Description : Excluding the stoppages, the speed of a bus is 64 km/hr and including the stoppages the speed of the bus is 48km/hr. For how many minutes does the bus stop per hour? 1) 15 min 2) 10 min 3) 12 min 4) 20 min 5) 18 min
Last Answer : 1) 15 min
Description : Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these
Last Answer : Answer – C (48 sec) Explanation – Relative speed = all lengths/time [60+90] = [1.10 +0.9 ]/time [ PLUS when opposite direction] time=2/150 = 1/75 h 1 hour______3600 sec 1/75 hr______? ?= 3600/75=48 sec
Description : A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is: A.35 km/hr B.50 km/hr C.48 km/hr D.55 km/hr E.None of these
Last Answer : Answer – B (50 km/hr) Explanation – Let speed be S Relative speed = total lengths/time [ in this case man length is neglible compare to train so neglected] (S – 5) x 5/18 = 125 /10 S- 5 = (125/10)x(18/5) S-5 = 45 S=50 km/hr
Description : Solar constant is equal to (in cal/cm2/min) (A) 1.94 (B) 194 (C) 19.4 (D) 0.194
Last Answer : (A) 1.94
Description : pulse rate of chicken?a 70-80/min b 40-80/ min c 130-160/min d 180-195/min
Last Answer : c 130-160/min
Description : The cutter bar of a tractor operated on owner makes strokes/min (a) 400 – 500 (b) 500 – 750 (c) 800 – 1200 (d) 1250 – 1500
Last Answer : (c) 800 – 1200
Description : A flight is planned from L to M, distance 850 nm. Wind component out is 35 kt(TWC), TAS 450kt. Mean fuel flow out is 2500kg/hr, mean fuel flow inbound is 1900kg/hr and the fuel available is 6000kg. The time ... 1hr 30 min, 660nm b. 1hr 30 min, 616nm c. 1hr 15 min, 606nm d. 1hr 16 min, 616nm
Last Answer : d. 1hr 16 min, 616nm
Description : A flight is planned from L to M, distance 850 nm. Wind component out is 35 kt(TWC), TAS 450kt. Mean fuel flow out is 2500kg/hr, mean fuel flow inbound is 1900kg/hr and the fuel available is 6000kg. The time ... 30 min, 660nm b. 1hr 30 min, 616nm c. 1hr 15 min, 606nm d. 1hr 16 min, 616nm
Description : The normal glucose tolerance curve reaches peak is (A) 15 min (B) 1 hr (C) 2 hrs (D) 2 ½ hrs
Last Answer : B
Description : One tonrefrigeration corresponds to (a) 50 kcal/min (b) 50 kcal/kr (c) 80 kcal/min (d) 80 kcal/hr
Last Answer : Ans: a
Description : We have defined EER by a) BTU/hr/W c) BTU/min/W b) BTU/sec/W d) BTU/hr/V
Last Answer : BTU/hr/W
Description : A train M speeding with 60km/hr crooses another train N, running in the same direction in 1 min. If the lengths of the trains M and N be 50m and 100m respectively. What is the speed of train N? A) 15 km/hr B) 61km/hr C) 51km/hr D) 50k/hr
Last Answer : ANSWER: C Explanation: Let the speed of be train N be ‘x’km/hr Speed of M relative to N = (60 – x)km/hr = (60-x) * 5/18]m/s = (300 – 5x / 18)m/s 150 / (300 – 5x / 18) =60 2700/300-5x=60 2700=18000-300x 300x=15300 x= 153/3 x=51km/hr Therefore the speed of the train is 51 km/hr
Description : Dhanvanth can swim at 15 km/hr in stagnant water. In a river with 3 km/hr current, he swims to a certain distance and comes back within 100 min. What is the distance between the two points? A) 11km B) 13km C) 19km D) 12km
Last Answer : ANSWER: D Explanation: Speed in still water (a) = 15 km/hr Speed in current( b) = 3 km/hr Upstream speed = a - b = 15 - 3 = 12 km/hr Downstream speed = a + b = 15 + 3 = 18 km/hr Let the ... 36 = 5 / 3 15x = 36 * 5 x = 36 * 5 / 15 = 12 km Distance between the two points is 12km
Description : A train overtakes two girls walking along a railway track. The first girl walks at 9 km/hr. The other girl walks at 10.8 km/hr. The train needs 16.8 and 17 seconds respectively to overtake them. What is the speed of the ... in the same direction as the train? A) 25 m/s B) 45 m/s C) 30m/s D) 40m/s
Last Answer : ANSWER:B Explanation: First girl speed = 9km/hr = 9 * 5 / 18 m/s = 5/2 m/s = 2.5 m/s second girl speed = 10.8 km/hr = 10.8 * 5/18 m/s = 54/18 = 3 m/s Let the speed of the train ... x - 3) * 17 16.8x - 42 = 17x - 51 0.2x = 9 x = 45 Therefore the speed of the train is 45 m/s
Description : A metro train 200 metres long takes 12 seconds to cross a man walking at 10 km/hr in a opposite to that of the train. Find the speed of the train? A) 50 km/hr B) 60km/hr C) 130km/hr D) 140km/hr
Last Answer : ANSWER: A Explanation: Length of the train = 200 m Man walking speed = 10 km/hr Let the speed of the train be x' km/hr Speed of the train relative to man = (x +10) km/hr Convert km/hr into m/s ... = 60(x +10) 3600 = 60x +600 60x = 3000 X = 50 So speed of the train is 110km/hr.
