The curve have b2 = 3 or Y2 = 0 is

Description : n an NC machining operation, the tool has to be moved from point (5, 4) to point (7, 2) alonga circular path with centre at (5, 2). Before starting the operation, the tool is at (5, 4). The G and N codes for this motion ... 0 I5.0 J2.0 c.N010 GO1 X7.0 Y2.0 I5.0 J2.0 d.N010 GOO X7.0 Y2.0 I5.0 J2.0

Last Answer : b.N010 GO2 X7.0 Y2.0 I5.0 J2.0

The x coordinate of the centroid of the area enclosed by the parabolas y = x2 and x = y2 will be a.107 dynes b.0.44 c.0.43 d.0.45 e.0.46

Description : The x coordinate of the centroid of the area enclosed by the parabolas y = x2 and x = y2 will be a.107 dynes b.0.44 c.0.43 d.0.45 e.0.46

Last Answer : d. 0.45

What is the distance from a point on the x axis to the centre of a circle when a tangent line at the point 3 4 meets the circle of x2 plus y2 -2x -6y plus 5 equals 0?

Description : What is the distance from a point on the x axis to the centre of a circle when a tangent line at the point 3 4 meets the circle of x2 plus y2 -2x -6y plus 5 equals 0?

Last Answer : Circle equation: x^2 +y^2 -2x -6y +5 = 0Completing the squares: (x-1)^2 +(y-3)^2 = 5Centre of circle: (1, 3)Tangent line meets the x-axis at: (0, 5)Distance from (0, 5) to (1, 3) = 5 units using the distanceformula

What is the length of the tangent line from the point 9 0 to the circle x2 plus 8x plus y2 -9 equals 0?

Description : What is the length of the tangent line from the point 9 0 to the circle x2 plus 8x plus y2 -9 equals 0?

Last Answer : Equation of circle: x^2 +8x +y^2 -9 = 0Completing the square: (x+4)^2 +y^2 = 25Radius of circle: 5Center of circle: (-4, 0)Distance from (9, 0) to (-4, 0) = 13 which is ... the length of the tangent line is 12 unitsNote that the tangent line of a circle meets the radius of thecircle at right angles

What is the point of contact when the line y equals 2x meets the circle x2 plus y2 -8x -y plus 5 equals 0?

Description : What is the point of contact when the line y equals 2x meets the circle x2 plus y2 -8x -y plus 5 equals 0?

Last Answer : If: y = 2xThen: y^2 = 4x^2If: x^2 +y^2 -8x -y +5 = 0Then: x^2 +4x^2 -8x -2x +5 = 0Transposing terms: 5x^2 -10x +5 = 0Dividing all terms by 5: x^2 -2x +1 = 0Factorizing the above: (x-1)(x-1) = 0 meaning x = 1By substitution into original equations point of contact is madeat: (1, 2)

What is the length of the tangent line from the point 8 2 to a point where it meets the circle x2 plus y2 -4x -8y -5 equals 0?

Description : What is the length of the tangent line from the point 8 2 to a point where it meets the circle x2 plus y2 -4x -8y -5 equals 0?

Last Answer : Equation of circle: x^2 +y^2 -4x -8y -5 = 0Completing the squares: (x-2)^2 +(y-4)^2 = 25 which is radiussquaredCenter of circle: (2, 4)Tangent line originates from: (8, ... angle triangleUsing Pythagoras theorem: distance^2 minus radius^2 = 15Therefore length of tangent line is the square root of 15

What is the center and the radius of the circle x2 plus y2 -4x -6y -3 equals 0?

Description : What is the center and the radius of the circle x2 plus y2 -4x -6y -3 equals 0?

