Description : The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :
Last Answer : The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :
Description : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is
Last Answer : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is A. 1350 B. 900 C. 1250 D. 1150
Description : 1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl required 50.0 mL of 0.500 M NaOH solution for
Last Answer : 1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl ... the metal M A. Mg B. Ca C. Sr D. Ba
Description : For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating value (number of milli moles of solute
Last Answer : For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating ... A. `200` B. `100` C. `50` D. `25`
Description : The number of ml of N/10 KOH required to neutralize the fatty acids in the distillate from 5 gm of fat is called (A) Reichert-Meissel number (B) Polenske number (C) Acetyl number (D) Non volatile fatty acid number
Last Answer : Answer : A
Description : Number of ml of 0.1 N KOH required to neutralize fatty acids from 5 gms of fat: (A) Iodine number (B) Polenske number (C) Reichert-Miessl number (D) None of these
Last Answer : Answer : B
Description : Study the following table and choose the correct option: Salt - Parent Acid - Parent Base - Nature of Salt (a) Soidum Chloride - HCI - NaOH - Basic (b) Sodium Carbonate - H2CO3 - NaOH - Neutral (c) Sodium Sulphate - H2SO4 - NaOH - Acidic (d) Sodium Acetate - CH3COOH - NaOH - Basic
Last Answer : Answer: (d) Sodium Acetate - CH3COOH - NaOH - Basic
Description : The volume of `0.1 N` dibasic acid sufficient to neutralize 1g of a base that furnishes `0.04` mole of `OH^-` in aqueous solution is :
Last Answer : The volume of `0.1 N` dibasic acid sufficient to neutralize 1g of a base that furnishes `0.04` mole of `OH^-` ... 400 mL B. 600 mL C. 200 mL D. 80 mL
Description : 10g sample of bleaching powder was dissolved into water to make the solution one litre. To this solution 35 mL of 1.0 M Mohr salt solution was added c
Last Answer : 10g sample of bleaching powder was dissolved into water to make the solution one litre. To this solution 35 ... Cl_(2)` approximately is (mol wt = 71)
Description : 25 ml of the given HCl solution requires 30 mL of 0.1M sodium carbonate solution. What is the volume of this HCl solution required to titrate 30 mL of
Last Answer : 25 ml of the given HCl solution requires 30 mL of 0.1M sodium carbonate solution. What is the volume of this HCl ... 5 mL B. 75 mL C. 50 mL D. 25 mL
Description : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to
Last Answer : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein ... solution is `(NaOH=40, Na_(2)CO_(3)=106)`
Description : What is the molarity of a solution made by dissolving 6 moles of naoh in 3 kg?
Last Answer : Need answer
Description : a gas has a pressure of 766.7 torr at a temperature of 10.0°C. the sample contains 2.35 moles of xenon. what is the volume of the gas in liters?
Last Answer : Using PV=nRT, 10.0ºC = 283.15ºK, R = 62.36 L torr/mol KV= (nRT)/PV = (2.35m*(62.36 L torr/mol K)*283.15ºK)/766.7 TorrV = 54.12 L
Description : HOW TO PREPARE 200 mL O.75 N NaOH SOLUTION?
Last Answer : Dissolve 6 g dry sodium hydroxide in 200 mL water.
Description : The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present in `30 mL` of `0.01M` solution of `[Cr(H_(2)O)_(
Last Answer : The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present ... Cl]Cl_(2)`, as silver chloride is close to:
Description : Why is the weight of 5 ml vinegar almost equal to its volume?
Last Answer : Water has a density of 1 gram per cubic centimetre because it is defined that way and vinegar is mostly water.
Description : How many mL of 0.3M `K_(2)Cr_(2)O_(7)` (acidic) is required for complete oxidation of 5 mL of 0.2 M `SnC_(2)O_(4)` solution.
Last Answer : How many mL of 0.3M `K_(2)Cr_(2)O_(7)` (acidic) is required for complete oxidation of 5 mL of 0.2 M `SnC_(2)O_(4)` solution.
