The octal equivalence of 111010 is a. 81 b. 72 c. 71 d. None of above

The octal equivalence of 111010 is
a. 81
b. 72
c. 71
d. None of above
by

1 Answer

Answer :

b. 72
by

Related questions

The octal equivalence of 111010 is A) 81 B) 72 C) 71 D) None of above

Description : The octal equivalence of 111010 is A) 81 B) 72 C) 71 D) None of above

Last Answer : Answer : B

The octal equivalence of 111010 is a. 81 b. 72 c. 71 d. None of above

Description : The octal equivalence of 111010 is a. 81 b. 72 c. 71 d. None of above

Last Answer : b. 72

The octal equivalent of 111010 is a. 81 b. 72 c. 71

Description : The octal equivalent of 111010 is a. 81 b. 72 c. 71

Last Answer : b. 72

The octal equivalent of 111010 is a. 81 b. 72 c. 71 d. None of above

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Last Answer : 72

Which number system is commonly used as a shortcut notation for groups of four binary digits? a. Binary b. Decimal c. Octal d. Hexadecimal

Description : Which number system is commonly used as a shortcut notation for groups of four binary digits? a. Binary b. Decimal c. Octal d. Hexadecimal

Last Answer : d. Hexadecimal

A nibble can be represented in the from of: a. Octal digit b. Decimal c. Hexadecimal d. None of these

Description : A nibble can be represented in the from of: a. Octal digit b. Decimal c. Hexadecimal d. None of these

Last Answer : c. Hexadecimal

The base of the octal system is 71) A) eight. B) two. C) ten. D) seven.

Description : The base of the octal system is 71) A) eight. B) two. C) ten. D) seven.

Last Answer : A) eight.

Germination percentage in sour orange rootstock is: a. 50-60% b. 61-70% c. 71-80% d. 81-90%

Description : Germination percentage in sour orange rootstock is: a. 50-60% b. 61-70% c. 71-80% d. 81-90%

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In shewak's opinion, his weight is greater than 76 kg but less than 83 kg. His sister doest not agree with shewak and she thinks that shewak’s weight is greater than 71 kg but less than 81 kg. His father's view is that his weight cannot be greater than 79 kg. If all are them are correct in their estimation, what is the average of different probable weights of shewak? A) 67kg B) 68kg C) 72kg D) 78kg

Description : In shewak's opinion, his weight is greater than 76 kg but less than 83 kg. His sister doest not agree with shewak and she thinks that shewak's weight is greater than 71 kg but less than 81 kg. His ... , what is the average of different probable weights of shewak? A) 67kg B) 68kg C) 72kg D) 78kg

Last Answer :  Answer: D) Let shewak's weight be X kg. According to shewak , 76 < X < 83 According to shewak 's sister, 71 < X < 81. According to shewak 's father, X ≤ 79 The values satisfying all the above conditions are 77, 78and 79. Required average=[ (77+78+79)/3] = 201/ 3 = 78kg.

Current SIMMs have either … or … connectors (pins) a. 9 or 32 b. 30 or 70 c. 28 or 72 d. 30 or 72

Description : Current SIMMs have either … or … connectors (pins) a. 9 or 32 b. 30 or 70 c. 28 or 72 d. 30 or 72

Last Answer : d. 30 or 72

What is the output of the following code AL= 49 BCD, BH= 72 BCD SUB AL, BH DAS a) AL=D7, CF=1. b) AL=7D, CF=1. c) AL=77, CF=1 d) none of them.

Description : What is the output of the following code AL= 49 BCD, BH= 72 BCD SUB AL, BH DAS a) AL=D7, CF=1. b) AL=7D, CF=1. c) AL=77, CF=1 d) none of them.

Last Answer : d) none of them.

