Description : In a one Kilometer race A beats B by 28 meters or 7 seconds. Find out the time taken by A to finish the race. A. 4 Mins 3 secs B. 3 min 4 secs C. 5 mins D. 4 mins 20 secs
Last Answer : ANSWER: A
Description : In a demand paging memory system, page table is held in registers. The time taken to service a page fault is 8 m.sec. if an empty frame is available or if the replaced page is not modified, and it takes 20 m.secs., if the replaced ... ? (A) 11.6 m.sec. (B) 16.4 m.sec. (C) 28 m.sec. (D) 14 m.sec.
Last Answer : (B) 16.4 m.sec.
Description : Write a program to declare class having data member as hrs, mins, secs. Write constructor to assign values and destructor to destroy values. Accept & display data for one object.
Last Answer : #include<iostream.h> #include<conio.h> class time { private: int hrs, mins,sec; public: time(int h,int m,int s) { hrs=h; mins=m; sec=s; } ~time() { cout<< hours ... } }; void main() { time t(2,43,56); t.display(); getch(); }
Description : 2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188
Last Answer : D Let the speed of the train be x m/sec Then distance travelled by the train in 15mins = distance travelled by sound in 15secs X*15*60 = 320*15 900x = 4800 X=4800/900 X=5.33 Speed of the train 5.33 m/s Convert m/s into km/hr 5.33m =(5.33*18/5) =(95.94/5) =19.188 km/hr
Description : In a 2280 m race Dinesh beats Aarav by 360 m or 6 seconds. In another race on the same track at the same speeds. Aarav and karthick start at one end while Dinesh starts at the opposite end. How many metres would Aarav ... is 16 m/sec more than that of karthick a) 1140 m b) 2280 m c) 2460 m d) 1180 m
Last Answer : B Aarav 's speed =360/6 =60 m/s Time taken by Aarav to cover 2280 m =2280/60= 38 seconds Dinesh 's speed = 2280/60=38 m/s karthick 's speed = 22m/s Time taken by Dinesh to meet karthick in ... direction: Distance covered by Aarav: =2280/(38+22) =2280/60 =38 seconds =(38*60)m =2280 m
Description : Pipe A can fill an empty tank in 20 minutes and Pipe B in 30 mins and Pipe C can empty the same in 40 mins. If all of them work together, find the time taken to fill the tank? (a) 17 1/7 mins (b) 20 mins (c) 8 mins (d) none of these
Last Answer : (a) 17 1/7 mins
Description : In a 2700 m race around a round track of length 300m, abi and kabi meet at the end of the 3rd minute, for the first time after the start of the race. All the runners maintain uniform speed throughout the race. ... time taken by abi to finish the race. a) 27 mints b) 32 mints c) 5 mints d) 23 mints
Last Answer : A As, abi is twice as fast as the kabi, abi would have completed two rounds by the time kabi completes one round. And that is their second meeting. Their first meeting takes place after the abi ... 300m ⇒He takes 2700/300 *3 =27 mints Hence he takes 27 minutes to finish the race.
Description : Question: When i finish my anytime mins on At&t do i start eating up my rollover mins?
Last Answer : Yes; except on Nights and Weekends, when minutes are free.
Description : A node X on a 10 Mbps network is regulated by a token bucket. The token bucket is filled at a rate of 2 Mbps. Token bucket is initially filled with 16 megabits. The maximum duration taken by X to transmit at full rate of 10 Mbps is ............ secs. (1) 1 (2) 2 (3) 3 (4) 4
Last Answer : (2) 2
Description : In covering a definite distance, the speeds of P & Q are in the ratio of 5:6. P takes 45 mins more than Q to reach the target. The time taken by P to reach the target is. a) 4 hrs 20 mins b) 4 hrs 45 mins c) 2hrs 30 mins d) 4hrs 30 mins
Last Answer : D Ratio of speeds = 5:6 Ratio of time =6:5 Suppose P takes 6x hrs and Q takes 5x hrs to reach the target. Then, 6x – 5x = 45/60 X=3/4 Time taken by P = 6x hrs =(6*3/4)hrs =4.5 hrs i.e., the time taken by P to reach the target is 4hrs 30mins
Description : How many miles will a person run during a 10 kilometer race?
Last Answer : What kind of mile? There are many.
