Description : What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?
Last Answer : moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml= 0.25 Lmolarity = moles/liter = 1.34 moles/0.25 L = 5.37 MSince KCl dissociates completely into K+ and Cl-, you have 5.37M of each = total of 10.74 osmolar
Description : Which will have greater molar conductivity ? Solution containing 1 mol KCl in 200 cc or 1 mol of KCl in 500 cc.
Last Answer : Ans. 1 mol of KCl in 500 cc.
Description : `CH_(3)NH_(2)+CHCl_(3)+KOH to` Nitrogen containing compound `+KCl + H_(2)O`.
Last Answer : `CH_(3)NH_(2)+CHCl_(3)+KOH to` Nitrogen containing compound `+KCl + H_(2)O`. A. `CH_(3)-C-=N` B. `CH_(3)-NH- ... -= C^(+)` D. `CH_(3)-N^(+)-=C^(-)`
Description : How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 4.5 M CH3OH?
Last Answer : The answer is 9.6 grams.
Description : How many grams of lidocaine are in 150 ml of a 2.5 M solution?
Last Answer : 150 mL of a 2.5 M lidocaine solution contain 87,9 g.
Description : 1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl required 50.0 mL of 0.500 M NaOH solution for
Last Answer : 1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl ... the metal M A. Mg B. Ca C. Sr D. Ba
Description : If there is 0.2 M glucose along with 0.15 M NaCl in solution what is the osmolarity of this solution?
Last Answer : What is the answer ?
Description : The following solutions are isotonic (same osmolarity as the plasma): a. Harman's solution b. 0.9% saline c. 10% mannitol d. 5% glucose
Last Answer : . 5% glucose
Description : The daily water allowance for normal infant is about (A) 100–200 ml (B) 250–300 ml (C) 330–1000 ml (D) 1000–2000 ml
Last Answer : Answer : C
Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56
Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101
Description : The normal concentration of chlorine in mg/100 ml of C.S.F is about (A) 200 (B) 250 (C) 300 (D) 440
Last Answer : Answer : D
Description : The normal concentration of chloride in mg/100 ml of whole blood is about (A) 200 (B) 250 (C) 400 (D) 450
Last Answer : Answer : B
Description : Potassium content of muscle tissue in mg/100 ml is about (A) 50–100 (B) 100–150 (C) 250–400 (D) 150–200
Description : The normal concentration of sodium (in mg/100 ml) of human plasma is (A) 100 (B) 200 (C) 250 (D) 330
Description : The total serum testosterone in adult men is (A) 50–100 ng/100 ml (B) 150–250 ng/100 ml (C) 300–1000 ng/100 ml (D) 1000–3000 ng/100 ml
Description : If the depletion of oxygen is found to be 2.5 mg/litre after incubating 2.5 ml of sewage diluted to 250 ml for 5 days at 20°C, B.O.D. of the sewage is A. 50 mg/l B. 100 mg/l C. 150 mg/l D. 250 mg/l
Last Answer : ANS: D
Description : A drug (200 mg dose) administered in tablet form and as intravenous injection (50 mg dose) showed AUG of 100 and 200 microgram hr/mL, respectively. The absolute availability of the drug through oral administration is : (A) 125% (B) 250 % (C) 12.5% (D) 1.25%
Last Answer : (C) 12.5%
Description : Perday secretion of bile juice is (a) 50 ml. (b) 100 ml. (c) 250 ml (d) 600 ml
Last Answer : (d) 600 ml
Description : in titration of 25 mL of the solution containing Cu2+ with the concentration of 0.01 molar , with SCN – (0.01 Molar) , if we use the indicator that changed its color in PSCN= 9. Calculate the error of titration PKSP(CuSCN) =13.4?
