Description : Arun started a business with Rs. 40,000 and is joined afterwards by Arul with Rs.60, 000. After how many months did Arul join if the profits at the end of the year are divided equally? a) 3 b) 4 c) 5 d) 6 e) 2
Last Answer : b Suppose, Arul joined after x months. Then, 40000 * 12 = 60000 * (12 – x) => 48 = 72 - 6x => 6x = 24 → x = 4
Description : Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. ... 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13
Last Answer : a Part of the tank filled by pipe P in 1 minute = 1 / 40 Part of the tank filled by pipe Q in 1 minute = 1 / 15 Part of the tank filled by pipe R in 1 minute = 1/ 30 Here we have to find the proportion of ... together in 5 minute = 5 1/8 = 5/ 8 Required proportion = (1/3) / ( 5/8) = 8 / 15
Description : Simple interest on a certain sum of money for 4 years at 5% per annum is half the compound interest on Rs. 8000 for 2 years at 10% per annum. The sum placed on simple interest is: a) Rs.4200 b) b)Rs.4250 c) Rs.5250 d) Rs.5200 e) Rs.4000
Last Answer : a C.I = 8000 * (1+(10/100))2 –8000 = 8000 *110/100 * 110/100 – 8000 = 9680 – 8000 = Rs.1680 Therefore, S.I = C.I / 2 = 1680 / 2=Rs. 840 840 = sum * 4 * 5 / 100 :. Sum = Rs.(840 * 100)/ (4 *5) = Rs.4200
Description : On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39
Last Answer : b Profit = (S.P of 25 balls) - (C.P of 25 balls) = 1015 - (C.P of 25 balls) Given that Profit = (C.P of 10 balls) => 1015 - (C.P of 25 balls) = (C.P of 10 balls) => (C.P of 25 balls) + (C.P of 10 balls) = 1015 => C.P of 35 balls = 1015 => C.P of 1 ball=1015 / 35 = Rs. 29
Description : Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am
Last Answer : e Suppose they meet z hours after 6 a.m. Distance covered by X in z hours = 25× z km. Distance covered by Y in (z - 2) hours = 35(z - 2) km. Therefore 25z + 35(z- 2) = 170 60z = 240 x = 4. So, they meet at 10 a.m.
Description : A boat running downstream covers a distance of 20 km in 5 hours while for covering the same distance upstream, it takes 10 hours. What is the speed of the stream? a) 2km/hr b) 4km/hr c) 1km/hr d) 1.5 km/hr e) None of these
Last Answer : c Rate of downstream=(20 / 5 ) kmph= 4kmph Rate of upstream =( 20/10) kmph= 2kmph Therefore Speed of the stream= (1/2)(4 - 2) kmph= 1 kmph
Description : Kathir and Anand can do a work in 20 days and 30 days respectively. Kathir started the work and left after 4 days. Anand took over and completed the work. In how many days was the total work completed? a) 28 days b) 20 days c) 23 days d) 25 days e) 26 days
Last Answer : a Kathir’s one day’s work= 1/20 Kathir’s 4 day’s work =4* (1/20) = 1/5 Work left= 1-1/5 = 4 /5 Anand’s one day’s work= 1/30 Anand can do work in = (4/5) *(30/ 1) = 24 days So total days = 24+4 = 28 days
Description : Ten years ago, Khush was thrice as old as Sam was but 10 years hence, he will be only twice as old. Find Khush’s present age? A.30 B.35 C.40 D.36 E.None of these
Last Answer : Answer - A (30) Explanation - Let Khush's present age be x years and Sam's present age be y years Then, according to the first condition, x - 10 = 3(y - 10) or, x - 3y = -20 ..(1) Now. Khush's age ... (1) and (2), we get x = 70 and y = 30 Khush's age = 70 years and Sam's age = 30 years
Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these
Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)
Description : A letter lock consists of four rings each marked with five different letters. The number of distinct unsuccessful attempts to open the lock is at the most -. a) 625 b) 676 c) 576 d) 624 e) 575
Last Answer : d Since each ring consists of five different letters, the total number of attempts possible with the four rings is =5 * 5 * 5 * 5 = 625. Of these attempts, one of them is a successful attempt. Maximum number of unsuccessful attempts = 625 - 1 = 624.
