How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 4.5 M CH3OH?

How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 4.5 M CH3OH?
by

1 Answer

Answer :

The answer is 9.6 grams.
by
selected by

Related questions

How many grams of lidocaine are in 150 ml of a 2.5 M solution?

Description : How many grams of lidocaine are in 150 ml of a 2.5 M solution?

Last Answer : 150 mL of a 2.5 M lidocaine solution contain 87,9 g.

The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is

Description : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is

Last Answer : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is A. 1350 B. 900 C. 1250 D. 1150

10g sample of bleaching powder was dissolved into water to make the solution one litre. To this solution 35 mL of 1.0 M Mohr salt solution was added c

Description : 10g sample of bleaching powder was dissolved into water to make the solution one litre. To this solution 35 mL of 1.0 M Mohr salt solution was added c

Last Answer : 10g sample of bleaching powder was dissolved into water to make the solution one litre. To this solution 35 ... Cl_(2)` approximately is (mol wt = 71)

What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Description : What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Last Answer : moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml= 0.25 Lmolarity = moles/liter = 1.34 moles/0.25 L = 5.37 MSince KCl dissociates completely into K+ and Cl-, you have 5.37M of each = total of 10.74 osmolar

What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Description : What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Last Answer : moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml= 0.25 Lmolarity = moles/liter = 1.34 moles/0.25 L = 5.37 MSince KCl dissociates completely into K+ and Cl-, you have 5.37M of each = total of 10.74 osmolar

How many ml of 50 percent dextrose solution and how many ml of water are needed to prepare 4.5 L of a 1 percent solution?

Description : How many ml of 50 percent dextrose solution and how many ml of water are needed to prepare 4.5 L of a 1 percent solution?

Last Answer : 90 ml of dextrose and 4.41 litres of water.

20 gram of caustic soda are dissolved in water to prepare 500 ml of solution. Find the normality and molarity of solution.

Description : 20 gram of caustic soda are dissolved in water to prepare 500 ml of solution. Find the normality and molarity of solution.

Last Answer : Basis: 500 ml solution. Weight of solute = 20 gm Molecular weight of NaOH = 40 Gram moles of solute = 20/40 = 0.5 Molarity = Gram moles/ Volume of solution in lit  0.5/0.5 = 1 M Normality = gram equivalent of solute/ volume of solution in lit  = 0.5/0.5 = 1N 

Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will be

Description : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will be

Last Answer : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will ... B. 1.6 g C. 3.2 g D. 0.8 g

HOW TO PREPARE 200 mL O.75 N NaOH SOLUTION?

Description : HOW TO PREPARE 200 mL O.75 N NaOH SOLUTION?

Last Answer : Dissolve 6 g dry sodium hydroxide in 200 mL water.

How many ml must be added to four and 1 quarter to make 5 liters?

Description : How many ml must be added to four and 1 quarter to make 5 liters?

Last Answer : 5.00 - 4.25 = 0.750.75 x 1,000 = 750

3 gram of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the fitr

Description : 3 gram of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the fitr

Last Answer : 3 gram of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was ... B. `36 mg` C. `42 mg` D. `54 mg`

A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to

Description : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to

Last Answer : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein ... solution is `(NaOH=40, Na_(2)CO_(3)=106)`

To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of 0.3 N sodium thiosulphate solution. Use thes

Description : To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of 0.3 N sodium thiosulphate solution. Use thes

Last Answer : To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of ... strength of `H_(2)O_(2)` is 1.344 L

10 ml 0.2 Molar Na2CO3 How many grams of 0.1 Molar HCl is needed to soothe ?

Description : 10 ml 0.2 Molar Na2CO3 How many grams of 0.1 Molar HCl is needed to soothe ?

Last Answer : Na₂CO₃ + 2HCl = NaCl + CO₂ + H₂O of Na₂CO₃ , density S₁ = 0.2 M; Volume , V₁ = 10 mL HCl density S₂ = 0.1 M; Volume = V₂ 2S₁V₁ = S₂V₂ ∴ V₂ = 2S₁V₁ / S₂ = 2 0.2 10 / 0.1 = 40 mL The molecular mass of HCl , M = ... / MV₂ ∴ w = S₂MV₂ / 1000 = 0.1 36.5 40/1000 = 0.146 g (Ans.)