Last Answer : just the color change from the indicator. Thus, a careful selection of the indicator will reduce the indicator error. For example, if the equivalence point is at a pH of 8.4, then the ... are in the range of aqueous pH changes are of little use. Instead, the titrant and indicator used
Description : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to
Last Answer : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein ... solution is `(NaOH=40, Na_(2)CO_(3)=106)`
Description : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for titration. The resulting solution is then acidified
Last Answer : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for ... +2H_(2)O " " `(Atomic weight : As = 75)
Description : What is the concentration in percent (vv) of a solution containing 50 mL of diethyl ether(C4H10O) in 2.5 L of solution?
Last Answer : Need answer
Description : A 2.5 gm impure sample containing weak monoacidic base (Mol. wt. = 45) is dissolved in 100 ml water and titrated with 0.5 M HCI when of `((1)/(5))^(th
Last Answer : A 2.5 gm impure sample containing weak monoacidic base (Mol. wt. = 45) is dissolved in 100 ml ... D. Weight percentage of base in given sample is 80%.
Description : The amount of lime, `Ca(OH)_(2)` required to remove the hardness in 60 L of pond water containing 1.62 mg of calcium bicarbonate per 100 ml of water,
Last Answer : The amount of lime, `Ca(OH)_(2)` required to remove the hardness in 60 L of pond water containing 1.62 mg of ... 0.222g` C. `2.22 g` D. `0.444 g`
Description : What is the molarity of 10.0 g of KCl in 0.500 L of solution?
Last Answer : The molarity is 0,268.
Description : By adding 1 ml of Orthotolidine solution to 100 ml chlorinated water taken after contact period, the residual chlorine makes the colour of solution (A) Yellowish (B) Greenish (C) Bluish (D) Reddish
Last Answer : (A) Yellowish
Description : Is 250 grams of water the same as 250 millimeters of water?
Last Answer : No - but try 250 milliliters.
Description : Take a 250 mL beaker/glass tumbler. Fill half of it with water. Now carefully cut a small piece of sodium metal. Dry it using filter paper and wrap it in a small piece of cotton. Put the sodium piece wrapped in cotton into the beaker. Observe carefully. -Science
Last Answer : On touching the beaker, it was felt hot. The solution turns the red litmus paper to blue which shows it is basic in nature. Blue litmus paper do not show any colour change with the solution.
Description : Laurie poured 4 cups of water into a bowl. Each cup contained 250 mL of water. Is it reasonable to say that the bowl contained 10 L?
Last Answer : A+LS No
Description : Antidiuretic hormone: a. decreases the osmolarity of urine b. decreases the volume of urine c. increases the reabsorption of water in the proximal tubules d. is synthesized in the posterior pituitary gland
Last Answer : decreases the volume of urine
Description : 10 ml 0.2 Molar Na2CO3 How many grams of 0.1 Molar HCl is needed to soothe ?
Last Answer : Na₂CO₃ + 2HCl = NaCl + CO₂ + H₂O of Na₂CO₃ , density S₁ = 0.2 M; Volume , V₁ = 10 mL HCl density S₂ = 0.1 M; Volume = V₂ 2S₁V₁ = S₂V₂ ∴ V₂ = 2S₁V₁ / S₂ = 2 0.2 10 / 0.1 = 40 mL The molecular mass of HCl , M = ... / MV₂ ∴ w = S₂MV₂ / 1000 = 0.1 36.5 40/1000 = 0.146 g (Ans.)
Description : How many grams of Na2SO4 are required to make 350 ml of 0.5M?
Last Answer : Molar mass Na2SO4 = 142 g/mole0.5 M = 0.5 moles/L = 0.5 moles x142 g/mole = 71 g/L350 ml = 0.350 L, therefore 71 g/L x 0.35 L = 24.85 gIf using proper significant figures, it would be 20 g
Description : What is the molarity of a soloution which contains 22.41 grams of NaCl in 50.0 mL of soloutuon?
Last Answer : 0.4482
Description : How would you make 100 grams of a saltwater solution that is 20 percent salt.?
