The colonies of recombinant bacteria appear white
in contrast to blue colonies of non-recombinant
bacteria because of
(a) insertional inactivation of alpha galactosidase
in recombinant bacteria
(b) inactivation of glycosidase enzyme in recombinant
bacteria
(c) non-recombinant bacteria containing beta
galactosidase
(d) insertional inactivation of alpha galactosidase
in non-recombinant bacteria.

1 Answer

Answer :

(c) non-recombinant bacteria containing beta
galactosidase

Related questions

Description : Assetion: Insertion of recombinant DNA within the coding sequence of `beta-`galactosidase result n colourless colonies. Reason : Presence of insert re

Last Answer : Assetion: Insertion of recombinant DNA within the coding sequence of `beta-`galactosidase result n ... D. If both assertion and reason are false

Description : .E.coli cells with a mutated z gene of the lac operon cannot grow in medium containing only lactose as the source of energy because (a) the lac operon is constitutively active in these cells ( ... coli cells do not utilise lactose (d) they cannot transport lactose from the medium into the cell.

Last Answer : (b) they cannot synthesise functional beta galactosidase

Description : The following are true about G proteins: a. they are first messengers b. when activated, the alpha subunit exchange GDP for GTP c. they are transmembrane signal receptor molecules d. vibrio cholerae secrets an exotoxin which makes G-proteins resistant to inactivation

Last Answer : when activated, the alpha subunit exchange GDP for GTP

Description : Jamaican vomiting sickness is due to inactivation of the enzyme (A) Pyruvate carboxylase (B) Acyl-Co-A synthetase (C) Acyl-Co-A dehydrogense (D) Thiolase

Last Answer : Answer : C

Description : The enzyme deficient in Sandhoff’s disease is (A) α-Fucosidase (B) Hexosaminidase A and B (C) β-Galactosidase (D) β-Glucosidase

Last Answer : Answer : B

Description : The enzyme deficient in Krabbe’s disease is (A) Hexosaminidase A(B) Arylsuphatase A (C) β-Galactosidase (D) α-Fucosidase

Last Answer : Answer : C

Description : α-Galactosidase enzyme is defective in (A) Tay-sach’s disease (B) Refsum’s disease (C) Sandhoff’s disease (D) Fabry’s disease

Last Answer : Answer : D

Description : Farber’s disease is due to the deficiency of the enzyme: (A) α-Galactosidase (B) Ceramidase (C) β-Glucocerebrosidase (D) Arylsulphatase A.

Last Answer : Answer : B

Description : Krabbe’s disease is due to the deficiency of the enzyme: (A) Ceramide lactosidase (B) Ceramidase (C) β-Galactosidase (D) GM1 β-Galactosidase

Last Answer : Answer : C

Description : Gaucher’s disease is due to the deficiency of the enzyme: (A) α-Fucosidase (B) β-Galactosidase (C) β-Glucosidase (D) Sphingomyelinase

Last Answer : Answer : C

Description : The enzyme deficient in Fabry’s disease is (A) α-Galactosidase (B) β-Galactosidase (C) α-Glucosidase (D) β-Glucosidase

Last Answer : Answer : A

Description : Gaucher’s disease is due to deficiency of the enzyme: (A) Sphingomyelinase (B) Glucocerebrosidase (C) Galactocerbrosidase (D) β-Galactosidase

Last Answer : Answer : B

Description : Which enzyme will be produced in a cell if there is a nonsense mutation in the lac Y gene? (a) Transacetylase (b) Lactose permease and transacetylase (c) β-galactosidase (d) Lactose permease

Last Answer : β-galactosidase

Description : The main reason why antibodies could not solve all the problems of bacteria mediated disease is (a) decreased efficiency of the immune system (b) insensitivity of the individual ... development of mutant strains resistant to antibodies (d) inactivation of antibiotics by bacterial enzymes.

Last Answer : (c) development of mutant strains resistant to antibodies

Description : Which testing methods are used by end-users who actually test software before they use it? A. Alpha & Beta Testing B. White Box Testing C. Black Box Testing D. Trial & Error Testing

Last Answer : A. Alpha & Beta Testing

Description : Alpha testing is differentiated from Beta testing by A. The location where the tests are conducted. B. The types of test conducted C. The people doing the testing D. The degree to which white box techniques are used

Last Answer : A. The location where the tests are conducted.

Description : V- model uses -------- test models a) Component testing, integration testing, system testing and acceptance testing b) alpha testing, beta testing , acceptance testing and user testing c) black box testing, white box testing and gray box testing

Last Answer : a

Description : Acceptance testing is also known as a) Grey box testing b) White box testing c) Alpha Testing d) Beta testing

Last Answer : Ans : d

Description : Of the hemolytic groups of streptococci, _____ is the most dangerous because the organisms completely destroy red blood cells. a. alpha hemolytic group b. the beta hemolytic group c. the gamma hemolytic d. strep viridins group

Last Answer : b. the beta hemolytic group

Description : Why does the media show that men sometimes appear to prefer steak over vegetables when in contrast to women ?

