Description : Eukaryotic promoters contain (A) TATA box 25bp upstream of transcription start site (B) CAAT box 70-80 bp upstream of transcription start site (C) Both (A) and (B) (D) None of these
Last Answer : Answer : C
Description : CAAT box is present in (A) Prokaryotic promoters 10 bp upstream of transcription start site (B) Prokaryotic promoters 35 bp upstream of transcription start site (C) Eukaryotic promoters 25 bp upstream of transcription start site (D) Eukaryotic promoters 70–80 bp upstream of transcription start site
Last Answer : Answer : D
Description : All of the following statements about eukaryotic promoters are true except (A) They may be located upstream or down stream from the structural gene (B) They have two consensus sequences ( ... (D) Mutations in promoter region can decrease the efficiency of transcription of the structural gene
Last Answer : Answer : A
Description : All of the following statements about bacterial promoters are true except (A) They are smaller than eukaryotic promoters (B) They have two consensus sequences upstream from the transcription star site (C) ... is the site for attachment of RNA polymerase (D) TATA box has a high melting temperature
Description : Silencer elements (A) Are trans-acting factors (B) Are present between promoters and the structural genes (C) Decrease the expression of some structural genes (D) Encode specific repressor proteins
Description : Enhancer elements have all the following features except (A) They increase gene expression through a promoter (B) Each enhancer activates a specific promoter (C) They may be located far away from the promoter (D) They may be upstream or downstream from the promoter
Last Answer : Answer : B
Description : All of the following statements about tRNA are true except (A) It is synthesized as a large precursor (B) It is processed in the nucelolus (C) It has no codons or anticodons (D) Genes for rRNA are present in single copies
Description : Mutations in promoter regions of genes can cause (A) Premature termination of translation (B) Change in reading frame of downstream structural gene (C) Decreased efficiency of transcription (D) All of these
Description : The regulatory i gene of lac operon (A) Is inhibited by lacotse (B) Is inhibited by its own product, the repressor protein (C) Forms a regulatory protein which increases the expression of downstream structural genes (D) Is constitutively expressed
Description : A diver rowing at the rate of 5 km/h in still water takes double the time in going 40 km upstream as in going 40 km downstream. Find the speed of the stream. -Maths 10th
Last Answer : 5/3 km/h Step-by-step explanation: Speed in still water = 5km/h Define x: Let the speed of the steam be x Upstream speed = (5 - x) km/h Downstream speed = (5 + x) km/h Time taken going upstream: Time taken = ... 40x = 400 - 80x 120x = 200 x = 200 120 = 5/3 The speed of the stream is 5/3 km/h
Description : A boat covers 14 kms in upstream and 20 kms downstream in 7 hours. Also it covers 22 kms upstream and 34 kms downstream in 10 hours. Find the speed of the boat in still water and of that the stream. -Maths 9th
Last Answer : Given, The boat covers 14 km upstream and 20km downstream . at time 7 hours also cover 22km ups. and 34km dwn in10 hours total speed = total distance/total time :.total distance = 14+20+22+34=90km and total time=7+10= ... =90/17 => 5.294km/h => 5.294km/h the speed of boat in still water is 5.29 km/h
Description : A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return downstream to the same spot. Find the speed of the stream. -Maths 10th
Last Answer : The given speed of the motor boat in the still water is equal to 18 km/ hr. The given distance travelled by motor boat is equal to 24 km. The time taken to travel 24 km downstream by motor boat = 1 hour. x=122=6 km/ hr.
Description : Explain upstream and downstream processing in biotechnology. -Biology
Last Answer : answer:
Description : Pick up the incorrect statement from the following for allowing workers to enter sewers A. The particular manhole and one manhole on upstream and one manhole on downstream should remain open for 30 ... entering the manhole should be advised to smoke in the sewer D. Warning signals should be erected
Last Answer : ANS: C
Description : The process of separation and purification of expressed protein before marketing is called (a) downstream processing (b) bioprocessing (c) postproduction processing (d) upstream processing.
