How do you calculate the density of oxygen gas (O2) at 30 degree C and 700 mmHg?

How do you calculate the density of oxygen gas (O2) at 30 degree C and 700 mmHg?
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How do you calculate the density of oxygen gas (O2) at 30 degreeC. and 700 mmHg?
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What is the density of O2 gas at 740 mmHg and 30 degree C.?

Description : What is the density of O2 gas at 740 mmHg and 30 degree C.?

Last Answer : How To Calculate The Density Of Oxygen Gas ,O2, At 30 Deg. C And 700 MmHg

Calculate the number of oxygen atoms in 1 mole of O2. -Chemistry 9th

Description : Calculate the number of oxygen atoms in 1 mole of O2. -Chemistry 9th

Last Answer : 1 molecule of O2 = 2 oxygen atoms So, 1 mole of O2 = 2 mole oxygen atoms = 2 × 6.022 × 1023 = 12.044 ×1023 oxygen atoms.

A 45-year-old solicitor had an onset of severe, crushing, substernal chest pain while attending a football match. He collapsed on his way to the car. Bystander Cardiorespiratory Resuscitation was begun immediately and continued until arrival in Casualty where an endotracheal tube was inserted and ventilation was maintained on 100% oxygen. Investigations revealed: pH 7.13 PaO2 560 mmHg PaCO2 18 mmHg Bicarbonate 5.8 SaO2 98% Based on these laboratory values, which of the following statements best describes his current pathophysiology? 1) He is demonstrating a primary respiratory alkalosis 2) He probably developed a large right to left intracardiac shunt 3) His anion gap is probably normal 4) His oxyhemoglobin curve is shifted to the left 5) His pulmonary artery pressure is probably elevated

Description : A 45-year-old solicitor had an onset of severe, crushing, substernal chest pain while attending a football match. He collapsed on his way to the car. Bystander Cardiorespiratory Resuscitation ... His oxyhemoglobin curve is shifted to the left 5) His pulmonary artery pressure is probably elevated

Last Answer : Answers-5 This young patient with severe central chest pain has probably arrested due to myocardial infarction and arrhythmia. His gases reveal high PO2 following 100% O2 but severe acidosis ... no left to right shunting and high pulmonary pressures would be expected after this arrest scenario.

Calculate the value of closing stock18th January, 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700 from the following according to Weighted Average method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units @ Rs. 4.50 Issues: 2nd January, 2014: 30 units

Description : Calculate the value of closing stock from the following according to Weighted Average method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units ... 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700

Last Answer : (c) Rs. 786

Calculate the value of closing stock from the following according to LIFO method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units @ Rs. 4.50 Issues: 2nd January, 2014: 30 units 18th January, 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700

Description : Calculate the value of closing stock from the following according to LIFO method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units @ Rs. 4.50 ... , 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700

Last Answer : (b) Rs. 805

Calculate the value of closing stock from the following according to FIFO method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units @ Rs. 4.50 Issues: 2nd January, 2014: 30 units 18th January, 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700

Description : Calculate the value of closing stock from the following according to FIFO method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units @ Rs. 4.50 ... , 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700

Last Answer : (a) Rs. 765

A 53-year-old man presented with hypertension of 150/110 mmHg. He is generally asymptomatic and has no previous medical history of note. He is a smoker of 5 cigarettes daily and drinks modest quantities of alcohol. He takes no prescribed medications. Examination reveals a BMI of 33.5 kg/2 but nil else. The following detail his investigations: Serum sodium 146 mmol/l (NR 133-145) Serum potassium 3.2 mmol/l (NR 3.5 - 5) Urinary potassium excretion 42 mmol/l (NR less than 30) What is the likely diagnosis? 1) Adrenocortical adenoma 2) Bartter's syndrome 3) Liddle's syndrome 4) Liquorice ingestion 5) Pheochromocytoma

Description : A 53-year-old man presented with hypertension of 150/110 mmHg. He is generally asymptomatic and has no previous medical history of note. He is a smoker of 5 cigarettes daily and drinks ... Adrenocortical adenoma 2) Bartter's syndrome 3) Liddle's syndrome 4) Liquorice ingestion 5) Pheochromocytoma

Last Answer : Answers-1 This patient is most likely to have Conn's syndrome as reflected by the hypokalaemic hypertension. Liquorice ingestion or Liddle's syndrome are again possible causes of ... hypertension (often diastolic hypertension), muscular weakness, paresthesias, headache, polyuria, and polydipsia."