How many grams of Na2SO4 are required to make 350 ml of 0.5M?

Description : How many grams of Na2SO4 are required to make 350 ml of 0.5M?

Last Answer : Molar mass Na2SO4 = 142 g/mole0.5 M = 0.5 moles/L = 0.5 moles x142 g/mole = 71 g/L350 ml = 0.350 L, therefore 71 g/L x 0.35 L = 24.85 gIf using proper significant figures, it would be 20 g

What is the molarity of a soloution which contains 22.41 grams of NaCl in 50.0 mL of soloutuon?

Description : What is the molarity of a soloution which contains 22.41 grams of NaCl in 50.0 mL of soloutuon?

Last Answer : 0.4482

How many grams of solute in 1.8 L of a 3.5 M NaOH solution?

Description : How many grams of solute in 1.8 L of a 3.5 M NaOH solution?

Last Answer : The mass of NaOH is 352 g.

How many mL of 0.3M `K_(2)Cr_(2)O_(7)` (acidic) is required for complete oxidation of 5 mL of 0.2 M `SnC_(2)O_(4)` solution.

Description : How many mL of 0.3M `K_(2)Cr_(2)O_(7)` (acidic) is required for complete oxidation of 5 mL of 0.2 M `SnC_(2)O_(4)` solution.

Last Answer : How many mL of 0.3M `K_(2)Cr_(2)O_(7)` (acidic) is required for complete oxidation of 5 mL of 0.2 M `SnC_(2)O_(4)` solution.

Which of the following is least soluble in water? (a) CH3OH (b) CH3CH2OH (c) CH3SH (d) HOCH2CH2OH

Description : Which of the following is least soluble in water? (a) CH3OH (b) CH3CH2OH (c) CH3SH (d) HOCH2CH2OH

Last Answer : CH3SH

The substance whose chemical formula is CH3OH is known as w) carbonated water x) grain alcohol y) potable alcohol z) methanol

Description : The substance whose chemical formula is CH3OH is known as w) carbonated water x) grain alcohol y) potable alcohol z) methanol

Last Answer : ANSWER: Z -- METHANOL

The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1)` = molecular weight of solute) :-

Description : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1)` = molecular weight of solute) :-

Last Answer : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1 ... ))` D. `m = (1000M)/(1000rho -MM_(1))`

100 mL of 0.3 M acetic acid is shaken with 0.8 g wood charcoal. The final concentration of acetic acid in the solution after adsorption is 0.125 M. Th

Description : 100 mL of 0.3 M acetic acid is shaken with 0.8 g wood charcoal. The final concentration of acetic acid in the solution after adsorption is 0.125 M. Th

Last Answer : 100 mL of 0.3 M acetic acid is shaken with 0.8 g wood charcoal. The final concentration of acetic acid in the ... g` C. `1.31 g` D. `0.131 g`

For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating value (number of milli moles of solute

Description : For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating value (number of milli moles of solute

Last Answer : For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating ... A. `200` B. `100` C. `50` D. `25`

1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl required 50.0 mL of 0.500 M NaOH solution for

Description : 1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl required 50.0 mL of 0.500 M NaOH solution for

Last Answer : 1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl ... the metal M A. Mg B. Ca C. Sr D. Ba

25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0

Description : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0

Last Answer : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration ... B. 0.96 M C. 0.24 M D. 0.024 M

`50 mL` of `0.1 M` solution of a salt reacted with `25 mL` of `0.1 M` solution of sodium sulphite. The half reaction for the oxidation of sulphite ion

Description : `50 mL` of `0.1 M` solution of a salt reacted with `25 mL` of `0.1 M` solution of sodium sulphite. The half reaction for the oxidation of sulphite ion

Last Answer : `50 mL` of `0.1 M` solution of a salt reacted with `25 mL` of `0.1 M` solution of sodium ... was `3`, what would be the new oxidation number of metal:

The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :

Description : The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :

Last Answer : The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :

`25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04(M)` acidified `KMnO_(4)` solution. Which

Description : `25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04(M)` acidified `KMnO_(4)` solution. Which

Last Answer : `25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04 ... 3+)rarrZ^(4+)` D. `Z^(2+)rarrZ^(4+)`

25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_(7)^(2-)` . 50 mL of 0.01 M `K_(2)Cr_(2)O_(7)` solu

Description : 25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_(7)^(2-)` . 50 mL of 0.01 M `K_(2)Cr_(2)O_(7)` solu

Last Answer : 25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_ ... is the molarity of the `Fe^(2+)` solution ?