Description : if john ran a 5-kilometer marathon, how long was that in meters? -General Knowledge
Last Answer : 1 km = 1000 meters, so if John ran a 5-kilometer marathon, it was 5 x 1000 = 5,000 meters.
Description : The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channel capacity. Assuming that processing ... maximum utilization, when the sliding window protocol used is: a. A b. B c. C d. D
Last Answer : c. C
Description : Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these
Last Answer : Answer – A (27 7/9 m) Explanation – When SAME direction- MINUS Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec. Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.
Description : The Time taken for sunlight to reach the Earth is------? A. 700 sec B. 8hrs 20 mins C. 8 mins 20 sec (Answer) D. 8 mins
Last Answer : C. 8 mins 20 sec (Answer)
Description : A father runs after his son, who is 1000 meters ahead. The father runs at a speed of 1 kilometre every 8 minutes, and the son runs at a speed of 1 kilometer every 12 minutes. How much distance has ... father overtakes him? a) 2500 meters b) 2000 meters c) 1500 meters d) 1000 meters e) 1200 meters
Last Answer : Time taken is same for both father and son Let x be the distance son travelled before being overtaken by his father Time taken by son = x/5 km/hour Time taken by father = (1000 + x) / 7.5 km/hr Since, time taken is same x/5 = (1000 + x) / 7.5 or x = 2000m Answer: b)
Description : A shatabadi express takes 240 seconds to cover a distance of length 700 meters at a speed of 270 km/hr. What will be the time taken by the train to cross a standing pole? A) 160sec B) 465sec C) 310sec D) 231sec
Last Answer : ANSWER:D Explanation: Speed of the train = 270 km/hr. Converting the speed into m/sec Speed = 270 km/hr = 270 x 5/18 m/sec = 75 m/sec First, we have to find the length of the train Let ... a standing Pole at 75 m/s =( 17300/75)seconds = 231 seconds. Hence the answer is 231 sec(approx.)
Description : What is the total acceleration of a point on the rim of a flywheel 4 mts in diameter 0.6 see after it has started from rest if it accelarates uniformly from rest to 2000 rpm in 20 secs. a.68.9 mts/sec2 b.102.6 mts/sec2 c.78.94 mts/sec2 d.107 dynes e.33.2 mts/sec2
Last Answer : c. 78.94 mts/sec2
Description : A tank has two faucet which fill it in 15 mins and 18 mins respectively. There is also a waste faucet in the tank. When all the 3 are opened the empty tank is full in 25 mins. How long the waste faucet take to empty the full tank? A) 450/17 mins B) 450/28 mins C) 450/37 mins D) 450/22 mins
Last Answer : C Work done by the waste faucet in 1 minute =>1/25 – (1/15 + 1/18) =>1/25 – (6+5/90) = 1/25 – 11/90 => - 37/450 Here negative sign means emptying Therefore waste faucet will empty the full tank in 450/37 mins.
Description : Two filling tap can fill a dumper in 14 and 28 min. respectively and when the waste tap is open, they can together fill it in 35 min. The waste pipe can empty the full dumper in – A) 152/9 hrs. B) 137/7 hrs. C) 60/9 hrs. D) 140/11 hrs.
Last Answer : D 1/14 + 1/28 – 1/35 =>10 + 5 – 4/140 =>11/140 =>140/11 => hence answer is 140/11 hours.
Description : If a car is traveling at 20 meters per second in a straight line, how many seconds will it take the car to stop if it decelerates at 5 meters per second squared?
Last Answer : ANSWER: 4 SECONDS
Description : If a sled has a constant acceleration of 2 meters per second squared and starts from rest, the distance in meters that it will have covered after 5 seconds is: w) 10 meters x) 20 meters y) 25 meters z) 50 meters
Last Answer : ANSWER: Y -- 25 METERS
Description : The latest finish time for an activity: A. Equals the min. of LFT − t for al immediate successors B. Equals the max. of LFT − t for al immediate predecessors. C. Equals the max. of EST + t for all immediate predecessors. D. Equals the min. of EST + t for all immediate successors
Last Answer : A. Equals the min. of LFT − t for al immediate successors
Description : At time t=0, a body has a velocity of 5 meters per second, EASTWARD; at time t=2 seconds, its velocity is 7 meters per second WESTWARD. What is the MAGNITUDE of the body's average acceleration?
