Three year ago, ratio of Tom and Ram age’s was 5 : 6 respectively. After 12 years, this ratio becomes 6 : 7. How old is Ram at present? a) 39years b) 93 years c) 78 years d) 87 years

Three year ago, ratio of Tom and Ram age’s was 5 : 6 respectively. After 12 years, this ratio becomes 6 : 7. How old is Ram at present? a) 39years b) 93 years c) 78 years d) 87 years
by

1 Answer

Answer :

B

We are given that age ratio of tom and ram = 5 : 6

Tom’s age = 5x and Ram’s age = 6x

3 years ago, their age was 5x and 6x.

Hence at present, Tom’s age = 5x +3 and Ram’s age = 6x +3

After 12years,

Tom’s age = (5x +3) + 12 = (5x + 15)

Ram’s age = (6x +3) + 12= (6x + 15)

After 12years, this ratio becomes => 6 : 7. Therefore,

Tom’s Age/ram’s Age =6/7

(5x + 15) / (6x +15) = 6 / 7

7 (5x + 15) = 6 (6x + 15)

X = 15

Ram’s present age = (6x + 3) = 93years 
by

Related questions

The ratio of kabil’s age 6 years ago and sahul’s age after 6 years is 3 : 3. If at present, the ratio of their ages is 7: 5, then find the ratio between kabil’s age 6 years hence and sahul’s age 6 years ago. a) 1 : 3 b) 2 : 1 c) 4 : 3 d) 3 : 4

Description : The ratio of kabil’s age 6 years ago and sahul’s age after 6 years is 3 : 3. If at present, the ratio of their ages is 7: 5, then find the ratio between kabil’s age 6 years hence and sahul’s age 6 years ago. a) 1 : 3 b) 2 : 1 c) 4 : 3 d) 3 : 4

Last Answer :  B At present: Ratio of their ages = 7 : 5. Therefore, 7: 5 will be 7x and 5x. kabil's age 6 years ago = 7x - 6 sahul's age after 6years = 5x + 6 Ratio of kabil's age 6years ago and sahul's age after 6 ... Ratio of sahul's age and kabil's age (7x + 6) / (5x - 6) = 48/24 =2/1 =2:1

Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36

Description : Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36

Last Answer : C Let the present ages are 5x, 8x, 10x. => (5x-6) + (8x-6) + (10x-6) = 28 => 23x = 46 => x = 2 So their present ages are: 10,16,20

One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Description : One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Last Answer : Answer - B (16) Explanation - Let one year ago Sam's age be 4X years And, Ash's age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam's age = (4X + 2) ... = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.

The ages of two sisters differ by 32 years. 12 years ago, the elder one was 7 times as old as the younger one. What are their present ages of the elder person a) 46.9 b) 49.3 c) 42.7 d) 45.4

Description : The ages of two sisters differ by 32 years. 12 years ago, the elder one was 7 times as old as the younger one. What are their present ages of the elder person a) 46.9 b) 49.3 c) 42.7 d) 45.4

Last Answer : B Let's take the present age of the elder person = x and the present age of the younger person = x – 32 (x – 12) = 7*(x-32-12) => x – 12 = 7x – 308 => 6x = 296 => x = 49years 3months

12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages a) 30 b) 35 c) 36 d) 32

Description : 12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages a) 30 b) 35 c) 36 d) 32

Last Answer : C Let M's age 12 years ago = x years. Then, N's age 12 years ago = 2x years. (x + 12) / (2x+ l2) = 4/5 => x = 4. So, the total of their present ages =(x + 12 + 2x + 12) = (3x + 24) = 36 years.

Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6. What is the age of Q at present a) 44 b) 30 c) 45 d) 33

Description : Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6. What is the age of Q at present a) 44 b) 30 c) 45 d) 33

Last Answer : D Let their ages 8 years ago is4x, 5x and 6x years.  4x+8+5x + 8 + 6x + 8= 99 hence x= 5 Q’s present age = (5x + 8)  =33 years

Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present a) 30 years b) 28 years c) 34 years d) 36 years

Description : Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present a) 30 years b) 28 years c) 34 years d) 36 years

Last Answer : B Let 8 years ago the age of Micky and Donald be 6x and 5x resp. then, ((6x+8)+12) / ((5x+8)+12) = 11/10 10(6x+20) = 11(5x+20) 5x = 20 => x = 4 So Donald age is (5x+8) = 28

Age of father 30 years ago was 9 times the age of her son. After 30 years, father’s age will be thrice that of his son. Find the ratio of their present ages. a) 21 : 5 b) 29 : 5 c) 27 : 4 d) 21 : 3

Description : Age of father 30 years ago was 9 times the age of her son. After 30 years, father’s age will be thrice that of his son. Find the ratio of their present ages. a) 21 : 5 b) 29 : 5 c) 27 : 4 d) 21 : 3

Last Answer : A At age of son be x and as father's age is 9 times the age of her son, let it be 9x, nine years ago. At present: father's age will be (9x + 30) and son's age will be (x + 30) After 30 years: father's age ... x = 20 We are asked to find the present ratio. (9x + 30) : (x + 30) = 210 : 50 = 21:5

Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Description : Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Last Answer : Answer – B (24) Explanation – Let the present ages of Simmi and Anu be 5x years and 4x years respectively Then, [5X + 3] / [4X + 3] =11/9 x=6 Anu’s present age = 4X = 24 years

The ratio between the present ages of M and N is 8:9. If N is 6 years old than M, what will be the ratio of the ages of M and N after 6 years a) 9:10 b) 7:9 c) 9:8 d) 11:10

Description : The ratio between the present ages of M and N is 8:9. If N is 6 years old than M, what will be the ratio of the ages of M and N after 6 years a) 9:10 b) 7:9 c) 9:8 d) 11:10

Last Answer : A Let M age and N age be 8x years and 9x years. Then 9x - 8x = 6 <=> x = 6 So required ratio will be (8x+6): (9x+6) 54:60 9:10

Nandhu is 80years old and Nalini is 90 years old. How many years ago was the ratio of their ages 8 : 10? a) 40 years b) 35 years c) 20 years d) 25 years

Description : Nandhu is 80years old and Nalini is 90 years old. How many years ago was the ratio of their ages 8 : 10? a) 40 years b) 35 years c) 20 years d) 25 years

Last Answer : A Let us assume x years ago At present: Nandhu is 80 years and Nalini is 90 years x years ago: Nandhu's age = (80 - x) and Nalini's age = (90 - x) Ratio of their ages x years ago was 8 : 10 ... 800-10x =720-8x 2x=80 x=40 Therefore, 40 years ago, the ratio of their ages was 8:10

The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son a) 34,17 b) 14,40 c) 40,14 d) 50,17

Description : The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son a) 34,17 b) 14,40 c) 40,14 d) 50,17 

Last Answer : C Let sons age = x years. Then mothers age = (54 - x)years. (x-8)(54-x-8) = 6(54- x - 8) hence (x-8) = 6 so x = 14 Their ages are 40 years and 14 years.

15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years

Description : 15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years

Last Answer : C

The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years

Description : The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years

Last Answer : A Son’s current age = x years. Then father’s age = (84 - x)years (84 - x) - 7 = 3(x - 7) 2x=56 x =28; after 7years it will be turn on 35 

Keerthi's grandfather was 16 times older to her 32 years ago. He would be 6times of her age 16 years from now. What was ratio of ages of keerthi and her grandfather 16 years ago. a) 1:10 b) 11:10 c) 10:11 d) 10:1

Description : Keerthi's grandfather was 16 times older to her 32 years ago. He would be 6times of her age 16 years from now. What was ratio of ages of keerthi and her grandfather 16 years ago. a) 1:10 b) 11:10 c) 10:11 d) 10:1 