What is the final volume, in liters, of the gas when measured at 24 ∘C and 635 mmHg, when n is constant?

Description : What is the final volume, in liters, of the gas when measured at 24 ∘C and 635 mmHg, when n is constant?

Last Answer : I don’t understand the question

Volumetric composition of flue gas analysed with the Orsat apparatus is : CO2 = 12%, O2 = 8%, CO = nil, N2 = 80%. This flue gas composition indicates that (A) Pure oxygen has been used for combustion (B) Nitrogen percentage in the fuel is very high (C) Excess air has been used for combustion (D) Hydrogen is not present in the fuel

Description : Volumetric composition of flue gas analysed with the Orsat apparatus is : CO2 = 12%, O2 = 8%, CO = nil, N2 = 80%. This flue gas composition indicates that (A) Pure oxygen has been used for combustion ... very high (C) Excess air has been used for combustion (D) Hydrogen is not present in the fuel

Last Answer : (C) Excess air has been used for combustion

What is the molecular mass of a gas that effuses through a small hole at twice the rate as oxygen gas at the same temperature. (The molecular mass of O2 is 32.) w) 8.0 atomic mass units x) 16 atomic mass units y) 48 atomic mass units z) 64 atomic mass units

Description : What is the molecular mass of a gas that effuses through a small hole at twice the rate as oxygen gas at the same temperature. (The molecular mass of O2 is 32.) w) 8.0 atomic mass units x) 16 atomic mass units y) 48 atomic mass units z) 64 atomic mass units

Last Answer : ANSWER: W -- 8.0 ATOMIC MASS UNITS

Calculate: a. Mass flow rate in lb/hr. b. The velocity at section 2 in fps  a. 800,000lb/hr;625ft/s  b. 900,000lb/hr;625 ft/s  c. 888,000lb/hr;269 ft/s  d. 700,000lb/hr;269 ft/s m = A1V!/V1

Description : Calculate: a. Mass flow rate in lb/hr. b. The velocity at section 2 in fps  a. 800,000lb/hr;625ft/s  b. 900,000lb/hr;625 ft/s  c. 888,000lb/hr;269 ft/s  d. 700,000lb/hr;269 ft/s m = A1V!/V1

Last Answer : 900,000 lb/hr;625 ft/s

Air contain 21% O2 and 79% N2 by volume. Calculate the composition in terms percentage by weight.

Description : Air contain 21% O2 and 79% N2 by volume. Calculate the composition in terms percentage by weight.

Last Answer : Basis: 100 kmole air Kmoles of O2 =21 Kmoles of N2 =79 Weight of O2 =21x32=672 kg Weight of N2 =79x28=2212 kg Total weight =2884 kg Weight% of O2 = (weight of O2/ total weight)x100  = (672/2884)x100  = 23.3% Weight% of N2 =(weight of N2/ total weight)x100  = (2212/2884)x100  = 76.7%

A 19 year-old female is referred following a visit to the dentist where marked erosion of her teeth was noted. She was entirely asymptomatic and her only medication was the oral contraceptive pill. On examination her blood pressure was 110/70 mmHg and her body mass index was 21.5 kg/m2 (18 - 25). Investigations sodium 135 mmol/l potassium 2.1 mmol/l bicarbonate 42 mmol/l urea 2.6 mol/L corrected calcium 2.08 mmol/ alkaline phosphatase 201 iu/l (50-110) What is the most likely diagnosis? 1) Bulimia nervosa 2) Conn's syndrome 3) Laxative abuse 4) Pregnancy 5) Primary hypoparathyroidism

