P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each one of them finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60

P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each one of them finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60 
by

1 Answer

Answer :

B

Time taken by (P + Q) to finish the job = 24days.

(P + Q)’s 1 day’s job = 1/24

Time taken by (Q +R) to finish the job = 30days.

(Q + R)’s 1 day’s job = 1/30

Time taken by (R + P) to finish the job = 40 days.

(R + P)’s 1 day’s job = 1/40

Therefore, 2(P + Q + R)’s 1 day’s job = (1/24+1/30+1/40)

=(5+4+3)/120

=12/120=1/10

⇒ (P + Q + R)’s 1 day’s job = ½*1/10 =1/20

Therefore, P, Q, R together can finish the job in 20 days.

Now, P’s 1 day’s job

= {(P + Q + R)’s 1 day’s job } - {(Q + R)’s 1 day’s job }

= (1/20 -1/30)=2/60=1/30

Hence, P alone can finish the job in 30 days.

Q’s 1 day’s work

{(P + Q + R)’s 1 day’s job } - {(R + P)’s 1 day’s job

= (1/20 -1/40)=1//40

Hence, Q alone can finish the job in 40 days.

R’s 1 days work

= {(P + Q + R)’s 1 day’s job } - {(P + Q)’s 1 day’s job }

= (1/20 -1/24)=1/120

Hence, R alone can finish the job in 120 days.
by

Related questions

P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Description : P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Last Answer : B Work done by P,Q & R in 8 days = 1/20 * 8 =2/5 Remaining work = (1 - 2/5) = 3/5 Now 3/5 work is done by Q & R in 20 days Whole work will be done by Q & R in(20*5/3) =100/3 days (P+Q+R ... (Q+R)'s 1 day work =1/20 - 3/100 =5-3/100 =2/100 =1/50 P alone could complete the work in 50 days..

Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Description : Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Last Answer : D Work done by pranesh in 4 days = 1/60 *4 =1/15 Remaining work = 1-1/15 =(15 - 1)/15 =14/15 Now 14/15 work done by sarvesh in 28 days Whole work will be done by sarvesh in(28*15 /14) = 2* 15 =30 ... 's work = 1/60 + 1/30 = (1+2) /60 = 3/60 =1/20 Hence both will finish the work in 20 days

P and Q undertake to do a piece of job for Rs.1200. P alone can do it in 12 days while Q alone can do it in 16 days. With the help of R , they finish it in 6 days. Find the share of P,Q & R. a) 400,600,200 b) 200,400,600 c) 450,400,250 d) 600,450,150

Description :  P and Q undertake to do a piece of job for Rs.1200. P alone can do it in 12 days while Q alone can do it in 16 days. With the help of R , they finish it in 6 days. Find the share of P,Q & R. a) 400,600,200 b) 200,400,600 c) 450,400,250 d) 600,450,150

Last Answer : D R;s 1 day work = 1/6 – (1/12 + 1/16) =1/6 – 1/12 – 1/16 = (8-4-3)/48 = 1/48 P:Q:R = ratio of 1 day work = 1/12:1/16 : 1/48 =4:3:1 P’s share = Rs(1200*4/8) =Rs.600 Q’s share = Rs(1200 * 3/8) =Rs.450 R’s share = Rs(1200 * 1/8) =Rs.150

A officer undertakes to complete a job in 250 days. He employs 300 male for 50 days and they complete 1/2 of the work . He then reduces the number of male to 100, who work for 120 days, after which there are 20 days holidays. How many male must be employed for the remaining period to finish the work? a) 25 b) 50 c) 45 d) 35

Description : A officer undertakes to complete a job in 250 days. He employs 300 male for 50 days and they complete 1/2 of the work . He then reduces the number of male to 100, who work for 120 days, after which there ... male must be employed for the remaining period to finish the work? a) 25 b) 50 c) 45 d) 35

Last Answer : B 300 male in 50 days do = 1/2work 1 male in 1 day does = ½*1/50*1/300 work 100 male in 120 days do = ½ *1/50*1/300 *100*120 =2/5 work Total work done = ½ + 2/5 =(5+4)/10=9/10 ... is done in 50 days by 300 male 1/10 work is done in 60 days by =300*50*1*2/10*60 =50 male

P and Q finished a work in 36 days; Q and R can do it in 60 days; P and R can do it in 45 days. In what time can P alone do it. a) 30 days b) 60 days c) 90 days d) 120 days

Description : P and Q finished a work in 36 days; Q and R can do it in 60 days; P and R can do it in 45 days. In what time can P alone do it. a) 30 days b) 60 days c) 90 days d) 120 days

Last Answer : B (P+Q)'s 1 day work = 1/36 ---1 (Q+R)'s 1 day work = 1/60 ----2 (P+R)'s 1 day work = 1/45 ----3 Adding 1 & 2 & 3 we get 2(P+Q+R)'s 1 day work = 1/36 + 1/60+ 1/45 =(5+3+4)/180 = 12/ ... +R)'s 1 day work - (Q+R)'s 1 days work = 1/30 - 1/60 = 2-1/60 = 1/60 P alone can do the work in 60 days.