Last Answer : A Let, keerthi’s age 32 years ago = x, Grandfather's age 32 years ago = 16x. 16 years from now, 6(x+32+16) = (16x+32+16) => x = 24 16 years ago ratio was: (x+16)/ (16x+16) = (24+16) / (16*24+16) 40 /400 = >1 / 10

The ratio of the ages of Bala and Babu is 13: 11. The total of their ages is 3.6decades. The proportion of their ages after 0.95decades will be [1 Decade = 10 years] a) 24:23 b) 12:11 c) 27:24 d) 29:26

Description : The ratio of the ages of Bala and Babu is 13: 11. The total of their ages is 3.6decades. The proportion of their ages after 0.95decades will be [1 Decade = 10 years] a) 24:23 b) 12:11 c) 27:24 d) 29:26

Last Answer : D Let, Bala’s age = 13A and babu’s age = 11A Then 13A + 11A = 36 A = 1.5 Bala’s age = 19.5years and Babu’s age = 16.5 years Proportion of their ages after 9.5 is = (19.5+9.5) : (16.5 + 9.5) = 29 : 26

The ratio of the age of a rithick and his wife is 12:9. At the time of marriage the ratio was 10:6 and After 6 years this ratio will become 18:14. How many years ago were they married? a) 27 b) 12 c) 18 d) 14

Description : The ratio of the age of a rithick and his wife is 12:9. At the time of marriage the ratio was 10:6 and After 6 years this ratio will become 18:14. How many years ago were they married? a) 27 b) 12 c) 18 d) 14

Last Answer : C Let the present age of the rithick and his wife be 12x and 9x respectively. After 6 years this ratio will become 18:14 =>9:7 (12x+6): (9x+6) = 9:7 84x+42 =81x+54 x=4 Present age of the rithick = ... that they got married before t years. Then, (48-t):(36-t)=10:6 144-3t=180-5t 2t=36 t=18

Shyam is younger than Sharuk by 22 years. If the ratio of their ages is 5:7, find the age of Shyam a) 55 b) 77 c) 66 d) 88

Description : Shyam is younger than Sharuk by 22 years. If the ratio of their ages is 5:7, find the age of Shyam a) 55 b) 77 c) 66 d) 88

Last Answer : A If sharuk age is x, then Shyam age is x-22, so (x-22)/x = 5/7 => 7x-154 = 5x => 2x = 154 => x = 77 So shyam age is 77 - 22 = 55

Amit is 18 years elder than Rohit. If 8 years ago, Amit was 6 times as old as Rohit, then find Amit’s present age. a). 32.5 years b) 27.5 years c) 29.6 years d) 24.9 years

Description : Amit is 18 years elder than Rohit. If 8 years ago, Amit was 6 times as old as Rohit, then find Amit’s present age. a). 32.5 years b) 27.5 years c) 29.6 years d) 24.9 years

Last Answer : C Let age of Rohit be y Amit is 18 years elder than Rohit = (y + 18). SoAmit's age 8 years ago = (y + 18 - 8) Rohit's age before 8 years = (y - 8) 8 years ago, Amit is 6 times as old as Rohit (y + 18 ... = 58 y = 11.6 Rohit's age = 11.6years Amit's age = (y + 18) = (11.6 + 18) = 29.6years

Fathima's father was 76 years of age when she was born while her mother was 72years old when her brother 8 years younger to her was born. What is the difference between the ages of her parents? a)12 years b)14 years c)16 years d)18 years

Description : Fathima's father was 76 years of age when she was born while her mother was 72years old when her brother 8 years younger to her was born. What is the difference between the ages of her parents? a)12 years b)14 years c)16 years d)18 years

Last Answer : A Mother's age when Fathima 's brother was born = 72 years. Father's age when Fathima 's brother was born = (76+8) years = 84 years. Required difference = (84-72) years = 12 years

