In a broad-crested weir, the discharge is maximum if the head of water on the downstream side of
weir is __________ the head of water on the upstream side of weir.
(A) Equal to
(B) One-third
(C) Two-third
(D) Three-fourth

1 Answer

Answer :

Answer: Option C

Related questions

Description : When the water level on the downstream side of a weir is above the top surface of a weir, the weir is known as (A) Narrow-crested weir (B) Broad-crested weir (C) Ogee weir (D) Submerged weir

Last Answer : Answer: Option D

Description : The maximum discharge over a broad crested weir is (A) 0.384 Cd × L × H1/2 (B) 0.384 Cd × L × H3/2 (C) 1.71 Cd × L × H1/ (D) 1.71 Cd × L × H 3/

Last Answer : Answer: Option D

Description : A weir is said to be broad crested weir, if the width of the crest of the weir is ________ half the height of water above the weir crest. (A) Equal to (B) Less than (C) More than (D) None of these

Last Answer : Answer: Option C

Description : A weir, generally, used as a spillway of a dam is (A) Narrow crested weir (B) Broad crested weir (C) Ogee weir (D) Submerged weir

Last Answer : Answer: Option C

Description : 06. The formula for discharge over a sharp-crested weir and Ogee weir is same as that of a rectangular weir. A) Agree B) Disagree

Last Answer : A

Description : divide wall is provided (A) At right angle to the axis of weir (B) Parallel to the axis of weir and upstream of it (C) Parallel to the axis of weir and downstream of it (D) At an inclination to the axis of weir

Last Answer : Answer: Option A

Description : A weir is said to be narrow-crested weir, if the width of the crest of the weir is __________ half the height of water above the weir crest. (A) Equal to (B) Less than (C) More than (D) None of these

Last Answer : Answer: Option B

Description : Coefficient of discharge of an ogee spillway (A) Depends on depth of approach and upstream slope (B) Depends on downstream apron interference and downstream submergence (C) Remains constant (D) Both (A) and (B

Last Answer : Answer: Option D

Description : A depth-discharge relationship of the canal section is maintained at a notch fall because the sill of the notches is : a) Level with downstream canal bed b) Below the upstream canal bed c) Level with upstream canal bed d) Above the upstream canal bed

Last Answer : c) Level with upstream canal bed

Description : 13. In a sharp-crested weir, the thickness of the weir is kept less than half of the height of water above the crest of the weir. A) True B) False

Last Answer : A

Description : The discharge through a convergent mouthpiece is __________ the discharge through an internal mouthpiece of the same diameter and head of water. (A) Equal to (B) One-half (C) Three fourth (D) Double

Last Answer : Answer: Option D

Description : The seepage exit gradient in a soil is the ratio of A) Total head to the length of seepage (B) Flow line to slope (C) Head upstream to that at downstream (D) Head loss to the length of the seepage

Last Answer : Answer: Option D

Description : Silt excluders are constructed on the (A) River bed upstream of head regulator (B) River bed downstream of head regulator (C) Canal bed upstream of head regulator (D) Canal bed downstream of head regulator

Last Answer : Answer: Option A

Description : The absolute percentage error in the computed discharge over a rectangular weir corresponding to an absolute error of 1.5 % in the measurement of head over the sill of the weir would be : (a) 1.5 (b) 2.25 (c) 2.5 (d) 3.75

Last Answer : (b) 2.25

Description : According to Bazin's formula, the discharge over a rectangular weir is mL2g x H 3/2where m is equal to (A) 0.405 + (0.003/H) (B) 0.003 + (0.405/H) (C) 0.405 + (H/0.003) (D) 0.003 + (H/0.405)

Last Answer : Answer: Option A

Description : The power transmitted through the pipe is maximum when the head lost due to friction is equal to (A) One-fourth of the total supply head (B) One-third of the total supply head (C) One-half of the total supply head (D) Two-third of the total supply head

Last Answer : Answer: Option B

Description : Air inlet valve in water mains, is generally provided at (A) Summit of the pipe (B) Upstream of sluice valve (C) Downstream of sluice valve (D) Both (a) and (c) of above

Last Answer : (D) Both (a) and (c) of above

Description : A repelling groyne is aligned (A) Pointing upstream (B) Pointing downstream (C) Perpendicular to bank (D) Parallel to bank

Last Answer : Answer: Option A

Description : Most important method for calculating discharge for planning a water supply project, is  (A) Velocity area method  (B) Weir or spillway method  (C) Use of venturi-meter  (D) Using power plant consumption 