P and Q together can complete a job in 30 days. Q and R together can complete the same job in 40 days. P and R together can complete the same job in 40 days. What is the respective ratio of the number of days taken by P when completing the same job alone to the number of days taken by R when completing the same job alone? a) A.2:5 b) B.1:2 c) C.3:4 d) D.2:3

Description : P and Q together can complete a job in 30 days. Q and R together can complete the same job in 40 days. P and R together can complete the same job in 40 days. What is the respective ratio of the number of days taken by P ... R when completing the same job alone? a) A.2:5 b) B.1:2 c) C.3:4 d) D.2:3

Last Answer : B Efficiency of P and Q= 1/30 per day ___________1 ⇒ Efficiency of Q and R = 1/40 per day_________2 ⇒ Efficiency of R and P = 1/40 per day _________3 Taking equation 2 and 3 together ⇒ Q + R = ... 120 days he they work alone. ⇒ Ratio of number of days in which P and R can complete the job 1:2.

X does half as much work as Yand Z does half as much work as X and Y together. If Z alone can finish the work in 120 days, then together ,all will finish the work in ? a) 14 1/2 b) 40 c) 24 1/2 d)17 1/3

Description : X does half as much work as Yand Z does half as much work as X and Y together. If Z alone can finish the work in 120 days, then together ,all will finish the work in ? a) 14 1/2 b) 40 c) 24 1/2 d)17 1/3

Last Answer : B Z alone can finish the work in 120 days. As given Z does half as much work as X and Y together => (X + Y) can do it in 60 days (X+ Y)s 1 days wok = 1/60. X's 1 days work : Y's 1 days Work = 1 ... (1/90) + (1/120) =(2+4+3)/360 =9/360 = 1/40 All the three together will finish it in 40 days

M do a piece of work in 45 days and N can finish it in 40 days. They work together for 5 days and then M leaves. In how many days will N finish the remaining work? a) 30 5/9 b) 29 4/9 c) 31 3/5 d) 29 5/9

Description : M do a piece of work in 45 days and N can finish it in 40 days. They work together for 5 days and then M leaves. In how many days will N finish the remaining work? a) 30 5/9 b) 29 4/9 c) 31 3/5 d) 29 5/9

Last Answer : A Time taken by M to finish the work = 45 days. M's 1 day's work = 1/45 Time taken by N to finish the work = 40 days. N's 1 day's work = 1/40 (M + N)'s 1 day's work = (1/40+1/45) = ... be done by N in (55/72*40) days = 30and 5/9 days. Hence, the remaining work is done by B in 30 and 5/9 days.

Adam and Smith are working on a project. Adam takes 18 hrs to type 108 pages on a computer, while Smith takes 15 hrs to type 120 pages. How much time will they take, working together on two different computers to type a project of 360 pages? a) 23 hrs 24 min b) 45 hrs 42 min c) 25 hrs 42 min d) 42 hrs 45 min

Description : Adam and Smith are working on a project. Adam takes 18 hrs to type 108 pages on a computer, while Smith takes 15 hrs to type 120 pages. How much time will they take, working together on two different computers to type a ... ? a) 23 hrs 24 min b) 45 hrs 42 min c) 25 hrs 42 min d) 42 hrs 45 min

Last Answer : C Number of pages typed by Adam=108 Number of pages typed by Adam in 1 hour = 108/18=6 Number of pages typed by Smith =120 Number of pages typed by Smith in 1 hour = 120/15 =8 Number of pages typed by both in ... (6 + 8) = 14 Time taken by both to type 360 pages, = (360 * 1/14) =25 hrs 42 min

Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Description : Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Last Answer : C Karthik’s 1 day work : Raghu’s 1 day work = 2:1 (Karthik + Raghu)’s 1 day work = 1/42 Divide 1/42 in the ratio 2:1 Therefore karthick’s 1 day work = 1/42 * 2/3 =1/63 Hence karthik alone can finish the work in 63 days.

P, Q and R together earn Rs.420 per day, while P and R together earn Rs.296 and Q and R together earn Rs.164. The daily earning of R is : a) Rs.50 b) Rs.80 c) Rs.40 d) Rs.60

Description : P, Q and R together earn Rs.420 per day, while P and R together earn Rs.296 and Q and R together earn Rs.164. The daily earning of R is : a) Rs.50 b) Rs.80 c) Rs.40 d) Rs.60

Last Answer : D (P+Q+R)’s earning = Rs. 420 (P+R)’s earning=Rs 296 (Q+R)’s earning=Rs 164 Q’s daily earning = Rs. (420 ⎯296) = Rs.124 P’s daily earning = Rs. (420 ⎯164) = Rs.236 Now (P+Q)’s earning=Rs 360 R’s daily earning = Rs. [420 ⎯360] = Rs.60

Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Description : Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Last Answer : C Praneetha's 10 day's work + Pooja 14 day's work + Priya's 26 days work = 1 (Praneetha's +pooja's) 10 day's work + (pooja + priya)'s 4 day's work +priya's 22 days work = 1 =>10/24 + 4/32 + priya' ... 13/24 =11/24 Priya's 1 day's work = 11/24 * 1/22 =1/48 Priya can finish the work in 48 days.

