Description : A train travels between two stations 15 km apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform retardation, the maximum speed attained by the train during the journey will by a.125 km/hr b.107 dynes c.80 km/hr d.100 km/hr e.60 km/hr
Last Answer : d. 100 km/hr
Description : A train travels between two stations 15 km, apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform relardation, the maximum speed attained by the train, during, the journey, will be a.60 km/hr b.80 km/hr c.125 km/hr d.100 km/hr e.107 dynes
Description : A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train? a) 120 meters b) 180 meters c) 324 meters d) 150 meters
Last Answer : d) 150 meters
Description : It takes 60 sec for a train running at 162 km/hr to cross a bridge. And it takes 36 sec for the same speed to cross a boy walking at the rate of 18km/hr in the same direction in which the train is ... the train and length of the platform. A) 1440 &1260m B) 1220 &60m C) 1000 & 1460m D) 1260 &1450m
Last Answer : ANSWER: A Explanation: Relative speed of the train to man = (162 - 18) = 144km/hr Convert km/hr into m/s 144km/hr = (144 * 5 /18) m/s = 40 m/s When the train passes ... of bridge = 2700 length of bridge = 1260 m the length of the bridge & train are 1260 and 1440m
Description : A car moves at a constant speed of 60 km/hr for 1 km and 40 km/hr for next 1 km. What is the average speed of the car?
Last Answer : A car moves at a constant speed of 60 km/hr for 1 km and 40 km/hr for next 1 km. What is the average speed of the car?
Description : Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77
Last Answer : D Total distance = (400+250+50+600)km =1300 km Total time taken = (400/70 + 600/80+250/60+50/40) hrs =(40/7 +60/8+25/6+5/4) =(24*40)+(21*60)+(28*25)+(42*5) / 168 =960+1260+700+210 / 168 =(3130 / 168) Average speed =(1300*168 / 3130) km/hr =218400/3130 =69.77 km/hr
Description : A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/hr more. Find the original speed of the train. -Maths 10th
Last Answer : Let the speed of train be x km/hr Distance to be travelled = 360km We know that, Time take by the train intially = If the speed was increased by 5km/hr Time taken by train = Difference in the time taken is 48 minutes, x2+5x -2250 = 0 (x+50)(x-45) Speed = 45 km/hr as speed cannot be negative
Description : Distance between two stations P & Q is 1556km. A passenger train covers the journey from P to Q at 168km per hr and return back to P with a uniform speed of 112km/hr. Find the Average speed of the train during the whole journey? A) 124.4 km/hr B) 130.4km/hr C) 134.4 km/hr D) 130.0 km/hr
Last Answer : C) Given x= 168 , y = 112 Required average speed = (2xy / x + y) km/hr = 2 * 168 *112 / 168 + 112 = 37632 / 280 =134.4 km/hr
Description : There is road besides a river. Two friends started from a place P, moved to a shopping mall situated at another place Q and then returned to P again. One of them moves on a cycle at a speed of 12 km/ ... which of the two friends will return to place P? A. Both B. Boater C. Cyclist D. None of these
Last Answer : Answer-C Explanation: The cyclist moves both ways at a speed of 12khr so average speed fo the cyclist - 12 km/hr boat sailor moves downstream at 10+4 = 14km/hr and upstream 10- 4 = 6km/hr ... 8.4km/hr The average speed of cyclist is greater .so,cyclist comes first and return to place P.
Description : The expenditure on fuels in running a train varies as the square of its speed measured in km/hr and it is Rs. 48 per hour at the speed of 16 km/hr. If
Last Answer : The expenditure on fuels in running a train varies as the square of its speed measured in km/ ... hour find the best speed of the train economically.