Last Answer : (A) Velocity area method

Description : 09. According to Bazin, the coefficient of discharge varies with the height of water over the sill of a weir. A) Correct B) Incorrect

Last Answer : A

Description : The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of ... 2g [H1 2 - Ha 2 ] (D) (2/3) Cd L. 2g [H1 5/2 - Ha 5/2]

Last Answer : Answer: Option B

Description : A weir is used to measure the large water discharge rate from a river or from an open channel. A weir is not of __________ shape. (A) Circular (B) Rectangular (C) Triangular (D) Trapezoidal

Last Answer : (A) Circular

Description : A control meter is preferred to a weir because (A) It measures the discharge even in silt Leiden streams (B) The velocity of approach of the channel increases above the control, and thus removes the silt completely (C) It is not damaged by floating debris (D) All the above

Last Answer : Answer: Option D

Description : The Francis formula for the discharge over Cipoletti weir is (A) 1.84 LH1/2 (B) 1.84 LH (C) 1.84 LH3/2 (D) 1.84 LH5/

Last Answer : Answer: Option C

Description : When the coefficient of discharge (Cd) is 0.623, then the general equation for discharge over a rectangular weir is (A) 1.84(L - 0.1nH)H 3/2 (B) 1.84(L - nH)H 2 (C) 1.84(L - 0.1nH)H 5/2 (D) 1.84(L - nH)H 3

Last Answer : Answer: Option A

Description : A diver rowing at the rate of 5 km/h in still water takes double the time in going 40 km upstream as in going 40 km downstream. Find the speed of the stream. -Maths 10th

Last Answer : 5/3 km/h Step-by-step explanation: Speed in still water = 5km/h Define x: Let the speed of the steam be x Upstream speed = (5 - x) km/h Downstream speed = (5 + x) km/h Time taken going upstream: Time taken = ... 40x = 400 - 80x 120x = 200 x = 200 120 = 5/3 The speed of the stream is 5/3 km/h

Description : A boat covers 14 kms in upstream and 20 kms downstream in 7 hours. Also it covers 22 kms upstream and 34 kms downstream in 10 hours. Find the speed of the boat in still water and of that the stream. -Maths 9th

Last Answer : Given, The boat covers 14 km upstream and 20km downstream . at time 7 hours also cover 22km ups. and 34km dwn in10 hours total speed = total distance/total time :.total distance = 14+20+22+34=90km and total time=7+10= ... =90/17 => 5.294km/h => 5.294km/h the speed of boat in still water is 5.29 km/h

Description : A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return downstream to the same spot. Find the speed of the stream. -Maths 10th

Last Answer : The given speed of the motor boat in the still water is equal to 18 km/ hr. The given distance travelled by motor boat is equal to 24 km. The time taken to travel 24 km downstream by motor boat = 1 hour. x=122=6 km/ hr.

Description : A man can row 15 km/hr in still water. It takes him twice as long to row upstream as to row downstream. Find the rate of stream? a) 5 km/hr b) 10 km/hr c) 7.5 km/hr d) 6 km/hr e) 8 km/hr

Last Answer : Let the man’s upstream speed be x km/hour and downstream speed will be 2x km/hour Speed in still water = 1/2 (2x + x) = 3x/2 km/hour 3x/2 = 15 X = 10 Hence, his downstream speed = 20km/hour Rate of stream = 1/2 (20-10) = 5km/hour Answer: a)

Description : A boat takes 4hours for traveling downstream from point P to point Q and coming back to point P upstream. If the velocity of the stream is 2km ph and the speed of the boat in still water is 4kmph, what is the distance between P and Q? A.9 km B.7 km C.5 km D.6km

Last Answer : Answer- D Basic Formula: Speed of stream = ½ (a-b) km/hr Speed of still water = ½ (a+b) km/hr Explanation: Time taken by boat to travel upstream and downstream = 4 hours Velocity of the stream, ½ (a-b) = 2km/hr a ... + x / 6 = 4 3x + x / 6 = 4 4x = 24 so,x = 6 distance between P and Q = 6km

Description : If Nishu can swim downstream at 6kmph and upstream at 2kmph.What is his speed in still water ? A.5 km/hr B.4 km/hr C.8km/hr D.7km/hr

Last Answer : Answer- B Basic Formula: If the speed downloadstream is a km/ hr and the speed upstream is b km/ hr then Speed in still water is = ½ (a+b) km / hr [memory tool last 2 L cross and make +] Explanation: Given ... still water = ½ (a+b) kmph = ½ (6+2) = 8/2 = 4kmph speed in still water = 4kmph