P is 6 years older than Q who is twice as old as R. If the total of the ages of P, Q and R be 81, the how old is Q? a) 27 b) 28 c) 29 d) 30

Description : P is 6 years older than Q who is twice as old as R. If the total of the ages of P, Q and R be 81, the how old is Q? a) 27 b) 28 c) 29 d) 30

Last Answer : D Let R's age be x years. Then, Q's age = 2x years. P's age = (2x + 6) years. (2x + 6) + 2x + x = 81 5x = 75=> x =15. Hence, Q's age = 2x = 30 years

Ten years ago, Khush was thrice as old as Sam was but 10 years hence, he will be only twice as old. Find Khush’s present age? A.30 B.35 C.40 D.36 E.None of these

Description : Ten years ago, Khush was thrice as old as Sam was but 10 years hence, he will be only twice as old. Find Khush’s present age? A.30 B.35 C.40 D.36 E.None of these

Last Answer : Answer - A (30) Explanation - Let Khush's present age be x years and Sam's present age be y years Then, according to the first condition, x - 10 = 3(y - 10) or, x - 3y = -20 ..(1) Now. Khush's age ... (1) and (2), we get x = 70 and y = 30 Khush's age = 70 years and Sam's age = 30 years

Ratio between vinodha and swetha is 7:6, After 8 Years vinodha’s age will be 29 years. What is swetha present age. a) 16 b) 18 c) 20 d) 22

Description : Ratio between vinodha and swetha is 7:6, After 8 Years vinodha’s age will be 29 years. What is swetha present age. a) 16 b) 18 c) 20 d) 22

Last Answer : B Present age is 7x and 6x, => 7x + 8 = 29 => x = 3 So swetha age is = 6(3) = 18

The father’s age 7years ago was 11 times the age of his daughter. At present the father’s age is 7 times that of his daughter. Find the daughter’s present age. a) 17.5 b) 18.2 c) 23 d) None

Description : The father’s age 7years ago was 11 times the age of his daughter. At present the father’s age is 7 times that of his daughter. Find the daughter’s present age. a) 17.5 b) 18.2 c) 23 d) None

Last Answer : A daughter’s present age = x At present the father’s age is 7 times that of his daughter i.e., Father’s present age = 7x. ‘Father’s age 7 years ago was 11 times the age of his daughter’ (7x – 7) = 11 * (x – 7) x = 17.5 years, The daughter’s present age = 17.5 years

The sum of ages of 4 puppies born at the intervals of 2 years each is 48 years. What is the age of the youngest puppy? a) 9years b) 8 years c) 10 years d) None of these

Description : The sum of ages of 4 puppies born at the intervals of 2 years each is 48 years. What is the age of the youngest puppy? a) 9years b) 8 years c) 10 years d) None of these 

Last Answer : A Let the ages of puppies be x, (x + 2), (x + 4)and (x + 6) years. Then, x + (x + 2) + (x + 4) + (x + 6) = 48 4x = 36,x = 9 Age of the youngest puppy = x = 9 years

The sum of the current ages of two persons M and N is 129. If the age of M is twice that of N, find the sum of their ages 8 years hence. a)125 b)145 c)137 d)149

Description : The sum of the current ages of two persons M and N is 129. If the age of M is twice that of N, find the sum of their ages 8 years hence. a)125 b)145 c)137 d)149

Last Answer : B M+N=129 Given M=2N From Which N =43,M=86 8 years their age will be 51 and 94 ,so the sum of their ages is 145

What is Kishore present age, if after 30 years his age will be 15times of his age 15 years back. a) 16.2 years b) 17.7 years c) 18.2years d) 15.4 years

Description : What is Kishore present age, if after 30 years his age will be 15times of his age 15 years back. a) 16.2 years b) 17.7 years c) 18.2years d) 15.4 years 