Description : A person runs opposite to that of chandigarh train at a speed of 10km/hr. If the relative speed between train and the boy running in opposite direction is 25km/hr. What is the length of the train, if it takes 10 seconds to cross a boy, when is at rest? A) 36.6 m B) 40.6 m C) 43.6m D) 41.6m
Last Answer : ANSWER : D Explanation: Speed of person = 10km/hr As the train and the running person are moving in opposite direction,therir speed values are added to find the relative speed. Relative speed = speed of train + speed of ... s Distance = speed * time = 25 / 6 * 10 = 250/6 m/s = 41.6 m
Description : In a one Kilometer race A beats B by 28 meters or 7 seconds. Find out the time taken by A to finish the race. A. 4 Mins 3 secs B. 3 min 4 secs C. 5 mins D. 4 mins 20 secs
Last Answer : ANSWER: A
Description : Temperature and duration in Flash method of Pasteurization is A 62.9℃, 30 min B 71.6℃, 30 min C 71.6℃, 15 seconds D 62.9℃, 15 seconds
Last Answer : C 71.6℃, 15 seconds
Description : A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed ... as the train? A.59 km/hr B.65 km/hr C.70 km/hr D.81 km/hr E. None of these
Last Answer : Answer-D (81 km/hr) Explanation4.5 km/hr =(4.5 x 5/18)m/sec =5m/4sec = 1.25 m/sec, and 5.4 km/hr =(5.4 x 5/18)m/sec =3m/2sec = 1.5 m/sec. Let the speed of the train be x m/sec. Then, (x - 1.25) ... - 12.75 => 0.1x = 2.25 => x = 22.5 Therefore Speed of the train =(22.5 x18 /5)km/hr = 81 km/hr.
Description : Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: A.40 m B.55 m C.65 m D.50 m E.None of these
Last Answer : Answer- D (50) Explanation – Relative speed= total lengths/time (46-36) x 5/18 = [L + L ] / 36 10 x (5/18) x36 x (1/2)= L L=50 m
Description : Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these
Last Answer : Answer – C (36 kmph) Explanation – Let the speed of each train be x m/sec. Then, relative speed of the two trains = 2x m/sec. So, 2x = (120 + 120)/12 ⇔ 2x = 20 ⇔ x = 10. ∴ Speed of each train = 10 m/sec = [10 x 18/5] km/hr = 36 km/hr
Description : Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these
Last Answer : Answer – A (27 7/9 m) Explanation – When SAME direction- MINUS Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec. Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.