Description : A man takes 10 hours to cover a distance while traveling upstream on a boat, whereas while traveling downstream it takes 6 hours. If the speed of the boat in still water is 6 kmph, what is the speed of the stream? 1 : 2.5 kmph 2 : 2.2 kmph 3 : 2 kmph 4 : 1.5 kmph 5 : None of these

Last Answer : 4 : 1.5 kmph

Description : A boat travels 20 kms upstream in 6 hours and 18 kms downstream in 4 hours. Find the speed of the boat in still water and the speed of the water current? (a) 1/2 kmph (b) 7/12 kmph (c) 5 kmph (d) none of these

Last Answer : (b) 7/12 kmph

Description : A motorboat running upstream takes 4 hrs 24 mins to cover a certain distance, while it takes 2hrs to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively? A) 8:3 B) 5:2 C) 3:7 D) 2:4

Last Answer : ANSWER : A Explanation: Let the man's rate upstream be x'km/hr and downstream be y'km/hr Then distance covered upstream by 4hrs 24mints = distance covered by downstream in 2hrs (x * 4 2/5) = y *2 22x/5 = 2y Y = ... = (y+x/2) : (y -x/2) = 16x/10 : 6x/10 = 16x : 6x = 8:3

Description : Mohana can row 80km upstream and 110km downstream in 26 hrs. Also she can 60km upstream and 88km downstream in 20 hrs. Find the speed of the girl in still water and the speed of the current in ratio: A) 5:6 B) 3:6 C) 7:9 D) 8:3 

Last Answer : ANSWER : D Explanation: Let rate upstream = x' km/hr and  Rate downstream = y' km/hr  Then 80/x + 110/y = 26 ---1  60/x + 88/y = 20--2  By solving 1 and 2  y= 11 ; x = 5  Rain in still water ... 5) km/hr = 8 km/hr  Rain of current = ½ (11 - 50) km/hr = 3 km/hr  The required answer is 8:3

Description : There are 3 poles M, N and O in a straight line such that point N is equidistant from points M and O. A boat can travel from point M to O downstream in 6 hours and from N to M upstream in 4 hours. Find the ratio of boat in still water to speed of stream. A) 2:3 B) 7:1 C) 3:2 D) 1:7

Last Answer : ANSWER: B Explanation: Let speed in still water = x km/hr, of current = y km/hr Downstream speed = (x+y) km/hr Upstream speed = (x - y) km/hr Let MO = 2p km. So MN = NO = p km.  So 2p/(x+y) = 6 --------1  p/ ... - 2y) = 6x + 6y  8x - 8y = 6x +6y  2x = 14y  x/y = 14 / 2 = 7/1  x : y = 7 :1

Description : A motorboat can cover 80 km upstream and 120 km downstream together in 26 hours. Also it can cover 100 km upstream and 144 km downstream together in 32 hours. What is the speed of the motorboat in still water? A) 12 km/hr B) 15km/hr C) 8.5km/hr D) 19km/hr 

Last Answer : ANSWER :C Explanation:  Upstream speed in both cases is 80 and 100.  Ratio is 80 : 100 = 8:10 = 4 : 5.  So let times in both cases be 4x and 5x  Downstream speed in both cases is 120 and 144 resp.  Ratio is ... 12 km/hr  So speed of boat = 1/2 * (5+12) =17/2km/hr  speed of boat = 8.5 km/hr

Description : A man goes 4km upstream of the stream in 2hr and goes 2km downstream of the stream in 20mints. How long will it take to go 10km in stationary water? A) 1hr 15mits B) 2hrs 30mints C) 5hrs 30mints D) 3hrs 45mints

Last Answer : ANSWER : B Explanation:  Rate downstream = (2/20 * 60) km/hr  = 6 km/hr  Rate upstream = 2 km/hr  Speed in still water = ½(6+2)km/hr  = 4 km/hr  Required time = distance / speed  = (10/4) hrs =(5/2)hrs =2 ½ hrs = 2hrs 30mits.