A vessel contains 100 litres of milk. From this, 10 litres of milk was taken out and replaced by water. The process was repeated further two times. How much milk is now contained by the vessel? a) 72.9 litres b) 60.4 litres c) 71.6 litres

Description : A vessel contains 100 litres of milk. From this, 10 litres of milk was taken out and replaced by water. The process was repeated further two times. How much milk is now contained by the vessel? a) 72.9 litres b) 60.4 litres c) 71.6 litres d) 81 litres e) None of these

Last Answer : Milk after three replacement =100 × (90/100)3 = 72.9 litres Answer: a)

Section -----------of companies act 1956 deals with the scheme of stock invest A. 69 to 70 B. 69 to 71 C. 69 to 72 D. 69 to 73

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Last Answer : D. 69 to 73

A tap can fill a cistern in 11hours, but due to a leakage it took 13hours to fill the cistern. If the cistern is full, in what time will the cistern become empty due to leakage ? A) 73.30hrs B) 77.50hrs C) 71.5 hrs D) 72.30hrs E) None of these

Description : A tap can fill a cistern in 11hours, but due to a leakage it took 13hours to fill the cistern. If the cistern is full, in what time will the cistern become empty due to leakage ? A) 73.30hrs B) 77.50hrs C) 71.5 hrs D) 72.30hrs E) None of these

Last Answer : C 1/11-1/13 = 13-11/143 =>2/143 =>1/71.5 =>71.5hours

3 faucet A,B,C can fill a cistern from empty to full in 45mins, 35mins, and 25 mins respectively. When the cistern is empty all the 3 faucets are opened. A,B,c discharge chemical solutions A,B,C respectively. What is the proportion of solution C in the liquid in the tank after 5 mins? A) 63/143 B) 72/151 c) 67/173 D) 81/167

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Last Answer : A Part filled by (A+B+C) in 5 mins = 5(1/45 +1/35 + 1/25) = 5 (35+45+63/1575) = 143/315 Part filled by c in 5 mins = 5/25 = 1/5 Required ratio = 1/5 * 315/143 =63/143.

Show that the relation ‘≅’ congruence on the set of all triangles in Euclidean plane geometry is an equivalence relation. -Maths 9th

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Write ‘yes’ if each of the following relations is an equivalence relation. -Maths 9th

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If R is a relation in N × N defined by (a, b) R (c, d) if and only if ad = bc, show that R is an equivalence relation. -Maths 9th

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Last Answer : (i) R is reflexive. For all (a, b) ∈ N N we have (a, b) R (a, b) because ab = ba ⇒ R is reflexive. (ii) R is symmetric. Suppose (a, b) R (c, d) Then (a, b) R (c, d) ⇒ ... ) R (e, f) ⇒ R is transitive. Since R is reflexive, symmetric and transitive, therefore, R is an equivalence relation on N N.

Which of the following is an equivalence relation defined on set A = {1, 2, 3} -Maths 9th

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Description : What is Electrochemical Equivalence ?

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For spark ignition engine, the equivalence ratio of mixture entering the combustion chamber has values (A) for idling and for peak power conditions (B) for both idling and peak power conditions (C) for idling and for peak power conditions (D) for both idling and peak power conditions

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The idea that irrespective of how a government chooses to increase spending, either by debt financing or tax financing, the outcome will be the same and demand will remain unchanged, is popularly known as: a) Ricardian theory of equivalence b) Ricardian theory of competitive advantage c) Ricardian theory of stability d) None of the above

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One of the fields on a form contains a text box which accepts alphabets in lower or upper case. Identify the invalid Equivalence class value. a. CLASS b. cLASS c. CLass d. CLa01ss

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In a system designed to work out the tax to be paid:An employee has £4000 of salary tax free. The next £1500 is taxed at 10% the next £28000 is taxed at 22%. Any further amount is taxed at 40% Which of these groups of numbers would fall into the same equivalence class? a) £4800; £14000; £28000 b) £5200; £5500; £28000 c) £28001; £32000; £35000 d) £5800; £28000; £32000

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Last Answer : d) £5800; £28000; £32000

Evaluating testability of the requirements and system are a part of which phase:- a) Test Analysis and Design b) Test Planning and control c) Test Implementation and execution d) Evaluating exit criteria and reporting Q4. One of the fields on a form contains a text box which accepts alphabets in lower or upper case. Identify the invalid Equivalence class value.