Description : In a first order reaction, the time required to reduce the concentration of reactant from 1 mole/litre to 0.5 mole/litre will be __________ that requiredto reduce it from 10 moles/litre to 5 moles/litre in the ... (A) More than (B) Less than (C) Same as (D) Data insufficient; can't be predicted
Last Answer : (C) Same as
Description : A 2.5 gm impure sample containing weak monoacidic base (Mol. wt. = 45) is dissolved in 100 ml water and titrated with 0.5 M HCI when of `((1)/(5))^(th
Last Answer : A 2.5 gm impure sample containing weak monoacidic base (Mol. wt. = 45) is dissolved in 100 ml ... D. Weight percentage of base in given sample is 80%.
Description : A 100 mL sample of water was treated to convert any iron present to `Fe^(2+)`. Addition of 25 mL of 0.002 M `K_(2)Cr_(2)O_(7)` resulted in the reactio
Last Answer : A 100 mL sample of water was treated to convert any iron present to `Fe^(2+)`. Addition of 25 ... parts per million (ppm) of iron in the water sample.
Description : In a 200-ml sample of 0.030 M Na3P04 what is the concentration of Na plus?
Last Answer : 200 mL sample of 0,030 M Na3P04 contain 0,414 g sodium; the concentration of Na is 2,07 g/L.
Description : The number of milliliters of 0.1 N KOH required to neutralize the insoluble fatty acids from 5 gms of fat is called (A) Acid number (B) Acetyl number (C) Halogenation (D) Polenske number
Last Answer : Answer : D
Description : The amount of wet NaOH containing 15% water required to prepare 70 liters of 0.5 N solution is:
Last Answer : The amount of wet NaOH containing 15% water required to prepare 70 liters of 0.5 N solution is: A. 1.65 kg B. 1.4 kg C. 16.5 kg D. 140 kg
Description : In the hofmann-bromamide degradation reaction, the number of moles of NaOH and `Br_(2)` used per mole of amine produced are
Last Answer : In the hofmann-bromamide degradation reaction, the number of moles of NaOH and `Br_(2)` used per mole of ... moles of NaOH and one mole of `Br_(2)`
Description : Complete hydrolysis product of 1 mole each of following will need how many total number of moles of NaOH for complete neutralisation? `SOCl_(2), SO_(2
Last Answer : Complete hydrolysis product of 1 mole each of following will need how many total number of moles of NaOH for ... ), PCl_(3), PCl_(5), NCl_(3)`
Description : Rate constant for a first order reaction does not depend upon reaction time, extent of reaction and the initial concentration of reactants; but it is afunction of reaction temperature. In a chemical reaction, the time required to ... Then the order of this reaction is: (A) 0 (B) 1 (C) 2 (D) 3
Last Answer : (B) 1
Description : Which of the following is NOT a general property of hydroxide bases in aqueous solution? w) High solubility x) Bitter taste y) Ability to neutralize aqueous acid solutions z) Ability to change phenolphthalein from colorless to red
Last Answer : ANSWER: W -- HIGH SOLUBILITY (The hydroxides of the alkali metals are soluble in water but all the other metal hydroxides are only moderately or sparingly soluble.)
Description : One litre of a solution contains 18.9 g of `HNO_(3)` and one litre of another solution contains 3.2 g of NaOH. In what volume ratio must these solutio
Last Answer : One litre of a solution contains 18.9 g of `HNO_(3)` and one litre of another solution contains 3.2 g of NaOH. In ... B. `8:3` C. `15:4` D. `4:15`
Description : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0
Last Answer : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration ... B. 0.96 M C. 0.24 M D. 0.024 M
Description : How many moles are in a sample containing 2.71 x 10^24 atoms of iron?
Last Answer : two or three
Description : What volume of water is requried to make `0.20 N` solution from `1600 mL` of `0.2050 N` solution?
Last Answer : What volume of water is requried to make `0.20 N` solution from `1600 mL` of `0.2050 N` solution? A. 40 mL B ... to `H_(3)AsO_(4)` C. 100 mL D. 20 mL
Description : What volume (in mL) of 0.25M NaSO4 solution is needed to precipitate all the barium as BaSO4(s) from 12.5mL of 0.15M Ba(NO3)2 solution?