Rishwi can finish a work in 6 days working 4 hours a day. Dhiviksha can complete the same work in 4 days working 5 hrs a day. If both rishwi and dhiviksha work together, working 4 hrs a day, in how many days can they finished the work? a) 30/11 b) 11/120 c) 11/30 d) 30/13

Description : Rishwi can finish a work in 6 days working 4 hours a day. Dhiviksha can complete the same work in 4 days working 5 hrs a day. If both rishwi and dhiviksha work together, working 4 hrs a day, in how many days can they finished the work? a) 30/11 b) 11/120 c) 11/30 d) 30/13

Last Answer : A Rishwi can complete the work in (6*4) = 24 hrs Dhiviksha can complete the work in (4*5) = 20 hrs Rishwi's 1 hr work = 1/24 Dhiviksh's 1 hr work = 1/20(Rishwi and dhivikasha)'s 1 hr work = (1/24 ... fininsh the work in (120/11)hrs Number of days of 4 hrs each = 120/11*1/4 =120/44 =30/11 days

Arfath is thrice as good workman as deekshith and together they finish a piece of work in 27 days. In how many days will arfath alone finish the work? a) 9 days b) 10 days c) 11 days d)12 days

Description :  Arfath is thrice as good workman as deekshith and together they finish a piece of work in 27 days. In how many days will arfath alone finish the work? a) 9 days b) 10 days c) 11 days d)12 days

Last Answer : A Arfath’s 1 days work = 3 Deekshith 1 day’s work = 1 Arfath 1 day’s work : Deekshith 1 days work = 3:1 (Arfath + deekshith )’s 1 day’s work = 1/27 Divide 1/27 in the ratio 3:1 Arfath’s 1 days work = 1/27 *3/1 = 3/27 =1/9 Hence Arfath’s alone can finish the work in 9 days

8 men and 8 boys can finish a piece of work in 10 days. 9 women and 7 boys can finish the same work in 10 days. Also 7 men and 6 women can finish the same work in 10 days. In how many days 1man, woman and one boy can finish the work, at their double efficiency? a) 25 days b) 20 days c) 15 days d) 10 days

Description : 8 men and 8 boys can finish a piece of work in 10 days. 9 women and 7 boys can finish the same work in 10 days. Also 7 men and 6 women can finish the same work in 10 days. In how many days 1man, ... boy can finish the work, at their double efficiency? a) 25 days b) 20 days c) 15 days d) 10 days

Last Answer : A Efficiency of 8 men and 8 boys = 10% Efficiency of 9 women and 7boys = 10% Efficiency of 7 men and 6 women = 10% So, Efficiency of 15 men, 15women and 15boys = 30% So, efficiency of 1 man ... efficiency Efficiency of 1 man, 1 woman and 1 boy = 4% Required number of days = 100/4=25 days

A task is done by 46 persons not all of them have the same capacity to task. Every day exactly 2 persons, do the task with no pair of persons working together twice. Even after all possible pairs have worked once, all the persons together works for two more days to finish the task. Find the number of days in which all the persons together will finish the whole task? a) 44 b) 45 c) 46 d) 47

Description : A task is done by 46 persons not all of them have the same capacity to task. Every day exactly 2 persons, do the task with no pair of persons working together twice. Even after all possible pairs have worked ... in which all the persons together will finish the whole task? a) 44 b) 45 c) 46 d) 47

Last Answer : D 46 persons task in pairs, with no same pair of persons working together. Each person will be working with other 45 which means each persons will work for 45 days in pair. Let the time taken by each ... +1/T46)= 1/47 If all the persons work together they will finish the whole task in 47 days.

A and B together can complete a work in 24 days. A alone can complete it in 40 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work? a) 24 days b) 15 days c) 21 days d) 19 days

Description : A and B together can complete a work in 24 days. A alone can complete it in 40 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work? a) 24 days b) 15 days c) 21 days d) 19 days

Last Answer : A B’s 1 day’s work = (1/24 -1/40) =(5-3)/120 =2/120=>1/60 Now, (A + B)’s 1 day’s work = (1/40 +1/60) =(3+2)/120 =5/120 So, A and B together will complete the work in 120/5 = 24 days.

Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Description : Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Last Answer : A Let sai's 1 day work = x Ram's 1 day work = y Then x+y = 1/10 ===>1 and 2x +2y /3 = 1/6 (6x+2y )/3 = 1/6 6x + 2y =1/2 ====>2 Multiply 1 by 6 =>6x+6y = 6/10 2 = ... /10 - 1/40 = 4-1/10 =3/40 Sai's 1 day work = 3/40 So sai alone could complete the work in 40/3 days.