Description : A 19 year-old female is referred following a visit to the dentist where marked erosion of her teeth was noted. She was entirely asymptomatic and her only medication was the oral contraceptive pill ... ) Bulimia nervosa 2) Conn's syndrome 3) Laxative abuse 4) Pregnancy 5) Primary hypoparathyroidism

Last Answer : Answers-5 This patient has tooth erosion associated with hypokalaemic metabolic alkalosis and hypocalcaemia. This suggests a diagnosis of hypoparathyroidism. Conn's is unlikely in this age group, is ... raised alkaline phosphatase would not be expected. Early pregnancy would not fit this picture.

The mean arterial pressure of a blood pressure of 160 80 is A. 90 mmHg B. 100 mmHg C. 110 mmHg D. 120 mmHg

Description : The mean arterial pressure of a blood pressure of 160 80 is A. 90 mmHg B. 100 mmHg C. 110 mmHg D. 120 mmHg

Last Answer : Ans: C

With regard to cerebral autoregulation: a. cerebral blood flow is constant over a diastolic blood pressure of 60 to 140 mmHg b. autoregulation is lost during the acute phase of subarachnoid haemorrhage c. it is impaired in hypercapnia d. it is impaired in hypoxia

Description : With regard to cerebral autoregulation: a. cerebral blood flow is constant over a diastolic blood pressure of 60 to 140 mmHg b. autoregulation is lost during the acute phase of subarachnoid haemorrhage c. it is impaired in hypercapnia d. it is impaired in hypoxia

Last Answer : it is impaired in hypoxia

The figure shows blood circulation in humans with labels A to D. Select the option which gives correct identification of label and functions of the part. (a) B - Capillary-Thin without muscle layer and wall two cell layers thick (b) C - Vein-Thin walled and blood flows in jerks/ spurts (c) D - Pulmonary vein-Takes oxygenated blood to heart, pO2 = 95 mmHg (d) A - Artery-Thick walled and blood flows evenly

Description : The figure shows blood circulation in humans with labels A to D. Select the option which gives correct identification of label and functions of the part. (a) B - Capillary-Thin without muscle layer and ... blood to heart, pO2 = 95 mmHg (d) A - Artery-Thick walled and blood flows evenly

Last Answer : (c) D - Pulmonary vein-Takes oxygenated blood to heart, pO2 = 95 mmHg

The standard reference atmospheric pressure  a. 760 mmHg  b. 1 atm  c. 14.696 psia  d. All of the above

Description : The standard reference atmospheric pressure  a. 760 mmHg  b. 1 atm  c. 14.696 psia  d. All of the above

Last Answer : All of the above

14.696 psia = _____ mmHg  a. 760  b. 1  c. 350  d. None of the above

Description : 14.696 psia = _____ mmHg  a. 760  b. 1  c. 350  d. None of the above

Last Answer : 1

A semiconscious patient of haemorrhagic cerebral stroke has been brought to the emergency. His blood pressure is 240/120 mmHg. Select the procedure to lower his blood pressure as rapidly as possible: A. Sublingual nifedipine B. Intramuscular injection of hydralazine C. Intravenous infusion of sodium nitroprusside D. Intravenous injection of clonidin

Description : A semiconscious patient of haemorrhagic cerebral stroke has been brought to the emergency. His blood pressure is 240/120 mmHg. Select the procedure to lower his blood pressure as ... injection of hydralazine C. Intravenous infusion of sodium nitroprusside D. Intravenous injection of clonidin

Last Answer : C. Intravenous infusion of sodium nitroprussid

The principles of antihypertensive drug usage enunciated in JNC VI and WHO-ISH guidelines include the following except: A. Therapy for grade I and II hypertension should be initiated with a single drug B. Dose of thiazide diuretic should be 12.5-25 mg hydrochlorothiazide or equivalent per day C. All subjects with BP higher than 140/90 mmHg should be put on antihypertensive medication immediately D. If the drug chosen initially fails to lower BP, it should be replaced by a drug/combination from another class