Description : A boat running downstream covers a distance of 20 km in 5 hours while for covering the same distance upstream, it takes 10 hours. What is the speed of the stream? a) 2km/hr b) 4km/hr c) 1km/hr d) 1.5 km/hr e) None of these
Last Answer : c Rate of downstream=(20 / 5 ) kmph= 4kmph Rate of upstream =( 20/10) kmph= 2kmph Therefore Speed of the stream= (1/2)(4 - 2) kmph= 1 kmph
Description : A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is: A.35 km/hr B.50 km/hr C.48 km/hr D.55 km/hr E.None of these
Last Answer : Answer – B (50 km/hr) Explanation – Let speed be S Relative speed = total lengths/time [ in this case man length is neglible compare to train so neglected] (S – 5) x 5/18 = 125 /10 S- 5 = (125/10)x(18/5) S-5 = 45 S=50 km/hr
Description : Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these
Last Answer : Answer – C (36 kmph) Explanation – Let the speed of each train be x m/sec. Then, relative speed of the two trains = 2x m/sec. So, 2x = (120 + 120)/12 ⇔ 2x = 20 ⇔ x = 10. ∴ Speed of each train = 10 m/sec = [10 x 18/5] km/hr = 36 km/hr
Description : A hare is spotted by a tiger from a distance of 50 metres. When the tiger starts a chase, the hare also starts running. If the speed of the hare be 4 km/hr and that of a tiger 5 km/hr, how far the hare will have run before its over taken? a) 100m b) 200m c) 300m d) 400m
Last Answer : B Relative speed of the tiger = (5-4)km/hr =1 km/hr Time taken by tiger to cover 50 m, =(50/1000)hr =1/20hr In 1/20 hrs, the tiger cover a distance of (4*1/20)km =1/5km =>(1/5*1000)m =200m
Description : A passenger train without stopping running at an average speed of 120 km/hr and with stoppages at an average speed of 80 km/hr. What is the total time taken by the train for stoppages on a route of length 480km? a) 2 hours b) 3 hours c) 4 hours d) 5 hours
Last Answer : A Let r = running time of the train s= stoppage time of the train D= total distance travelled by train We have: D/r= 120 and ..(1) D/(r+s) =80 ..(2) Diviving (1)&(2), D/r *(r+s)/D = ... , D=480 kms 480/r= 120 r=4 put r value in (3),we get s/4 =1/2 S = 2 hours
Description : A train M speeding with 60km/hr crooses another train N, running in the same direction in 1 min. If the lengths of the trains M and N be 50m and 100m respectively. What is the speed of train N? A) 15 km/hr B) 61km/hr C) 51km/hr D) 50k/hr
Last Answer : ANSWER: C Explanation: Let the speed of be train N be ‘x’km/hr Speed of M relative to N = (60 – x)km/hr = (60-x) * 5/18]m/s = (300 – 5x / 18)m/s 150 / (300 – 5x / 18) =60 2700/300-5x=60 2700=18000-300x 300x=15300 x= 153/3 x=51km/hr Therefore the speed of the train is 51 km/hr
Description : Find the time taken by mailtrain 200m long running at a speed of 120 km/hr to cross another train of length 160m running at a speed of 96km/hr in the same direction. A) 34sec B) 52sec C) 45sec D) 54sec
Last Answer : ANSWER: D Explanation: Total distance covered to cross each other = 200 + 160 = 360m If the direction is given in the same direction then we subtract Relative speed of two trains (same direction) = ... * 3 / 20 = 54sec Time taken by the faster train to cross the slower train is 54sec.
Description : Let p and q be two trains 65m and 70m long are running on parallel tracks in the same direction with a speed of 34km/hr and 25 km/hr. how long will it take to clear off each other from the moment they met? A) 54sec B) 56sec C) 45sec D) None of these
Last Answer : ANSWER : A Explanation : Speed of the train p = 34km/hr Speed of the train q = 25 km/hr If the direction is given in the same direction then we subtract So relative speed of trains = (34 - 25)km/hr = 9 km ... 65 + 70)m = 135m Therefore time = (135 / (5/2))sec = 270/5 sec =54 sec.
Description : A person runs on the platform of 90 m at a speed of 5km/hr in the same direction of the passenger train. Find the time taken by the train to cross the running person if speed of the train is 35.5 km/hr? (Length of train = Length of platform) A) 5.32sec B) 7.5sec C) 12.6sec D) 10.62sec
Last Answer : ANSWER:D Explanation: speed of the train = 35.5 km/hr speed of the person = 5 km/hr As the train and the running person move in same direction, their speed values are subtracted to find the relative ... =10.62 sec Hence, the time taken by the train to cross the running person is 10.62 sec
Description : A train 330 m long passes a man, running at 18 km/hr in the direction opposite to that of the train in 18 seconds. The speed of the train is. A) 38 km/hr B) 29km/hr C) 48km/hr D) 44km/hr
Last Answer : ANSWER: C Explanation: Length of the train = 330 m Speed = distance / time. Speed of the train relative to man = 330 / 18 m/s = 110 / 6 m/s Convert m/s into km/hr Therefore 110 / 6 m/s = (110 / ... (x +18) = 66 km/hr X + 18 = 66 X = 48 Therefore the speed of the train is 48 km/hr.