X and Y can do a job in 24 days, Y & Z can do the same job in 36 days. X,Y,Z together can finish it in 18 days. X and Z together will do it in. a) 24 b) 36 c) 12 d) 26

Description : X and Y can do a job in 24 days, Y & Z can do the same job in 36 days. X,Y,Z together can finish it in 18 days. X and Z together will do it in. a) 24 b) 36 c) 12 d) 26

Last Answer : A (X+Y+Z) s 1 day work =1/18 (X+Y)'s 1 day work = 1/24 (Y+Z)'s 1 day work = 1/36 (X+Z)'s 1 day work = 2[X+Y+Z]'s 1 day work - [(X+Y)'s 1 day work + (Y+Z)'s 1 day work]= 2 [1/18]- (1/24 + ... /24 + 1/36) = 1/9 -1/24 - 1/36 =(8-3-2)/72 =3/72 = 1/24 So X & Z together will do the work in 24 days

M & N do a certain work in 40 days and 24 days respectively. M started the work alone and then after 8 days N joined him till the completion of the work. How long did the work last? a) 16days b) 18days c) 20 days d) 22 days

Description : M & N do a certain work in 40 days and 24 days respectively. M started the work alone and then after 8 days N joined him till the completion of the work. How long did the work last? a) 16days b) 18days c) 20 days d) 22 days

Last Answer : C Work done by M in 8 days = 1/40*8 =1/5 Remaining work = 1-1/5 = 4/5 (M+N)’s 1 day work = 1/40 + 1/24 =(3+5)/120 =8/120 =1/15 Now 1/15 work is done by M & N in 1 day. So 4/5 work will be done by X and Y is, =15 / 1 * 4/5 =12 days Hence total time taken = 12+8 = 20 days

60 girls can do a work in 48 days. 48 boys can finish the same work in 45 days. What is the ratio between the capacity of a boys and girls? a) 2:1 b) 3:6 c) 2:4 d) 4:3

Description : 60 girls can do a work in 48 days. 48 boys can finish the same work in 45 days. What is the ratio between the capacity of a boys and girls? a) 2:1 b) 3:6 c) 2:4 d) 4:3

Last Answer : D  Total number of girls =60 Total number of boys =48 (60*48) girls can complete the work in 1 day 2880 girls can complete the work in 1 day 1 girls 1 day work =1/2880 (48*45) boys can complete the work ... day 1 boys 1 day work =1/2160 So required ratio =1/2160 : 1/2880 =2880 : 2160 =4:3

8 male can finish a work in 6 days.12 female can complete the same work in 9 days. 6 male and 4 female started working and after 4 days 3 more female joined them. How many days will they now take to complete the remaining work? a) 76/41 days b) 25/62days c) 3/31days d) 4/77days

Description : 8 male can finish a work in 6 days.12 female can complete the same work in 9 days. 6 male and 4 female started working and after 4 days 3 more female joined them. How many days will they now take to complete the remaining work? a) 76/41 days b) 25/62days c) 3/31days d) 4/77days

Last Answer : A 1 male's 1 day work = 1/48 1 female's 1 day work = 1/108 Work done in 4 days = 4 (6/48 +4/108) =4(1/8+1/27) =1/2+4/27 =(27+8)/54 =35/54 Remaining work = (1 - 35/54) = 19/ ... (27+14)/216 =41/216 Now 41/216 work is done by them in 1 day Therefore time taken = 216/41 * 19/54 = 76/41 days

A motor bike tyre has two punctures. The 1st puncture alone would have made the tyre flat in 27 minutes and the 2nd alone would have done it in 18 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat? a) 20 4/3 minutes b) 15 4/7 minutes c) 10 4/5 minutes d) 25 4/3 minutes

Description : A motor bike tyre has two punctures. The 1st puncture alone would have made the tyre flat in 27 minutes and the 2nd alone would have done it in 18 minutes. If air leaks out at a constant rate, how long does it take ... flat? a) 20 4/3 minutes b) 15 4/7 minutes c) 10 4/5 minutes d) 25 4/3 minutes

Last Answer : C 1st puncture made the tyre flat in 27 mins 2nd puncture made the tyre flat in 18 mins 1 minute’s work of both the punctures = (1/27 + 1/18) =(2+3)/54 =5/54 So, both the punctures will make the tyre flat in 54/5 mins =>10 4/5 minutes

6 boys and 5girls can do a job in 8 days. When 7 boys and 10 girls work on the same job, the work gets completed in 5 days. How many days will a boy take to do the job, if he works alone on it? a) A.25 b) B.50 c) C.75 d) D.100

Description : 6 boys and 5girls can do a job in 8 days. When 7 boys and 10 girls work on the same job, the work gets completed in 5 days. How many days will a boy take to do the job, if he works alone on it? a) A.25 b) B.50 c) C.75 d) D.100

Last Answer : D Let the amount of work done by a boy in a day be B′ and the amount of work done by a girl in a day be G′. Therefore, 6 boys and 5 girls will do 6B+5G amount of work in a day. If 6 boys and 5 ... 1/100 i.e. a boy does 1/100th of the work in a day. Hence he will take 100 days to do the work.