Description : P walks around a circular field at the rate of two rounds per hour while Q runs around it at the rate of eight rounds per hour. They start in the opposite direction from the same point at 6.45 a.m. They shall first cross each other at? a) 6.45 a.m b) 6.50 a.m c) 7.51 a.m d) 6.51 a.m e) 7.45 am
Last Answer : d Since P and Q move in the opposite direction along the circular field, so they will first meet each other when there is a difference of one round between the two. Relative speed of P and Q = 8+2 = 10 rounds per hour. Time ... 1/10 hr = 6 min. 6 Hrs 45 min + 6 min = 6 hrs 51 min i.e, 6.51 a.m
Description : 10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. ... 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above
Last Answer : Let current year be 2015 In 2005, sum of all ages = 25 45 = 1125 In 2015, sum of all ages = 1125 + (25 10) = 1375 Now 60 year old teacher was replaced by a 54 year old teacher. So we need ... all ages in 2015 considering the replacement teacher = 1375 - 6 = 1369 Average = 1369/25 = 54.76 Answer: c)
Description : A and B are 3 years and 2 years old respectively. Their father is 40 years. After how many years, father’s age would be twice of combined age of A and B? a) 5 years b) 10 years c) 15 years d) 20 years e) None of these
Last Answer : Father’s age = 40 years. Children’s combined age = 3 + 2= 5 years Double of their ages = 2 × 5 = 10 years Difference between father’s age and combined age = 40 – 10 = 30 years required time = 1/ (2 + 1) × 30 = 10 years Answer: b)
Description : X says to Y, I am 3 times as old as you were 3 years ago .How old is X? I. Y s age 17 years from now is same as X's present age. II. X's age nine years from now is ... with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question
Last Answer : Let the current ages of X and Y be a and b respectively From the question: A=3(a-b) From statement I: A=b + 17 B = a-17 Therefore, a = 3(a-17-3) a=3a-60 2a=60 A=30 Hence, X ... a+9)/3 Substituting this in first equation, A=a+9-9 Hence, no result Therefore, statement I alone is sufficient Answer :a
Description : At present, a mother is 3 times older than her son. After 5 years, the sum of their ages will be 70 years. The age of the mother after 10 years will be (A) 40 (B) 55 (C) 45 (D) 60
Last Answer : 45
Description : A father said to his son, “I was as old as you are at present at the time of your birth.” If the father’s age is 38 years now, the son’s age five years back was: A.14 B.19 C.38 D.40 E.None of these
Last Answer : Answer – A (14) Explanation – Let son’s present age be X years. Then, (38 – X) = X 2X = 38 X = 19 Son’s age 5 years back = (19 – 5) years = 14 years
Description : Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these
Last Answer : Sum of present ages of A, B and C is 72 years. sum of their ages (4 years ago) = 72 – (3 × 4) = 60 years 4 years ago, ratio of ages of A, B and C was 1 : 2 :3. A’s age, 4 years ago = (1/6) ×60 = 10 years A’s present age = 10 + 4 = 14 years Answer: d)
Description : In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these
Last Answer : Let current age of Ram and his son be R,S (R + 10) = 3(S + 10) [2 times older = 3 times the age] R = 3S + 20 (R - 5) = 9(S - 5) 3S + 20 – 5= 9S – 45 3S + 15 = 9S – 45 or S = 10., R = 50 sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66. Answer: b)
Description : The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these
Last Answer : Difference in two sums = 80- 36 = 44 Age of both are increased by 44/2 = 22 years Difference in ages of father and son = 22 years sum of present ages of father and son = 36 years Son’s present age = 1/2 × (36 - 22) = 7 years Answer: b)
Description : How do I compute the financial advantages and disadvantages of taking Social Security as soon as I'm eligible?
Last Answer : I receive a statement every year from Social Security 2 months before my birthday. It tells me what my payment will be at age 62 if I stop working then. It tells me what the payment will be at full ... It also tells me what I would make if I became disabled at this time. Is this what you mean?
Description : In the 8085A Microprocessor, arithmetic and logical operations are performed through which of the following? A) Stack B) ALU C) I/O D) Register
Last Answer : In the 8085A Microprocessor, arithmetic and logical operations are performed through which of the following? A) Stack B) ALU C) I/O D) Register
Description : If 6 years are subtracted from the present age of Anuj and the remainder is divided by 18, then the present age of his grandson Gopal is obtained.If Gopal is 2 years younger to Mohan whose age is 5 years, then what is the age of Anuj? A.44 B.60 C.80 D.92
Last Answer : Answer : B (60) Explanation - Let Anuj's age be X Gopal is 2 years younger than Mohan, so Gopal is 3 years (i.e 5 - 2 = 3) If Arun had born 6 years before, his age would had been X - 6. As per the ... as that of Gokul's age. i.e. (X - 6) /18= 3 X-6 =3 x 18 x = 60
Description : One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these
Last Answer : Answer - B (16) Explanation - Let one year ago Sam's age be 4X years And, Ash's age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam's age = (4X + 2) ... = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.