Description : A motor boat sails 30 km of a river towards upstream in 10hrs. How long will it take to cover the same distance downstream, if the speed of the current is ½ of the speed of the boat in still water. A) 1.8hrs B) 3.33hrs C) 5hrs D) None of these

Last Answer : ANSWER : B  Explanation:  Upstream speed = x –y  Downstream speed = x + y  x– y = 30/10 = 3km/hr  Again x = 2y  Therefore x – y = 3  y= 3km/hr ; x = 6km/hr  Therefore x + y = 9 km/hr  Time during downstream = 30/9 = 3.33hrs

Description :  Sakthi rows a boat at 4 km upstream in 1hour and 1 km downstream in 20 minutes. How long will he take to reach 3.5km in still water? A) 1 B) 2 C) 3 D) 4

Last Answer : ANSWER:A Explanation: Upstream Speed = 4/1 = 4km/hr Downstream Speed = 1/20 = 0.05 km/min = 0.05*60 = 3 km/hr Hence, speed of boat = 1/2( Upstream Speed + Downstream Speed) = 1/2 (4+3 ... , the time required to reach the distance of 3.5 km=DistanceCovered/Speed of boat = 3.5/3.5km/hr =1 km/hr

Description : A boatman can take the same time to row6.5km downstream and 3.5km upstream. His speed in still water 2.5 km/hr. The speed of the stream is. A) 0.75 km/hr B) 2.5 km/hr C) 1.5km/hr D) 7.5km/hr

Last Answer : ANSWER: A Explanation: Given that the speed in still water = 2.5 km/hr Let the speed of the stream be x; km/hr speed in upstream = (2.5 - x)km/hr Then time taken to cover 6.5 km downstream = 6.5 / (2.5+x) ... 5x = 8.75 + 3.5x 10 x = 7.5 x = 0.75 km/hr The speed of the stream is 0.75 km/hr

Description : A pedal boat goes 12km upstream and 14km downstream in 3hrs. It goes 15km upstream and 10.5km downstream in 3 hrs 15mints. The speed of the boat in still water is A) 10 B) 15 C) 20 D) 25 

Last Answer : ANSWER: A

Description : If a boy rows 8 km downstream in 6 hours and 4 km upstream in 4 hours then how long will he take to cover 16 km in stationary (still) water? A) 8 B) 14 C) 22 D) 16 

Last Answer : Answer: B Explanation: Distance covered in downstream = 8 km Time taken in downstream = 6 hours. Rate of downstream = 8/6=4/3 km/hr Distance covered in upstream = 4 km Time taken in upstream = 4hours. ... 3+1) = 7/6km/hr Time Taken to cover 16 km in still water = 16*6/7=14hrs (approximately)

Description : A boat takes 24 hours to cover 128 km downstream and 16 hours to cover 64 km upstream. Then the speed of the boat in still water is: A) 14/3 B) 8/7 C) 3/2 D) 9/5

Last Answer : Answer: A Explanation: Distance covered in downstream = 128km Time taken in downstream = 24 hours. Rate of downstream = distance / time = a = 128 km /24 hours = 16/3km/hr Distance covered in upstream = 64km Time taken in upstream ... / 2 = (1/2)(16/3+4) km/hr = (1/2)(28/3)km/hr = 14/3km/hr.

Description : A boat takes 27 hrs to travel a distance upstream and takes 9hrs to travel the same distance downstream. If the speed of the boat in still water is 12km/hr, then what is the velocity of the stream? A) 8km/hr B) 6km/hr C) 4km/hr D) None of these

Last Answer : ANSWER : B  Explanation: Let the velocity of the stream be ‘ y’ km/hr Then the speed of the downstream = (12 + y)km/hr The speed of the upstream = (12 – y)km/hr 9 (12 + y) = 27 (12 – y) 108 + 9y = 324 – 27y 27y + 9y = 324 - 108 36y = 216 y = 6 km/hr

Description : Explain upstream and downstream processing in biotechnology. -Biology

Last Answer : answer:

Description : Enhancer elements have all the following features except (A) They increase gene expression through a promoter (B) Each enhancer activates a specific promoter (C) They may be located far away from the promoter (D) They may be upstream or downstream from the promoter

Last Answer : Answer : B

Description : tRNA genes have (A) Upstream promoters (B) Downstream promoters (C) Intragenic promoters (D) No promoters

Last Answer : Answer : C

Description : Pick up the incorrect statement from the following for allowing workers to enter sewers A. The particular manhole and one manhole on upstream and one manhole on downstream should remain open for 30 ... entering the manhole should be advised to smoke in the sewer D. Warning signals should be erected

Last Answer : ANS: C

Description : The process of separation and purification of expressed protein before marketing is called (a) downstream processing (b) bioprocessing (c) postproduction processing (d) upstream processing.

Last Answer : (a) downstream processing