Description : The principles of antihypertensive drug usage enunciated in JNC VI and WHO-ISH guidelines include the following except: A. Therapy for grade I and II hypertension should be initiated with a single drug ... initially fails to lower BP, it should be replaced by a drug/combination from another class

Last Answer : C. All subjects with BP higher than 140/90 mmHg should be put on antihypertensive medication immediately

Art B Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 4.30 moles moles of magnesium perchlorate, Mg(Cl O 4 ) 2 Mg(ClO4)2 . Express the number of moles of Mg Mg , Cl Cl , and O O atoms numerically, separated by comma?

Description : Art B Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 4.30 moles moles of magnesium perchlorate, Mg(Cl O 4 ) 2 Mg(ClO4)2 . Express the number of moles of Mg Mg , Cl Cl , and O O atoms numerically, separated by comma?

Last Answer : Answers is the place to go to get the answers you need and to ask the questions you want

The Manufacturer of aeration devices reports the oxygen transfer rate of the device obtained through laboratory tests carried under standard conditions. Such standard condition are : (a) Wastewater at zero DO, 25°C and 760 mm Hg (b) Tapwater at zero DO, 0°C and 700 mm Hg (c) Tapwater at zero DO, 20°C and 760 mm Hg (d) Wastewater at zero DO, 0°C and 700 mm Hg

Description : The Manufacturer of aeration devices reports the oxygen transfer rate of the device obtained through laboratory tests carried under standard conditions. Such standard condition are : (a) Wastewater at zero DO, 25°C and 760 mm ... DO, 20°C and 760 mm Hg (d) Wastewater at zero DO, 0°C and 700 mm Hg

Last Answer : (c) Tapwater at zero DO, 20°C and 760 mm Hg

Why are electrons shared equally in oxygen O2 but not in carbon monoxide CO?

Description : Why are electrons shared equally in oxygen O2 but not in carbon monoxide CO?

Last Answer : Feel Free to Answer

The oxygen d issoc iat ion curve for hemoglobin is shifted to the right by (A) Decreased O2 tension (B) Decreased CO2 tension (C) Increased CO2 tension (D) Increased pH

Description : The oxygen d issoc iat ion curve for hemoglobin is shifted to the right by (A) Decreased O2 tension (B) Decreased CO2 tension (C) Increased CO2 tension (D) Increased pH

Last Answer : Answer : C

Which of the following statement(s) is/are true concerning oxygen delivery? a. The amount of oxygen delivered to peripheral tissues is dependent upon the oxygen content in arterial blood and cardiac output b. Oxygen content is commonly measured in arterial blood c. The normal arterial-venous difference is 4 cc O2/dL d. Normal systemic oxygen delivery for a typical adult is approximately 1000 cc/min

Description : Which of the following statement(s) is/are true concerning oxygen delivery? a. The amount of oxygen delivered to peripheral tissues is dependent upon the oxygen content in arterial blood and cardiac ... O2/dL d. Normal systemic oxygen delivery for a typical adult is approximately 1000 cc/min

Last Answer : Answer: a, c, d The amount of oxygen that is delivered to peripheral tissues is the product of the oxygen content in arterial blood times the cardiac output. Normally, oxygen content of arterial blood is ... of venous blood is 16 cc/dL. Hence, the normal arterial-venous difference is 4 cc O2/dL

Which of the following statement(s) is/are true concerning oxygen consumption (O2)? a. O2 is normally 100–120 cc2/m2/min b. Resting O2 is controlled by the level of thyroid and catecholamine hormones c. Under steady state conditions the amount of oxygen consumed exceeds the amount of oxygen taken up by the pulmonary capillaries d. O2 is dependent on the status of pulmonary function