Description : A goods train 110m long is running with the speed of 30 km/hr. in what time will it pass a boy who is running at 3.5 km/hr in the direction opposite to that in which the train is going. A) 9 sec B) 10sec C) 12sec D) 13sec
Last Answer : ANSWER : C Explanation: Length of the train = 110 m Speed of the train = 30 km/hr Speed of the boy = 3.5 km/hr Speed of the train relative to man = (30 + 3.5) km/hr = 33.5 km/hr Convert km/ ... cover 110 m at 9.30 m/s = 110 / 9.30 = 11.8 seconds = 12 sec(approx.).
Description : A passenger train 165 m long which is running at a speed of 30km/hr. In what time will it pass a man who is running at a speed of 3 km/hr in the opposite direction. In which the train is moving. A)14 sec B) 17sec C)16sec D)18sec
Last Answer : ANSWER: D Explanation: Speed of the train = 30 km/hr Speed of man = 3 km/hr Length of the train = 165m If direction is given in opposite direction then we add both speed. That is (30 + 3 )= 33 km/hr ... can easily get the distance of m/s So it cover 165 m i.e., 165 * 6 /55 = 18 sec.
Description : The rajdhani express of 400m runs at a speed of 124 km/hr and a person runs on the platform at a speed of 40km/hr in the direction opposite to that of the train. Find the time taken by the train to cross the running person? A) 7 sec B) 8.78sec C) 7.78sec D) 8 sec
Last Answer : ANSWER : B Explanation: Length of the train = 400m Speed of train = 124 km/hr Speed of person = 40 km/hr Relative speed (speed of trai relative to man) = (124 + 40) km/hr = 164 km/hr [As the ... train to cover 400m at a relative of 45.55 m/s = 400 / 45.55 = 8.78 sec.
Description : A mail train 220 m long is running with a sped of 120 km/hr. What is the time in which it will pass a man who starts from the engine running at the speed of 12km/hr in the direction opposite to that of the train. A) 6sec B) 5sec C) 4sec D) 3sec
Last Answer : ANSWER: A Explanation: We know as the train and the running person are moving in opposite direction,therir speed values are added to find the relative speed. Relative speed = speed of mail train + speed of running ... [ from the length of the mail train is the distance] = 220 / 36.66 = 6 sec.
Description : A passenger train 300m long is running with a speed of 136 km/hr. In what time will it pass a boy who is running at 6 km/hr in opposite direction in which the train is moving? A) 8.6sec B) 7.6sec C) 3.6sec D) 2.6sec
Last Answer : ANSWER: B Explanation: Speed of the train = 136 km/hr Speed of boy = 6 km/hr Speed of the train relative to boy = (13 + 6)km/hr = 142 km/hr Convert km/hr into m/s 142 km /hr = (142 * 5 / 18 ... taken bt it to cover 300 m at 39.44 m/s =300 / 39.44 [speed time= distance / speed] = 7.6 sec
Description : A train 170 m long is running at a speed of 22.5 km/hr. what time will it take to cross a 80m long bridge? A) 20 sec B) 40 sec C) 15 sec D) 30sec
Last Answer : ANSWER:B Explanation: Length of the train = 170 m Length of the bridge = 80 m Therefore, length of the train + length of the bridge = (170 + 80) m = 250m Speed of the train = 22.5 km/hr Speed ... .25m/sec Therefore, time taken by the train to cross the bridge = 250 m/6.25 m/sec. = 40 seconds.
Description : A pedal boat can cover 20km in 1 hr in still water. And it takes thrice as much as time to cover up than as to cover down the same distance in running water. The speed of the current is. A) 7.5 km/hr B) 20 km/hr C) 5 km/hr D) 10 km/hr
Last Answer : ANSWER : D Explanation: Let the speed of upstream be x' km/hr Then speed in downstream = 3x km/hr[thrice as much as time to cover up than as to cover down the same distance in running water] Speed in ... Speed in downstream = 30 km/hr Hence speed of the current = (30 -10)/2 = 10 km/hr.
