Description : A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving with a speed of 80 km/hr. What i
Last Answer : A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving ... A. 2 m B. 4 m C. 6 m D. 8 m
Description : A car is moving along a straight horizontal road at a speed of 20 meters per second. The brakes are applied and a constant force of 5000 Newtons decelerates the car to a stop in 10 seconds. The mass of the car is: w) 1250 kilograms x) 2500 kilograms y) 5000 kilograms z) 10,000 kilograms
Last Answer : ANSWER: X -- 2500 KILOGRAMS
Description : A car moving with a speed of 40 km/h can be stopped by applying brakes after at least 2m. If the same car is moving with a speed of 80 km/h., what is
Last Answer : A car moving with a speed of 40 km/h can be stopped by applying brakes after at least 2m. If the same car is moving ... A. 2 m B. 4 m C. 6 m D. 8 m
Description : Stopping distance of vehicles : When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on ... the brake with the deceleration of 5m/s2. Find the stopping distance of the car -Science
Last Answer : Here u=72 km/hr = 72×10003600m/s=2072×10003600m/s=20 m/s , v=0 a= -5 m/s2 Now using the relation v2=u2+2asv2=u2+2as 0=(20)2+2×(−5)×s0=(20)2+2×(−5)×s s=40ms=40m
Description : A car travelling at a speed of 60 km/hour is braked and comes to rest 6 seconds after the brakes are applied. The minimum coefficient of driction between the wheels and the road would be a.0.107 b.0.3 c.0.283 d.0.417 e.0.5
Last Answer : c. 0.283
Description : Minimum stopping distance for moving vehicles on road with a design speed of 80 km/hour, is (A) 80 m (B) 100 m (C) 120 m (D) 150 m
Last Answer : Answer: Option C
Description : A car is travelling at 90 km/hour on a rough road where the coefficient of friction between the road and the tyre is 0.5. The distance the car will skid before stopping when the brakes are jammed suddenly would be a.127.4 m b.95.55 m c.63.7 m d.31.85 m e.90 m
Last Answer : c. 63.7 m
Description : A car is running on a road at a uniform speed of 60 km/hr. What is the net resultant force on the car?
Last Answer : Equal to zero
Description : It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is? a) 2 : 3 b) 3: 2 c) 3 : 4 d) 4 : 3 e) None of these
Last Answer : Let the speed of the train be x km/hr and that of the car be y km/hr. Then, 120/x+480/y= 8 1/x+4/y=1/15 ....(i) And, 200/x+400/y=25/3 1/x+2/y=1/24 ....(ii) Solving (i) and (ii), we get: x = 60 and y = 80. Ratio of speeds = 60 : 80 = 3 : 4. Answer: c)
Description : A moving fluid mass may be brought to a static equilibrium position, by applying an imaginary inertia force of the same magnitude as that of the accelerating force but in the opposite direction. This statement is called (A) Pascal's law (B) (C) D-Alembert's principle (D) None of these
Description : Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these
Last Answer : Answer – C (36 kmph) Explanation – Let the speed of each train be x m/sec. Then, relative speed of the two trains = 2x m/sec. So, 2x = (120 + 120)/12 ⇔ 2x = 20 ⇔ x = 10. ∴ Speed of each train = 10 m/sec = [10 x 18/5] km/hr = 36 km/hr
Description : A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train? a) 120 meters b) 180 meters c) 324 meters d) 150 meters
Last Answer : d) 150 meters
Description : 2 bus start from A & B respectively and travel towards each other at a speed of 150 km/hr and 120 km/hr respectively. By the time they meet, the first bus has travelled by 300km more than the second. The distance between A & B is a) 2700 b) 2800 c) 2750 d) 2457
Last Answer : A At the time of meeting, Let the distance travelled by the second bus be xkm Then distance covered by the 1st bus is (x+300)km x/120= (x+300) /150 150x = 120(x+300) 150x = 120x +36000 30x = ... X=36000/30 X=1200 So the distance covered between A & B =(x+x+300) =(1200+1200+300) =2700km.
