Description : 3 gram of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the fitr
Last Answer : 3 gram of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was ... B. `36 mg` C. `42 mg` D. `54 mg`
Description : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0
Last Answer : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration ... B. 0.96 M C. 0.24 M D. 0.024 M
Description : A 2.5 gm impure sample containing weak monoacidic base (Mol. wt. = 45) is dissolved in 100 ml water and titrated with 0.5 M HCI when of `((1)/(5))^(th
Last Answer : A 2.5 gm impure sample containing weak monoacidic base (Mol. wt. = 45) is dissolved in 100 ml ... D. Weight percentage of base in given sample is 80%.
Description : If mass of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100 mL of 0.02 M `KMnO_(4)` in acidic medium is x g and to neutralise 100 mL of
Last Answer : If mass of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100 mL of 0.02 M `KMnO_(4)` in acidic ... y is 1g D. If x is 11g then y is 5.5g
Description : If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L
Last Answer : B. 80 L
Description : 2 If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L
Description : If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μ g/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L
Description : a) 110 g of salt is present in 550g of solution. Calculate the concentration of solution. b) 10 ml of H2SO 4 is dissolved in 90 ml of H2O. Calculate the concentration of solution. -Chemistry
Last Answer : The concentration of salt is determined by the division of mass of the solute by the mass of the solution and the percentage is obtained by multiplying the value by 100. The quotient of the division of 110 by 550 is 0.2 here. So after multiplying it with 100, it is 20%. So the concentration is 20%.
Description : 3.0 ml of raw sewage is diluted to 300 ml. The D.O. concentration of the diluted sample at the beginning of the test was 8 mg/l. After 5 dayincubation at 20°C, the D.O. concentration was 5 mg/l. The BOD of raw sewerage is A. 100 mg/l B. 200 mg/l C. 300 mg/l D. 400 mg/l
Last Answer : ANS: C
Description : What is the resulting concentration (in molL) of aqueous hydrochloric acid if 500 mL of its gaseous form at 300 K and 100 kPa will be dissolved in 100 mL pure water Use 8.314 kPaL(Kmol)?
Last Answer : Feel Free to Answer
Description : 1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl required 50.0 mL of 0.500 M NaOH solution for
Last Answer : 1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl ... the metal M A. Mg B. Ca C. Sr D. Ba
Description : The normal concentration of magnesium in whole blood is (A) 0–1 mg/100 ml (B) 1–2 mg/100 ml (C) 2–4 mg/100 ml (D) 4–8 mg/100 ml
Last Answer : Answer : C
Description : The normal serum concentration of 25-hydroxycholecalciferol in ng/ml is (A) 0–8 (B) 60–100 (C) 100–150 (D) 8–55
Last Answer : Answer : D
Description : What would be the heart rate of a person if the cardiac output is 5 L, blood volume in the ventricles at the end of diastole is 100 mL and at the end of ventricular systole is 50 mL ? (a) 125 beats per minute (b) 50 beats per minute (c) 75 beats per minute (d) 100 beats per minute
Last Answer : (d) 100 beats per minute
Description : Which of the following pairs will have greater conduction and why ? (a) Copper wire at 25 °C and Copper wire at 50 °C. (b) 0.1 M acetic acid solution or 1 M acetic acid solution ?
Last Answer : (a) Copper wire at 25 °C because with increase in temperature metallic conduction decreases due to vibration of kernels. (b) 0.1 M acetic acid solution because with dilution degree of dissosciation increases and hence no. of ions.
Description : Activated Charcoal is used to remove colouring matter from pure substances by – (1) Bleaching (2) Oxidation (3) Adsorption (4) Reduction
Last Answer : (3) Adsorption Explanation: Heating wood to a very high temperature in the absence of air makes charcoal. When it is heated to an even higher temperature, about 930°C, impurities are driven from its ... . It does so by the process of adsorption, or by attracting these molecules to the surface.