Description : A car moving along a straight road with a speed of 120 km/hr, is brought to rest by applying brakes.
Last Answer : A car moving along a straight road with a speed of 120 km/hr, is brought to rest by applying brakes. ... (ii) time taken by the car to come to rest.
Description : A car travelling at a speed of 60 km/hour is braked and comes to rest 6 seconds after the brakes are applied. The minimum coefficient of driction between the wheels and the road would be a.0.107 b.0.3 c.0.283 d.0.417 e.0.5
Last Answer : c. 0.283
Description : A bike starts with a speed of 60 km/hr at 8a.m. Due to the problem in engine it reduces its speed as 20 km/hr for every 1 hour. After 9 am, the time taken to covers 15 km is: a) 13 minutes and 20 seconds b) 15 minutes and 09 seconds c) 18 minutes and 15 seconds d) 22 minutes and 30 seconds
Last Answer : 15 min
Description : A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60
Last Answer : D Let distance = x km Rate = y km/hr x/y - x / (y+6) = 30/60 (x(y+6)-xy) / y(y+6) = ½ (xy +6x - xy) / y(y+6) = ½ 12x = y(y+6) ------------>1 And x/ (y-4) - x/y = 30/60 (Xy - x(y-4 ... = (y+6) / (y-4) 3y - 12 = 2y +12 Y = 24km Put y value in 1 we get 12x = 24 (24+6) 12x = 24 *30 X=60km
Description : P,Q & R are on a journey by scorpio. P drives during the 1st 2 hrs at an average speed of 60 km/hr. Q drives during the next 3 hrs at an average speed of 58 km/hr R drives for the next 4 hrs at an average speed of 62 ... exactly 5 hrs. Their main speed is. a) 60 2/9 b) 62 2/9 c) 60 4/8 d) 62 4 /8
Last Answer : A Distance covered by P = 2*60 = 120 km Distance covered by Q = 3* 58 = 174 km Distance covered by R = 4*62 = 248 km Total distance = (120+174+248)km =542 km Total time taken = 2+3+4 = 9 hrs Mean speed = diatance/ time =(542 / 9)km/hr =60 2/9 km/hr
Description : A taxi driver make a trip from the plains to ooty which are 340km apart at an average speed of 60km/hr. In the return trip, he covers the speed distance at an average of 30 km/hr. the average speed of the taxi over the entire distance of 680 km is a) 30 b) 40 c) 50 d) 60
Last Answer : B Average speed =(2xy/( x+y)) km/hr Given x =60 km/hr y = 30km/hr Average speed = (2*60*30/ (60+30)) km/hr =(3600/ 90) =40 km/hr
Description : Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr
Last Answer : A As per the question, let D be the total distance and ‘t’ is the time taken. So we have: D=20t 20t =30(t-0.5) 20t=30t-15 10t=15 t=3/2 D= 30 km Now, for the condition given we have: 30=S(t-3/4) 30=S(3/2-3/4) 30=S((6-3)/4) 30=S(3/4) S=40 km/hr
Description : X and y are two trains of length 500m and 400m run on parallel lines. When they run in the same direction it will take 60 sec to cross each other. When they run in opposite direction, it will take 20 sec to cross each ... ) A) 116 and 42 km/hr B) 54 and 78km/hr C) 104 and 60km/hr D) 108 and 54km/hr
Last Answer : ANSWER : D Explanation: Let the speed of 2 trains be a1 and a2 Total distance covered to cross each other = (500 + 400)m = 900m When they run in the same direction, Relative speed = a1 - a2 = 900 /60 ... hr a 2= (15 * 18 / 5)m/s = 54km/hr Speed of two trains are 108 and 54 km/hr
Description : The resultant of a force acting on a body will be zero, if the body a.Rotates with uniform acceleration b.Moves along a curved path c.Rotates d.Does not rotate e.Rotates with uniform deceleration
Last Answer : d. Does not rotate
Description : A truck of mass 5 ton is travelling on a horizontal road with 36 km hr^-1 stops on travelling 1 km after its engine fails suddenly.
