Consider a source with symbols A, B, C, D with probabilities 1/2, 1/4, 1/8, 1/8 respectively. What is the average number of bits per symbol for the Huffman code generated from above information? (A) 2 bits per symbol (B) 1.75 bits per symbol (C) 1.50 bits per symbol (D) 1.25 bits per symbol

Consider a source with symbols A, B, C, D with probabilities 1/2, 1/4, 1/8, 1/8 respectively. What is the average number of bits per symbol for the Huffman code generated from above information? (A) 2 bits per symbol (B) 1.75 bits per symbol (C) 1.50 bits per symbol (D) 1.25 bits per symbol
by

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Answer :

(B) 1.75 bits per symbol
by

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Given the symbols A, B, C, D, E, F, G and H with the probabilities 1/30, 1/30, 1/30, 2/30, 3/30, 5/30, 5/30 and 12/30 respectively. The average Huffman code size in bits per symbol is: (A) 67/30 (B) 70/34 (C) 76/30 (D) 78/30

Description : Given the symbols A, B, C, D, E, F, G and H with the probabilities 1/30, 1/30, 1/30, 2/30, 3/30, 5/30, 5/30 and 12/30 respectively. The average Huffman code size in bits per symbol is: (A) 67/30 (B) 70/34 (C) 76/30 (D) 78/30

Last Answer : (C) 76/30

A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is A. 8.0 bit B. 2.0 bit C. 1.9 bit D. 2.1 bit

Description : A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is A. 8.0 bit B. 2.0 bit C. 1.9 bit D. 2.1 bit

Last Answer : C. 1.9 bit

A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is a. 8.0 bit b. 2.0 bit c. 1.9 bit d. 2.1 bit

Description : A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is a. 8.0 bit b. 2.0 bit c. 1.9 bit d. 2.1 bit

Last Answer : c. 1.9 bit

A data file of 1,00,000 characters contains only the characters g-l, with the frequencies as indicated in table: using the variable-length code by Huffman codes, the file can be encoded with (A) 2,52,000 bits (B) 2,64,000 bits (C) 2,46,000 bits (D) 2,24,000 bits

Description : A data file of 1,00,000 characters contains only the characters g-l, with the frequencies as indicated in table:  using the variable-length code by Huffman codes, the file can be encoded with (A) 2,52,000 bits (B) 2,64,000 bits (C) 2,46,000 bits (D) 2,24,000 bits

Last Answer : (D) 2,24,000 bits 

The number of function points of a proposed system is calculated as 500. Suppose that the system is planned to be developed in Java and the LOC/FP ratio of Java is 50. Estimate the effort (E) required to complete the project using the effort formula of basic COCOMO given below: E = a(KLOC)b Assume that the values of a and b are 2.5 and 1.0 respectively. (A) 25 person months (B) 75 person months (C) 62.5 person months (D) 72.5 person months

Description : The number of function points of a proposed system is calculated as 500. Suppose that the system is planned to be developed in Java and the LOC/FP ratio of Java is 50. Estimate the effort (E) required to ... ) 25 person months (B) 75 person months (C) 62.5 person months (D) 72.5 person months

Last Answer : (C) 62.5 person months 

Consider a discrete memoryless channel and assume that H(x) is the amount of information per symbol at the input of the channel; H(y) is the amount of information per symbol at the output of the channel; H(x|y) is the amount of uncertainty remaining on x knowing y; and I(x;y) is the information transmission. Which of the following does not define the channel capacity of a discrete memoryless channel?

Description : Consider a discrete memoryless channel and assume that H(x) is the amount of information per symbol at the input of the channel; H(y) is the amount of information per symbol at the output of the channel; H(x|y) is the amount of uncertainty ... (H(x) - H(x|y))]  p(x) (D) max H(x|y)  p(x)

Last Answer : (D) max H(x|y)   p(x)

A source code whose average word length approaches the fundamental limit set by the entropy of a discrete memoryless source. A. Prefix code B. Huffman code C. Entropy code D. Source code

Description : A source code whose average word length approaches the fundamental limit set by the entropy of a discrete memoryless source. A. Prefix code B. Huffman code C. Entropy code D. Source code

Last Answer : B. Huffman code

A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps

Last Answer : (A) 2 Mbps Explanation: In data transmission, throughput is the amount of data moved successfully from one place to another in a given period of time, and typically measured in bits per second (bps), ... second (Mbps) or gigabits per second (Gbps). Here, Throughput = 15000 x 8000/60 = 2 Mbps 

Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ................ (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps

Description : Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ... ...... (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps

Last Answer : Answer: Marks given to all

The virtual address generated by a CPU is 32 bits. The Translation Lookaside Buffer (TLB) can hold total 64 page table entries and a 4-way set associative (i.e. with 4- cache lines in the set). The page size is 4 KB. The minimum size of TLB tag is (A) 12 bits (B) 15 bits (C) 16 bits (D) 20 bits

Description : The virtual address generated by a CPU is 32 bits. The Translation Lookaside Buffer (TLB) can hold total 64 page table entries and a 4-way set associative (i.e. with 4- cache lines in the set). The page size is 4 KB. The minimum size of TLB tag is (A) 12 bits (B) 15 bits (C) 16 bits (D) 20 bits

Last Answer : (C) 16 bits Explanation: VirtualAddress = 32 bits PageSize = 4KB = 12 bits therefore : VPNTag = 20 bits, OffsetTag = 12 bits TLBEntryLength = VPNTag = 20 bits TotalTLBEntries = 64, 4-way implies ... therefore : TLBIndex = 4 bits TLBTag = TLBEntryLength - TLBIndex = 20 - 4 = 16 bits

Shift-Reduce parsers perform the following : (A) Shift step that advances in the input stream by K(K>1) symbols and Reduce step that applies a completed grammar rule to some recent parse trees, joining them together as one tree with a new root symbol. (B) Shift step that advances in the input stream by one symbol and Reduce step that applies a completed grammar rule to some recent parse trees, joining them together as one tree with a new root symbol. (C) Shift step that advances in the input stream by K(K = 2) symbols and Reduce step that applies a completed grammar rule to form a single tree. (D) Shift step that does not advance in the input stream and Reduce step that applies a completed grammar rule to form a single tree.

Description : Shift-Reduce parsers perform the following : (A) Shift step that advances in the input stream by K(K>1) symbols and Reduce step that applies a completed grammar rule to some recent parse trees, ... in the input stream and Reduce step that applies a completed grammar rule to form a single tree.

Last Answer : (B) Shift step that advances in the input stream by one symbol and Reduce step that applies a completed grammar rule to some recent parse trees, joining them together as one tree with a new root symbol.

Consider a uniprocessor system where new processes arrive at an average of five processes per minute and each process needs an average of 6 seconds of service time. What will be the CPU utilization ? (A) 80 % (B) 50 % (C) 60 % (D) 30 %

Description : Consider a uniprocessor system where new processes arrive at an average of five processes per minute and each process needs an average of 6 seconds of service time. What will be the CPU utilization ? (A) 80 % (B) 50 % (C) 60 % (D) 30 %

Last Answer : (B) 50 %

A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? (A) 1 Mbps (B) 2 Mbps (C) 10 Mbps (D) 12 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? (A) 1 Mbps (B) 2 Mbps (C) 10 Mbps (D) 12 Mbps

Last Answer : (B) 2 Mbps

In a two-pass assembler, symbol table is (A) Generated in first pass (B) Generated in second pass (C) Not generated at all (D) Generated and used only in second pass

Description : In a two-pass assembler, symbol table is (A) Generated in first pass (B) Generated in second pass (C) Not generated at all (D) Generated and used only in second pass

Last Answer : (A) Generated in first pass

A memory management system has 64 pages with 512 bytes page size. Physical memory consists of 32 page frames. Number of bits required in logical and physical address are respectively: (1) 14 and 15 (2) 14 and 29 (3) 15 and 14 (4) 16 and 32

Description : A memory management system has 64 pages with 512 bytes page size. Physical memory consists of 32 page frames. Number of bits required in logical and physical address are respectively: (1) 14 and 15 (2) 14 and 29 (3) 15 and 14 (4) 16 and 32

Last Answer : (3) 15 and 14

Number of bits per symbol used in Baudot code is a. 7 b. 5 c. 8d. 9

Description : Number of bits per symbol used in Baudot code is a. 7 b. 5 c. 8 d. 9

Last Answer : 5

How do you calculate the number of bits of a body of text in ASCII? A. Number of characters * 7 B. Number of characters (including spaces) *7 C. bits in Huffman * 7 D. bits in Huffman / 7

Description : How do you calculate the number of bits of a body of text in ASCII? A. Number of characters * 7 B. Number of characters (including spaces) *7 C. bits in Huffman * 7 D. bits in Huffman / 7