Description : Mr.Aneesh left for city 1 from city 2 at 3.00 pm. He travelled at the speed of 60km/hr for 1 and half hours. After that the speed was reduced to 15 km/hr. If the distance between two cities is 120 kms, at what time did Mr.Aneesh reach city 1 ? a) 6.30 pm. b) 5.30 pm. c) 7.30 pm. d) 8.30 pm.
Last Answer : A Mr.Aneesh travelled 60 km/hr for 1 1/2 hours (3/2 hours). Distance covered in 3/2 hours = 60 x 3/2 = 90 km. Therefore, remaining distance = 120 -90 = 30 km After 3/2 hours, the speed was ... village 2 at 3.00 pm + 3 hours 30 minutes = 6.30pm Hence the required answer is 6.30 pm.
Description : A passenger train without stopping running at an average speed of 120 km/hr and with stoppages at an average speed of 80 km/hr. What is the total time taken by the train for stoppages on a route of length 480km? a) 2 hours b) 3 hours c) 4 hours d) 5 hours
Last Answer : A Let r = running time of the train s= stoppage time of the train D= total distance travelled by train We have: D/r= 120 and ..(1) D/(r+s) =80 ..(2) Diviving (1)&(2), D/r *(r+s)/D = ... , D=480 kms 480/r= 120 r=4 put r value in (3),we get s/4 =1/2 S = 2 hours
Description : Two trains are running at 120 km/hr and 60km/hr respectively in the same direction. Fast train completely passes a boy sitting in the slower train in 15 seconds. What is the length of the fast train? A) 150m B) 550 m C) 250m D) 215m
Last Answer : ANSWER: C Explanation: Speed of the 1st train = 120km/hr Speed of the 2nd train = 60km/hr If the direction is given in the same direction then we subtract the relative speed. Relative speed = (120 - 60) ... / 3 * 15)m =(750/3)m = 250m Therefore the length of the faster train is 250m
Description : Find the time taken by mailtrain 200m long running at a speed of 120 km/hr to cross another train of length 160m running at a speed of 96km/hr in the same direction. A) 34sec B) 52sec C) 45sec D) 54sec
Last Answer : ANSWER: D Explanation: Total distance covered to cross each other = 200 + 160 = 360m If the direction is given in the same direction then we subtract Relative speed of two trains (same direction) = ... * 3 / 20 = 54sec Time taken by the faster train to cross the slower train is 54sec.
Description : A train 200m in length, travels at 120 km/hr. In what time it will pass a boy who is walking at 12km an hour. a) against(opposite) it: b) in the same direction? A) 5.4,6.66 B) 7.2,5.2 C) 3.5,6 D) 12,16
Last Answer : ANSWER: A Explanation: I) Speed of the train = 120 km/hr Speed of the boy = 12 km/hr Relative speed = (120 + 12) km/hr Convert km/hr into m/s 132 km/hr = (132 * 5/ 18)m/s = 36.66 m/s Time = ... km/hr = (108 * 5 / 18)m/s = 30 sec Time = distance / speed = 200 / 30 = 6.66 sec
Description : A mail train 220 m long is running with a sped of 120 km/hr. What is the time in which it will pass a man who starts from the engine running at the speed of 12km/hr in the direction opposite to that of the train. A) 6sec B) 5sec C) 4sec D) 3sec
Last Answer : ANSWER: A Explanation: We know as the train and the running person are moving in opposite direction,therir speed values are added to find the relative speed. Relative speed = speed of mail train + speed of running ... [ from the length of the mail train is the distance] = 220 / 36.66 = 6 sec.