Pump A can fill the empty bunker in 6 hours, but due to a leak in the bottom it is filled in 7.5 hours, if the bunker is full and then Pump A is closed then in how many hours the leak can empty it? a) 30 hours. b) 45 hours. c) 50 hours. d) 35 hours.

Description : Pump A can fill the empty bunker in 6 hours, but due to a leak in the bottom it is filled in 7.5 hours, if the bunker is full and then Pump A is closed then in how many hours the leak can empty it? a) 30 hours. b) 45 hours. c) 50 hours. d) 35 hours.

Last Answer : A Efficiency of A = 16.666% Effective of leak = 13.333%when there is leakage So, efficiency of leakage =( Efficiency of A- Effective of leak) =16.666%-13.333%= 3.333% It means due to leakage a full bunker will be empty in 30 hours.

Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6

Description : Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6 

Last Answer : D 6 days before the completion of the work Rakchita left the work means in last 6 days only Shreya has worked alone So, in last 6 days worked done by Shreya = 6*1/42=6/42=1/7 So, the rest = 1-1/7 =6/7 So 6/7work was done by Rakchita and Shreya worked together=6/7*70/10 =420/70=6 days

A bakery P can sold 500 breads in 4 hours, bakery Q can sold the same number of bread in 5 hrs while bakery R can sold them in 6 hrs. All the bakeries are opened at 8 a.m while bakery P is closed at 9 p.m and the remaining 2 bakeries complete their target. Approximately at what time will the work be finished? a) 10 b) 8 c) 12 d) 6

Description : A bakery P can sold 500 breads in 4 hours, bakery Q can sold the same number of bread in 5 hrs while bakery R can sold them in 6 hrs. All the bakeries are opened at 8 a.m while bakery P is closed ... complete their target. Approximately at what time will the work be finished? a) 10 b) 8 c) 12 d) 6

Last Answer : A (P+Q+R)'s 1 hour work = (1/4 +1/5+ 1/6) =(15+12+10)/60 =37/60 Remaining work = 1- 37/60 = 23/60 (Q+R)'s 1 hour work = (1/5 +1/6) =11/30 Now 11/30 work is done by Q and R ... R in(30/11*23/60) =23/22 hrs = 1hr So the work will be finished approximately 1 hr after 9.am i.e., around 10 a.m

90 persons can complete a job in 32 days. 12 days after they started working, 60 more persons joined them. How many days will they now take to complete the remaining work? a) 10 days b) 12 days c) 14 days d) 16 days

Description : 90 persons can complete a job in 32 days. 12 days after they started working, 60 more persons joined them. How many days will they now take to complete the remaining work? a) 10 days b) 12 days c) 14 days d) 16 days

Last Answer : B (90 * 32) persons can complete the work in 1 day. 1 person 1 day's work = 1/(90 *32) i.e., 1/2880 90 person's 12 day's work = 1/32 * 12 = 3/8 Remaining work =(1- 3/8) = 5/8 150 persons 1 ... 5/96 work is done by them in 1 day . Therefore 5/8 work is done by them, = (96/5*5/8) =12 days.

Hanisha can do a work in 25 days, while sudha can do the same work in 50 days. They started the work jointly.Few days sughana also joined them and thus all of them completed the whole work in 12 days. All of them were paid total Rs.900. What is the Share of sughana? a) 252 b) 346 c) 454 d).359

Description : Hanisha can do a work in 25 days, while sudha can do the same work in 50 days. They started the work jointly.Few days sughana also joined them and thus all of them completed the whole work in 12 days. All of them were paid total Rs.900. What is the Share of sughana? a) 252 b) 346 c) 454 d).359

Last Answer : A Efficiency of Hanisha = 1/100*25 =25/100=1/4=>4% Efficiency of sudha = 2% Thus, in 12 days working together they will complete only 72% of the work. [(4+2)*12] =72 Hence, the remaining work will ... which is =(100-72)=28% Thus, sughana will get 28% of Rs. 900, =28/100*900 which is Rs.252

Nandhu, naren and abishek can do a piece of work in 10,15, and 30 days respectively. In how many days can Nandhu do the work if he is assisted by naren and abishek on alternate days? a) 6.6 days b) 7.5 days c) 8.4 days d) 9.1 days

Description : Nandhu, naren and abishek can do a piece of work in 10,15, and 30 days respectively. In how many days can Nandhu do the work if he is assisted by naren and abishek on alternate days? a) 6.6 days b) 7.5 days c) 8.4 days d) 9.1 days 