Description : How many missions are launched under National Action Plan on Climate Change? a. 5 b. 6 c. 7 d. 8 e. 9
Last Answer : d. 8
Description : A bike starts with a speed of 60 km/hr at 8a.m. Due to the problem in engine it reduces its speed as 20 km/hr for every 1 hour. After 9 am, the time taken to covers 15 km is: a) 13 minutes and 20 seconds b) 15 minutes and 09 seconds c) 18 minutes and 15 seconds d) 22 minutes and 30 seconds
Last Answer : 15 min
Description : If a train crosses a tree in 24 seconds while travelling at a speed of 90km/hr, then in how much time will the train cross a telegraph post of length 1200m at same speed? A) 26 sec B) 48 sec C) 72 sec D) 38 sec
Last Answer : ANSWER:C Explanation: Speed of the train = 90 km/hr Converting the speed into m/sec 90 km/hr = (90* 5/18)m/s = 25m/s length of the train = distance travelled we know distance = speed * ... Time = distance / speed = ( 1800/25) sec = 72 seconds Hence the required answer is 72 seconds
Description : A shatabadi express takes 240 seconds to cover a distance of length 700 meters at a speed of 270 km/hr. What will be the time taken by the train to cross a standing pole? A) 160sec B) 465sec C) 310sec D) 231sec
Last Answer : ANSWER:D Explanation: Speed of the train = 270 km/hr. Converting the speed into m/sec Speed = 270 km/hr = 270 x 5/18 m/sec = 75 m/sec First, we have to find the length of the train Let ... a standing Pole at 75 m/s =( 17300/75)seconds = 231 seconds. Hence the answer is 231 sec(approx.)
Description : What is the difference between a micro-planning region and a meso-planning region? -Geography
Last Answer : Micro-planning regions are the smallest of all planning regions and have the potential for developing at least one specialization of production cycle of great significance. A region that possesses ... bond. Unlike micro-regions, mesoregions are multipurpose regions, e.g., Damodar Valley Basin.
Description : What is meso compound ?
Last Answer : Even if a compound has asymmetric carbon atoms, if one part of the compound alleviates the surface rotation of the polarized light of the other part, so that the sum as a whole is light inactive, then such a compound is called meso compound.
Description : Total number of meso forms possible for 1,2,3,4 -Tetrachlorocyclobutane.
Last Answer : Total number of meso forms possible for 1,2,3,4 -Tetrachlorocyclobutane.
Description : Which of the following is/are optically inactive? (a) a 50-50 mixture of R and S enantiomers (b) a meso compound (c) a racemic mixture (d) all the above
Last Answer : all the above
Description : Which of the statements below correctly describes an achiral molecule? (a) The molecule has a nonsuperimposable mirror image. (b) The molecule exhibits optical activity when it interacts with plane-polarized light. (c) The molecule has an enantiomer. (d) The molecule might be a meso form
Last Answer : The molecule might be a meso form
Description : Which of the following is a true statement? (a) All chiral molecules possess a plane of symmetry. (b) All achiral molecules are meso. (c) All molecules which possess a single asymmetric center of the S configuration are levorotatory. (d) A mixture of achiral compounds will be optically inactive
Last Answer : A mixture of achiral compounds will be optically inactive
Description : Which of the following compounds will be optically active? (a) Succinic acid (b) meso-Tartaric acid (d) Lactic acid (d) Chloroacetic acid
Last Answer : Lactic acid
Description : meso-Tartaric acid is (a) sometimes optically active (b) always optically active (c) sometimes optically inactive (d) always optically inactive
Last Answer : always optically inactive
Description : A meso compound : (a) is an achiral molecule which contains chiral carbons (b) contains a plane of symmetry or a centre of symmetry (c) is optically inactive (d) is characterized by all of the above
Last Answer : ) is characterized by all of the above
Description : Optical isomers that are not mirror images are called (a) Diastereomers (b) Enantiomers (c) Metamers (d) Meso compounds
Last Answer : Diastereomers
Description : A man rows 750m in 775 seconds against the stream and returns in 7 1/2 minutes. What is rowing speed in still water ? A.4.7km/hr B. 4km/hr C.3.5km/hr D.6km/hr
Last Answer : Answer-A Basic Formula: i) Speed in still water = ½ (a+b) kmph where a' is speed downstream and b' is speed upstream ii) a km / hr = a x 5/18 m /s iii) a m/sec = a x 18/5 km/hr Explanation: Speed upstream b' ... (750/450 + 750/675 ) x 18/5 km/hr = ½ (5/3 + 30/31) x 18/5 km/hr = 4.7 km/hr