Last Answer : (a) downstream processing
Description : A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr
Last Answer : (a) 3km/hr
Description : A boat is rowed downstream at 15.5 km/h and upstream at 8.5 km/h. The speed of the stream is: (a) 3.5 km/h (b) 5.75 km/h (c) 6.5 km/h (d) 7 km/h
Last Answer : (a) 3.5 km/h
Description : A traditional cable TV network transmits signals ______. A) upstream B) downstream C) upstream and downstream D) none of the above
Last Answer : downstream
Description : The largest portionof the bandwidth for ADSLcarries_______. A) voice communication B) upstream data C) downstream data D) control data
Last Answer : downstream data
Description : _______ is suitable for businesses that require comparable upstream and downstream data rates. A) VDSL B) ADSL C) SDSL D) (a) and (b)
Last Answer : SDSL
Description : Air inlet valve in water mains, is generally provided at (A) Summit of the pipe (B) Upstream of sluice valve (C) Downstream of sluice valve (D) Both (a) and (c) of above
Last Answer : (D) Both (a) and (c) of above
Description : The seepage exit gradient in a soil is the ratio of A) Total head to the length of seepage (B) Flow line to slope (C) Head upstream to that at downstream (D) Head loss to the length of the seepage
Last Answer : Answer: Option D
Description : Coefficient of discharge of an ogee spillway (A) Depends on depth of approach and upstream slope (B) Depends on downstream apron interference and downstream submergence (C) Remains constant (D) Both (A) and (B
Description : A repelling groyne is aligned (A) Pointing upstream (B) Pointing downstream (C) Perpendicular to bank (D) Parallel to bank
Last Answer : Answer: Option A
Description : Silt excluders are constructed on the (A) River bed upstream of head regulator (B) River bed downstream of head regulator (C) Canal bed upstream of head regulator (D) Canal bed downstream of head regulator
Description : divide wall is provided (A) At right angle to the axis of weir (B) Parallel to the axis of weir and upstream of it (C) Parallel to the axis of weir and downstream of it (D) At an inclination to the axis of weir
Description : In a broad-crested weir, the discharge is maximum if the head of water on the downstream side of weir is __________ the head of water on the upstream side of weir. (A) Equal to (B) One-third (C) Two-third (D) Three-fourth
Last Answer : Answer: Option C
Description : A man can row 15 km/hr in still water. It takes him twice as long to row upstream as to row downstream. Find the rate of stream? a) 5 km/hr b) 10 km/hr c) 7.5 km/hr d) 6 km/hr e) 8 km/hr
Last Answer : Let the man’s upstream speed be x km/hour and downstream speed will be 2x km/hour Speed in still water = 1/2 (2x + x) = 3x/2 km/hour 3x/2 = 15 X = 10 Hence, his downstream speed = 20km/hour Rate of stream = 1/2 (20-10) = 5km/hour Answer: a)
Description : A boat running downstream covers a distance of 20 km in 5 hours while for covering the same distance upstream, it takes 10 hours. What is the speed of the stream? a) 2km/hr b) 4km/hr c) 1km/hr d) 1.5 km/hr e) None of these
Last Answer : c Rate of downstream=(20 / 5 ) kmph= 4kmph Rate of upstream =( 20/10) kmph= 2kmph Therefore Speed of the stream= (1/2)(4 - 2) kmph= 1 kmph
Description : A this usual rowing rate, Mohit can travel 12 miles downstream in a certain river in 6 hours less than it takes him to travel the same distance upstream. But if he could double his usual rowing rate for his 24 miles round trip, ... current in miles per hour? A.2.5m/hr B.4 m/hr C.8/3 m/hr D. 5/3m/hr
Last Answer : Answer-C Basic Formula: Speed of the stream = ½ (a-b) km/hr Explanation: Let the speed in still water be x m/hr Speed of stream be y m/hr Then, speed upstream = x-y m/hr and Speed downstream = x+y m/hr 12/x-y - ... 1] 3y^2 = 8 y so, y = 8/3 speed of the current = 8/3 m/hr = 2 (2/3) m/hr
Description : A boat takes 4hours for traveling downstream from point P to point Q and coming back to point P upstream. If the velocity of the stream is 2km ph and the speed of the boat in still water is 4kmph, what is the distance between P and Q? A.9 km B.7 km C.5 km D.6km