Last Answer : B. Number of characters (including spaces) *7

Consider the following database table having A, B, C and D as its four attributes and four possible candidate keys (I, II, III and IV) for this table: Image I: {B} II: {B, C} III: {A, D} IV: {C, D} If different symbols stand for different values in the table (e.g., d1 is definitely not equal to d2), then which of the above could not be the candidate key for the database table? (A) I and III only (B) III and IV only (C) II only (D) I only

Description : Consider the following database table having A, B, C and D as its four attributes and four possible candidate keys (I, II, III and IV) for this table: I: {B} II: {B, C} III: {A, D} IV: {C, D} If ... the database table? (A) I and III only (B) III and IV only (C) II only (D) I only

Last Answer : (C) II only

Consider the following Entity-Relationship (E-R) diagram and three possible relationship sets (I, II and III) for this E-R diagram: Image If different symbols stand for different values (e.g., t1 is definitely not equal to t2), then which of the above could not be the relationship set for the E-R diagram ? (A) I only (B) I and II only (C) II only (D) I, II and III

Description : Consider the following Entity-Relationship (E-R) diagram and three possible relationship sets (I, II and III) for this E-R diagram: If different symbols stand for different values (e.g., t1 is definitely not equal to t2 ... diagram ? (A) I only (B) I and II only (C) II only (D) I, II and III

Last Answer : (A) I only

Consider a program that consists of 8 pages (from 0 to 7) and we have 4 page frames in the physical memory for the pages. The page reference string is : 1 2 3 2 5 6 3 4 6 3 7 3 1 5 3 6 3 4 2 4 3 4 5 1 The number of page faults in LRU and optimal page replacement algorithms are respectively (without including initial page faults to fill available page frames with pages): (A) 9 and 6 (B) 10 and 7 (C) 9 and 7 (D) 10 and 6

Description : Consider a program that consists of 8 pages (from 0 to 7) and we have 4 page frames in the physical memory for the pages. The page reference string is :  1 2 3 2 5 6 3 4 6 3 7 3 1 5 3 6 3 4 2 4 3 4 5 ... to fill available page frames with pages): (A) 9 and 6 (B) 10 and 7 (C) 9 and 7 (D) 10 and 6

Last Answer : (B) 10 and 7

Suppose a digitized voice channel is made by digitizing 8 kHz bandwidth analog voice signal. It is required to sample the signal at twice the highest frequency (two samples per hertz). What is the bit rate required, if it is assumed that each sample requires 8 bits? (A) 32 kbps (B) 64 kbps (C) 128 kbps (D) 256 kbps

Description : Suppose a digitized voice channel is made by digitizing 8 kHz bandwidth analog voice signal. It is required to sample the signal at twice the highest frequency (two samples per hertz). What is the bit rate required, if it ... sample requires 8 bits? (A) 32 kbps (B) 64 kbps (C) 128 kbps (D) 256 kbps

Last Answer : (C) 128 kbps

If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ............... (A) 64 Kbps (B) 32 Mbps (C) 32 Kbps (D) 64 Mbps

Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ............... (A) 64 Kbps (B) 32 Mbps (C) 32 Kbps (D) 64 Mbps

Last Answer : (C) 32 Kbps

Which formula shows how to work out the percentage a file has been compressed by? A. bits in (Huffman *7) /100 B. bits in ASCii - bits in Huffman C. difference in bits / bits in ASCII * 100

Description : Which formula shows how to work out the percentage a file has been compressed by? A. bits in (Huffman *7) /100 B. bits in ASCii - bits in Huffman C. difference in bits / bits in ASCII * 100

Last Answer : C. difference in bits / bits in ASCII * 100

The basic idea behind Huffman coding is to A. compress data by using fewer bits to encode fewer frequently occuring characters B. compress data by using fewer bits to encode more frequently occuring characters C. compress data by using more bits to encode more frequently occuring characters D. expand data by using fewer bits to encode more frequently occuring characters

Description : The basic idea behind Huffman coding is to A. compress data by using fewer bits to encode fewer frequently occuring characters B. compress data by using fewer bits to encode more ... frequently occuring characters D. expand data by using fewer bits to encode more frequently occuring characters

Last Answer : B. compress data by using fewer bits to encode more frequently occuring characters

The basic idea behind Huffman coding is to a. compress data by using fewer bits to encode fewer frequently occuring characters b. compress data by using fewer bits to encode more frequently occuring characters c. compress data by using more bits to encode more frequently occuring characters d. expand data by using fewer bits to encode more frequently occuring characters