Last Answer : Equation of circle: x^2 +y^2 -4x -6y -3 = 0Completing the squares: (x-2)^2 +(y-3)^2 = 16 square unitsTherefore center of circle is at (2, 3) and its radius is 4units

Center point of circle a.[x1+x2]/2; [y1+y2]/2; [z1+z2]/2 b.[x1-x2]/2; [y1-y2]/2; [z1-z2]/2 c.[x1-x2]; [y1-y2]; [z1-z2] d.[x2-x1]; [y2-y1]; [z2-z1]

Description : Center point of circle a.[x1+x2]/2; [y1+y2]/2; [z1+z2]/2 b.[x1-x2]/2; [y1-y2]/2; [z1-z2]/2 c.[x1-x2]; [y1-y2]; [z1-z2] d.[x2-x1]; [y2-y1]; [z2-z1]

Last Answer : a.[x1+x2]/2; [y1+y2]/2; [z1+z2]/2

The centroid of the area between the circle x2 + y2 = 16 and the line x + y = 4 will have the coordinates a.(4, 2) b.(2, 4) c.(2.34, 2.34) d.(1.16, 1.16) e.None of the above

Description : The centroid of the area between the circle x2 + y2 = 16 and the line x + y = 4 will have the coordinates a.(4, 2) b.(2, 4) c.(2.34, 2.34) d.(1.16, 1.16) e.None of the above

Last Answer : c. (2.34, 2.34)

Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Description : Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Last Answer : Remainder = 145 Again, we should evaluate p(5) Let p(y) = y3 + y2 - 2y + 5 ∴ p(5) = 53 + 52 - 2 x 5 + 5 = 125 + 25 - 10 + 5 = 145 Thus , we find that p(5) is the remainder when p(y) is divided by y - 5 .

Find (2x – y + 3z) (4x2 + y2 + 9z2 + 2xy + 3yz – 6xz). -Maths 9th

Description : Find (2x – y + 3z) (4x2 + y2 + 9z2 + 2xy + 3yz – 6xz). -Maths 9th

Last Answer : Solution of this question

Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Description : Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Last Answer : Remainder = 145 Again, we should evaluate p(5) Let p(y) = y3 + y2 - 2y + 5 ∴ p(5) = 53 + 52 - 2 x 5 + 5 = 125 + 25 - 10 + 5 = 145 Thus , we find that p(5) is the remainder when p(y) is divided by y - 5 .

Find (2x – y + 3z) (4x2 + y2 + 9z2 + 2xy + 3yz – 6xz). -Maths 9th

Description : Find (2x – y + 3z) (4x2 + y2 + 9z2 + 2xy + 3yz – 6xz). -Maths 9th

Last Answer : Solution of this question

Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Description : Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Last Answer : NEED ANSWER

Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Description : Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Last Answer : According to question find the value of z

Simplify: (i) (a + b + c)2 + (a – b + c)2 (ii) (a + b + c)2 – (a – b + c)2 (iii) (a + b + c)2 + (a – b + c)2 + (a + b – c)2 (iv) (2x + p – c)2 – (2x – p + c)2 (v) (x2 + y2 – z2)2 – (x2 – y2 + z2)2 -Maths 9th

Description : Simplify: (i) (a + b + c)2 + (a – b + c)2 (ii) (a + b + c)2 – (a – b + c)2 (iii) (a + b + c)2 + (a – b + c)2 + (a + b – c)2 (iv) (2x + p – c)2 – (2x – p + c)2 (v) (x2 + y2 – z2)2 – (x2 – y2 + z2)2 -Maths 9th

Last Answer : answer:

Find the value of 4x2 + y2 + 25z2 + 4xy – 10yz – 20zx when x = 4, y = 3 and z = 2. -Maths 9th

Description : Find the value of 4x2 + y2 + 25z2 + 4xy – 10yz – 20zx when x = 4, y = 3 and z = 2. -Maths 9th

Last Answer : 4x²+y²+25z²+4xy-10yz-20zx when x=4, y=3 &z=2 so =>4(4)²+(3)²+ 25(2)²+4(4)(3)-10(3)(2)-20(2)(4) =>64+9+100+48-60-160 =>221-220 =>1

Find the value of x3 + y3 + z3 – 3xyz if x2 + y2 + z2 = 83 and x + y + z = 15 -Maths 9th