Last Answer : The chemical equation is:Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3The volume (in mL) of 0,25M Na2SO4 solution needed to precipitate all the barium as BaSO4(s) from 12,5mL of 0,15M Ba(NO3)2 solution is 7,5 mL.
Description : Saponification number is (A) mg of KOH required to saponify one gm of fat or oil (B) mg of KOH required to neutralize free fatty acids of one gms of fat (C) mg of KOH required to neutralize the acetic acid obtained by saponification of one gm of fat after it has been acetylated (D) None of these
Last Answer : Answer : C
Description : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1)` = molecular weight of solute) :-
Last Answer : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1 ... ))` D. `m = (1000M)/(1000rho -MM_(1))`
Description : Number of particles in a crushed solid sample is given by (where, m = mass of particles in a sample, Vp = volume of one particle, ρ= density of particles) (A) m/ρ . Vp (B) m . ρ/Vp (C) m . Vp /ρ (D) Vp /m . ρ
Last Answer : (A) m/ρ . Vp
Description : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)
Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated ... 56 mL B. 112 mL C. 168 mL D. 224 mL
Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required ... . 0.8 g C. 4.2 g D. 0.98 g
Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required ... 37.2 mL C. 5.6 mL D. 22.4 mL
Description : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for titration. The resulting solution is then acidified
Last Answer : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for ... +2H_(2)O " " `(Atomic weight : As = 75)
Description : How many grams of solute in 1.8 L of a 3.5 M NaOH solution?
Last Answer : The mass of NaOH is 352 g.
Description : 3.0 ml of raw sewage is diluted to 300 ml. The D.O. concentration of the diluted sample at the beginning of the test was 8 mg/l. After 5 dayincubation at 20°C, the D.O. concentration was 5 mg/l. The BOD of raw sewerage is A. 100 mg/l B. 200 mg/l C. 300 mg/l D. 400 mg/l
Last Answer : ANS: C
Description : 100 mL of 0.3 M acetic acid is shaken with 0.8 g wood charcoal. The final concentration of acetic acid in the solution after adsorption is 0.125 M. Th
Last Answer : 100 mL of 0.3 M acetic acid is shaken with 0.8 g wood charcoal. The final concentration of acetic acid in the ... g` C. `1.31 g` D. `0.131 g`
Description : `50 mL` of `0.1 M` solution of a salt reacted with `25 mL` of `0.1 M` solution of sodium sulphite. The half reaction for the oxidation of sulphite ion
Last Answer : `50 mL` of `0.1 M` solution of a salt reacted with `25 mL` of `0.1 M` solution of sodium ... was `3`, what would be the new oxidation number of metal:
Description : `25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04(M)` acidified `KMnO_(4)` solution. Which
Last Answer : `25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04 ... 3+)rarrZ^(4+)` D. `Z^(2+)rarrZ^(4+)`
Description : 25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_(7)^(2-)` . 50 mL of 0.01 M `K_(2)Cr_(2)O_(7)` solu
Last Answer : 25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_ ... is the molarity of the `Fe^(2+)` solution ?
Description : What is .0091 to the thousandths?
Last Answer : It is .009 when rounded to the nearest thousandth
Description : The device in figure 'B' shown in the illustration can be used to control an AC load yet maintain its high gain by ______________. EL-0091 A. connecting the load to the output side of the ... connecting the load to the input side of the bridge D. reversing the current flow through the bias winding
Last Answer : Answer: C
Description : What type of current would flow through the load in figure 'B' shown in the illustration? EL-0091 A. AC only B. DC only C. AC or DC depending on control winding polarity D. AC or DC depending on instantaneous polarity of the source
Last Answer : Answer: B
Description : The purpose of the bias winding in figure 'B' shown in the illustration is for ____________. EL-0091 A. changing the direction of current in the control winding B. setting the operating point of the ... use of either AC or DC in the load circuit D. changing the direction of current through the load