Description : Which of the following statement(s) is/are true concerning oxygen consumption (O2)? a. O2 is normally 100-120 cc2/m2/min b. Resting O2 is controlled by the level of thyroid and catecholamine ... of oxygen taken up by the pulmonary capillaries d. O2 is dependent on the status of pulmonary function

Last Answer : Answer: a, b Oxygen consumed in the process of metabolism is expressed as the volume of oxygen per minute (O2). O2 is normally 100-120 cc2/m2/min, or 200 cc/min for a typical adult. ... , so we measure O2 across the lung and assume that it is exactly the amount consumed in the systemic metabolism

Which of the following statement(s) is/are true concerning O2 venous saturation monitoring? a. The normal saturation of mixed venous blood is 50% b. Mixed venous blood obtained for saturation monitoring can be obtained from any peripheral vein c. If arterial blood is fully saturated, the saturation of mixed venous blood is 80% d. In less than fully saturated blood, the difference between arterial and venous saturation corresponds to oxygen extraction

Description : Which of the following statement(s) is/are true concerning O2 venous saturation monitoring? a. The normal saturation of mixed venous blood is 50% b. Mixed venous blood obtained ... than fully saturated blood, the difference between arterial and venous saturation corresponds to oxygen extraction

Last Answer : Answer: c, d The relationship between oxygen delivery and oxygen consumption is reflected in the amount of oxygen in venous blood. Under normal circumstances, oxygen delivery is 1000 ... and venous saturation corresponds to the oxygen extraction, hence the oxygen delivery/oxygen consumption ratio

45.4 L of nitrogen reacted with 22.7 L of oxygen and 45.4 L of nitrogen oxide was formed. The reaction is given below: 2N2(g) + O2(g) →2N2O(g) Which law is being obeyed in this experiment? Write the statement of this law.

Description : 45.4 L of nitrogen reacted with 22.7 L of oxygen and 45.4 L of nitrogen oxide was formed. The reaction is given below: 2N2(g) + O2(g) →2N2O(g) Which law is being obeyed in this experiment? Write the statement of this law.

Last Answer : Ans. Gay lussac’s law of gaseous volume is being obeyed. According to gay lussac’s law of gaseous volumes, gases combine or are produced in a chemical reaction in a simple ration by volume, provided that all gases are the same temperature and pressure.

People living at sea level have around 5 million RBC per cubic millimeter of their blood whereas those living at an altitude to 5400 metres have around 8 million. This is because at high altitude (a) people eat more nutritive food, therefore more RBCs are formed (b) people get pollution-free air to breath and more oxygen is available (c) atmospheric O2 level is less and hence more RBCs are needed to absorb the required amount of O2 to survive (d) there is more UV radiation which enhances RBC production.

Description : People living at sea level have around 5 million RBC per cubic millimeter of their blood whereas those living at an altitude to 5400 metres have around 8 million. This is because at high altitude ... required amount of O2 to survive (d) there is more UV radiation which enhances RBC production.

Last Answer : (c) atmospheric O2 level is less and hence more RBCs are needed to absorb the required amount of O2 to survive

What is true about RBCs in humans? (a) They carry about 20-25 percent of CO2. (b) They transport 99.5 percent of O2. (c) They transport about 80 percent oxygen only and the rest 20 percent of it is transported in dissolved state in blood plasma. (d) They do not carry CO2 at all.

Description : What is true about RBCs in humans? (a) They carry about 20-25 percent of CO2. (b) They transport 99.5 percent of O2. (c) They transport about 80 percent oxygen only and the rest 20 percent of it is transported in dissolved state in blood plasma. (d) They do not carry CO2 at all.

Last Answer : (a) They carry about 20-25 percent of CO2.

A large proportion of oxygen remains unused in the human blood even after its uptake by the body tissues. This O2 (a) acts as a reserve during muscular exercise (b) raises the pCO2 of blood to 75 mm of Hg (c) is enough to keep oxyhaemoglobin saturation at 96% (d) helps in releasing more O2 to the epithelial tissues.