Description : Find the value of x3 + y3 + z3 – 3xyz if x2 + y2 + z2 = 83 and x + y + z = 15 -Maths 9th

Last Answer : Consider the equation x + y + z = 15 From algebraic identities, we know that (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) So, (x + y + z)2 = x2 + y2 + z2 + 2(xy + yz + xz) From the question, x2 + y2 + z2 ... y3 + z3 - 3xyz = 15(83 - 71) => x3 + y3 + z3 - 3xyz = 15 12 Or, x3 + y3 + z3 - 3xyz = 180

Last Answer : xsin3θ+ycos3θ=sinθcosθ (xsinθ)sin2θ+(ycosθ)cos2θ=sinθcosθ (xsinθ)sin2θ+(xsinθ)cos2θ=sinθcosθ xsinθ=sinθcosθ x=cosθ Again, ycosθ=xsinθ ycosθ=cosθsinθ y=sinθ Therefore, x2+y2=sin2θ+cos2θ=1.

Find dy/dx by implicit differentiation. 7x2 + 5xy − y2 = 8

Description : Find dy/dx by implicit differentiation. 7x2 + 5xy − y2 = 8

Last Answer : Need Answer

What is the result of isolating y2 in the equation below 9x2 plus 7y2 42?

Description : What is the result of isolating y2 in the equation below 9x2 plus 7y2 42?

Last Answer : Need answer

What is the length of a tangent line from the point 7 -2 to a point when it touches the circle x2 plus y2 -10 equals 49?

Description : What is the length of a tangent line from the point 7 -2 to a point when it touches the circle x2 plus y2 -10 equals 49?

Last Answer : x² + y² - 10 = 49→ x² + y² = 59= (x - 0)² + (y - 0)² = (√59)²→ circle has centre (0, 0) - the origin - and radius √59The point (7, -2) has a distance from the centre of the circleof:√((7 - 0)² + (-2 - 0)²) = √(7² + (-2)²) = √(49 + 4) = √53

What is the length of the circle radius if the circle is x2 plus y2 equals 1?

Description : What is the length of the circle radius if the circle is x2 plus y2 equals 1?

Last Answer : The center of the circle is at (0, 0) and its radius is thesquare root of 1 which is 1

What is the length of the circles radius for the circle x2 plus y2 169.?

Description : What is the length of the circles radius for the circle x2 plus y2 169.?

Last Answer : If x^2 plus y^2 = 169 then the center of the circle is at (0, 0)and its radius is the square root of 169 which is 13

What is the point of contact between the line y equals x plus 4 and the circle x2 plus y2 -8x plus 4y equals 30?

Description : What is the point of contact between the line y equals x plus 4 and the circle x2 plus y2 -8x plus 4y equals 30?

Last Answer : Equations: y = x+4 and x^2 +y^2 -8x +4y = 30It appears that the given line is a tangent line to the givencircle and the point of contact works out as (-1, 3)

What is the equation of the tangent line that meets the circle x2 -4x plus y2 -6y equals 4 at the point 6 4?

Description : What is the equation of the tangent line that meets the circle x2 -4x plus y2 -6y equals 4 at the point 6 4?

Last Answer : Circle equation: x^2 -4x +y^2 -6y = 4Completing the squares: (x-2)^2 +(y-3)^2 = 17Point of contact: (6, 4)Center of circle: (2, 3)Slope of radius: 1/4Slope of tangent line: -4Tangent equation: y-4 = -4(x-6) => y = -4x+28Tangent line equation in its general form: 4x+y-28 = 0

What are the solutions to the simultaneous equations of y equals -2x and x2 plus y2 equals 80?

Description : What are the solutions to the simultaneous equations of y equals -2x and x2 plus y2 equals 80?

Last Answer : If: y = -2x then y ^2 = 4x^2If: x^2 + y^2 = 80 then x^2 +4x^2 = 80So: 5x^2 = 80Divide all terms by 5: x^2 = 16Square root both sides: x = -4 or +4By substitution into the original equation solutions are: (-4,8) and (4, -8)

What is the center and the radius of the circle x2 plus y2 equals 12x -10y -12?