Last Answer : Answer- D Basic Formula: Speed of stream = ½ (a-b) km/hr Speed of still water = ½ (a+b) km/hr Explanation: Time taken by boat to travel upstream and downstream = 4 hours Velocity of the stream, ½ (a-b) = 2km/hr a ... + x / 6 = 4 3x + x / 6 = 4 4x = 24 so,x = 6 distance between P and Q = 6km
Description : Ashok can row upstream at 8kmph and downstream at 12kmph.What is the speed of the stream ? A.6km/hr B.3km/h C.2 km/hr D.4km/hr
Last Answer : Answer -C Basic Formula: If the speed downstream is a kmph and the speed upstream is b kmph then Speed of the stream = ½ (a-b) kmph Explanation: Speed downstream a = 12kmph Speed upstream b = 8 kmph Speed of the stream = ½ (a-b) = ½ (12-8) = 4/2 = 2 kmph speed of the stream = 2kmph
Description : If Nishu can swim downstream at 6kmph and upstream at 2kmph.What is his speed in still water ? A.5 km/hr B.4 km/hr C.8km/hr D.7km/hr
Last Answer : Answer- B Basic Formula: If the speed downloadstream is a km/ hr and the speed upstream is b km/ hr then Speed in still water is = ½ (a+b) km / hr [memory tool last 2 L cross and make +] Explanation: Given ... still water = ½ (a+b) kmph = ½ (6+2) = 8/2 = 4kmph speed in still water = 4kmph
Description : A man takes 10 hours to cover a distance while traveling upstream on a boat, whereas while traveling downstream it takes 6 hours. If the speed of the boat in still water is 6 kmph, what is the speed of the stream? 1 : 2.5 kmph 2 : 2.2 kmph 3 : 2 kmph 4 : 1.5 kmph 5 : None of these
Last Answer : 4 : 1.5 kmph
Description : A depth-discharge relationship of the canal section is maintained at a notch fall because the sill of the notches is : a) Level with downstream canal bed b) Below the upstream canal bed c) Level with upstream canal bed d) Above the upstream canal bed
Last Answer : c) Level with upstream canal bed
Description : A boat travels 20 kms upstream in 6 hours and 18 kms downstream in 4 hours. Find the speed of the boat in still water and the speed of the water current? (a) 1/2 kmph (b) 7/12 kmph (c) 5 kmph (d) none of these
Last Answer : (b) 7/12 kmph
Description : Process of managing upstream and downstream of final goods, flow of raw materials and information about resellers and final consumers is classified as A. marketing logistics network B. supply chain management C. delivery network D. physical distribution network
Last Answer : B. supply chain management
Description : The process of separation and purification of expressed protein before marketing is called : (1) Downstream processing (2) Bioprocessing (3) Postproduction processing (4) Upstream processing
Last Answer : (1) Downstream processing
Description : A motorboat running upstream takes 4 hrs 24 mins to cover a certain distance, while it takes 2hrs to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively? A) 8:3 B) 5:2 C) 3:7 D) 2:4
Last Answer : ANSWER : A Explanation: Let the man's rate upstream be x'km/hr and downstream be y'km/hr Then distance covered upstream by 4hrs 24mints = distance covered by downstream in 2hrs (x * 4 2/5) = y *2 22x/5 = 2y Y = ... = (y+x/2) : (y -x/2) = 16x/10 : 6x/10 = 16x : 6x = 8:3
Description : Mohana can row 80km upstream and 110km downstream in 26 hrs. Also she can 60km upstream and 88km downstream in 20 hrs. Find the speed of the girl in still water and the speed of the current in ratio: A) 5:6 B) 3:6 C) 7:9 D) 8:3
Last Answer : ANSWER : D Explanation: Let rate upstream = x' km/hr and Rate downstream = y' km/hr Then 80/x + 110/y = 26 ---1 60/x + 88/y = 20--2 By solving 1 and 2 y= 11 ; x = 5 Rain in still water ... 5) km/hr = 8 km/hr Rain of current = ½ (11 - 50) km/hr = 3 km/hr The required answer is 8:3
Description : There are 3 poles M, N and O in a straight line such that point N is equidistant from points M and O. A boat can travel from point M to O downstream in 6 hours and from N to M upstream in 4 hours. Find the ratio of boat in still water to speed of stream. A) 2:3 B) 7:1 C) 3:2 D) 1:7