Description : A motorboat can cover 80 km upstream and 120 km downstream together in 26 hours. Also it can cover 100 km upstream and 144 km downstream together in 32 hours. What is the speed of the motorboat in still water? A) 12 km/hr B) 15km/hr C) 8.5km/hr D) 19km/hr
Last Answer : ANSWER :C Explanation: Upstream speed in both cases is 80 and 100. Ratio is 80 : 100 = 8:10 = 4 : 5. So let times in both cases be 4x and 5x Downstream speed in both cases is 120 and 144 resp. Ratio is ... 12 km/hr So speed of boat = 1/2 * (5+12) =17/2km/hr speed of boat = 8.5 km/hr
Description : A car starts from rest and moves on a straight road with a uniform acceleration of 10 m/s2 for the first 10 s. During the next 10 s, the car move s with the velocity it has attained. What is the total distance covered by the car in 20 s? (a) 500 m (b) 1000 m (c) 1,500 m (d) 2,000 m
Last Answer : Ans:(c)
Description : 1/2of a certain travel is covered at the rate of 30km/hr, one-third at the rate of 40 km/hr and the rest at 35km/hr. Find the average speed for the whole travel. A) 33 1/3 B) 33 3/5 C) 34 3/7 D) None of these
Last Answer : B) let the total travel be X km. Then X/2 km at the speed of 30 km/hr and X/3 km at 40 km/hr and the rest distance( X - X/2 - X/3) =1/6 X at the speed of 35km/hr. Total time taken during the travel ... 2*30 hrs+ X/3*40hrs+ X/6*35hrs = 5X/168 hrs Average speed =X/(5x/168) = 168/5 =33 3/5km hr
Description : An aeroplane A, is travelling in a straight line with a velocity of 300 km/hr with respect to Earth. Another aeroplane B, is travelling
Last Answer : An aeroplane A, is travelling in a straight line with a velocity of 300 km/hr with respect to ... relative velocity of 100 km/hr with respect to A?
Description : A truck of mass 5 ton is travelling on a horizontal road with 36 km hr^-1 stops on travelling 1 km after its engine fails suddenly.
Last Answer : A truck of mass 5 ton is travelling on a horizontal road with 36 km hr-1 stops on travelling ... similar distance same how much will the fraction be?
Description : There is road besides a river. Two friends started from a place P, moved to a shopping mall situated at another place Q and then returned to P again. One of them moves on a cycle at a speed of 12 km/ ... which of the two friends will return to place P? A. Both B. Boater C. Cyclist D. None of these
Last Answer : Answer-C Explanation: The cyclist moves both ways at a speed of 12khr so average speed fo the cyclist - 12 km/hr boat sailor moves downstream at 10+4 = 14km/hr and upstream 10- 4 = 6km/hr ... 8.4km/hr The average speed of cyclist is greater .so,cyclist comes first and return to place P.
Description : A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed ... as the train? A.59 km/hr B.65 km/hr C.70 km/hr D.81 km/hr E. None of these
Last Answer : Answer-D (81 km/hr) Explanation4.5 km/hr =(4.5 x 5/18)m/sec =5m/4sec = 1.25 m/sec, and 5.4 km/hr =(5.4 x 5/18)m/sec =3m/2sec = 1.5 m/sec. Let the speed of the train be x m/sec. Then, (x - 1.25) ... - 12.75 => 0.1x = 2.25 => x = 22.5 Therefore Speed of the train =(22.5 x18 /5)km/hr = 81 km/hr.
Description : A Superfast train overtakes two persons walking along a railway track. The first one walks at 9 km/hr. The other one walks at 10.8 km/hr. The train needs 16.8and 17seconds respectively to overtake them. ... are walking in the same direction as the train? A) 250 kmph B) 487kmph C) 162kmph D) 312kmph
Last Answer : ANSWER:C Explanation: Given that the first one walks at 9 km/hr convert the speed in the unit of m/sec 9 km/hr = (9*5/18) m/s = 5/2 m/s = 2.5 m/s Another one walks at 10.8 km/hr ... the speed in the unit of km/hr Speed of the train = (45*18/5)kmph Speed of the train = 162 km/ hr
Description : A train overtakes two girls walking along a railway track. The first girl walks at 9 km/hr. The other girl walks at 10.8 km/hr. The train needs 16.8 and 17 seconds respectively to overtake them. What is the speed of the ... in the same direction as the train? A) 25 m/s B) 45 m/s C) 30m/s D) 40m/s
Last Answer : ANSWER:B Explanation: First girl speed = 9km/hr = 9 * 5 / 18 m/s = 5/2 m/s = 2.5 m/s second girl speed = 10.8 km/hr = 10.8 * 5/18 m/s = 54/18 = 3 m/s Let the speed of the train ... x - 3) * 17 16.8x - 42 = 17x - 51 0.2x = 9 x = 45 Therefore the speed of the train is 45 m/s
Description : A girl is walking at a speed of 15 km/hr along a railway track. If she is 600 m ahead of the train which is 300 m long and runs at a speed of 180 km/hr in same direction, then what is the time required to pass a girl? A) 19.63sec B) 32sec C) 8.2sec D) 28.3sec
Last Answer : ANSWER:A Explanation: Speed of a girl = 15 km/hr speed of train = 180 km/hr By using the condition, The speed values of train and the moving object are subtracted if they are moving in same ... /45.83 = 19.63 Hence the time taken by the train to cross the girl is 19.63seconds
Description : A boy sitting in a rail road car throws a ball straight up into the air. The ball will fall back into his hands when the rail road car is a.moving at constant velocity b.accelerating ... inclined plane, while another identical block B is released for free fall from the same height e.decelerating
Last Answer : a. moving at constant velocity
Description : A car moving at a speed 10 m/s on a straight road is ahead of car B moving in the same direction at 6 m/s. Find the velocity of A relative
Last Answer : A car moving at a speed 10 m/s on a straight road is ahead of car B moving in the same ... Find the velocity of A relative to B and vice-versa.
