Mr. Nagar is 6 times more aged than his daughter. If after 10 years, he would be 6 times of daughter’s age, then further after 10 years, how many times he would be of his daughter’s age? a) 5 .5 times b) 5.8 times c) 2.5 times d) 5.1 times 

1 Answer

Answer :

D

Let daughter’s age be x and father’s age be 6x.

Father’s age is 6 times more aged than his daughter, therefore father’s present age = x + 6x = 7x

After 10years, father’s age is 6 times more than his daughter age.

(7x + 10) = 6 (x + 10)

(7x+10)=6x+60

x = 50

After 10 years it was (7x + 10), then after further 10 years, father’s age = (x +20) and daughter’s age = (x +

20)

 (7x+10) /(x+20) = ?

Substitute the value of x, we get

= (350+10) /70

= 360 /70

=5.14

After further 10 years, father will be 5.1 times of daughter’s age

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