Last Answer : ANSWER: 6 METERS PER SECOND SQUARED
Description : The time needed for a net force of 10 newtons to change the velocity of a 5 kilograms mass by 3 meters/second is: w) 1.5 seconds x) 6 seconds y) 16.7 seconds z) 150 seconds
Last Answer : ANSWER: W -- 1.5 SECONDS
Description : In a construction site, a crane lifts 1000 kg of concrete mix to roof top at a height of 20 meters in 50 seconds. If the value of gravity 'g' due to earth is 10 m s-2, the power of elevator will be. -Physics
Last Answer : 4 KW (kilowatt)
Description : A car traveling at a constant velocity of 20 meters per second passes a second car which is initially at rest. The car which was at rest starts accelerating at 10 meters per second squared the instant it is passed ... car. They will meet again in: w) 2 seconds x) 4 seconds y) 6 seconds z) 8 seconds
Last Answer : ANSWER: X -- 4 SECONDS
Description : A 10,000-watt motor operates an elevator weighing 5000 newtons. Assuming no frictional losses, how high is the elevator raised in 10 seconds. Is it raised: w) 2 meters x) 20 meters y) 50 meters z) 100 meters
Last Answer : ANSWER: X -- 20 METERS
Description : A car is moving along a straight horizontal road at a speed of 20 meters per second. The brakes are applied and a constant force of 5000 Newtons decelerates the car to a stop in 10 seconds. The mass of the car is: w) 1250 kilograms x) 2500 kilograms y) 5000 kilograms z) 10,000 kilograms
Last Answer : ANSWER: X -- 2500 KILOGRAMS
Description : Calculate the emf in a material with flux linkage of 3.5t 2 at 2 seconds. a) 3.5 b) -7 c) -14 d) 28
Last Answer : c) -14
Description : A ball falling vertically from rest for 3 seconds travels very nearly: w) 14.7 meters x) 29.4 meters y) 44.1 meters z) 88.2 meters
Last Answer : ANSWER: Y -- 44.1 METERS
Description : What is the Time Scale for Meso Climate? [a] 1-10 hr [b] 1-10 min [c] 1-10 seconds [d] 1-10 days [e] None of the above
Last Answer : [d] 1-10 days
Description : Over taking time required for a vehicle with design speed 50 km ph and overtaking acceleration 1.25 m/sec2 to overtake a vehicle moving at a speed 30 km ph, is (A) 5.0 secs (B) 6.12 secs (C) 225.48 secs (D) 30 secs
Last Answer : Answer: Option B
Description : A van travels from namakkal to Madurai at a constant speed. If its speed were increased by 40km/hr it would have taken 1 hr lesser to cover the distance. It would have taken further 45 mins lesser if the speed ... by 40km/hr. what is distance between the 2 cities. a) 1680 b) B1660 c) 1670 d) 1675
Last Answer : A Let distance = x km Usual rate = y km/hr Then x/y - x/(y+40) =1 X(y+40) / y(y+40) = 1 Xy+40x - xy = y(y+40) 40x = y(y+40) ---------->1 x/y - x/y+80 = 7/4 x(y+80) - xy / y(y+ ... (y+80) / y(y+40) 8(y+40) = 7y + 560 8y +320 = 7y+560 Y=240 Substitute y value in 1 40x = 240*280 X=1680 km
Description : A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60
Last Answer : D Let distance = x km Rate = y km/hr x/y - x / (y+6) = 30/60 (x(y+6)-xy) / y(y+6) = ½ (xy +6x - xy) / y(y+6) = ½ 12x = y(y+6) ------------>1 And x/ (y-4) - x/y = 30/60 (Xy - x(y-4 ... = (y+6) / (y-4) 3y - 12 = 2y +12 Y = 24km Put y value in 1 we get 12x = 24 (24+6) 12x = 24 *30 X=60km
Description : A man standing at the finish line is recording the time of a race competition by means of a stop watch. He must start the watch when (a) He hears the sound of the starting gun (b) He sees flash ... gun (c) He sees first man leaving the starting line (d) He either sees the flash or hears the sound
Last Answer : Ans:(b)
Description : Temperature and duration in Flash method of Pasteurization is A 62.9℃, 30 min B 71.6℃, 30 min C 71.6℃, 15 seconds D 62.9℃, 15 seconds
Last Answer : C 71.6℃, 15 seconds
Description : You’re running a race and at the very end, you pass the person in 2nd place. What place did you finish the race in? -Riddles
Last Answer : You would be in 2nd.