What volume in mL of a 0.10 M NaOH solution would be required to neutralize 0.0091 moles of CH3COOH in a given vinegar sample?

Description : What volume in mL of a 0.10 M NaOH solution would be required to neutralize 0.0091 moles of CH3COOH in a given vinegar sample?

Last Answer : The volume of NaOH is 99 mL.

The normal serum concentration of vitamin A in mg/100 ml is (A) 5–10 (B) 15–60 (C) 100–150 (D) 0–5

Description : The normal serum concentration of vitamin A in mg/100 ml is (A) 5–10 (B) 15–60 (C) 100–150 (D) 0–5

Last Answer : Answer : B

If the depletion of oxygen is found to be 2.5 mg/litre after incubating 2.5 ml of sewage diluted to 250 ml for 5 days at 20°C, B.O.D. of the sewage is A. 50 mg/l B. 100 mg/l C. 150 mg/l D. 250 mg/l

Description : If the depletion of oxygen is found to be 2.5 mg/litre after incubating 2.5 ml of sewage diluted to 250 ml for 5 days at 20°C, B.O.D. of the sewage is A. 50 mg/l B. 100 mg/l C. 150 mg/l D. 250 mg/l

Last Answer : ANS: D

In a solution of 45 litres of milk and water, ` 40%` is water. How many litres of milk must be added to become the ratio of milk and water ` 5 : 3` ?

Description : In a solution of 45 litres of milk and water, ` 40%` is water. How many litres of milk must be added to become the ratio of milk and water ` 5 : 3` ?

Last Answer : In a solution of 45 litres of milk and water, ` 40%` is water. How many litres of milk must be added to become the ... : 3` ? A. 8 B. 3 C. 7 D. 6

Two samples of `HCl` of `1.0 M` and `0.25 M` are mixed. Find volumes of these samples taken in order to prepare `0.75 M HCl` solution. Assume no water

Description : Two samples of `HCl` of `1.0 M` and `0.25 M` are mixed. Find volumes of these samples taken in order to prepare `0.75 M HCl` solution. Assume no water

Last Answer : Two samples of `HCl` of `1.0 M` and `0.25 M` are mixed. Find volumes of these samples taken in order ... B. 100mL, 50mL C. 40mL, 20mL D. 50mL, 25 mL

How much in cup the amount of 150 grams of milk?

Description : How much in cup the amount of 150 grams of milk?

Last Answer : Need answer

How would you prepare 3 liters of a 1.5 M NaCl solution?

Description : How would you prepare 3 liters of a 1.5 M NaCl solution?

Last Answer : 1.5 M solution contains 1.5 moles in a litre. For sodium chloride this is (58.5 x 1.5) g = 87.75 grams. For 3 litres we will need 3 times as much, i.e. 263.25 g. To make the solution, dissolve this amount of salt in water, and make the solution up to exactly 3 litres.

What intermolecular forces exist in CH3OH?

Description : What intermolecular forces exist in CH3OH?

Last Answer : Need answer

How do i Calculate the mass of 2.50 mol of CH3OH(l). Show my work and Use the appropriate number of significant digits in your final answer.?

Description : How do i Calculate the mass of 2.50 mol of CH3OH(l). Show my work and Use the appropriate number of significant digits in your final answer.?