Last Answer : B Nandhu's 1 day work = 1/10 Naren's 1 day work = 1/15 Abishek's 1 day work =1/30 Nandhu's 2 day's work =(1/10*2) =1/5 (nandhu + naren+abishek)'s 1 day work = 1/10+1/15+1/30 =3+2+1/30 =6/30 ... +1/5 = 2/5 Now 2/5 work is done in 3 days Whole work will be done in 3 *5/2 = 15/2 = 7.5 days

4 male and 6 female do a piece of work in 20 days while 6 male and 4 female can do the same work in16 days. In how many days can 4 male and 2 female do the work? a) 3 62/142 b) 2 18/124 c) 4 81/165 d) 1 67/133

Description : 4 male and 6 female do a piece of work in 20 days while 6 male and 4 female can do the same work in16 days. In how many days can 4 male and 2 female do the work? a) 3 62/142 b) 2 18/124 c) 4 81/165 d) 1 67/133

Last Answer : D Let 1 male's 1 day's work = x 1 female's 1 day's work = y Then 4x + 6y = 1/20 ---------->A 80x + 120y = 1 -----------1 6x + 4y = 1/16 ----------B 96x + 64y = ... (1/400) =132/200+1/200 = 133/200 So 4 male and 2 female together can finish the work in 200/133 = 1 67 /133 days

A cistern can be filled in 25 minutes. There is a leakage which can empty it in 50 minutes. In how many minutes cistern can be filled? a) 20 mints b) 25mints c) 45 mints d) 50 mints

Description : A cistern can be filled in 25 minutes. There is a leakage which can empty it in 50 minutes. In how many minutes cistern can be filled? a) 20 mints b) 25mints c) 45 mints d) 50 mints

Last Answer : D Efficiency of filling faucet= 100/25 = 4% ⇒ Efficiency of leakage faucet = 100/50= 2% ⇒ Net filling efficiency = (4-2)% =2% So, t cistern can be filled in = 100/2 = 50 minutes

X,Y and Z can do a certain job in 72,108 and 144 days respectively. They started the job but X left 16 days before the completion of the job while Y left 24 days before the completion. The number of days for which Z worked is. a) 12 days b) 24 days c) 36 days d) 48 days

Description : X,Y and Z can do a certain job in 72,108 and 144 days respectively. They started the job but X left 16 days before the completion of the job while Y left 24 days before the completion. The number of days for which Z worked is. a) 12 days b) 24 days c) 36 days d) 48 days

Last Answer : D Suppose the work was finished in a' days Then X's (a - 16) day's work + Y's (a - 24) days + Z's a days work = 1 (a-16)/72 + (a-24)/108 + a/144 =1 lcm of 72,108,144 is 432 (6(a-16) + 4( ... = 432 6a - 96 +4a - 96 =3a = 432 13a - 192 = 432 13a = 624 => a =48 Therefore Z worked in 48 days.

M & N can do a work together in 12 days. M is 2 ½ time as efficient as N. the same work can be done by M alone in. a) 84/5 b) 6/84 c) 82/5 d) 6/82

Description : M & N can do a work together in 12 days. M is 2 ½ time as efficient as N. the same work can be done by M alone in. a) 84/5 b) 6/84 c) 82/5 d) 6/82

Last Answer : A M’s 1 day work = 2 ½ = 5/2 N’s 1 day work = 1 Ratio of M and N = 5/2 : 1= 5:2 Let M’s and N’s 1 day work be 5x and 2x respectively. Then 5x+2x = 1/12 7x=1/12 X= 1/(12*7) X=1/84 M’s 1 day work = 1/84 * 5 = 5/84 Hence M alone can finish the work in 84/5 days.

If 24 women and 32 girls can do a piece of work in 5 days; 26 women and 48 girls can do it in 4 days then the ratio of the daily work done by a women to that of a girl is. a) 2:1 b) 1:3 c) 3:1 d) 1:2

Description : If 24 women and 32 girls can do a piece of work in 5 days; 26 women and 48 girls can do it in 4 days then the ratio of the daily work done by a women to that of a girl is. a) 2:1 b) 1:3 c) 3:1 d) 1:2

Last Answer : A Let 1 women's 1 day work = x 1 girl's 1 day work = y Then 24x+32y = 1/5 =>6x+8y = 1/20 ------->1 26x + 48y = 1 / 4 => 13x + 24y = 1/8 -------->2 Multiply 1 by 3 18x + 24y = 3/20 13x + ... 200 = (10 - 6)/ 200 = 4/200 8y = 1/50 Y=1/400 Required ratio = x:y = 1/200: 1/400 =400:200 =2:1

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

Arul can do a certain work in 9 days while Ravi can do the same work in 7 days. Both of them complete the work together and get Rs.288. what is the share of Arul? a) Rs.124 b) RS.126 c) Rs.128 d) Rs.130

Description : Arul can do a certain work in 9 days while Ravi can do the same work in 7 days. Both of them complete the work together and get Rs.288. what is the share of Arul? a) Rs.124 b) RS.126 c) Rs.128 d) Rs.130