Description : A large proportion of oxygen remains unused in the human blood even after its uptake by the body tissues. This O2 (a) acts as a reserve during muscular exercise (b) raises the pCO2 of ... enough to keep oxyhaemoglobin saturation at 96% (d) helps in releasing more O2 to the epithelial tissues.

Last Answer : (a) acts as a reserve during muscular exercise

Identify the wrong statement with reference to transport of oxygen. (a) Binding of oxygen with haemoglobin is mainly related to partial pressure of O2. (b) Partial pressure of CO2 can interfere with O2 binding with haemoglobin. (c) Higher H+ conc. in alveoli favours the formation of oxyhaemoglobin. (d) Low pCO2 in alveoli favours the formation of oxyhaemoglobin.

Description : Identify the wrong statement with reference to transport of oxygen. (a) Binding of oxygen with haemoglobin is mainly related to partial pressure of O2. (b) Partial pressure of CO2 can interfere ... the formation of oxyhaemoglobin. (d) Low pCO2 in alveoli favours the formation of oxyhaemoglobin.

Last Answer : (c) Higher H+ conc. in alveoli favours the formation of oxyhaemoglobin.

The figure given below shows a small part of human lung where exchange of gases takes place. Select the option which represents labelled part (A, B, C or D) correctly identified along with its function. (a) C : Arterial capillary - Passes oxygen to tissues (b) A : Alveolar cavity - Main site of exchange of respiratory gases (c) D : Capillary wall - Exchange of O2 and CO2 takes place here (d) B : Red blood cells - Transport of CO2 mainly

Description : The figure given below shows a small part of human lung where exchange of gases takes place. Select the option which represents labelled part (A, B, C or D) correctly identified along with its function. ... Exchange of O2 and CO2 takes place here (d) B : Red blood cells - Transport of CO2 mainly

Last Answer : (b) A : Alveolar cavity - Main site of exchange of respiratory gases

R.Q. is ratio of (a) CO2 produced to substrate consumed (b) CO2 produced to O2 consumed (c) oxygen consumed to water produced (d) oxygen consumed to CO2 produced

Description : R.Q. is ratio of (a) CO2 produced to substrate consumed (b) CO2 produced to O2 consumed (c) oxygen consumed to water produced (d) oxygen consumed to CO2 produced

Last Answer : b) CO2 produced to O2 consumed

Which one of the following is one of the paths followed by air or O2 during respiration in the adult male Periplaneta  americana as it enters the animal body? (a) Spiracle in metathorax, trachea, tracheoles, oxygen diffuses into cells (b) Mouth, bronchial tube, trachea, oxygen enters cells (c) Spiracles in prothorax, tracheoles, trachea, oxygen diffuses into cells (d) Hypopharynx, mouth, pharynx, trachea, tissues

Description : Which one of the following is one of the paths followed by air or O2 during respiration in the adult male Periplaneta  americana as it enters the animal body? (a) Spiracle in ... prothorax, tracheoles, trachea, oxygen diffuses into cells (d) Hypopharynx, mouth, pharynx, trachea, tissues

Last Answer : (a) Spiracle in metathorax, trachea, tracheoles, oxygen diffuses into cells

In multistage equilibrium conversion of SO2 to SO3 (2SO2 + O2 ⇌ 2SO3 ), the reverse reaction becomes appreciable at a temperature of 550° C. The percentage equilibrium conversion of SO2 to SO3 can be increased by (A) Increasing the oxygen concentration (B) Putting more quantity of V2O5 catalyst in the converter (C) Removing some quantity of SO3 during intermediate stage (D) Maintaining low temperature & pressure in the converter

Description : In multistage equilibrium conversion of SO2 to SO3 (2SO2 + O2 ⇌ 2SO3 ), the reverse reaction becomes appreciable at a temperature of 550° C. The percentage equilibrium conversion of SO2 to ... some quantity of SO3 during intermediate stage (D) Maintaining low temperature & pressure in the converter

