D
Let daughter’s age be x and father’s age be 6x.
Father’s age is 6 times more aged than his daughter, therefore father’s present age = x + 6x = 7x
After 10years, father’s age is 6 times more than his daughter age.
(7x + 10) = 6 (x + 10)
(7x+10)=6x+60
x = 50
After 10 years it was (7x + 10), then after further 10 years, father’s age = (x +20) and daughter’s age = (x +
20)
(7x+10) /(x+20) = ?
Substitute the value of x, we get
= (350+10) /70
= 360 /70
=5.14
After further 10 years, father will be 5.1 times of daughter’s age