Description : In a spring-mass system, which of the following force is not considered? A Spring force B Damping force C Accelerating force D A and B
Last Answer : B Damping force
Description : A single degree of freedom spring-mass system is subjected to a harmonic force of constant amplitude. For an excitation frequency of √3k/m , the ratio of the amplitude of steady state response to the static deflection of the spring is __________ A. 0.2 B. 0.5 C. 0.8 D. None of the above
Last Answer : B. 0.5
Description : Calculate damped natural frequency, if a spring mass damper system is subjected to periodic disturbing force of 30 N. Damping coefficient is equal to 0.76 times of critical damping coefficient and undamped natural frequency is 5 rad/sec A. 3.99 rad/sec B. 2.13 rad/sec C. 4.12 rad/sec D. 3.24 rad/sec
Last Answer : D. 3.24 rad/sec
Description : In a spring-mass system, which of the following force is not considered? B ( A ) Spring force ( B ) Damping force ( C ) Accelerating force ( D ) A and B
Last Answer : B ) Damping force
Description : When a running car stops suddenly, the passengers tends to lean forward because of: (1) centrifugal force (2) inertia of rest (3) inertia of motion (4) gravitational force
Last Answer : (3) inertia of motion Explanation: When a running car stops suddenly, the passengers tend to lean forward due to inertia of motion. Inertia is that property of a body due to which it resists a change in its state of rest or of uniform motion.
Last Answer : inertia of motion
Description : When a periodic disturbing force is applied to a machine, the force is transmitted to the ___________ by the means of spring. (A) dampers (B) foundation (C) mass (D) none of the above
Last Answer : (B) foundation
Description : For a two-rotor system, the length of one shaft (A) is twice the other (B), then what is the relation between the mass moment of inertia of the shafts. A 2I(A) = I(B) B I(A) = 2I(B) C I(A) = I(B) D 2I(A) = 3I(B)
Last Answer : A 2I(A) = I(B)
Description : If the mass moment of inertia is increased to four times, then what will be the effect on free torsional vibrations of a single motor system? a) Increases 4 times b) Increases 2 times c) Decreases 4 times d) Decreases 2 times
Last Answer : d) Decreases 2 times
Description : Which of the following relation is correct regarding free torsional vibrations of a single motor system? a) Independent of modulus of rigidity b) Independent of polar moment of inertia c) Dependent on mass moment of inertia d) Independent of length of shaft
Last Answer : c) Dependent on mass moment of inertia
Description : Increasing which of the following factor would result in increase of free torsional vibration? A. Radius of gyration B. Mass moment of inertia C. Polar moment of inertia D. Length
Last Answer : C. Polar moment of inertia
Description : An increase in the mass moment of inertia results in ________ in vibration frequency. A. increase B. decrease C. unchanged D. none of the above
Last Answer : B. decrease
Description : Which formula is used to calculate mass moment of inertia (I G ) of a circular rim about the axis through centre of gravity? a. mr 2 /2b. mr 2 /12 c. mr 2 /4 d. mr 2
Last Answer : d. mr 2
Description : Increasing which of the following factor would result in increase of free torsional vibration? a) Radius of gyration b) Mass moment of inertiac) Polar moment of inertia d) Length
Last Answer : c) Polar moment of inertia
Description : If a mass whose moment of inertia is Ic/3 is placed at the free end and the constraint is assumed to be of negligible mass, then the kinetic energy is ______ a) 1/6 Icω 2 b) 1/2Icω 2 c) 1/3Icω 2 d) 1/12Icω 2
Last Answer : a) 1/6 Icω 2
Description : The equation of motion for a vibrating system with viscous damping is d 2 x/dt 2 + c/m X dx/dt + s/m X x = 0 If the roots of this equation are real, then the system will be A. over damped B. under damped C. critically damped D. none of the mentioned
Last Answer : A. over damped
Description : The equation of motion for a vibrating system with viscous damping is d 2 x/dt 2 + c/m X dx/dt + k/m X x = 0 If the roots of this equation are real, then the system will be a) over damped b) under damped c) critically damped d) none of the mentioned Ans:a
Last Answer : a) over damped
Description : The ratio of the force transmitted to the force applied is known as the ____________ of the spring support. A. isolation factor B. transmissibility ratio C. both A and B D. none of the above
Last Answer : C. both A and B
Description : The ratio of the force transmitted to the force applied is known as the ____________ of the spring support. (A) isolation factor (B) transmissibility ratio (C) both A and B (D) none of the above
Last Answer : (C) both A and B
Description : Which of the following statements are TRUE for damped vibrations? (P) . For a system having critical damping, the value of the damping ratio is unity and system does not undergo a vibratory motion. (Q) . Logarithmic decrement method ... Q only (B) P and S only (C) P, Q and R only (D) Q and S only
Last Answer : (C) P, Q and R only
Description : If the spring mass system with m and spring stiffness k is taken to very high altitude, the natural frequency of longitudinal vibrations * 1 point (A) increases (B) decreases (C) remain unchanged (D) may increase or decrease depending upon the value of the mass
Last Answer : (C) remain unchanged
Description : The natural frequency of a spring-mass system on earth is ωn. The natural frequency of this system on the moon (g of moon = g of earth /6) is * 1 point (A) ωn (B) 0.408ωn (C) 0.204ωn (D) 0.167ωn
