Let C be a binary linear code with minimum distance 2t + 1 then it can correct upto ............bits of error. (1) t + 1 (2) t (3) t - 2 (4) t/2

1 Answer

Answer :

(2) t 

Related questions

Description : Let C be a binary linear code with minimum distance 2t + 1 then it can correct upto _____ bits of error. a. t + 1 b. t c. t - 2 d. t / 2

Last Answer : b. t

Description : To guarantee correction of upto t errors, the minimum Hamming distance d min in a block code must be ________. a. t+1 b. t−2 c. 2t−1 d. 2t+1

Last Answer : d. 2t+1

Description : Let G(x) be generator polynomial used for CRC checking. The condition that should be satisfied by G(x) to correct odd numbered error bits, will be: (1) (1+x) is factor of G(x) (2) (1-x) is factor of G(x) (3) (1+x2) is factor of G(x) (4) x is factor of G(x)

Last Answer : (1+x) is factor of G(x)

Description : For any B-tree of minimum degree t ≥2, every node other than the root must have atleast ............... keys and every node can have at most .............. keys. (A) t-1, 2t+1 (B) t+1, 2t+1 (C) t-1, 2t-1 (D) t+1, 2t-1

Last Answer : (C) t-1, 2t-1 

Description : A t-error correcting q-nary linear code must satisfy:  Where M is the number of code words and X is (1) qn (2) qt (3) q-n (4) q-t

Last Answer : (1) qn 

Description : The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channel capacity. Assuming that processing ... maximum utilization, when the sliding window protocol used is: a. A b. B c. C d. D

Last Answer : c. C

Description : The solution of recurrence relation, T(n) = 2T(floor (√n)) + logn is (A) O(n log log logn) (B) O(n log logn) (C) O(log logn) (D) O(logn log logn)

Last Answer : (D) O(logn log logn)

Description : The asymptotic upper bound solution of the recurrence relation given by T(n)= 2T(n/2)+n/log n is: (1) O(n2) (2) O(n log n) (3) O(n log log n) (4) O(log log n)

Last Answer : (3) O(n log log n) 

Description : The start and stop bits are used in serial communication for (A) error detection (B) error correction (C) synchronization (D) slowing down the communication

Last Answer : (C) synchronization 

Description : What is the difference between linear and binary search?

Last Answer : A: Linear search does not require the array to be sorted, whereas, binary search requires that the array be sorted. Linear search checks for the search item in a linear fashion from the beginning cell till the end, ... tell what is control variable in your loop. So if your loop is for(int i = 1; i

Description : In ……………, search start at the beginning of the list and check every element in the list. A) Linear search B) Binary search C) Hash Search D) Binary Tree search

Last Answer : A) Linear search

Description : In a binary Hamming code the number of check digits is r then number of message digits is equal to: (A) 2r-1 (B) 2r-r-1 (C) 2r-r+1 (D) 2r+r-1

Last Answer : (B) 2r-r-1

Description : The virtual address generated by a CPU is 32 bits. The Translation Lookaside Buffer (TLB) can hold total 64 page table entries and a 4-way set associative (i.e. with 4- cache lines in the set). The page size is 4 KB. The minimum size of TLB tag is (A) 12 bits (B) 15 bits (C) 16 bits (D) 20 bits

Last Answer : (C) 16 bits Explanation: VirtualAddress = 32 bits PageSize = 4KB = 12 bits therefore : VPNTag = 20 bits, OffsetTag = 12 bits TLBEntryLength = VPNTag = 20 bits TotalTLBEntries = 64, 4-way implies ... therefore : TLBIndex = 4 bits TLBTag = TLBEntryLength - TLBIndex = 20 - 4 = 16 bits

Description : hat is the output when following code is executed ? >>>print r"\nhello" The output is a) a new line and hello b) \nhello c) the letter r and then hello d) error

Last Answer : d) error

Description : A data file of 1,00,000 characters contains only the characters g-l, with the frequencies as indicated in table:  using the variable-length code by Huffman codes, the file can be encoded with (A) 2,52,000 bits (B) 2,64,000 bits (C) 2,46,000 bits (D) 2,24,000 bits

Last Answer : (D) 2,24,000 bits 

Description : Given the symbols A, B, C, D, E, F, G and H with the probabilities 1/30, 1/30, 1/30, 2/30, 3/30, 5/30, 5/30 and 12/30 respectively. The average Huffman code size in bits per symbol is: (A) 67/30 (B) 70/34 (C) 76/30 (D) 78/30