Description : Activated Charcoal is used to remove colouring matter from pure substances by (1) Bleaching (2) Oxidation (3) Adsorption (4) Reduction
Last Answer : Adsorption
Description : The charcoal used to decolorize brown sugar solution is (1) Wood charcoal (2) Coconut charcoal (3) Animal charcoal (4) Sugar charcoal
Last Answer : (3) Animal charcoal Explanation: A special characteristic of animal charcoal is its power to remove substances from solution. A brown solution of raw sugar is decolourized when boiled with animal ... brown matter of peaty water or sewage, astringent principles, and certain basic salts, etc.
Description : The charcoal used to decolourise brown sugar solution is (1) Wood charcoal (2) Coconut charcoal (3) Animal charcoal (4) Sugar charcoal
Last Answer : Animal charcoal
Description : What happens when freshly precipitated Fe (OH)3 is shaken with a little amount of dilute solution of FeCl3 ?
Last Answer : Ans. It causes peptization leading to the formation of a positively charged sol of Fe (OH)3
Description : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1)` = molecular weight of solute) :-
Last Answer : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1 ... ))` D. `m = (1000M)/(1000rho -MM_(1))`
Description : What is the percentage by mass concentration of a solution made by combining 12.0 g of NaNO3 with 100.0 g of water?
Last Answer : The percentage concentration is 12 %.
Description : How many millilitres of `0.1 NH_(2)SO_(4)` solution will be required for complete reaction with a solution containing 0.125 g of pure `Na_(2)CO_(3)`?
Last Answer : How many millilitres of `0.1 NH_(2)SO_(4)` solution will be required for complete reaction with a solution containing ... .6 mL C. 26.3 mL D. 32.6 mL
Description : The normal concentration of magnesium in C.S.F is about (A) 1 mg/100 ml (B) 3 mg/100 ml (C) 5 mg/100 ml (D) 8 mg/100 ml
Last Answer : Answer : B
Description : The normal serum concentration of 24,25- dihydroxycholecalciferol in ng/ml is (A) 8–20 (B) 25–50 (C) 1–5 (D) 60–100
Description : in titration of 25 mL of the solution containing Cu2+ with the concentration of 0.01 molar , with SCN – (0.01 Molar) , if we use the indicator that changed its color in PSCN= 9. Calculate the error of titration PKSP(CuSCN) =13.4?
Last Answer : just the color change from the indicator. Thus, a careful selection of the indicator will reduce the indicator error. For example, if the equivalence point is at a pH of 8.4, then the ... are in the range of aqueous pH changes are of little use. Instead, the titrant and indicator used
Description : In the resting state plasma concentration of cortisol is (A) 0.4–2.0 µg/100 ml (B) 2.0–4.0 µg/100 ml (C) 5.0–15.0 µg/100 ml (D) 18.0–25.0 µg/100 ml
Description : The circulating concentration of ACTH in plasma is (A) 0.05 mµ/100 ml (B) 0.1–2.0 mµ/100 ml (C) 2.5–3.5 mµ/100 ml (D) 3.0–5.0 mµ/100 ml
Description : The normal serum of concentration of copper in mg/100 ml varies between (A) 0–5 (B) 50–100 (C) 100–200 (D) 200–300
Description : The normal serum concentration of vitamin A in mg/100 ml is (A) 5–10 (B) 15–60 (C) 100–150 (D) 0–5
Description : The Volume of distribution of a drug administered at a dose of 300 mg and exhibiting 30 microgram/mL instantaneous concentration in plasma shall be (A)10 L (B) 100 L (C) 1.0 L (D) 0.10 L
Last Answer : (A)10 L
Description : Of the 125 ml of glomerular filtrate produces each minute, the amount of urine formed is (a) 1 ml/mt (b) 1.5 ml/mt (c) 2.0 ml/mt (d) 5.0 ml/mt
Last Answer : Ans:(b)
Description : In a 200-ml sample of 0.030 M Na3P04 what is the concentration of Na plus?