Last Answer : ANSWER: B Explanation: Let speed in still water = x km/hr, of current = y km/hr Downstream speed = (x+y) km/hr Upstream speed = (x - y) km/hr Let MO = 2p km. So MN = NO = p km. So 2p/(x+y) = 6 --------1 p/ ... - 2y) = 6x + 6y 8x - 8y = 6x +6y 2x = 14y x/y = 14 / 2 = 7/1 x : y = 7 :1
Description : A motorboat can cover 80 km upstream and 120 km downstream together in 26 hours. Also it can cover 100 km upstream and 144 km downstream together in 32 hours. What is the speed of the motorboat in still water? A) 12 km/hr B) 15km/hr C) 8.5km/hr D) 19km/hr
Last Answer : ANSWER :C Explanation: Upstream speed in both cases is 80 and 100. Ratio is 80 : 100 = 8:10 = 4 : 5. So let times in both cases be 4x and 5x Downstream speed in both cases is 120 and 144 resp. Ratio is ... 12 km/hr So speed of boat = 1/2 * (5+12) =17/2km/hr speed of boat = 8.5 km/hr
Description : A boys rows to a certain place and comes back, but by mistake he covers 2/3rd more distance while coming back. The total time for this journey is 20 hours. The ratio of speed of boat to that of ... starting point from his present position? A) 2hr 13mints B)1hr 30 mins C) 2hr 30mins D)1hr 40 mins
Last Answer : ANSWER : A Explanation: let speed of boat and stream be 2x and x respectively So downstream speed = 2x+x = 3x, and upstream speed = 2x-x = x Let total distance between points is d km So he covered d ... with speed 3x = 48 km/hr(downstream) So time is 80/36 * 60 = 133.33 minutes = 2hr 13mins
Description : A man goes 4km upstream of the stream in 2hr and goes 2km downstream of the stream in 20mints. How long will it take to go 10km in stationary water? A) 1hr 15mits B) 2hrs 30mints C) 5hrs 30mints D) 3hrs 45mints
Last Answer : ANSWER : B Explanation: Rate downstream = (2/20 * 60) km/hr = 6 km/hr Rate upstream = 2 km/hr Speed in still water = ½(6+2)km/hr = 4 km/hr Required time = distance / speed = (10/4) hrs =(5/2)hrs =2 ½ hrs = 2hrs 30mits.
Description : A motor boat sails 30 km of a river towards upstream in 10hrs. How long will it take to cover the same distance downstream, if the speed of the current is ½ of the speed of the boat in still water. A) 1.8hrs B) 3.33hrs C) 5hrs D) None of these
Last Answer : ANSWER : B Explanation: Upstream speed = x –y Downstream speed = x + y x– y = 30/10 = 3km/hr Again x = 2y Therefore x – y = 3 y= 3km/hr ; x = 6km/hr Therefore x + y = 9 km/hr Time during downstream = 30/9 = 3.33hrs
Description : Sakthi rows a boat at 4 km upstream in 1hour and 1 km downstream in 20 minutes. How long will he take to reach 3.5km in still water? A) 1 B) 2 C) 3 D) 4
Last Answer : ANSWER:A Explanation: Upstream Speed = 4/1 = 4km/hr Downstream Speed = 1/20 = 0.05 km/min = 0.05*60 = 3 km/hr Hence, speed of boat = 1/2( Upstream Speed + Downstream Speed) = 1/2 (4+3 ... , the time required to reach the distance of 3.5 km=DistanceCovered/Speed of boat = 3.5/3.5km/hr =1 km/hr
Description : A boat man lakes 5hrs 30 mins to row a boat 30km downstream of a river and 4 hrs 15mints to cover a distance of 10km upstream. Find the speed of the river current in km/hr. A) 1.5 km/hr B) 3km/hr C) 5km/hr D) 7 km/hr
Last Answer : ANSWER: A Explanation: Rate downstream = (30 / 5 ½ ) km/hr = 30 / (11/2) km/hr = 30 * 2 / 11 km/hr = 60/11 km/hr Rate upstream = (10 / 4 ¼)km/hr = 10 / (17/4)km/hr = 10 * 4 / 17 km/hr = ... Speed of current = 1 / 2 (a - b) km/hr =1 / 2 (60 / 11 - 40 / 17) = 1.5 km/hr (approx.)
Description : A boatman can take the same time to row6.5km downstream and 3.5km upstream. His speed in still water 2.5 km/hr. The speed of the stream is. A) 0.75 km/hr B) 2.5 km/hr C) 1.5km/hr D) 7.5km/hr
Last Answer : ANSWER: A Explanation: Given that the speed in still water = 2.5 km/hr Let the speed of the stream be x; km/hr speed in upstream = (2.5 - x)km/hr Then time taken to cover 6.5 km downstream = 6.5 / (2.5+x) ... 5x = 8.75 + 3.5x 10 x = 7.5 x = 0.75 km/hr The speed of the stream is 0.75 km/hr
Description : A pedal boat goes 12km upstream and 14km downstream in 3hrs. It goes 15km upstream and 10.5km downstream in 3 hrs 15mints. The speed of the boat in still water is A) 10 B) 15 C) 20 D) 25
Last Answer : ANSWER: A