Description : The basic idea behind Huffman coding is to a. compress data by using fewer bits to encode fewer frequently occuring characters b. compress data by using fewer bits to encode more ... frequently occuring characters d. expand data by using fewer bits to encode more frequently occuring characters

Last Answer : b. compress data by using fewer bits to encode more frequently occuring characters

Consider a project with the following functional units : Number of user inputs = 50 Number of user outputs = 40 Number of user enquiries = 35 Number of user files = 06 Number of external interfaces = 04 Assuming all complexity adjustment factors and weighing factors as average, the function points for the project will be (A) 135 (B) 722 (C) 675 (D) 672

Description : Consider a project with the following functional units : Number of user inputs = 50 Number of user outputs = 40 Number of user enquiries = 35 Number of user files = 06 Number of external interfaces = 04 ... average, the function points for the project will be (A) 135 (B) 722 (C) 675 (D) 672

Last Answer : (D) 672

Average length of Extended Huffman code is upper bounded by : a. R b. R+1 c. R-1 d. R+1/n

Description : Average length of Extended Huffman code is upper bounded by : a. R b. R+1 c. R-1 d. R+1/n

Last Answer : d. R+1/n

Let L be the language generated by regular expression 0*10* and accepted by the deterministic finite automata M. Consider the relation RM defined by M. As all states are reachable from the start state, RM has ................ equivalence classes. (A) 2 (B) 4 (C) 5 (D) 6

Description : Let L be the language generated by regular expression 0*10* and accepted by the deterministic finite automata M. Consider the relation RM defined by M. As all states are reachable from the start state, RM has ................ equivalence classes. (A) 2 (B) 4 (C) 5 (D) 6

Last Answer : (D) 6

A software project was estimated at 352 Function Points (FP). A four person team will be assigned to this project consisting of an architect, two programmers, and a tester. The salary of the architect is Rs.80,000 per month, the programmer Rs.60,000 per month and the tester Rs.50,000 per month. The average productivity for the team is 8 FP per person month. Which of the following represents the projected cost of the project? (1) Rs.28,16,000 (2) Rs.20,90,000 (3) Rs.26,95,000 (4) Rs.27,50,000

Description : A software project was estimated at 352 Function Points (FP). A four person team will be assigned to this project consisting of an architect, two programmers, and a tester. The salary of the architect is Rs.80,000 per month, the ... ) Rs.28,16,000 (2) Rs.20,90,000 (3) Rs.26,95,000 (4) Rs.27,50,000

Last Answer : (4) Rs.27,50,000 

Suppose ORACLE relation R(A, B) currently has tuples {(1, 2), (1, 3), (3, 4)} and relation S(B, C) currently has {(2, 5), (4, 6), (7, 8)}. Consider the following two SQL queries SQ1 and SQ2 : SQ1 : Select * From R Full Join S On R.B=S.B; SQ2 : Select * From R Inner Join S On R.B=S.B; The numbers of tuples in the result of the SQL query SQ1 and the SQL query SQ2 are given by : (A) 2 and 6 respectively (B) 6 and 2 respectively (C) 2 and 4 respectively (D) 4 and 2 respectively

Description : Suppose ORACLE relation R(A, B) currently has tuples {(1, 2), (1, 3), (3, 4)} and relation S(B, C) currently has {(2, 5), (4, 6), (7, 8)}. Consider the following two SQL queries SQ1 and SQ2 ... (A) 2 and 6 respectively (B) 6 and 2 respectively (C) 2 and 4 respectively (D) 4 and 2 respectively

Last Answer : (D) 4 and 2 respectively

The Excess-3 decimal code is a self-complementing code because (A) The binary sum of a code and its 9’s complement is equal to 9. (B) It is a weighted code. (C) Complement can be generated by inverting each bit pattern. (D) The binary sum of a code and its 10’s complement is equal to 9.

Description : The Excess-3 decimal code is a self-complementing code because (A) The binary sum of a code and its 9’s complement is equal to 9. (B) It is a weighted code. (C) Complement can be generated by inverting each bit pattern. (D) The binary sum of a code and its 10’s complement is equal to 9.