Description : What is the center and the radius of the circle x2 plus y2 equals 12x -10y -12?

Last Answer : Equation of circle: x^2 +y^2 = 12x-10y-12Completing the squares: (x-6)^2 +(y+5)^2 = 49So center of circle is at (6, -5) and its radius is 7 units

If z equals yf x2 - y2 show that ydz divided by dx plus xdz divided by dy equals xz divided by y?

Description : If z equals yf x2 - y2 show that ydz divided by dx plus xdz divided by dy equals xz divided by y?

Last Answer : 4

The point (-1,2) divides the line segment joining the points A(2,5) and B(x,y) in the ratio 3:4, then the value of x2 + y2 is : (a) 27 (b) 28 (c) 29 (d) 30

Description : The point (-1,2) divides the line segment joining the points A(2,5) and B(x,y) in the ratio 3:4, then the value of x2 + y2 is : (a) 27 (b) 28 (c) 29 (d) 30

Last Answer : (c) 29

The thickness of oxide film is y at time t. If K1, K2 and K3 are the temperature dependent constants, the parabolic law of oxidation is given by (A) y2 = 2k1t + k2 (B) y = k1 ln (k2t + k3) (C) y = k1 t + k2 (D) y = k1t3 + k2

Description : The thickness of oxide film is y at time t. If K1, K2 and K3 are the temperature dependent constants, the parabolic law of oxidation is given by (A) y2 = 2k1t + k2 (B) y = k1 ln (k2t + k3) (C) y = k1 t + k2 (D) y = k1t3 + k2

Last Answer : Option A

Solve for x and y: 1/x - 1/y = 1/3, 1/x2 + 1/y2 = 5/9.

Description : Solve for x and y: 1/x - 1/y = 1/3, 1/x2 + 1/y2 = 5/9.

Last Answer : Answer: x = 3/2 or -3 and y = 3 or -3/2.

Two sources of sound placed close to each other, are emitting progressive waves given by y1 = 4 sin 600 t and y2 = 5 sin 608 t. An observer located near these two sources of sound will hear: (1) 4 beats per second with intensity ratio 81 : 1 between waxing and waning (2) 4 beats per second with intensity ratio 25 : 16 between waxing and waning (3) 8 beats per second with intensity ratio 25 : 16 between waxing and waning (4) 8 beats per second with intensity ratio 81 : 1 between waxing and waning

Description : Two sources of sound placed close to each other, are emitting progressive waves given by y1 = 4 sin 600 t and y2 = 5 sin 608 t. An observer located near these two sources of sound will ... between waxing and waning (4) 8 beats per second with intensity ratio 81 : 1 between waxing and waning

Last Answer : (1) 4 beats per second with intensity ratio 81 : 1 between waxing and waning

If ax + by = a2 – b2 and bx + ay = 0, find the value of (x + y). -Maths 10th

Description : If ax + by = a2 – b2 and bx + ay = 0, find the value of (x + y). -Maths 10th

Last Answer : Given, ax+by=a2−b2......(1) bx+ay=0.......(2). Now adding (1) and (2) we get, x(a+b)x+(a+b)y=a2−b2 or, (a+b)(x+y)=a2−b2 or, x+y=a−b.

If a,b,c are all non-zero and a + b + c = 0, prove that a2/bc + b2/ca+ c2/ab = 3. -Maths 9th

Description : If a,b,c are all non-zero and a + b + c = 0, prove that a2/bc + b2/ca+ c2/ab = 3. -Maths 9th

Last Answer : Solution :-

If a + b + c = 0 and a2 + b2 + c2 = 16, find the value of ab + be + ca. -Maths 9th

Description : If a + b + c = 0 and a2 + b2 + c2 = 16, find the value of ab + be + ca. -Maths 9th

Last Answer : (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca = a2 + b2 + c2 + 2(ab + bc + ca) 0 = 16 + 2(ab + bc + ca) 2(ab + bc + ca) = - 16 (ab + bc + ca) = -8