Last Answer : Like diamond wedding rings, I would chalk this one up to advertising. When I was a kid there were ads like.. Protein makes men manly.. Eat a steak and get big and strong. Paid for by the beef lobby. I barely eat any meat. But I have watched my sister devour a bucket from KFC and it is sickening.

Description : Human insulins are obtained by the following sources/methods except: A. Cadaver pancreas B. Proinsulin recombinant bacterial C. Precursor yeast recombinant D. Enzyme modification of pork insulin

Last Answer : . Cadaver pancreas

Description : 7. In a recombinant DNA technology a plasmid vector must be cleaved by a) the same enzyme that leaves the donor gene b) modified DNA ligase c) a heated alkaline solution d) four separate enzymes

Last Answer : a) the same enzyme that leaves the donor gene

Description : Unidirectional tandem gene arrays are significant in ________ a. Increase in recombinant gene product with increasing plasmid number. b. Increase in recombinant gene product without increasing plasmid ... increasing plasmid numbers. d. Decrease in strong promotor with increase in plasmid number

Last Answer : b. Increase in recombinant gene product without increasing plasmid number.

Description : Why are bacteria used in recombinant DNA technology? -Biology

Last Answer : answer:

Description : Assetion: In recombinant DNA technology, human genes are often transferred into bacteria (prokaryotes) or yeast (eukaryote) Reason : Both bacteria and

Last Answer : Assetion: In recombinant DNA technology, human genes are often transferred into bacteria (prokaryotes) or ... . If both assertion and reason are false

Description : What aspects of bacteria makes recombinant DNA technology effective?

Last Answer : Bacteria reproduce very quickly.

Description : For production of eukaryotic protein by recombinant DNA technology in bacteria, the template used is (A) Eukaryotic gene (B) hnRNA (C) mRNA (D) All of these

Last Answer : Answer : C

Description : Which of the following features of genetic code does allow bacteria to produce human insulin by recombinant DNA technology? (a) Genetic code is specific. (b) Genetic code is not ambiguous. (c) Genetic code is redundant. (d) Genetic code is nearly universal

Last Answer : (c) Genetic code is redundant.

Description : Which of the following features of genetic code does allow bacteria to produce human insulin by recombinant DNA technology? (a) Genetic code is specific. (b) Genetic code is not ambiguous. (c) Genetic code is redundant. (d) Genetic code is nearly universal.

Last Answer : (d) Genetic code is nearly universal

Description : Without restriction endonucleases, it would be very difficult to a. Force Plasmids into Bacteria. b. Chemically Open Dna Molecules. c. Replicate Dna In A Recombinant Cell. d. Bring About Mutations In Bacteria.

Last Answer : b. Chemically Open Dna Molecules.

Description : .Gene regulation governing lactose operon of E.coli that involves the lac I gene product is (a) negative and repressible because repressor protein prevents transcription (b) feedback inhibition ... be induced by lactose (d) negative and inducible because repressor protein prevents transcription.

Last Answer : (d) negative and inducible because repressor protein prevents transcription.

Description : Gene regulation governing lactose operon of E.coli that involves the lac I gene product is (a) negative and repressible because repressor protein prevents transcription (b) feedback inhibition ... be induced by lactose (d) negative and inducible because repressor protein prevents transcription.

Last Answer : (d) negative and inducible because repressor protein prevents transcription.

Description : Ladies, what'd you say to a guy who watch pick up artists, dating gurus, alpha beta mating breeding strategies videos on youtube?

Last Answer : Not a lady, but that sounds kind of culty.

Description : Which is the electromagnetic wave ? ① Alpha ray , ② beta ray , gamma ray , ④ cathode ray

Last Answer : Gamma ray electromagnetic waves.

Description : If `alpha, beta` are the roots of the equation `x^2 + (sin phi -1)x-1/2 cos^2 phi = 0 (phi in R),` then the maximum value of the sum of the squares of

Last Answer : If `alpha, beta` are the roots of the equation `x^2 + (sin phi -1)x-1/2 cos^2 phi = 0 (phi in R),` then ... the roots is. A. 4 B. 3 C. `9//4` D. 2

Description : Statement -I: If `alpha gt beta gt 1`, then `(alpha^(sqrt(log_(alpha)beta)))/(beta^(sqrt(log_(beta)alpha)))` is greater than 1. Statement-2 : `log_(c)

Last Answer : Statement -I: If `alpha gt beta gt 1`, then `(alpha^(sqrt(log_(alpha)beta)))/(beta^(sqrt(log_( ... . D. Statement -1 is false, statement -2 is ture.

Description : If `alpha` and `beta` are the roots of the quadratic equation `x^(2) + 3x - 4 = 0`, then `alpha^(-1) + beta^(-1) = "_____"`.

Last Answer : If `alpha` and `beta` are the roots of the quadratic equation `x^(2) + 3x - 4 = 0`, then `alpha^(-1) + beta^(-1) = "_____"`.