Last Answer : (C) 76/30

Description : Consider a source with symbols A, B, C, D with probabilities 1/2, 1/4, 1/8, 1/8 respectively. What is the average number of bits per symbol for the Huffman code generated from above information? (A) 2 bits per symbol (B) 1.75 bits per symbol (C) 1.50 bits per symbol (D) 1.25 bits per symbol

Last Answer : (B) 1.75 bits per symbol

Description : Let R and S be two fuzzy relations defined as: Then, the resulting relation, T, which relates elements of universe x to elements of universe z using max-min composition is given by

Last Answer : Answer: C

Description : Let G(x) be the generator polynomial used for CRC checking. What is the condition that should be satisfied by G(x) to detect odd number of bits in error? a. G(x) contains more than two terms b. G(x) does ... exceeding the frame length c. 1+x is a factor of G(x) d. G(x) has an odd number of terms

Last Answer : c. 1+x is a factor of G(x)

Description : The command javac A) Converts a java program into binary code B) Converts a java program into bytecode C) Converts a java program into machine language D) None of the above.

Last Answer : B) Converts a java program into bytecode

Description : Binary code "0" means ............ A) State of absence B) State of presence C) State of Negative D) State of Positive

Last Answer : B) State of presence

Description : The Excess-3 decimal code is a self-complementing code because (A) The binary sum of a code and its 9’s complement is equal to 9. (B) It is a weighted code. (C) Complement can be generated by inverting each bit pattern. (D) The binary sum of a code and its 10’s complement is equal to 9.

Last Answer : Answer: A, C

Description : A string of linear mass density 0.005 kg/m is stretched by a force F=2t^2 N

Last Answer : A string of linear mass density 0.005 kg/m is stretched by a force F=2t^2 N ( t is in sec) as shown in figure. ... 24.5 m/s C) 32 m/s D) 40 m/s

Description : If T and R are tread and rise respectively of a stair, then (A) 2R + T = 60 (B) R + 2T = 60 (C) 2R + T = 30 (D) R + 2T = 30

Last Answer : Answer: Option A

Description : Group of binary bits(0&1) is known as: a. Binary code b. Digit code

Last Answer : a. Binary code

Description : If a modulating wave is sampled 10 times per cycle with a 5-element binary code, how many bits of information are required to transmit the signal?

Last Answer : 28. 50.

Description : Let E1 and E2 be two entities in E-R diagram with simple single valued attributes. R1 and R2 are two relationships between E1 and E2 where R1 is one-many and R2 is many-many. R1 and R2 do not have any ... are required to represent this situation in the Relational Model? (A) 4 (B) 3 (C) 2 (D) 1

Last Answer : (B) 3 

Description : Let M and N be two entities in an E-R diagram with simple single vale attributes. R1 and R2 are two relationship between M and N, whereas R1 is one-to-many and R2 is many-to-many. The minimum number of tables required to ... and R2 in the relational model are .......... (1) 4 (2) 6 (3) 7 (4) 3

Last Answer : Answer: 4

Description : Match the following HTTP status code to their respective definitions. i) 400 a) OK ii) 500 b) Not found iii) 200 c) Continue iv) 100 d) Internal server error A) i-b, ii-d, iii-a, iv-c B) i-a, ii-b, iii-c, iv-d C) i-b, ii-c, iii-a, iv-d D) i-b, ii-a, iii-c, iv-d

Last Answer : A) i-b, ii-d, iii-a, iv-c

Description : Match the following HTTP status code to their respective definitions. i) 400 a) OK ii) 500 b) Not found iii) 200 c) Continue iv) 100 d) Internal server error A) i-b, ii-d, iii-a, iv-c B) i-a, ii-b, iii-c, iv-d C) i-b, ii-c, iii-a, iv-d D) i-b, ii-a, iii-c, iv-d

Last Answer : A) i-b, ii-d, iii-a, iv-c

Description : What is the output of the following code? a={1:"A",2:"B",3:"C"} a.setdefault(4,"D") print(a) a) {1: ‘A’, 2: ‘B’, 3: ‘C’, 4: ‘D’}. b) None. c) Error.

Last Answer : a) {1: ‘A’, 2: ‘B’, 3: ‘C’, 4: ‘D’}.