Last Answer : C Let kishore's present age be x kishore's age before 15 years = (x - 15) kishore's's age after 30 years = (x + 30) We are given that, kishore's's age after 30 years (x + 30) is 15 times his age 15 ... = 15 (x - 15) Solving the equation, we get x + 30 =15x -225 14x = 255 x = 18.2 years

A father said to his son, “I was as old as you are at present at the time of your birth.” If the father’s age is 38 years now, the son’s age five years back was: A.14 B.19 C.38 D.40 E.None of these

Description : A father said to his son, “I was as old as you are at present at the time of your birth.” If the father’s age is 38 years now, the son’s age five years back was: A.14 B.19 C.38 D.40 E.None of these

Last Answer : Answer – A (14) Explanation – Let son’s present age be X years. Then, (38 – X) = X 2X = 38 X = 19 Son’s age 5 years back = (19 – 5) years = 14 years

If 6 years are subtracted from the present age of Anuj and the remainder is divided by 18, then the present age of his grandson Gopal is obtained.If Gopal is 2 years younger to Mohan whose age is 5 years, then what is the age of Anuj? A.44 B.60 C.80 D.92

Description : If 6 years are subtracted from the present age of Anuj and the remainder is divided by 18, then the present age of his grandson Gopal is obtained.If Gopal is 2 years younger to Mohan whose age is 5 years, then what is the age of Anuj? A.44 B.60 C.80 D.92

Last Answer : Answer : B (60) Explanation - Let Anuj's age be X Gopal is 2 years younger than Mohan, so Gopal is 3 years (i.e 5 - 2 = 3) If Arun had born 6 years before, his age would had been X - 6. As per the ... as that of Gokul's age. i.e. (X - 6) /18= 3 X-6 =3 x 18 x = 60

Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these

Description : Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these

Last Answer : Present ratio of Deepa&Subha = 5 : 6 Six year hence ratio of Deepa&Subha = 6 : 7 Difference between ratio = 1 Difference in ages between present & future = 6 year. 1 ratio=6 yrs & SUBHA's age = 6 6 =36 year 5 year ago ... = 7 6 = 42 year B's age 5 year ago = 42-6-5 = 42-11 = 31 year Answer: d)

Mani is 32years older than his son Dinesh. In 4 years, his age will be twice the age of his son. The present age of his son is a) 26 years b) 28years c) 22 years d) 24 years

Description : Mani is 32years older than his son Dinesh. In 4 years, his age will be twice the age of his son. The present age of his son is a) 26 years b) 28years c) 22 years d) 24 years

Last Answer : B Let the son's present age be x years. Then, mani's present age = (x + 32) years => (x + 32) + 4 = 2(x + 4) => x + 36 = 2x + 8 So, x = 28

Father is aged three times more than his son Mohit. After 8 years, he would be two and a half times of Mohit’s age. After further 8 years, how many times would he be of Mohit’s age? A.4 B.2 C.2.5 D.3 E.None of these

Description : Father is aged three times more than his son Mohit. After 8 years, he would be two and a half times of Mohit’s age. After further 8 years, how many times would he be of Mohit’s age? A.4 B.2 C.2.5 D.3 E.None of these

Last Answer : Answer – B (2) Explanation – Let Monit’s present age be X years. Then, father’s present age = (X + 3X) years = 4X years. (4X + 8) =5/2 x (X + 8) 8X + 16 = 5X + 40 3X = 24 so, X=8 Hence, required ratio = (4X + 16) / (X + 16)=48 / 24 = 2

Mr. Nagar is 6 times more aged than his daughter. If after 10 years, he would be 6 times of daughter’s age, then further after 10 years, how many times he would be of his daughter’s age? a) 5 .5 times b) 5.8 times c) 2.5 times d) 5.1 times

Description : Mr. Nagar is 6 times more aged than his daughter. If after 10 years, he would be 6 times of daughter’s age, then further after 10 years, how many times he would be of his daughter’s age? a) 5 .5 times b) 5.8 times c) 2.5 times d) 5.1 times 