Last Answer : Answers is the place to go to get the answers you need and to ask the questions you want

Methanol cannot be dried with anhydrous CaCl2 because - (1) CaCl2 dissolves in it (2) it is not good dehydrating agent (3) it forms a solid CaCl2 × 4CH3OH (4) it reacts with CH3OH

Description : Methanol cannot be dried with anhydrous CaCl2 because - (1) CaCl2 dissolves in it (2) it is not good dehydrating agent (3) it forms a solid CaCl2 × 4CH3OH (4) it reacts with CH3OH

Last Answer : (3) it forms a solid CaCl2 × 4CH3OH

Oil of Wintergreen (Methyl salicylate) is obtained by treating salicylic acid with (a) Methane at 150°C (b) CH3OH and conc. H2SO4 (c) Methyl chloride (d) NaOH and then CH3OH

Description : Oil of Wintergreen (Methyl salicylate) is obtained by treating salicylic acid with (a) Methane at 150°C (b) CH3OH and conc. H2SO4 (c) Methyl chloride (d) NaOH and then CH3OH

Last Answer : CH3OH and conc. H2SO4

Anisole on heating with concentrated HI gives (a) Iodobenzene (b) Phenol + CH3I (c) Iodobenzene + CH3OH (d) Phenol + CH3OH

Description : Anisole on heating with concentrated HI gives (a) Iodobenzene (b) Phenol + CH3I (c) Iodobenzene + CH3OH (d) Phenol + CH3OH

Last Answer : Phenol + CH3I

Methylamine reacts with nitrous acid to form (a) CH3CH3 (b) CH3OH (c) CH3NO2 (d) CH3CH2OH

Description : Methylamine reacts with nitrous acid to form (a) CH3CH3 (b) CH3OH (c) CH3NO2 (d) CH3CH2OH

Last Answer : CH3OH

Which of the following pairs of compounds will not form hydrogen bonds with each other? (a) CH3OH and CH3CH2OH (b) CH3SH and CH3CH2SH (c) CH3OCH3 and CH3CH2OCH2CH3 (d) CH3COOH and H2O

Description : Which of the following pairs of compounds will not form hydrogen bonds with each other? (a) CH3OH and CH3CH2OH (b) CH3SH and CH3CH2SH (c) CH3OCH3 and CH3CH2OCH2CH3 (d) CH3COOH and H2O

Last Answer : CH3OCH3 and CH3CH2OCH2CH3

Which of the following is the best method for preparing CH3Br? (a) CH3OH + Br– (b) CH3OH + HBr (c) CH3OH + Br2 (d) CH3OH + NaBr

Description : Which of the following is the best method for preparing CH3Br? (a) CH3OH + Br– (b) CH3OH + HBr (c) CH3OH + Br2 (d) CH3OH + NaBr

Last Answer : CH3OH + HBr

Which of the following has the highest boiling point? (a) CH3CH2OH (b) CH3CH2CH2CH2OH (c) CH3OH (d) CH3CH2CH2OH

Description : Which of the following has the highest boiling point? (a) CH3CH2OH (b) CH3CH2CH2CH2OH (c) CH3OH (d) CH3CH2CH2OH

Last Answer : CH3CH2CH2CH2OH

Which of the following is the strongest base? (a) HOMgBr (b) H2O (c) CH3OH (d) CH3MgBr

Description : Which of the following is the strongest base? (a) HOMgBr (b) H2O (c) CH3OH (d) CH3MgBr

Last Answer : CH3MgBr

Which of the following has the greatest solubility in CH3CH2CH2CH3? (a) CH3OH (b) CH3NH2 (c) CH3OCH3 (d) (CH3)3CH

Description : Which of the following has the greatest solubility in CH3CH2CH2CH3? (a) CH3OH (b) CH3NH2 (c) CH3OCH3 (d) (CH3)3CH

Last Answer : (CH3)3CH

Which of the following is the strongest acid? (a) HI (b) H2O (c) CH4 (d) CH3OH

Description : Which of the following is the strongest acid? (a) HI (b) H2O (c) CH4 (d) CH3OH

Last Answer : HI

Which of the following is a Lewis acid? (a) AlCl3 (b) CH3OH (c) NH3 (d) CH3OCH3

Description : Which of the following is a Lewis acid? (a) AlCl3 (b) CH3OH (c) NH3 (d) CH3OCH3

Last Answer : AlCl3

Which of the following molecules or ions is NOT formed when K metal reacts with liquid CH3OH? Is it: w) potassium ion x) hydrogen ion y) methoxy ion z) hydrogen molecule

Description : Which of the following molecules or ions is NOT formed when K metal reacts with liquid CH3OH? Is it: w) potassium ion x) hydrogen ion y) methoxy ion z) hydrogen molecule

Last Answer : ANSWER: X -- HYDROGEN ION