Last Answer : 200 mL sample of 0,030 M Na3P04 contain 0,414 g sodium; the concentration of Na is 2,07 g/L.
Description : For the estimation of nitrogen, 1.4 g of an organic compound was digested by Kjeldahl method and the evolved ammonia acid absorbed in 60 mL of `M/10`
Last Answer : For the estimation of nitrogen, 1.4 g of an organic compound was digested by Kjeldahl method and the evolved ammonia ... ` B. `10%` C. `3%` D. `5%`
Description : What is the concentration in percent (vv) of a solution containing 50 mL of diethyl ether(C4H10O) in 2.5 L of solution?
Last Answer : Need answer
Description : Which of the following materials may prove unsuitable for handling acetic acid (glacial & anhydrous) at 40°C? (A) Silicone rubber, teflon, porcelain and wood (B) Nickel, monel, stainless steel and graphite (C) Aluminium, copper, high silicon iron (D) Brass, cast iron, mild steel and tin
Last Answer : (D) Brass, cast iron, mild steel and tin
Description : The normal serum acid phosphatase activity ranges from (A) 5.0–13.0 KA units/100 ml (B) 1.0–5.0 KA units/100 ml (C) 13.0–18.0 KA units/100 ml (D) 0.2–0.8 KA units/100 ml
Description : what is the density of CO GAS IF 0.196 g occupied a volume of 100 ml?
Last Answer : 100ml = 1 dm3 0.196g = 196x10-6kg Density = mass/volume Density of CO = 196x10-6 / 1 = 196x10-6 kg/dm3
Description : Flat rate parcel rates Flat Rate Parcel Boxes size Dimension of boxes (in mm) Weight (in Kg.) Tariff (in Rs.) Small - S 250*50*300 0 to 1 125 Medium - M 250*100*300 Above 1 to 2.5 200 Large - L 300*250*200 Above 2.5 to 5 400
Last Answer : Large - L 300*250*200 Above 2.5 to 5 400
Description : Gold number of haemoglobin is 0.03. Hence 100 ml of gold sol will require haemoglobin so that gold is not coagulated by 10 ml of 10% NaCl solution
Last Answer : Gold number of haemoglobin is 0.03. Hence 100 ml of gold sol will require haemoglobin so that gold is not coagulated ... B. 30 mg C. 0.30 mg D. 3 mg
Description : Which of the following aqueous solutions would hav the lowest boiling point? Would it be a 1.0 molal solution of: w) Hydrochloric acid x) Sodium Hydroxide y) Acetic Acid, z) Magnesium Chloride
Last Answer : ANSWER: Y -- ACETIC ACID
Description : The normal concentration of chlorine in mg/100 ml of C.S.F is about (A) 200 (B) 250 (C) 300 (D) 440
Description : The normal concentration of chloride in mg/100 ml of plasma is about (A) 100 (B) 200 (C) 365 (D) 450
Description : The normal concentration of chloride in mg/100 ml of whole blood is about (A) 200 (B) 250 (C) 400 (D) 450
Description : The normal concentration of potassium in cells in ng/100 ml is about (A) 100 (B) 200 (C) 350 (D) 440
Description : The normal concentration of potassium in whole blood is (A) 50 mg/100 ml (B) 100 mg/100 ml (C) 150 mg/100 ml (D) 200 mg/100 ml
Description : The normal concentration of sodium (in mg/100 ml) of human plasma is (A) 100 (B) 200 (C) 250 (D) 330
Description : The normal concentration of calcium in C.S.F is (A) 1.5–2.5 mg/100 ml (B) 2.5–4 mg/100 ml (C) 4.5–5 mg/100 ml (D) 9–10 mg/100 ml
Description : Average concentration of chloride ions in cerebrospinal fluid per 100 ml is (A) 40 mg (B) 440 mg (C) 160 mg (D) 365 mg
Description : The normal serum concentration of ceruloplasmin in mg/100 ml varies between (A) 5–10 (B) 10–20 (C) 25–43 (D) 50–100