Last Answer : D Let daughter's age be x and father's age be 6x. Father's age is 6 times more aged than his daughter, therefore father's present age = x + 6x = 7x After 10years, father's age is 6 times more than his ... ) /70 = 360 /70 =5.14 After further 10 years, father will be 5.1 times of daughter's age

The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313

Description : The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313

Last Answer : Answer: C The present population = (1+4/100)×(1+6/100)×(1+10/100)×200000  = (104/100) × (106/100) × (110/100) × 200000  = 1.04×1.06×1.1×200000  = 2,42,528

The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be as old as the present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these

Description : The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be ... present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these

Last Answer : Answer: B Let their ages 8 years ago be 2x, 3x, 7x, and 8x. Their ages now 2x+8, 3x+8, 7x+8, 8x+8. According to the question, =2x+8+3x+8+7x+8+8x+8=172 20x+32=172 =>x=140/20=7 Present age of Nishu=2×7+8=22 years Present age of mother=7×7+8=57 years Hence, required years (57-22)=35 years

Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Description : Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Last Answer : Sum of present ages of A, B and C is 72 years. sum of their ages (4 years ago) = 72 – (3 × 4) = 60 years 4 years ago, ratio of ages of A, B and C was 1 : 2 :3. A’s age, 4 years ago = (1/6) ×60 = 10 years A’s present age = 10 + 4 = 14 years Answer: d)

Vasu said to his son, "I was as old as you at the time of your birth". If vasu’s age is 76 years now, the son's age ten years back was: a)14 years b)19 years c)33 years d)28 years

Description : Vasu said to his son, "I was as old as you at the time of your birth". If vasu’s age is 76 years now, the son's age ten years back was: a)14 years b)19 years c)33 years d)28 years

Last Answer : D Let the son's present age be x years. Then, (76 - x) = x 2x = 76 x = 38 Son's age 10 years back (38-10) = 28 years

The total age of x and y is 48 years more than the total age of y and z. z is how many year younger than x a) 44 b) 24 c) 96 d) 48

Description : The total age of x and y is 48 years more than the total age of y and z. z is how many year younger than x a) 44 b) 24 c) 96 d) 48

Last Answer : D Given that x+y = 48 + y+ z x – z= 48 + y – y = 48 z is younger than x by 48 years

The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10

Description : The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10

Last Answer : Answer: A

Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)

In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Description : In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Last Answer : Let current age of Ram and his son be R,S (R + 10) = 3(S + 10) [2 times older = 3 times the age] R = 3S + 20 (R - 5) = 9(S - 5) 3S + 20 – 5= 9S – 45 3S + 15 = 9S – 45 or S = 10., R = 50 sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66. Answer: b)

Five years hence , the age of Ram will be 10 more than the two thirds of Ravi’s age . Assume the present ages of Ram and Ravi as x and y respectively . Express the statement in the form of a linear equation in two variables. -Maths 9th

Description : Five years hence , the age of Ram will be 10 more than the two thirds of Ravi’s age . Assume the present ages of Ram and Ravi as x and y respectively . Express the statement in the form of a linear equation in two variables. -Maths 9th

Last Answer : answer:

A container contains a mixture of two liquids P and Q in the ratio 7 : 5. When 9 litres of mixture are drawn off and the container is filled with Q, the ratio of P and Q becomes 7 : 9. How many litres of liquid P was contained in the container initially? a) 12 b) 21 c) 93 d)17 e) None

Description : A container contains a mixture of two liquids P and Q in the ratio 7 : 5. When 9 litres of mixture are drawn off and the container is filled with Q, the ratio of P and Q becomes 7 : 9. How many litres of liquid P was contained in the container initially? a) 12 b) 21 c) 93 d)17 e) None 