Description : A car moving on a straight road is a ____.
Last Answer : Rectilinear motion
Description : A train 100 m long is moving with the velocity of 72 km/hr. Find the time it takes to cross the bridge which is 2 km long? -Science
Last Answer : Given Lenght of Train = 100m , velocity = 72 km/hr = 20 m/s, Lenght of the Bridge =2 Km. Total distance covered by the train to fully pass the bridge = 2000 + 100 = 2100 m So, time taken time=distancevelocity=210020=105sectime=distancevelocity=210020=105sec
Description : If a bus keeps moving at 60 km/hr, how many hours will it take for the bus to travel the 600 km distance from Manila to Sorsogon?
Last Answer : 10 hours
Description : Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these
Last Answer : Answer – C (48 sec) Explanation – Relative speed = all lengths/time [60+90] = [1.10 +0.9 ]/time [ PLUS when opposite direction] time=2/150 = 1/75 h 1 hour______3600 sec 1/75 hr______? ?= 3600/75=48 sec
Description : A goodstrain of 700 m runs at a speed of 165 km/hr. A person traveling in it observes that the mail train moving in opposite direction takes 30 seconds to cross him. Find the speed of the mail train, if it is 750 m long. A) 8.4 m/s B) 5.3 m/s C) 2.5 m/s D) 6.8 m/s
Last Answer : ANSWER:C Explanation: Speed of goods train = 165km/hr length of mail train (P) = 750m length of goods train (Q) = 700m Alternately, we can directly use the formula: Time = ( p+q) / (v1+v2) sec ( ... 45.833+v2 = 48.333 V2 = 2.5 m/s Therefore the speed of the mail train is 2.5 m/s
Description : Two trains, both 50m long, moving in opposite directions cross each other in 4 seconds. If one is moving thrice as fast the other, then the speed of the faster train is. A) 45km/hr B) 19 km/hr C) 95 km/hr D) 67.5 km/hr
Last Answer : ANSWER:D Explanation: Let the speed of the slower train be x' m/sec The speed of the sfaster train = 3x m/s Relative speed = (x +3x)m/sec = 4x m/sec 50 + 50 / 4 = 4x 100 / 4 = 4x 100 = 16x x = 100 ... the faster train = 3 * 25 / 4 = 75 / 4 m/s = (75/4 *18 /5)km/hr = 67.5 km/hr
Description : Two trains A and B are moving in opposite directions at 180 km/hr and 270 km/hr. their lengths are 3.30 km and 2.7 km respectively. The time taken by the slower train to cross the faster train in second is. A) 48sec B) 13 sec C) 38sec D) 24sec
Last Answer : ANSWER: A Explanation: Speed of 1st train = 180 km/hr Speed of 2nd train = 270 km/hr Relative speed = (180 + 270)km/hr = 450 km/hr = (450 * 5 / 180)m/s = (2250 / 18)m/s =125 m/s Distance covered = (3.30 + 2.70)km = 6km = 6000m Required time = 6000 / 125 = 48sec
Description : A passenger train 165 m long which is running at a speed of 30km/hr. In what time will it pass a man who is running at a speed of 3 km/hr in the opposite direction. In which the train is moving. A)14 sec B) 17sec C)16sec D)18sec
Last Answer : ANSWER: D Explanation: Speed of the train = 30 km/hr Speed of man = 3 km/hr Length of the train = 165m If direction is given in opposite direction then we add both speed. That is (30 + 3 )= 33 km/hr ... can easily get the distance of m/s So it cover 165 m i.e., 165 * 6 /55 = 18 sec.