Last Answer : (C) Removing some quantity of SO3 during intermediate stage

The point of ultra-supercritical steam generator is to save on coal to heat the water and reduce ________ emissions. a. Oxygen (O2) b. Water (H2O) c. Carbon dioxide (CO2) d. Both ‘a’ and ‘c’

Description : The point of ultra-supercritical steam generator is to save on coal to heat the water and reduce ________ emissions. a. Oxygen (O2) b. Water (H2O) c. Carbon dioxide (CO2) d. Both ‘a’ and ‘c’

Last Answer : c. Carbon dioxide (CO2)

This cause the depletion of ozone layer by decomposing ozone to oxygen . a) CFC b)UV radiations c)CO2 d)O2

Description : This cause the depletion of ozone layer by decomposing ozone to oxygen . a) CFC b)UV radiations c)CO2 d)O2

Last Answer : b)UV radiations

Calculate the recoverable waste heat (Q, in kCal/hour) from flue gases using the followingparameters: V (flow rate of the substance) 2000 m3/hr r (density of the flue gas): 0.9 kg/m3 Cp (specific heat of the substance): 0.20 kCal/kg oC DT (temperature difference): 120 oC h (recovery factor): 50% a. 21600 b. 43200 c. 25600 d. 34000

Description : Calculate the recoverable waste heat (Q, in kCal/hour) from flue gases using the followingparameters: V (flow rate of the substance) 2000 m3/hr r (density of the flue gas): 0.9 kg/m3 Cp (specific heat ... (temperature difference): 120 oC h (recovery factor): 50% a. 21600 b. 43200 c. 25600 d. 34000

Last Answer : 21600

A train travelling at 20 m s-1 accelerates at 0.5 m s-2 for 30 s, the distance travelled by train is A. 825 m B. 700 m C. 650 m D. 600 m

Description : A train travelling at 20 m s-1 accelerates at 0.5 m s-2 for 30 s, the distance travelled by train is A. 825 m B. 700 m C. 650 m D. 600 m

Last Answer : 825 m

If +0.8% grade meets -0.7% grade and the rate of change of grade for 30 m distance is 0.05, the length of the vertical curve will be (A) 600 m (B) 700 m (C) 800 m (D) 900 m

Description : If +0.8% grade meets -0.7% grade and the rate of change of grade for 30 m distance is 0.05, the  length of the vertical curve will be  (A) 600 m  (B) 700 m  (C) 800 m  (D) 900 m

Last Answer : (D) 900 m

Which constant pressure altitude chart is standard for a 30,065 ft pressure level (FL 300)? a. 200 hPa b. 700 hPa c. 500 hPa d. 300 hPa

Description : Which constant pressure altitude chart is standard for a 30,065 ft pressure level (FL 300)?  a. 200 hPa  b. 700 hPa  c. 500 hPa  d. 300 hPa

Last Answer : d. 300 hPa

Jake’s Market recorded the following events involving a recent purchase of merchandise: Received goods for $20,000, terms 2/10, n/30. Returned $400 of the shipment for credit. Paid $100 freight on the shipment. Paid the invoice within the discount period. As a result of these events, the company’s merchandise inventory a. increased by $19,208. b. increased by $19,700. c. increased by $19,306. d. increased by $19,308.

Description : Jake's Market recorded the following events involving a recent purchase of merchandise: Received goods for $20,000, terms 2/10, n/30. Returned $400 of the shipment for credit. Paid $100 freight on the shipment. ... . b. increased by $19,700. c. increased by $19,306. d. increased by $19,308.

Last Answer : d. increased by $19,308.