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Last Answer : a) Test Analysis and Design

Which technique can be used to achieve input and output coverage? It can be applied to human input, input via interfaces to a system, or interface parameters in integration testing. A. Error Guessing B. Boundary Value Analysis C. Decision Table testing D. Equivalence partitioning

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When testing a grade calculation system, a tester determines that all scores from 90 to 100 will yield a grade of A, but scores below 90 will not. This analysis is known as: A. Equivalence partitioning B. Boundary value analysis C. Decision table D. Hybrid analysis

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When testing a grade calculation system, a tester determines that all scores from 90 to 100 will yield a grade of A, but scores below 90 will not. This analysis is known as: A. Equivalence partitioning B. Boundary value analysis C. Decision table D. Hybrid analysis

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Last Answer : B. Boundary value analysis

Given the following specification, which of the following values for age are in the SAME equivalence partition? If you are less than 18, you are too young to be insured. Between 18 and 30 inclusive, you will receive a 20% discount. Anyone over 30 is not eligible for a discount. A. 17, 18, 19. B. 29, 30, 31. C. 18, 29, 30. D. 17, 29, 31.

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Last Answer : C. 18, 29, 30.

f the temperature falls below 18 degrees, the heating is switched on. When the temperature reaches 21 degrees, the heating is switched off. What is the minimum set of test input values to cover all valid equivalence partitions? A. 15, 19 and 25 degrees B. 17, 18, 20 and 21 degrees C. 18, 20 and 22 degrees D. 16 and 26 degrees

Description : f the temperature falls below 18 degrees, the heating is switched on. When the temperature reaches 21 degrees, the heating is switched off. What is the minimum set of test input values to cover all valid equivalence ... 17, 18, 20 and 21 degrees C. 18, 20 and 22 degrees D. 16 and 26 degrees

Last Answer : A. 15, 19 and 25 degrees

A thermometer measures temperature in whole degrees only. If the temperature falls below 18 degrees, the heating is switched off. It is switched on again when the temperature reaches 21 degrees. What are the best values in degrees to cover all equivalence partitions? A. 15,19 and 25. B. 17,18 and19. C. 18, 20 and22. D. 16, 26 and 32.

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Last Answer : A. 15,19 and 25.

One of the fields on a form contains a text box which accepts alpha numeric values. Identify the Valid Equivalence class A. BOOK B. Book C. Boo01k D. book

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Which technique can be used to achieve input and output coverage? It can be applied to human input, input via interfaces to a system, or interface parameters in integration testing. a) Error Guessing b) Boundary Value Analysis c) Decision Table testing d) Equivalence partitioning

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Last Answer : D. All numbers between 1 and 99

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One technique of Black Box testing is Equivalence Partitioning. In a programstatement that accepts only one choice from among 10 possible choices,numbered 1 through 10, the middle partition would be from _____ to _____ a) 4 to 6 b) 0 to 10 c) 1 to 10 d) None of the above

Description : One technique of Black Box testing is Equivalence Partitioning. In a programstatement that accepts only one choice from among 10 possible choices,numbered 1 through 10, the middle partition would be from _____ to _____ a) 4 to 6 b) 0 to 10 c) 1 to 10 d) None of the above

Last Answer : c) 1 to 10

Which of the following designs permits a comparison of pretest scores to determine the initial equivalence of groups on the pretest before the treatment variable is introduced into the research setting. a. One-group pretest-posttest design b. Pretest-posttest control group design c. Posttest-only design with nonequivalent groups d. Both b and c

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Last Answer : b. Pretest-posttest control group design

Explain Equivalence Class Partitioning and Boundary value analysis. Compare the two.

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Last Answer : d.All of these

DeMorgan’s first theorem shows the equivalence of (A) OR gate and Exclusive OR gate. (B) NOR gate and Bubbled AND gate. (C) NOR gate and NAND gate. (D) NAND gate and NOT gate

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Last Answer : Ans : c

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Description : _____ is a white-box testing technique first proposed by Tom McCabe. a) Equivalence Partitioning b) Basis Path Testing c.) Boundary Value Analysis d) None of the above.

Last Answer : Ans : b. 

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