If the roots of the equations ax2 + 2bx + c = 0 and bx2 – are simultanously real then prove that b2 = 4ac. -Maths 10th

Description : If the roots of the equations ax2 + 2bx + c = 0 and bx2 – are simultanously real then prove that b2 = 4ac. -Maths 10th

Last Answer : Let D1 and D2 be the discriminants of the two equations, then D1≥0 and D2≥0 ⇒4b2−4ac≥0 and 4ac−4b2≥0 ⇒b2≥ac and ac≥b2 ⇒b2=ac

If the roots ff the equation (c2 – ab)x2 – 2(a2 – bc)x + b2 – ac = 0 are equal, then prove that either a = 0 or a3 + b3 + c3 = 3abc -Maths 10th

Description : If the roots ff the equation (c2 – ab)x2 – 2(a2 – bc)x + b2 – ac = 0 are equal, then prove that either a = 0 or a3 + b3 + c3 = 3abc -Maths 10th

Last Answer : (c2 – ab) x2 + 2(bc - a2 ) x+ (b2 – ac) = 0 Comparing with Ax2 + Bx + C = 0 A = (c2 – ab), B = 2(bc - a2 ) and C = b2 – ac According to the question, B2 - 4AC = 0 Put the values in the above equation we get 4a(a3 + b3 + c3 -3abc) = 0 hence, a = 0 or a3 + b3 + c3 = 3ab

In the quadratic equation ax2 plus bx plus c 0 if b2 - 4ac?

Description : In the quadratic equation ax2 plus bx plus c 0 if b2 - 4ac?

Last Answer : If you mean b^2 -4ac then it is the discriminant of a quadraticequation.If the discriminant equals 0 then the equation has 2 equalroots.If the discriminant is greater than 0 then the equation has 2different roots.If the discriminant is less than 0 then it has no realroots.

If a + b + c = 9 and ab + bc + ca = 26, find a2 + b2 +c2. -Maths 9th

Description : If a + b + c = 9 and ab + bc + ca = 26, find a2 + b2 +c2. -Maths 9th

Last Answer : Find a2 + b2 +c2.

If a + b + c = 9 and ab + bc + ca = 26, find a2 + b2 +c2. -Maths 9th

Description : If a + b + c = 9 and ab + bc + ca = 26, find a2 + b2 +c2. -Maths 9th

Last Answer : Find a2 + b2 +c2.

The product (a + b) (a – b) (a2 – ab + b2) (a2 + ab + b2) is equal to (a) a6 + b6 (b) a6 – b6 (c) a3 – b3 (d) a3 + b3 -Maths 9th

Description : The product (a + b) (a – b) (a2 – ab + b2) (a2 + ab + b2) is equal to (a) a6 + b6 (b) a6 – b6 (c) a3 – b3 (d) a3 + b3 -Maths 9th

Last Answer : answer:

If a + b + c = 9 and ab + bc + ca = 23, find the value of a2 + b2 + c2 -Maths 9th

Description : If a + b + c = 9 and ab + bc + ca = 23, find the value of a2 + b2 + c2 -Maths 9th

Last Answer : (a+b+c)2=a2+b2+c2+2ab+2bc+2ca =a2+b2+c2+2(ab+bc+ca) Given, ⇒92=a2+b2+c2+2(23) ⇒81−46=a2+b2+c2 ∴a2+b2+c2=35

If a2 + b2 + c2 = 16 and ab + bc + ca = 10, find the value of a + b + c. -Maths 9th

Description : If a2 + b2 + c2 = 16 and ab + bc + ca = 10, find the value of a + b + c. -Maths 9th

Last Answer : ( a + b + c )^2 = a^2 + b^2 + c^2 + 2( ab + bc + ca ) => ( a + b + c )^2 = 16 + 2×10 => ( a + b + c )^2 = 36 => a + b + c = Root 36 = 6

The curve have b2 = 3 or Y2 = 0 is

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