Which constant pressure altitude chart is standard for a 30,065 ft pressure level (FL 300)? a. 200 hPa b. 700 hPa c. 500 hPa d. 300 hPa

Description : Which constant pressure altitude chart is standard for a 30,065 ft pressure level (FL 300)? a. 200 hPa b. 700 hPa c. 500 hPa d. 300 hPa

Last Answer : d. 300 hPa

A hollow shaft of 1 m length is designed to transmit a power of 30 kW at 700 rpm. The maximum permissible angle of twist in the shaft is 1o. The inner diameter of the shaft is 0.7 times the outer diameter. The modulus of rigidity is 80 GPa. The outside diameter (in mm) of the shaft is _______. (a) 43 to 45 (b) 50to 60 (c) 70 to 80 (d) 85 to 100

Description : A hollow shaft of 1 m length is designed to transmit a power of 30 kW at 700 rpm. The maximum permissible angle of twist in the shaft is 1o. The inner diameter of the shaft is 0.7 times the outer diameter. The modulus of ... shaft is _______. (a) 43 to 45 (b) 50to 60 (c) 70 to 80 (d) 85 to 100

Last Answer : (a) 43 to 45

Ten signals, each requiring 3000 Hz, are multiplexed on to a single channel using FDM. How much minimum bandwidth is required for the multiplexed channel ? Assume that the guard bands are 300 Hz wide. (A) 30,000 (B) 32,700 (C) 33,000 (D) None of the above

Description : Ten signals, each requiring 3000 Hz, are multiplexed on to a single channel using FDM. How much minimum bandwidth is required for the multiplexed channel ? Assume that the guard bands are 300 Hz wide. (A) 30,000 (B) 32,700 (C) 33,000 (D) None of the above

Last Answer : (B) 32,700

A goodstrain of 700 m runs at a speed of 165 km/hr. A person traveling in it observes that the mail train moving in opposite direction takes 30 seconds to cross him. Find the speed of the mail train, if it is 750 m long. A) 8.4 m/s B) 5.3 m/s C) 2.5 m/s D) 6.8 m/s

Description : A goodstrain of 700 m runs at a speed of 165 km/hr. A person traveling in it observes that the mail train moving in opposite direction takes 30 seconds to cross him. Find the speed of the mail train, if it is 750 m long. A) 8.4 m/s B) 5.3 m/s C) 2.5 m/s D) 6.8 m/s

Last Answer : ANSWER:C Explanation:  Speed of goods train = 165km/hr  length of mail train (P) = 750m  length of goods train (Q) = 700m  Alternately, we can directly use the formula:  Time = ( p+q) / (v1+v2) sec  ( ...  45.833+v2 = 48.333  V2 = 2.5 m/s  Therefore the speed of the mail train is 2.5 m/s

A patient on the dental chair has cardiac arrest. What is INCORRECT, A. Observing the vital signs and check that the air way is clear is at high importance B. Expired air has 15% O2 only, and cardiac compressions achieve 30-40% of cardiac output C. Intermittent positive pressure at the rate of 40/min will reduce the chances of cerebral hypoxia D. Intermittent positive pressure is better than mouth to mouth when it has been given at the same rate.

Description : A patient on the dental chair has cardiac arrest. What is INCORRECT, A. Observing the vital signs and check that the air way is clear is at high importance B. Expired air has 15% O2 only, ... D. Intermittent positive pressure is better than mouth to mouth when it has been given at the same rate.

Last Answer : C. Intermittent positive pressure at the rate of 40/min will reduce the chances of cerebral hypoxia

The waste gases coming out from gas turbine exhausts are of the order of: a) 370-540 b) 450 – 700 c) 700- 800 d) 250-440

Description : The waste gases coming out from gas turbine exhausts are of the order of: a) 370-540 b) 450 – 700 c) 700- 800 d) 250-440

Last Answer : 370-540

In a petrol engine, which of the following gas gets exhausted out without burning and without transformation? a. CO2 b. CO c. O2 d. N2

Description : In a petrol engine, which of the following gas gets exhausted out without burning and without transformation? a. CO2 b. CO c. O2 d. N2

Last Answer : ANSWER d. N2