Last Answer : Answer: A, C

Let C be a binary linear code with minimum distance 2t + 1 then it can correct upto ............bits of error. (1) t + 1 (2) t (3) t - 2 (4) t/2

Description : Let C be a binary linear code with minimum distance 2t + 1 then it can correct upto ............bits of error. (1) t + 1 (2) t (3) t - 2 (4) t/2

Last Answer : (2) t 

A certain company employed 600 men and 400 women and the average wage was 2.55 per hour.If a women got 50 paise less than a man, what were their wages per hour ? (a) Man rs 3.00,Woman Rs 2.50 (b) Man Rs 3.50, Woman Rs 3.00 (c) Man Rs 2.75, Woman Rs 2.25 (d) Man Rs 3.25, Woman Rs 2.75

Description : A certain company employed 600 men and 400 women and the average wage was 2.55 per hour.If a women got 50 paise less than a man, what were their wages per hour ? (a) Man rs 3.00,Woman Rs 2.50 (b) Man Rs 3.50, Woman Rs 3.00 (c) Man Rs 2.75, Woman Rs 2.25 (d) Man Rs 3.25, Woman Rs 2.75

Last Answer : Man = Rs 2.75, woman = Rs 2.25

Consider a disk with 16384 bytes per track having a rotation time of 16 msec and average seek time of 40 msec. What is the time in msec to read a block of 1024 bytes from this disk? (A) 57 msec (B) 49 msec (C) 48 msec (D) 17 msec

Description : Consider a disk with 16384 bytes per track having a rotation time of 16 msec and average seek time of 40 msec. What is the time in msec to read a block of 1024 bytes from this disk? (A) 57 msec (B) 49 msec (C) 48 msec (D) 17 msec

Last Answer : Answer: B

Let the page fault service time be 10 millisecond(ms) in a computer with average memory access time being 20 nanosecond(ns). If one page fault is generated for every 106 memory accesses, what is the effective access time for memory? (A) 21 ns (B) 23 ns (C) 30 ns (D) 35 ns

Description : Let the page fault service time be 10 millisecond(ms) in a computer with average memory access time being 20 nanosecond(ns). If one page fault is generated for every 106 memory accesses, what is the effective access time for memory? (A) 21 ns (B) 23 ns (C) 30 ns (D) 35 ns

Last Answer : (C) 30 ns

Consider a disk queue with request for input/output to block on cylinders 98, 183, 37, 122, 14, 124, 65, 67 in that order. Assume that disk head is initially positioned at cylinder 53 and moving towards cylinder number 0. The total number of head movements using Shortest Seek Time First (SSTF) and SCAN algorithms are respectively (A) 236 and 252 cylinders (B) 640 and 236 cylinders (C) 235 and 640 cylinders (D) 235 and 252 cylinders

Description : Consider a disk queue with request for input/output to block on cylinders  98, 183, 37, 122, 14, 124, 65, 67  in that order. Assume that disk head is initially positioned at cylinder 53 and moving ... and 252 cylinders (B) 640 and 236 cylinders (C) 235 and 640 cylinders (D) 235 and 252 cylinders

Last Answer : Answer: 236 and 208 cylinders Explanation: SSTF Initial head position =53 The closest queue to initial head position=65 head moves from 53 to 65=12 head moves from 65 to 67=2 head moves from 67 ... 122=24 head moves from 122 to 124=2 head moves from 124 to 183=59 Total head movement=208 

Consider the following three SQL queries (Assume the data in the people table) : (a) Select Name from people where Age>21; (b) Select Name from people where Height>180; (c) Select Name from people where (Age>21) or (Height>180); If the SQL queries (a) and (b) above, return 10 rows and 7 rows in the result set respectively, then what is one possible number of rows returned by the SQL query (c) ? (A) 3 (B) 7 (C) 10 (D) 21

Description : Consider the following three SQL queries (Assume the data in the people table) : (a) Select Name from people where Age>21; (b) Select Name from people where Height>180; (c) Select Name from people where (Age>21) or (Height ... number of rows returned by the SQL query (c) ? (A) 3 (B) 7 (C) 10 (D) 21

Last Answer : (C) 10

Consider the reference string 0 1 2 3 0 1 4 0 1 2 3 4 If FIFO page replacement algorithm is used, then the number of page faults with three page frames and four page frames are .......... and ........... respectively. (A) 10, 9 (B) 9, 9 (C) 10, 10 (D) 9, 10

Description : Consider the reference string 0 1 2 3 0 1 4 0 1 2 3 4 If FIFO page replacement algorithm is used, then the number of page faults with three page frames and four page frames are .......... and ........... respectively. (A) 10, 9 (B) 9, 9 (C) 10, 10 (D) 9, 10