Description : What is the output of the following code? a={1:"A",2:"B",3:"C"} print(a.get(5,4)) a) Error, invalid syntax b) A c) 5 d) 4

Last Answer : d) 4

Description : What is the output of the following code? >>> a=(1,2,3,4) >>> del(a[2]) a) Now, a=(1,2,4) b) Now, a=(1,3,4) c) Now a=(3,4) d) Error as tuple is immutable

Last Answer : d) Error as tuple is immutable

Description : What is the output when following code is executed ? >>>list1 = [11, 2, 23] >>>list2 = [11, 2, 2] >>>list1 < list2 is a) True b) False c) Error d) None

Last Answer : b) False

Description : What is the output when following code is executed ? >>>names = ['Amir', 'Bear', 'Charlton', 'Daman'] >>>print(names[-1][-1]) a) A b) Daman c) Error d) n

Last Answer : b) Daman

Description : IPv4 and IPv6 are addresses used to identify computers on the internet. Find the correct statement out of the following: (A) Number of bits required for IPv4 address is more than number of bits required for ... of bits required for IPv6 address. (D) Number of bits required for IPv4 address is 64. 

Last Answer : (C) Number of bits required for IPv4 address is less than number of bits required for IPv6 address.

Description : The baud rate of a signal is 600 baud/second. If each signal unit carries 6 bits, then the bit rate of a signal is ................. (A) 3600 (B) 100 (C) 6/600 (D) None of the above

Last Answer : (A) 3600 

Description : An analog signal carries 4 bits in each signal unit. If 1000 signal units are sent per second, then baud rate and bit rate of the signal are ............... and .............. (A) 4000 bauds \ sec & ... (B) 2000 bauds \ sec & 1000 bps (C) 1000 bauds \ sec & 500 bps (D) 1000 bauds \ sec & 4000 bps

Last Answer : (D) 1000 bauds \ sec & 4000 bps Explanation: Bit rate is the number of bits per second. Baud rate is the number of signal units per second. Baud rate is less than or equal to the bit rate. Baud rate = 1000 bauds per second (baud/s) Bit rate = 1000 x 4 = 4000 bps

Description : Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ... ...... (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps

Last Answer : Answer: Marks given to all

Description : _______ can detect burst error of length less than or equal to degree of the polynomial and detects burst errors that affect odd number of bits. a. Hamming Code b. CRC c. VRC d. None of the above

Last Answer : b. CRC

Description : The original ASCII code used…bits of each byte, reserving that last bit for error checking a. 5 b. 6 c. 7 d. 8

Last Answer : c. 7

Description : The original ASCII code used…bits of each byte, reserving that last bit for error checking a. 5 b. 6 c. 7 d. 8

Last Answer : c. 7

Description : If X is a binary number which is power of 2, then the value of X&(X-1) is: (1) 11....11 (2) 00.....00 (3) 100.....0 (4) 000.....1

Last Answer : Answer: 2

Description : ……………….. is a high performance fiber optic token ring LAN running at 100 Mbps over distances upto 1000 stations connected. A) FDDI B) FDDT C) FDDR D) FOTR

Last Answer : A) FDDI

Description : The compiler converts all operands upto the type of the largest operand is called (A) Type Promotion (B) Type Evaluation (C) Type Conversion (D) Type Declaration

Last Answer : (A) Type Promotion 

Description : Consider a system with twelve magnetic tape drives and three processes P1, P2 and P3. Process P1 requires maximum ten tape drives, process P2 may need as many as four tape drives and P3 may need upto nine ... , system is in: (A) safe state (B) unsafe state (C) deadlocked state (D) starvation state

Last Answer : Answer: B

Description : Refer to CAP697 MRJT1 Fig. 4.3.1 Given: Estimated zero fuel mass 50t; estimated landing mass at destination 52t; final reserve fuel 2t; alternate fuel 1t; flight to destination distance 720nm, true course 030, W/V ... b. 4,400kg / 02hr 02min c. 4,750kg / 02hr 00min d. 4,600kg / 02hr 05min

Last Answer : a. 4,800kg / 01hr 45min

Description : The number of disk pages access in B-tree search, where h is height, n is the number of keys, and t is the minimum degree, is: (A) θ(logn h*t) (B) θ(logt n*h) (C) θ(logh n) (D) θ(logt n)

Last Answer : Answer: D