Last Answer : B Arul’s 1 day work = 1/9 Ravi’s 1 day work = 1/7 Arul’s salary : Ravi’s salary = Arul’s 1 day work : Ravi’s 1 day work = 1/9 : 1/7 = 7 :9 Arul’s share = Rs.(7/16 *288) =Rs.126

6 male , 8 female and 12 children can complete a work in 14 days .a female does twice the work of a male does and a child does half the work a male does . how many female alone can complete this work in 14 days? a) 15 b) 10 c) 12 d) 14

Description :  6 male , 8 female and 12 children can complete a work in 14 days .a female does twice the work of a male does and a child does half the work a male does . how many female alone can complete this work in 14 days? a) 15 b) 10 c) 12 d) 14

Last Answer :  D Let 1 female ‘s 1 day work= x Then 1 male’s 1 day work =x/2 And 1 child’s 1 day work =x/4 So 6x/2 + 8x +12x/4 =1/14 3x+8x+3x = 1/14 14x = 1/14 X=196 1 female alone can complete the work in 196 days So, to complete the work in 14 days number of female required = 14.

Among 4 persons A, B, C and D. A takes twice as much time as B to complete a piece of work. B takes twice as much time as C and C takes twice as much time as D to complete the same work. One group of three of the four men can complete the work in 11 days while another group of three can do so in 7 days. Which is the group that takes 11 days? a) A.B.C b) A,B,D c) B,C,D d) None of the above

Description : Among 4 persons A, B, C and D. A takes twice as much time as B to complete a piece of work. B takes twice as much time as C and C takes twice as much time as D to complete the same work. One group of three of the ... is the group that takes 11 days? a) A.B.C b) A,B,D c) B,C,D d) None of the above

Last Answer : B From the given information B is twice as efficient as A. C is twice as efficient as B. D is twice efficient as C. If work done by A in a day is 'n' units, the work done in a day by B, ... of times taken to complete the work by the former and later groups is 11:7 A, B and D take 11 days.

48 boys complete a work in 36 days. After they have worked for 24 days, 24 more boys join them. How many days will they take to complete the remaining work? a) 8 days b) 6 days c) 4 days d) 3 days

Description : 48 boys complete a work in 36 days. After they have worked for 24 days, 24 more boys join them. How many days will they take to complete the remaining work? a) 8 days b) 6 days c) 4 days d) 3 days

Last Answer : A 1 boy’s 1 day’s work = 1/(36*48) =1/1728 48 boy’s 24 day’s work=48*24/1728=2/3 Remaining work = 1-2/3=1/3 72 boy’s 1 day’s work =72/1728=1/24 1/24 work is done by them in 1 day. So, 1/3 work is done by them in 24/3= 8 days

P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Description : P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Last Answer : 2;

Madhesh does half work as much as vinith in three eighth of the time. If together they take a day to complete the work, how much time shall vinith take to do it? a) 21 b) 22 c) 23 d) 24

Description : Madhesh does half work as much as vinith in three eighth of the time. If together they take a day to complete the work, how much time shall vinith take to do it? a) 21 b) 22 c) 23 d) 24

Last Answer : A Suppose vinith takes x days to do the work Madhesh takes (2*3/8 x) = 6/8x i.e., 3/4x days to do it (madhesh + vinith’s) 1 day work = 1/9 Therefore 1/x +4/3x = 1/9 (3+4) / 3x = 1/9 7/3x = 1/9 3x = 9*7 X = 63/ 3 =21 Vinith takes 21 days to do the work.

Vinay can do a work in 28 days. Vikram is 75% more efficient than vinay. The number of days taken by vikram to do the same piece of work. a) 12 days b) 14 days c) 16 days d) 18 days

Description : Vinay can do a work in 28 days. Vikram is 75% more efficient than vinay. The number of days taken by vikram to do the same piece of work.  a) 12 days b) 14 days c) 16 days d) 18 days

Last Answer : C Given a certain work done by vinay = 28 days Efficient percentage of vikram = 75% Ratio of time taken by vinay and vikram = 175 : 100 = 7:4 Suppose vikram takes ‘x’ days to do the work. 7:4 :: 28 : x 7x = 4*28 X= 4*28/7 X= 4*4 = 16 days So vikram takes 16 days to do the work.