Description : A train 135m long is moving at a speed of 12.5 km/h. It will cross a girl coming from the opposite direction at a speed of 1km/hr in. A) 36sec B) 46sec C) 56sec D) 66sec
Last Answer : ANSWER : A Explanation: Speed of the train = 12.5 km/hr Speed of girl = 1 km/hr Relative speed = speed of train + speed of girl = (12.5 + 1) km/hr = 13.5 km/hr Convert km/hr into m/s 13.5 ... .75 m/s Time = distance / speed Time taken by the train to pass the man = 135 / 3.75 = 36 sec.
Description : A passenger train 300m long is running with a speed of 136 km/hr. In what time will it pass a boy who is running at 6 km/hr in opposite direction in which the train is moving? A) 8.6sec B) 7.6sec C) 3.6sec D) 2.6sec
Last Answer : ANSWER: B Explanation: Speed of the train = 136 km/hr Speed of boy = 6 km/hr Speed of the train relative to boy = (13 + 6)km/hr = 142 km/hr Convert km/hr into m/s 142 km /hr = (142 * 5 / 18 ... taken bt it to cover 300 m at 39.44 m/s =300 / 39.44 [speed time= distance / speed] = 7.6 sec
Description : A railway wagon moving with a speed of 1.5m/s is brought to rest by bumper consisting of two springs. Mass of wagon is 100kg. The springs are compressed by 125mm. Calculate the maximum force acting on each spring. a) 1200N b) 1500N c) 1800N d) 2000N
Last Answer : c) 1800N
Description : 120 men can lay a road 80 km long in 20 days. In how many days can 100 men lay a road of length 90 km?
Last Answer : 120 men can lay a road 80 km long in 20 days. In how many days can 100 men lay a road of length 90 km?
Description : When slowing to a stop there is a slight jerk without applying the brakes?
Last Answer : The year, make, model, transmission and engine info would helpbut it is probably the transmission down shifting if the vehicle isan automatic.
Description : When coming to a stop it is a good idea to tap your brakes before applying full pressure to let others know what your intentions are?
Last Answer : Feel Free to Answer
Description : The reduced levels of points, 30 metres apart along the longitudinal section of a road portion between chainages 5 and 9 are shown in the given figure. If there is a uniform up-gradient of the road 120 in 1, the chainage ... 15) chains (B) (6 + 12) chains (C) (6 + 18) chains (D) None of these
Last Answer : (B) (6 + 12) chains
Description : If you want to stop the car in the shortest distance on an icy road, you should a.107 dynes b.not apply the brakes c.pump' the brakes d.push hard the brakes to lock the wheels e.push just hard enough to prevent slipping
Last Answer : e. push just hard enough to prevent slipping
Description : If a child runs into the road 45 to 50 feet ahead of your car what is the highest speed from which you can stop with good brakes?
Last Answer : About 20 mph, but it would depend greatly on other factors suchas road conditions, size and weight of vehicle, operator reactionspeed, etc.
Description : If the velocity of moving vehicles on a road is 24 km/per hour, stopping distance is 19 metres and average length of vehicles is 6 metres, the basic capacity of lane, is (A) 500 vehicles per hour (B) 700 vehicles per hour (C) 1000 vehicles per hour (D) 1250 vehicles per hour
Description : A person walks from point P to point Q along a straight road ¡n 10 minutes, then turns back and returns to point R which is midway
Last Answer : A person walks from point P to point Q along a straight road n 10 minutes, then turns back and ... velocity of the person in going from P to R.