Description : 3 years ago, the average of a family of 5 members was 17 years. A baby having been born, the average age of the family is the same today. The present age of the baby is: A.5 years B.2 years C.1 year D.4 years E.None of these
Last Answer : Answer – B (2 years) Explanation – Total age of 5 members, 3 years ago = (17 x 5) years = 85 years Total age of 5 members now = (85 + 3 x 5) years = 100 years Total age of 6 members now = (17 x 6) years = 102 years Age of the baby = (102 – 100) years = 2 years
Description : The average age of the students in a class is 14. The average age of half of the students in that class and the class teacher is 16. The average age of the remaining half of the students is 15. What is the number of students in that class? a) 20 b) 70 c) 80 d) Cannot be determined e) None of these
Last Answer : Because total no. of students is not known we cannot find the answer. Answer: d)
Description : The average age of four boys, five years ago was 9 of all the five is 15 years. The present age of the new boy is 1. 22 years 2. 24 years 3. 21 years 4. 18 years 5. 19 years
Last Answer : 5; Five years ago the average age of 4 boys = 9 years The present average age of 4 boys = 9+5 = 14 So the present age of new boys = 15 + 4 x 1 = 19 years
Description : A is 2 years older than B who is twice as old as C. If sum of ages of A, B and C is 37 years, find the age of A. a) 7 years b) 9 years c) 14 years d) 16 years e) None of these
Last Answer : Let the age of C be x years. Then age of B = 2x and age of A = 2x + 2 sum of ages of A, B and C = (2x + 2) + (2x) + x = 37 (5x + 2) = 37 x = 7 Age of A = 2x + 2 = 16 years Answer: d)
Description : Four years ago, the average of a 4 member family was 40 years. 3 years ago, a boy got married to a 23 years old girl, and they had a baby boy last year. what is the average of the family 2 years from now assuming no ... leaves from the family in the next 2 years. a) 40 b) 42.5 c) 36.5 d) 34 e) 35.8
Last Answer : Four years ago, sum of all the family members age = 4× 40 = 160 three years ago, sum of all the family members age = 164 + 23 = 187 last year, sum = 197 (187 + 5 + 5) two years from now, sum = 197 + 18 = 215 hence, average = 215/6 = 35.8 Answer: e)
Description : Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these
Last Answer : Let the required time be x years. then (50+x) = 2 (18 + x) = 50 + x = 36 + 2x x = 14 years. Alternative method : Double of B’s age = 2 × 18 = 36 years difference between A’s present age and double of B’s age = 50 – 36= 14 years. A will be twice of B’s age after 14 years. Answer: a)
Description : Anil is twice as old as Sunita. Three years ago, he was three times as old as Sunita. The present age of Anil is (A) 6 years (B) 8 years (C) 12 years (D) 16 years
Last Answer : Answer: C
Description : If the price of Mango is Rs. 130 per kg, Apple is Rs. 140 per kg and Orange is Rs. 80 per kg, Grapes is Rs. 115 per kg and Guava is Rs. 68 per kg at both vendor A and B then what is the difference between ... at vendor A and that at Vendor B? 1) Rs. 72000 2) Rs. 55000 3) Rs. 64000 4) Rs. 51000
Last Answer : 4) Rs. 51000
Description : The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these
Last Answer : Sum of their ages, 3 years ago = 46 – (2 × 3) = 40 years sunil’s age, 3 years ago = 1/5 × 40 = 8 years sunil’s present age = 8 + 3 = 11 years Answer: c)
Description : Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these
Last Answer : Sum of their present ages = 60 years sum of their ages, 5 years hence = 60 + (5 × 2) = 70 years. after 5 years, ratio of ages of A and B will be 3 : 4. A’s age after 5 years = (3/7) × 70 = 30 years A’s present age = 30 – 5 = 25 years Answer: a)
Description : A person travels from P to Q at a speed of 40 kmph and returns by increasing his speed by 50%. What is his average speed for the both the trips? A.35 kmph B.4o kmph C.48 kmph D.55 kmph E.None of these
Last Answer : Answer – C (48 kmph) Explanation – Speed on return trip = 150% of 40 = 60 kmph Average speed = [2 x 40 x 60] / [40 + 6]km/hr =4800/100km/hr = 48 km/hr.