Last Answer : A truck of mass 5 ton is travelling on a horizontal road with 36 km hr-1 stops on travelling ... similar distance same how much will the fraction be?
Description : A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is (A) 1 in 40 (B) 1 in 50 (C) 1 in 60 (D) 1 in 70
Last Answer : Answer: Option A
Description : A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving with a speed of 80 km/hr. What i
Last Answer : A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving ... A. 2 m B. 4 m C. 6 m D. 8 m
Description : A car travels at a speed of 50 km/hr for 30 minutes, at 30 km/hr for next 15 minutes and then 70 km/hr for next 45 minutes.
Last Answer : A car travels at a speed of 50 km/hr for 30 minutes, at 30 km/hr for next 15 minutes and ... next 45 minutes. What is the average speed of the car?
Description : A motor car starts with the speed of 70 km/hr with its speed increasing every two hours by 10 kmph. In how many hours will it cover 345 kms? A.4 hrs B.4 hrs 5 mins C.4 1/2 hrs D.2 hrs E.None of these
Last Answer : Answer - C (4 1/2 hrs) Explanation - Distance covered in first 2 hours = (70 x 2) km = 140 km Distance covered in next 2 hours = (80 x 2) km = 160 km Remaining distance = 345 - (140 + 160) = 45 km. Speed in the ... ..1 hr 45km .? ?=45/90hr=1/2hr Total time taken = 2 + 2 +1/2=4 (1/2)hrs
Description : Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: A.40 m B.55 m C.65 m D.50 m E.None of these
Last Answer : Answer- D (50) Explanation – Relative speed= total lengths/time (46-36) x 5/18 = [L + L ] / 36 10 x (5/18) x36 x (1/2)= L L=50 m
Description : Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these
Last Answer : Answer – A (27 7/9 m) Explanation – When SAME direction- MINUS Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec. Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.
Description : Two trains are running at 120 km/hr and 60km/hr respectively in the same direction. Fast train completely passes a boy sitting in the slower train in 15 seconds. What is the length of the fast train? A) 150m B) 550 m C) 250m D) 215m
Last Answer : ANSWER: C Explanation: Speed of the 1st train = 120km/hr Speed of the 2nd train = 60km/hr If the direction is given in the same direction then we subtract the relative speed. Relative speed = (120 - 60) ... / 3 * 15)m =(750/3)m = 250m Therefore the length of the faster train is 250m
Description : A train, 1800 meters long running at the rate of 204 km/hr will cross a platform in: A) 16 B) 32 C) 45 D) 64
Last Answer : ANSWER: B Explanation: Speed of the train = 204 km/hr. We have to find the time in seconds, so convert the speed in the unit of m/sec. Therefore 204 km/hr = 204 x 5/18 m/s = 1020/18 m/s Length ... m/sec Time = distance/speed = 1800/(1020/18)sec = (1800*18/1020)sec = 32 sec (approx.)
Description : An intense rain is falling at a uniform rate of 7.5 cm/hour for a period of 60 minutes on a basin whose area is 500 hectares. If the average infiltration capacity during the entire rain period is assumed to be 1.5 ... of the basin, is (A) 40 cumecs (B) 60 cumecs (C) 80 cumecs (D) 100 cumecs
Last Answer : Answer: Option C
Description : Stopping distance of vehicles : When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on ... the brake with the deceleration of 5m/s2. Find the stopping distance of the car -Science
Last Answer : Here u=72 km/hr = 72×10003600m/s=2072×10003600m/s=20 m/s , v=0 a= -5 m/s2 Now using the relation v2=u2+2asv2=u2+2as 0=(20)2+2×(−5)×s0=(20)2+2×(−5)×s s=40ms=40m
Description : The coefficient of friction is a.The tangent of the angle between the normal reaction and direction of limiting friction b.The tangent of the angle between the normal reaction and the resultant ... e.The angle between the normal reaction and the resultant of normal reaction and the limiting friction
Last Answer : a. The tangent of the angle between the normal reaction and direction of limiting friction
Description : Combined effect of several forces is known as A. net force B. resultant force C. normal force D. weight
Last Answer : resultant force
Description : If a bus keeps moving at 60 km/hr, how many hours will it take for the bus to travel the 600 km distance from Manila to Sorsogon?
Last Answer : 10 hours