A task was assigned to P, Q and R to be completed by not more than seven days. P alone can complete the task in ten days. Q alone can complete the task in twelve days and R alone can complete the task in fifteen days. All three of them worked for two days and P and Q together worked for another two days. What portion of the task will remain after four days? a) 3/10 b) 1/15 c) 1/9 d) 5/16 e) None of these

Description : A task was assigned to P, Q and R to be completed by not more than seven days. P alone can complete the task in ten days. Q alone can complete the task in twelve days and R alone can complete the task in fifteen days. ... will remain after four days? a) 3/10 b) 1/15 c) 1/9 d) 5/16 e) None of these

Last Answer : 1day's work of (P + Q+ R) = 1/10 + 1/12 +1/15 = 15/60 2 day's work of (P + Q+ R) = 15/60 × 2 = 1/2 1 day's work of (P+Q) = 1/10 +1/12 = 11/60 2 day's work of (P+Q) = 11/60 × 2 = 11/30 Rem. work of 4 days = 1- 1/2 + 11/30 = 2/15 Answer: e)

A sum of amount of money is adequate to pay peter’s salary for 42 days and Harish’s salary for 56 days. The same money is adequate to pay the salary of both for. a) 12 days b) 24 days c) 36 days d) 48 days

Description : A sum of amount of money is adequate to pay peter’s salary for 42 days and Harish’s salary for 56 days. The same money is adequate to pay the salary of both for. a) 12 days b) 24 days c) 36 days d) 48 days

Last Answer : B Let the total money be Rs.x Peter’s 1 day salary = Rs. x/42 Harish 1 day salary = Rs. x/56 (peter+harish)’s 1 day salary = Rs(x/42+x/56) =(4x+3x)/168 =7x/168 =x/24 Money is adequate to pay the salary of both for 24 days.

A and B together can do a piece of work in 20 days, while B and C together can do the same work in 15 days. If A ,B and C together can finish this wor

Description : A and B together can do a piece of work in 20 days, while B and C together can do the same work in 15 days. If A ,B and C together can finish this wor

Last Answer : A and B together can do a piece of work in 20 days, while B and C together can do the same ... number of days in which B alone can finish the work.

P started a business in 1990 by investing Rs.25,000. She invested Rs. 10,000 as additional amount in 1991 and her friend Q joined her with an amount of Rs.35,000. P invested another Rs. 10,000 in 1992 and R joined them with Rs. 35,000. At the end of these 3 years, they earned a profit of Rs. 150,000. Find Q's share? a) Rs.50,000 b) Rs.65,000 c) Rs.75,000 d) Rs.15,000

Description : P started a business in 1990 by investing Rs.25,000. She invested Rs. 10,000 as additional amount in 1991 and her friend Q joined her with an amount of Rs.35,000. P invested another Rs. 10,000 in 1992 and R joined them ... ,000. Find Q's share? a) Rs.50,000 b) Rs.65,000 c) Rs.75,000 d) Rs.15,000

Last Answer : Answer: A) P invested Rs.25,000 for 12 months, Rs.(25000 + 10000) for 12 months, , Rs.(25000 + 10000 + 10000) for 12 months. i.e., P invested Rs.25,000 for 12 months, Rs.35000 for 12 months Rs.45000 for 12 months. Q ... Q's share = Rs.(1,50,000 x 2 /(3+2+1)) = Rs.(1,50,000 x 2/6) = Rs.50,000

Rubika can do the 12 times the actual work in 72 days while sathya can do the one-half of the original work in 6 days. In how many days will both working together complete the 6 times of the original work? a) 20 days b) 25 days c) 30 days d) 35 days

Description : Rubika can do the 12 times the actual work in 72 days while sathya can do the one-half of the original work in 6 days. In how many days will both working together complete the 6 times of the original work? a) 20 days b) 25 days c) 30 days d) 35 days

Last Answer :  C Efficiency of Rubika = 16.666% Efficiency of sathya = 4.166% Total efficiency of rubika and sathya =(16+4) =20% Actual work 100/20=5 So, they can do actual work in 5 days So, 6 times work requires 30 days.

A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Description : A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Last Answer : Work done by A in one day = 1/5 and work done by B in one day = 1/7 They are working alternately. Therefore, Work done in first two day = (1/5 + 1/7) = 12/35 Work done in first four day = 24/35 Work done in ... = 4/35/1/7 = 4/5 of the day. Therefore Total days taken = 5 + 4/5 = 29/5 days Answer: b)

3 faucet P,Q & R can fill a cistern in 12 hrs. After working together for 4hrs, R is closed P and Q can fill the remaining part in 14 hrs. The number of hrs taken by R alone to fill the cistern is. A) 18 hrs B) 20 hrs C) 28hrs D) 30hrs

Description :  3 faucet P,Q & R can fill a cistern in 12 hrs. After working together for 4hrs, R is closed P and Q can fill the remaining part in 14 hrs. The number of hrs taken by R alone to fill the cistern is. A) 18 hrs B) 20 hrs C) 28hrs D) 30hrs

Last Answer : C  Part filled in 4 hrs = 4/12 = 1/3 Remaining part = 2/3 (P+Q)’s 14 hrs work = 2/3 (P+Q)’s 1 hr work = 2/ 3 *14 = 1/21 R’s 1 hr work = (P+Q+R)’s 1 hr work – (P+Q)’s 1 hr work = 1/12 – 1/21 = 7-4/84 = 3/84 = 1/28 R alone can fill the tank in 28 hrs.