Last Answer : (D) 9, 10

An analog signal carries 4 bits in each signal unit. If 1000 signal units are sent per second, then baud rate and bit rate of the signal are ............... and .............. (A) 4000 bauds \ sec & 1000 bps (B) 2000 bauds \ sec & 1000 bps (C) 1000 bauds \ sec & 500 bps (D) 1000 bauds \ sec & 4000 bps

Description : An analog signal carries 4 bits in each signal unit. If 1000 signal units are sent per second, then baud rate and bit rate of the signal are ............... and .............. (A) 4000 bauds \ sec & ... (B) 2000 bauds \ sec & 1000 bps (C) 1000 bauds \ sec & 500 bps (D) 1000 bauds \ sec & 4000 bps

Last Answer : (D) 1000 bauds \ sec & 4000 bps Explanation: Bit rate is the number of bits per second. Baud rate is the number of signal units per second. Baud rate is less than or equal to the bit rate. Baud rate = 1000 bauds per second (baud/s) Bit rate = 1000 x 4 = 4000 bps

In a digital transmission, the receiver clock is 0.1 percent faster than the sender clock. How many extra bits per second does the receiver receive if the data rate is 1 Mbps ? (A) 10 bps (B) 100 bps (C) 1000 bps (D) 10000 bps

Description : In a digital transmission, the receiver clock is 0.1 percent faster than the sender clock. How many extra bits per second does the receiver receive if the data rate is 1 Mbps ? (A) 10 bps (B) 100 bps (C) 1000 bps (D) 10000 bps

Last Answer : (C) 1000 bps 

Consider a code with five valid code words of length ten : 0000000000, 0000011111, 1111100000, 1110000011, 1111111111 Hamming distance of the code is (A) 5 (B) 10 (C) 8 (D) 9

Description : Consider a code with five valid code words of length ten : 0000000000, 0000011111, 1111100000, 1110000011, 1111111111 Hamming distance of the code is (A) 5 (B) 10 (C) 8 (D) 9

Last Answer : Answer: Marks to all

A software company needs to develop a project that is estimated as 1000 function points and is planning to use JAVA as the programming language whose approximate lines of code per function point is accepted as 50. Considering a=1.4 as multiplicative factor, b=1.0 as exponention factor for the basic COCOMO effort equation and c=3.0 as multiplicative factor, d=0.33 as exponention factor for the basic COCOMO duration equation, approximately how long does the project take to complete? (1) 11.2 months (2) 12.2 months (3) 13.2 months (4) 10.2 months

Description : A software company needs to develop a project that is estimated as 1000 function points and is planning to use JAVA as the programming language whose approximate lines of code per function point is accepted as 50. Considering a=1. ... ? (1) 11.2 months (2) 12.2 months (3) 13.2 months (4) 10.2 months

Last Answer : Generally, any projects are measured in weeks. However, the complex project might take more time depending on the level of object re-use available.

In the hypermedia database, information bits are stored in the form of: (A) signals (B) cubes (C) nodes (D) symbols

Description : In the hypermedia database, information bits are stored in the form of: (A) signals (B) cubes (C) nodes (D) symbols

Last Answer : Answer: C Explanation: Hypermedia database model stores chunks of information in the form of nodes connected by links established by the user. The nodes can contain text, graphics, sound, full-motion video, or executable computer programs. 

3 partners A , B, C starts a business. 4 times of A's capital is equal to 6 times of B's Capital and B's Capital is 8 times of C's capital if profit of B is Rs.6300. Then find the average profit A and C A) 7000.50 B) 5118.75 C) 4475.25 D) none

Description : 3 partners A , B, C starts a business. 4 times of A's capital is equal to 6 times of B's Capital and B's Capital is 8 times of C's capital if profit of B is Rs.6300. Then find the average profit A and C A) 7000.50 B) 5118.75 C) 4475.25 D) none

Last Answer : Answer: B)  Let the capital of C be y  Let the capital of B be 8y  Let the capital of A be 48y/4=12y  Ratio of their profit is ,  A:B:C = 12y : 8y :y  =12:8:1  Total of A&C =6300/8 *13  =Rs .10237.5  Average profit of A&C  =10237.5/2 =Rs.5118.75

The process of assigning load addresses to the various parts of the program and adjusting the code and data in the program to reflect the assigned addresses is called .................. (A) Symbol resolution (B) Parsing (C) Assembly (D) Relocation

Description : The process of assigning load addresses to the various parts of the program and adjusting the code and data in the program to reflect the assigned addresses is called .................. (A) Symbol resolution (B) Parsing (C) Assembly (D) Relocation

Last Answer : (D) Relocation