is: a. 50-60% b. 61-70% c. 71-80% d. 81-90%

Description : Germination percentage in sour orange rootstock is: a. 50-60% b. 61-70% c. 71-80% d. 81-90%

Last Answer : 50-60%

In shewak's opinion, his weight is greater than 76 kg but less than 83 kg. His sister doest not agree with shewak and she thinks that shewak’s weight is greater than 71 kg but less than 81 kg. His father's view is that his weight cannot be greater than 79 kg. If all are them are correct in their estimation, what is the average of different probable weights of shewak? A) 67kg B) 68kg C) 72kg D) 78kg

Description : In shewak's opinion, his weight is greater than 76 kg but less than 83 kg. His sister doest not agree with shewak and she thinks that shewak's weight is greater than 71 kg but less than 81 kg. His ... , what is the average of different probable weights of shewak? A) 67kg B) 68kg C) 72kg D) 78kg

Last Answer :  Answer: D) Let shewak's weight be X kg. According to shewak , 76 < X < 83 According to shewak 's sister, 71 < X < 81. According to shewak 's father, X ≤ 79 The values satisfying all the above conditions are 77, 78and 79. Required average=[ (77+78+79)/3] = 201/ 3 = 78kg.

A vessel contains 100 litres of milk. From this, 10 litres of milk was taken out and replaced by water. The process was repeated further two times. How much milk is now contained by the vessel? a) 72.9 litres b) 60.4 litres c) 71.6 litres

Description : A vessel contains 100 litres of milk. From this, 10 litres of milk was taken out and replaced by water. The process was repeated further two times. How much milk is now contained by the vessel? a) 72.9 litres b) 60.4 litres c) 71.6 litres d) 81 litres e) None of these

Last Answer : Milk after three replacement =100 × (90/100)3 = 72.9 litres Answer: a)

Section -----------of companies act 1956 deals with the scheme of stock invest A. 69 to 70 B. 69 to 71 C. 69 to 72 D. 69 to 73

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A tap can fill a cistern in 11hours, but due to a leakage it took 13hours to fill the cistern. If the cistern is full, in what time will the cistern become empty due to leakage ? A) 73.30hrs B) 77.50hrs C) 71.5 hrs D) 72.30hrs E) None of these

Description : A tap can fill a cistern in 11hours, but due to a leakage it took 13hours to fill the cistern. If the cistern is full, in what time will the cistern become empty due to leakage ? A) 73.30hrs B) 77.50hrs C) 71.5 hrs D) 72.30hrs E) None of these

Last Answer : C 1/11-1/13 = 13-11/143 =>2/143 =>1/71.5 =>71.5hours

Which number system is commonly used as a shortcut notation for groups of four binary digits? a. Binary b. Decimal c. Octal d. Hexadecimal

Description : Which number system is commonly used as a shortcut notation for groups of four binary digits? a. Binary b. Decimal c. Octal d. Hexadecimal

Last Answer : Hexadecimal

Computeruses the“““.number system to store data and perform calculations. (A) binary (B) octal (C) decimal (D) hexadecimal (E) None of these

Description : Computeruses the“““.number system to store data and perform calculations. (A) binary (B) octal (C) decimal (D) hexadecimal (E) None of these

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3 faucet A,B,C can fill a cistern from empty to full in 45mins, 35mins, and 25 mins respectively. When the cistern is empty all the 3 faucets are opened. A,B,c discharge chemical solutions A,B,C respectively. What is the proportion of solution C in the liquid in the tank after 5 mins? A) 63/143 B) 72/151 c) 67/173 D) 81/167

Description : 3 faucet A,B,C can fill a cistern from empty to full in 45mins, 35mins, and 25 mins respectively. When the cistern is empty all the 3 faucets are opened. A,B,c discharge chemical solutions A,B,C respectively. What is ... the liquid in the tank after 5 mins? A) 63/143 B) 72/151 c) 67/173 D) 81/167

Last Answer : A Part filled by (A+B+C) in 5 mins = 5(1/45 +1/35 + 1/25) = 5 (35+45+63/1575) = 143/315 Part filled by c in 5 mins = 5/25 = 1/5 Required ratio = 1/5 * 315/143 =63/143.

. What is the hexadecimal equivalentof the Ethernet address 01011010 0001000101010101 00011000 10101010 00001111? A) 5A:88:AA:18:55:F0 B) 5A:81:BA:81:AA:0F C) 5A:18:5A:18:55:0F D) 5A:11:55:18:AA:0F

Description : . What is the hexadecimal equivalentof the Ethernet address 01011010 0001000101010101 00011000 10101010 00001111? A) 5A:88:AA:18:55:F0 B) 5A:81:BA:81:AA:0F C) 5A:18:5A:18:55:0F D) 5A:11:55:18:AA:0F

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Four routers haveto be interconnected in a point-to-point Network. Each pair of root us may connect by a high-speed line, a medium speed line ora low speed line. Find the total number of topologies. A. 12 B. 81 C. 48 D. 729

Description : Four routers haveto be interconnected in a point-to-point Network. Each pair of root us may connect by a high-speed line, a medium speed line ora low speed line. Find the total number of topologies. A. 12 B. 81 C. 48 D. 729

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The octal equivalent of 1100101.001010 is ______ a) 624.12 b) 145.12 c) 154.12 d) 145.21

Description : The octal equivalent of 1100101.001010 is ______ a) 624.12 b) 145.12 c) 154.12 d) 145.21

Last Answer : Answer: b Explanation: The octal equivalent is obtained by grouping the numbers into three, from right to left before decimal and from right to left after the decimal place. Here, i.e. 145.12 is the octal equivalent of the number

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The equivalent hexadecimal notation for octal number 2550276 is: (A) FADED (B) AEOBE (C) ADOBE (D) ACABE

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The octal number 326.4 is equivalent to (A) (214.2)10 and (D6.8)16 (B) (212.5)10 and (D6.8)16 (C) (214.5)10 and (D6.8)16 (D) (214.5)10 and (D6.4)16

Description : The octal number 326.4 is equivalent to (A) (214.2)10 and (D6.8)16 (B) (212.5)10 and (D6.8)16 (C) (214.5)10 and (D6.8)16 (D) (214.5)10 and (D6.4)16

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The hexadecimal equivalent of the octal number 2357 is: (1) 2EE (2) 2FF (3) 4EF (4) 4FE

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