Description : A tube of uniform cross sectional sectional area `1 cm^(2)` is closed at one end with semi permeable membrane. A solution having 6g glucose per 100 ml
Last Answer : A tube of uniform cross sectional sectional area `1 cm^(2)` is closed at one end with semi permeable membrane. A ... k^(-1)`, density of Hg=13.8 g/cc)
Description : Gold number of haemoglobin is 0.03. Hence 100 ml of gold sol will require haemoglobin so that gold is not coagulated by 10 ml of 10% NaCl solution
Last Answer : Gold number of haemoglobin is 0.03. Hence 100 ml of gold sol will require haemoglobin so that gold is not coagulated ... B. 30 mg C. 0.30 mg D. 3 mg
Description : Number of equivalents of HCl present in 100 mL of its solution whose pH is 4:
Last Answer : Number of equivalents of HCl present in 100 mL of its solution whose pH is 4: A. `10^(-4)` B. `10^(-3)` C. `10^(-2)` D. `10^(-5)`
Description : 100 mL of 0.3 M acetic acid is shaken with 0.8 g wood charcoal. The final concentration of acetic acid in the solution after adsorption is 0.125 M. Th
Last Answer : 100 mL of 0.3 M acetic acid is shaken with 0.8 g wood charcoal. The final concentration of acetic acid in the ... g` C. `1.31 g` D. `0.131 g`
Description : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will be
Last Answer : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will ... B. 1.6 g C. 3.2 g D. 0.8 g
Description : The pressure is changed from 500 kPa to 250 kPa. What would you expect the new volume to be if the initial volume is 200 mL?
Last Answer : 400 mL(Explanation): again boyle's law PV=PV. Since the pressure is halved (500 to 250), then the volume must be doubled in order to maintain this equation. 200 x2=400 so that's the answer
Description : For the just coagultion of 250 mL of `Fe(OH)_(3)` sol, 2 mL of `1 M Na_(2)SO_(4)` electrolyte is required. What is the coagulating value of `Na_(2)SO_
Last Answer : For the just coagultion of 250 mL of `Fe(OH)_(3)` sol, 2 mL of `1 M Na_(2)SO_(4)` ... What is the coagulating value of `Na_(2)SO_(4)` electrolyte.
Description : Express the ratio ` 1. 5` litres : 250 ml in the lowest terms.
Last Answer : Express the ratio ` 1. 5` litres : 250 ml in the lowest terms.
Description : How many 250 ml glasses can be filled from 2.5 l container of juice?
Last Answer : ten2.5 / 0.25 = 10
Description : What is 250 ml as a fraction of a litre?
Last Answer : 250/1,000 = 25/100 = 5/20 = 1/4
Description : The amount of air breathed in and out in a single quiet respiration is about (a) 250 ml (b) 500 ml (c) 750 ml (d) 1000 ml
Last Answer : Ans:(d)
Description : In man, the bile juice secreted per day is (a) 250 ml (b) 600 ml (c) 1000 ml (d) 1500 ml
Last Answer : (b) 600 ml
Description : Select the correct order of osmolarity changes in fillrate w.r.t. plasma in `:-` Bowmans capsul `rarr` PCT `rarr` Descending loop of henle `rarr `Asce
Last Answer : Select the correct order of osmolarity changes in fillrate w.r.t. plasma in `:-` Bowmans ... `rarr` Isotonic `rarr` Hypotonic `rarr` Hypertonic
Description : Which of the following play a significant role in the maintenance of high osmolarity of cortex interstitial fluid ?
Last Answer : Which of the following play a significant role in the maintenance of high osmolarity of cortex interstitial fluid ? ... B. DCT C. PCT D. NaCl and urea
Description : The high osmolarity of the renal medulla is maintained by all of the following except (i) Active transport of salt from the upper region of the ascend
Last Answer : The high osmolarity of the renal medulla is maintained by all of the following except (i) Active transport of salt ... v C. ii and iii D. iv and v