Description : The present age of Roshan’s father is four times Roshan’s present age. Five years back, Roshan’s father seven times as old as Roshan was at that time. What is the present age of Roshan’s father? a) 43 years b) 67 years c) 40 years d) 69 years e) 72 years
Last Answer : Present age of Roshan – x Present age of Roshan’s father = 4x Five years ago, Roshan’s father age = 7 * Ravi’s age 4x – 5 = 7(x – 5) x = 10 Present age of Roshan’s father = 4x = 40 years. Answer: c)
Description : A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr
Last Answer : Total time taken = (160/64) + (160/80) = 9/2 hrs. Avg Speed – 320 × (2/9) km/hr = 71.11km/hr Answer: c)
Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63
Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c
Description : A,B are start walking around a Circular park of radius 70m. They start at the same point, and A goes clockwise at 10m/s, while b goes anti-clockwise at 20m/s.How many times will they cross each other at the starting point if they walk for 30 minutes? a) 20 b) 40 c) 60 d) 80 e) None of the above
Last Answer : Radius = 70m, So circumference = 2 (22/7) 70 =440m Relative speed = 10 +20 = 30m/s They will meet everytime at the starting point when the distance covered by both put together is a multiple of 440 ... =1800/44 =40.9 So they will meet 40 times (we need to ignore the decimal part). Answer : b
Description : A,B are start walking around a Circular park of radius 70m. They start at the same point, and A goes clockwise at 10m/s, while b goes anti-clockwise at 20m/s. How many times will they cross each other at the starting point if they walk for 30 minutes? a) 20 b) 40 c) 60 d) 80 e) None of the above
Description : One-fifth of a number is equal to 5/8th of another number. If 35 is added to the first number, it becomes four times of the second number. Find the second number. 1. 39 2. 70 3. 40 4. 25 5. None of these
Last Answer : Answer- 3(40) Explanation:- (1/5)x =(5/8)y………..1 if 35 is added to first no. , x + 35= 4y so,x= 4y -35 put in eq 1… (1/5)( 4y-35) = (5/8)y y=40 =second number
Description : Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these
Last Answer : Present ratio of Deepa&Subha = 5 : 6 Six year hence ratio of Deepa&Subha = 6 : 7 Difference between ratio = 1 Difference in ages between present & future = 6 year. 1 ratio=6 yrs & SUBHA's age = 6 6 =36 year 5 year ago ... = 7 6 = 42 year B's age 5 year ago = 42-6-5 = 42-11 = 31 year Answer: d)
Description : In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65
Last Answer : d) 85
Description : The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C ... 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg
Last Answer : A+B+C = 3×84=252 A+B+C+D= (4×80)=320 D = (320-252)=68 and E = (68+3)=71 Now, B+C+D+E = (4×79)=316 B+C+D=(316-71)=245 kg So, A = (320-245)=75 kg Answer: c)
Description : At the time of marriage, a man was 6 years older to his wife. 12 years after their marriage, his age is 6/5 times the age of his wife. What was wife’s age at the time of marriage? a) 18 years b) 24 years c) 30 years d) 36 years e) None of these
Last Answer : ratio of their ages, 12 years hence = 6 : 5 Difference in ages = 1 ratio = 6 years wife’s age (12 years hence) = 5 ratio = 5 × 6 years = 30 years wife’s age at the time of marriage = 30 – 12 = 18 years Answer: a)
Description : Father is aged three times more than his son Mohit. After 8 years, he would be two and a half times of Mohit’s age. After further 8 years, how many times would he be of Mohit’s age? A.4 B.2 C.2.5 D.3 E.None of these
Last Answer : Answer – B (2) Explanation – Let Monit’s present age be X years. Then, father’s present age = (X + 3X) years = 4X years. (4X + 8) =5/2 x (X + 8) 8X + 16 = 5X + 40 3X = 24 so, X=8 Hence, required ratio = (4X + 16) / (X + 16)=48 / 24 = 2
Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70
Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.
Description : The father’s age 7years ago was 11 times the age of his daughter. At present the father’s age is 7 times that of his daughter. Find the daughter’s present age. a) 17.5 b) 18.2 c) 23 d) None
Last Answer : A daughter’s present age = x At present the father’s age is 7 times that of his daughter i.e., Father’s present age = 7x. ‘Father’s age 7 years ago was 11 times the age of his daughter’ (7x – 7) = 11 * (x – 7) x = 17.5 years, The daughter’s present age = 17.5 years
Description : Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: A.40 m B.55 m C.65 m D.50 m E.None of these
Last Answer : Answer- D (50) Explanation – Relative speed= total lengths/time (46-36) x 5/18 = [L + L ] / 36 10 x (5/18) x36 x (1/2)= L L=50 m