Last Answer : (A) ωn
Description : The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250
Last Answer : A 100
Description : A vehicle suspension system consists of a spring and a damper. Stiffness of spring is 3.5 KN/m and damping constant of damper is 400Ns/m. If mass is 50 kg, then damping factor is A 0.606 B 0.10 C 0.666 D 0.471
Last Answer : D 0.471
Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above
Last Answer : C 6.16 Hz
Description : A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m
Last Answer : A 9810 N/m
Description : While calculating the natural frequency of a spring-mass system, the effect of the mass of the spring is accounted for by adding X times its value to the mass, where X is A 1/2 B 1/3 C 1/4 D 3⁄4
Last Answer : B 1/3
Description : A vibrating system having mass 1kg, a spring of stiffness 1000N/m and damping factor of 0.632 and it is put to harmonic excitation of 10N. Find the amplitude at resonance. A 0.079 B 7.9C 0.056 D 0.00791
Last Answer : D 0.00791
Description : A spring mass system has time period of oscillation of 0.25 sec. What will be the natural frequency of the system? A 1 Hz B 2 rad sec C 4 rad/sec D 4 Hz
Last Answer : D 4 Hz
Last Answer : D 9801 N/m
Description : Determine natural frequency of a system, which has equivalent spring stiffness of 43200 N/m and mass of 12 kg. A 40.22 rad/sec B 40 Hz C 60 Hz D 60 rad/sec
Last Answer : D 60 rad/sec
Description : While calculating the natural frequency of a spring-mass system, the effect of the mass of the spring is accounted for by adding X times its value to the mass, where X is A. 1/2 B. 1/3 C. 1/4 D. 3/4
Last Answer : B. 1/3
Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A. 12.32 Hz B. 4.10 Hz C. 6.16 Hz D. None of the above
Last Answer : C. 6.16 Hz
Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m B. 80 x 10 3 N-s/m C. 42 x 10 3 N-s/m D. None of the above
Last Answer : C. 42 x 10 3 N-s/m
Description : A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. A. 5.14 Hz B. 9.14 Hz C. 11.14 Hz D. 28.14 Hz
Last Answer : C. 11.14 Hz
Description : A vertical spring-mass system has a mass of 0.5 kg and an initial deflection of 0.2 cm. Find the spring stiffness. A. 345 N/m B. 245 N/m C. 3452 N/mD. 2452 N/m
Last Answer : D. 2452 N/m
Description : In a 2-mass 3 spring vibrating system the two masses each are of 9.8 kg coupling spring is having a stiffness of 3430 N/m whereas the other two springs have each a stiffness of 8820 N/m. The two natural frequencies in rad /sec are A) 10 & 20 B) 20 & 30 C) 30 & 40D) 40 & 50
Last Answer : C) 30 & 40
Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A) 12.32 Hz B) 4.10 Hz C) 6.16 Hz D) None of the above
Last Answer : C) 6.16 Hz
Description : In a spring mass system of mass m and stiffness k, the end of the spring are securely fixed and mass is attached to intermediate point of spring. The natural frequency of longitudinal ... is attached decreases D) Decreases as the distance from the bottom end where mass is attached decreases
Last Answer : B) Is minimum when mass is attached to mid point of the spring
Description : If the spring mass system with m and spring stiffness k is taken to very high altitude , the natural frequency of longitudinal vibrations A) Increases B) Decreases C) Remain unchanged D) May be increase or decrease depending upon the value of the mass
Last Answer : C) Remain unchanged
Description : In the spring mass system if the mass of the system is doubled with spring stiffness halved, the natural frequency of longitudinal vibration A) Remained unchanged B) Is doubled C) Is halved D) Is quadruped
Last Answer : C) Is halved
Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? C ( A )12.32 Hz (B) 4.10 Hz ( C )6.16 Hz (D)None of the above
Last Answer : ( C )6.16 Hz
Description : A mass of 10 kg when suspended from a spring causes a static deflection of A 0.01m. Find the spring stiffness for the same system. (A) 9810 N/m (B) 8910 N/m (C)1098 N/m (D) 9801 N/m
Last Answer : A) 9810 N/m
Description : While calculating the natural frequency of a spring-mass system, the effect of the B mass of the spring is accounted for by adding X times its value to the mass, where X is (A) 1/2 (B) 1/3 (C) 1/4 (D) 3/4
Last Answer : (B) 1/3
Description : Identify the given system [fixed--spring—mass—spring—mass—spring--fixed] A. Single Degree of Freedom System B. Several Degree of Freedom System C. Two Degree of Freedom System D. None
Last Answer : C. Two Degree of Freedom System
Description : A 10 Kg mass suspended by spring of stiffness 1000 N/m. the natural frequency of the system after giving excitation will be A. 0 Hz B. 1.59 Hz C. 2 Hz D. 15.9 Hz
Last Answer : B. 1.59 Hz
Description : The number of degrees of freedom in simple spring mass system is A. Zero B. One C. Two D. Three
Last Answer : B. One
Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... , are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz
Last Answer : a) 0.471 and 1.19 Hz
Description : The natural frequency of a spring-mass system on earth is ω n . The natural frequency of this system on the moon (g moon = g earth /6) is a) ω n b) 0.408ω n c) 0.204ω n d) 0.167ω n
Last Answer : a) ω n
Description : While calculating the natural frequency of a spring-mass system, the effect of the mass of the spring is accounted for by adding X times its value to the mass, where X is a) 1/2 b) 1/3 c) 1/4 d) 3/4
Last Answer : b) 1/3