Description : Two trains are running in opposite direction with the same speed. If the length of each train is 135 meters and they cross each other in 18 seconds, the speed of each train is a) 29km/hr b) 35km/hr c) 27km/hr d) 28km/hr
Last Answer : c) 27km/hr
Description : A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train? a) 120 meters b) 180 meters c) 324 meters d) 150 meters
Last Answer : d) 150 meters
Description : Two trains are running at 120 km/hr and 60km/hr respectively in the same direction. Fast train completely passes a boy sitting in the slower train in 15 seconds. What is the length of the fast train? A) 150m B) 550 m C) 250m D) 215m
Last Answer : ANSWER: C Explanation: Speed of the 1st train = 120km/hr Speed of the 2nd train = 60km/hr If the direction is given in the same direction then we subtract the relative speed. Relative speed = (120 - 60) ... / 3 * 15)m =(750/3)m = 250m Therefore the length of the faster train is 250m
Description : A goodstrain of 700 m runs at a speed of 165 km/hr. A person traveling in it observes that the mail train moving in opposite direction takes 30 seconds to cross him. Find the speed of the mail train, if it is 750 m long. A) 8.4 m/s B) 5.3 m/s C) 2.5 m/s D) 6.8 m/s
Last Answer : ANSWER:C Explanation: Speed of goods train = 165km/hr length of mail train (P) = 750m length of goods train (Q) = 700m Alternately, we can directly use the formula: Time = ( p+q) / (v1+v2) sec ( ... 45.833+v2 = 48.333 V2 = 2.5 m/s Therefore the speed of the mail train is 2.5 m/s
Description : Two trains, both 50m long, moving in opposite directions cross each other in 4 seconds. If one is moving thrice as fast the other, then the speed of the faster train is. A) 45km/hr B) 19 km/hr C) 95 km/hr D) 67.5 km/hr
Last Answer : ANSWER:D Explanation: Let the speed of the slower train be x' m/sec The speed of the sfaster train = 3x m/s Relative speed = (x +3x)m/sec = 4x m/sec 50 + 50 / 4 = 4x 100 / 4 = 4x 100 = 16x x = 100 ... the faster train = 3 * 25 / 4 = 75 / 4 m/s = (75/4 *18 /5)km/hr = 67.5 km/hr
Description : A train 330 m long passes a man, running at 18 km/hr in the direction opposite to that of the train in 18 seconds. The speed of the train is. A) 38 km/hr B) 29km/hr C) 48km/hr D) 44km/hr
Last Answer : ANSWER: C Explanation: Length of the train = 330 m Speed = distance / time. Speed of the train relative to man = 330 / 18 m/s = 110 / 6 m/s Convert m/s into km/hr Therefore 110 / 6 m/s = (110 / ... (x +18) = 66 km/hr X + 18 = 66 X = 48 Therefore the speed of the train is 48 km/hr.
Description : A boy sitting in a train which is travelling at 25 km/hr observes that a goods train travelling in opposite direction, takes 4.5 seconds to pass him. If the train is 140 m long, find its speed. A) 77km/hr B) 79km/hr C) 87km/hr D) 89km/hr
Last Answer : ANSWER : C Explanation: Relative speed = distance / time = (140 / 4.5) m/s = 31.11 m/s Convert m/s into km/hr 31.11 m/s = (31.11 * 18 / 50 km/hr = (560 / 5) km/hr = ... train (by sitting) = (112 - 25) km/hr = 87 km/hr Therefore the speed of goods train is 87 km/hr.
Description : A train crosses a platform and a scooter standing on the platform in 20 seconds, 12seconds respectively.What is the length of the platform if the speed of the train is 25 km/hr? A) 55.8 m B) 75m C) 124m D) 68.5m
Last Answer : Answer: A Explanation: Given that, The speed of the train = 25km/hr = 25x 5/18 m/sec = 125/18 m/sec The train crosses a scooter in 12 seconds. Then, Length of the train = 125/18*12= 83.33 Now, ... 18(X +83.3)= 2500 18X=1000.6 X=55.58 m Hence the platform is 55.58 m long.
Description : A boy rows 1500m in 1350 seconds against the stream and returns in 15 minutes. His rowing speed in still water is. A) 5km/hr B) 4km/hr C) 7km/hr D) 9km/hr
Last Answer : ANSWER : A Explanation: Rate upstream = (1500 / 1350) m/s = (150/135) m/s = 10/9 m/s Rate downstream = (1500 / 900)m/s = (15/9)m/s = 5/3 m/s Rate in still water = ½ [ a+ b] = ½[10 / 9 + 5 /3 ... +15 / 9] = ½[25/9] = 25/18 m/s = (25/18) * (18/5)km/hr speed in still water = 5km/hr
Description : What is the climate like in Bangladesh ?
Last Answer : The climate of Bangladesh is temperate
Description : The mineral weathering and clay formation are rapid where the climate is- (a) Warm and moist (b) Warm and dry (c) Cold and moist (d) Cold and dry
Last Answer : (c) Cold and moist