Description : If `alpha, beta` are the roots of the quadratic equation `lx^(2) + mx + n = 0`,then evaluate the following expressions. (a) `alpha^(2) + beta^(2)` (b)

Last Answer : If `alpha, beta` are the roots of the quadratic equation `lx^(2) + mx + n = 0`,then evaluate the following ... ) `1/(alpha^(3)) + 1/(beta^(3))`

Description : If the equation `3x^(2) - 2x-3 = 0`has roots `alpha`, and `beta` then `alpha.beta = "______"`.

Last Answer : If the equation `3x^(2) - 2x-3 = 0`has roots `alpha`, and `beta` then `alpha.beta = "______"`.

Description : If `sin^4 alpha + 4 cos^4 beta + 2 = 4sqrt2 sin alpha cos beta ; alpha, beta in [0,pi],` then `cos(alpha+beta) - cos(alpha - beta)` is equal to :

Last Answer : If `sin^4 alpha + 4 cos^4 beta + 2 = 4sqrt2 sin alpha cos beta ; alpha, beta in [0,pi],` then `cos(alpha+beta ... sqrt(2)` B. `0` C. `sqrt(2)` D. `-1`

Description : If `alpha, beta` are roots of equation `x^(2)-4x-3=0` and `s_(n)=alpha^(n)+beta^(n), n in N` then the value of `(s_(7)-4s_(6))/s_(5)` is

Last Answer : If `alpha, beta` are roots of equation `x^(2)-4x-3=0` and `s_(n)=alpha^(n)+beta^(n), n in N` then the value ... 4s_(6))/s_(5)` is A. 4 B. 3 C. 5 D. 7

Description : Let `cos(alpha+beta)=(4)/(5)` and let `sin(alpha-beta)=(5)/(13)`, where `0 le alpha`, `beta=(pi)/(4)`. Then`tan2alpha=`

Last Answer : Let `cos(alpha+beta)=(4)/(5)` and let `sin(alpha-beta)=(5)/(13)`, where `0 le alpha`, `beta=(pi)/(4)`. Then ... 19)/(12)` C. `(20)/(7)` D. `(25)/(16)`

Description : If `cosalpha+cosbeta+cosgamma=0=sinalpha+sinbeta+singamma`, then which of the following is/are true:- (a)`cos(alpha-beta)+cos(beta-gamma)+cos(gamma-de

Last Answer : If `cosalpha+cosbeta+cosgamma=0=sinalpha+sinbeta+singamma`, then which of the following is/are true:- (a)`cos( ... D. `A` is true and `B` is false

Description : Let `alpha,beta`, are two real solution of equation `(log_(10)x)^2 + log_(10)x^2 = (log_(10))^2 -1,` then ` sqrt1/(alpha beta)`equal to `(i) 20 (ii) 3

Last Answer : Let `alpha,beta`, are two real solution of equation `(log_(10)x)^2 + log_(10)x^2 = (log_(10))^2 -1,` then ` ... 1` A. `20` B. `3` C. `10` D. `1`

Description : The order of acidic strength of the hydrogen atom `(H_(alpha), H_(beta), H_(gamma))` in the given molecule is : `CH_(3)-underset(H_(beta))underset(|)(

Last Answer : The order of acidic strength of the hydrogen atom `(H_(alpha), H_(beta), H_(gamma))` in the given molecule ... D. `H_(beta)gt H_(alpha) gt H_(gamma)`

Description : $ The endocrine part of human pancreas is represented by `alpha` a and `beta` cells. ! Endocrine gland have ducts.

Last Answer : $ The endocrine part of human pancreas is represented by `alpha` a and `beta` cells. ! Endocrine gland ... is wrong D. If both As and R are wrong.

Description : In the disintegration of a radioactive element, `alpha` and `beta`-particles are evolved from the nucleus: `._(0)^(1)n to ._(1)^(1)H + ._(-1)^(0)e` +

Last Answer : In the disintegration of a radioactive element, `alpha` and `beta`-particles are evolved from ... of `gamma`-radiations may yield nuclear isomer

Description : In the disintegration of a radioactive element, `alpha`- and `beta`-particles are evolved from the nucleus. `._(0)n^(1) rarr ._(1)H^(1) + ._(-1)e^(0)

Last Answer : In the disintegration of a radioactive element, `alpha`- and `beta`-particles are evolved from the nucleus. `._(0 ... C. `2 alpha, 2 beta` D. `n beta`

Description : In the disintegration of a radioactive element, `alpha`- and `beta`-particles are evolved from the nucleus. `._(0)n^(1) rarr ._(1)H^(1) + ._(-1)e^(0)

Last Answer : In the disintegration of a radioactive element, `alpha`- and `beta`-particles are evolved from the ... C. decreases by 2 unit D. remains unaffected

Description : In the disintegration of a radioactive element, `alpha`- and `beta`-particles are evolved from the nucleus. `._(0)n^(1) rarr ._(1)H^(1) + ._(-1)e^(0)

Last Answer : In the disintegration of a radioactive element, `alpha`- and `beta`-particles are evolved from the nucleus. `._(0) ... in A. IIA B. IA C. IIB D. IVB