Description : a riddle
Last Answer : You'll be second.
Description : Guessing question
Last Answer : Second
Description : What would you say to someone who had 10 seconds left to climb a 15 foot rope to finish an obstacle course?
Last Answer : “I’m setting fire to the bottom of this rope. The fire will engulf the entire rope within 11 seconds.”
Description : A stone dropped from a baloon that was ascending at the rate of 30 ft/sec, reaches ground after 10 secs. The height of the baloon where stone was dropped was a.3420 ft b.107 dynes c.4520 ft d.2310 ft e.1310 ft
Last Answer : e. 1310 ft
Description : Size limit of Inland letter card folded and unfolded is a) Min15.2X9cm & max 21X10cm, min 28.2X18.2cm max 30X21cm b) Min10X7cm & max 50X100cm, min 15X25cm &max 80X100cm c) Min11X22cm & max 60X40cm, min 20X17cm &max 90X100cm d) None of these
Last Answer : a) Min15.2X9cm & max 21X10cm, min 28.2X18.2cm max 30X21cm
Description : Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike ... /hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14
Last Answer : D Time taken = 2 hr 15 mins = 2 ¼ hrs Time = 9/4 hrs Let the required distance be x km Then x/20 + x/1 = 9/4 (X+20x) / 20 = 9/4 21x / 20 = 9/4 84x = 180 X= 2.14 km Therefore the required diatance is 2.14 km
Description : What is the free space loss, in dB, between two microwave parabolic antennas 38.0 kilometer apart operating at 7.0 GHz? A. 145.6 dB B. 138.5 dB C. 135.5 dB D. 140.89 dB
Last Answer : D. 140.89 dB
Description : You make a diversion from the route given in the flight plan and land at an uncontrolled airfield. Within what time after landing should you inform ATC? a. 10 mins b. 20 mins c. 30 mins d. 45 mins
Last Answer : c. 30 mins
Description : A barrier has four inlets A, B, C and D. The barrier can be filled in 24 minutes through the first three inlets and it can be filled in 30 minutes through the second, the third and fourth inlet also it can be ... all the four inlets? A) 10 mins B) 15 mins C) 20 mins D) 25 mins E) None of the Above
Last Answer : C (1/A + 1/B + 1/C) = 1/24 …(i) (1/B + 1/C + 1/D) = 1/30 …(ii) (1/A + 1/D) = 1/40…(iii) From eqn (i) and (ii) (1/A – 1/D) = 1/120…(iv) From eqn (iii) and (iv) A=60,D=120. Let the time taken to full the tank = s S(1/A + 1/B +1/C +1/D)= 1 S(1/24+1/120) = 1 S= 20 mins
Description : Two tube A and B can fill a cistern in 48 mins and 64 mins. If both the tubes are opened simultaneously, after how much time B should be closed so that the cistern is full in 36 minutes? A) 20 mins B) 16mins C) 22mins D) 14mins
Last Answer : B Let B be closed after ‘x’ mins. Then part filled by (A+B) in x mins + part filled by A in (36 – x) mins = 1 Therefore x(1/48 + 1/64) + (36 – x)* 1/48 = 1 7x/192 + 36 – x/48 = 1 7x + 4(36-x)/192 = 1 7x+144 – 4x = 192 3x = 48 =>x = 16 Here B must be closed after 16 mins.
Description : A boys rows to a certain place and comes back, but by mistake he covers 2/3rd more distance while coming back. The total time for this journey is 20 hours. The ratio of speed of boat to that of ... starting point from his present position? A) 2hr 13mints B)1hr 30 mins C) 2hr 30mins D)1hr 40 mins
Last Answer : ANSWER : A Explanation: let speed of boat and stream be 2x and x respectively So downstream speed = 2x+x = 3x, and upstream speed = 2x-x = x Let total distance between points is d km So he covered d ... with speed 3x = 48 km/hr(downstream) So time is 80/36 * 60 = 133.33 minutes = 2hr 13mins