Last Answer : B Let initial quantity of P in the container be 7x and initial quantity of Q in the container be 5x Now 9 litres of mixture is drawn off from the container. Quantity of P in 9 litres of the mixture drawn off ... = 7 : 9 x=16* 21/4*28 Litres of P contained in the container initially =7x = 21

The ratio between the present ages of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years? A.5 : 7 B.7 : 8 C.8 : 7 D.Data inadequate E.None of these

Description : The ratio between the present ages of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years? A.5 : 7 B.7 : 8 C.8 : 7 D.Data inadequate E.None of these

Last Answer : Answer – B (7 : 8) Explanation – Let A’s age and B’s age be 6X years and 7X years respectively Then, 7X – 6X = 4 X = 4 Required ratio = (6X + 4) : (7X + 4) = (6*4+4) : (7*4 +4) =28 : 32 = 7 : 8

if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be the sum of their ages 8 years from now?

Description : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be the sum of their ages 8 years from now?

Last Answer : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be ... years from now? A. 82 B. 97 C. 75 D. 94

Seven years ago the ratio of the ages of P and Q (in years) was ` 7 : 6` . Which of the following cannot be the ratio of their ages 6 years from now ?

Description : Seven years ago the ratio of the ages of P and Q (in years) was ` 7 : 6` . Which of the following cannot be the ratio of their ages 6 years from now ?

Last Answer : Seven years ago the ratio of the ages of P and Q (in years) was ` 7 : 6` . Which of the following cannot be the ... : 14` C. ` 13 : 12` D. ` 16 : 15`

The age of vaishu is 18 times that of her daughter raiza. If the age of raiza is 6years, what is the age of vaishu? a) 98 b) 110 c) 90 d) 108

Description : The age of vaishu is 18 times that of her daughter raiza. If the age of raiza is 6years, what is the age of vaishu? a) 98 b) 110 c) 90 d) 108

Last Answer : D vaishu’s present age = x vaishu’a age is 18 times her daughter’s age. Daughter’s age = 6. Therefore, 18 times of 6 = x 18 x 6 = x x= 108 years = vaishu’s age.

2 male, 6 female, and 8 girls can do a work in 192 hrs, 4 male and 16 girls can do it in 160 hrs, 4 male and 6 female can do it in 240 hrs.10 male and 24 girls can do it in. a) A.87 3/ 11 hrs b) B.78 4 /11 hrs c) C.88 6 /12 hrs d) 80 4 /5 hrs

Description : 2 male, 6 female, and 8 girls can do a work in 192 hrs, 4 male and 16 girls can do it in 160 hrs, 4 male and 6 female can do it in 240 hrs.10 male and 24 girls can do it in. a) A.87 3/ 11 hrs b) B.78 4 /11 hrs c) C.88 6 /12 hrs d) 80 4 /5 hrs

Last Answer : A Let 1 males 1 hr work = x 1 female 1 hour work = y 1 girl 1 hour work = z Then 2x + 6y + 8z = 1/192 ------>1 4x + 16z = 1/160 --------->2 4x + 6y = 1/240 ------------->3 Adding 2 and ... 1/192 + 1/160 =(5+6) / 960 = 11/960 10 male and 24 girls can do work in 960/11 hrs i.e., 87 3 /11 hrs

The ratio of the present ages of Rupa and her daughter is ` 7 : 3`. When Rupa was 26 years old, her daughter was 6 years old . Find the present age of

Description : The ratio of the present ages of Rupa and her daughter is ` 7 : 3`. When Rupa was 26 years old, her daughter was 6 years old . Find the present age of

Last Answer : The ratio of the present ages of Rupa and her daughter is ` 7 : 3`. When Rupa was 26 years old, ... old . Find the present age of Rupa. (in years)

if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be the sum of their ages 5 years from now?

Description : if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be the sum of their ages 5 years from now?

Last Answer : if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be ... years from now? A. 90 B. 98 C. 92 D. 87