What moving object travels the same distance in equal units of time?

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Last Answer : Here u=72 km/hr = 72×10003600m/s=2072×10003600m/s=20 m/s , v=0 a= -5 m/s2 Now using the relation v2=u2+2asv2=u2+2as 0=(20)2+2×(−5)×s0=(20)2+2×(−5)×s s=40ms=40m

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Last Answer : (d) only. Distance and displacement in all other cases

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Last Answer : Uniform acceleration in the interval between 4th and 5th seconds = = (5u + 1/2 * a * 5^2) - (4u + 1/2 * a * 4^2) = 5u + 1/2 *a * 25 - 4u + 1/2 * a * 16 = u + 1/2 * a * (25-16) = u + 1/2 * a * 9 = u + 9/2 * a If it starts from rest then the displacement will be 9/2a. hope this helps!

Description : A car and lorry are both moving with equal kinetic energy. If equal breaking force is applied on both, then before coming to rest the (a) Car will cover a greater distance (b) Lorry ... will cover the same distance (d) The distance covered by them will depend only on their respective velocities

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Last Answer : Total distance travelled by the object =20 m + 16 m = 36 m Total time taken = 4 s + 2 s = 6 s Average Speed=total Distance travelledtotal time taken Average Speed=total Distance travelledtotal time taken Average Speed=366=6Average Speed=366=6 m/s

Description : An object travels from a fixed position 5 seconds to start the journey. After 20 m / s. Velocity is. Next 10 sec. How far will it cover ?

Last Answer : The distance covered by the object in the next 10 seconds s = vt s = 20 × 10 = 200m

Description : What occurs when a object travels in a curved path?

Last Answer : Acceleration

Description : What occurs when a object travels in a curved path?

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Last Answer : 5i446

Description : A sprinter travels a distance of 200 m in a time of 18.53 seconds.What is the sprinter's average speed rounded to 4 sf?

Last Answer : 5i446

Description : The distance between two cities A and B is 330km. A train starts from A at 8 (a)m. and travels towards B at 60 km/hr. Another train starts from B at 9 (a)m. and travels towards A at 75 km/hr. At what time do they meet? a) 10 am. b) 10 : 30 am. c) 11 am. d) 11 : 30 am. e) None of these

Last Answer : Distance travelled by first train in one hour = 60 x 1 = 60 km Therefore, distance between two train at 9 a.m. = 330 – 60 = 270 km Now, Relative speed of two trains = 60 + 75 = 135 km/hr Time of meeting of two trains =270/135=2 hrs. Therefore, both the trains will meet at 9 + 2 = 11 A.M. Answer: c)

Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Last Answer : Answer – C (11 am) Explanation – Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330 60x + 75(x – 1) = 330 x = 3 So, they meet at (8 + 3), i.e. 11 a.m

Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Last Answer : Answer – C (11 am) Explanation – Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330 60x + 75(x – 1) = 330 x = 3 So, they meet at (8 + 3), i.e. 11 a.m

Description : Jackson travels a distance of 100km in 5 hrs. How much faster in kilometer per hr, on an average, must he travel to make a journey in 5/3 hr less time? a) 5 km/hr b) 10km/hr c) 6 km/hr d) 8 km/hr

Last Answer : B Time required = (5 hrs – 5/3 hrs) =(5 hrs – 100 mints) = (5 hrs – 1hr 40 mints) = 3 hrs 20 mints = 3 1/3 hrs Required speed = (100*3/10) km/hr =30 km/hr Original speed = (100/5)km/hr = 20 km/hr Difference speed = required speed – original speed =(30-20) =10km/hr

Description : The distance between salem and trichy is 170 km. A bus starts from salem at 6 a.m. and travels towards trichy at 20 km/hr. Another bus starts from trichy at 7 a.m. and travels towards salem at 30 km/hr. At what time will they meet? a) 7a.m b) 8a.m c) 9a.m d) 10a.m

Last Answer : D Assume that they meet x hours after 6 a.m. Then, Bus 1, starting from salem, travels x hours till the bus meet. Distance travelled by bus 1 in x hours =20x km bus 2, starting from trichy , travels (x−1) hours ... +30=50x 200=50x X=4 Hence, the bus meet 4 hours after 6 a.m., i.e. at 10a.m

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Last Answer : v²⁄r

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Last Answer : ANSWER: Z -- DIRECTED RADIALLY INWARD

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Last Answer : The camel operates a mill and travels in a circular clockwise direction. The two outside legs will travel a greater distance than the two inside legs.

Description : A camel travels a certain distance each day. Strangely enough, two of its legs travel 30 miles each day and the other two legs travel nearly 31 miles. It would seem that two of the camel's legs ... but of course this can't be true.Since the camel is normal, how is this situation possible? -Riddles

Last Answer : The camel operates a mill and travels in a circular clockwise direction. The two outside legs will travel a greater distance than the two inside legs.

Description : A horse travels a certain distance each day. Strangely enough, two of its legs travel 30 miles each day and the other two legs travel nearly 31 miles. It would seem that two of the horse's legs must be ... , but of course this can't be true, since the horse is normal. How is this possible? -Riddles

Last Answer : The horse operates a mill and travels in a circular clockwise direction. The two outside legs will travel a greater distance than the two inside legs.

Description : A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance D1 in the first 10 seconds and distance D2 in the next 10 seconds then, (a) D2 = D1 (b) D2 = 2D1 (c) D2 = 3D1 (d) D2 = 4D1 -Science

Last Answer : (c) is the answer

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Description : A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km

Last Answer : 3) 840 km

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Description : A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is a) 177.7 km b) 154.2 km c) 163.5 km d) 147.3 km

Last Answer : A Let the distance between bus stop and destination be X. The total time taken by the bus to cover X = 4 hours Since X/2 by 40km/hr and remaining X/2 by 50km/hr Then by Time = distance/speed, we have ... = 1600 9X = 1600 X = 1600/9 = 177.7 Hence 177.7 km is the required answer.

Description : A van travels from namakkal to Madurai at a constant speed. If its speed were increased by 40km/hr it would have taken 1 hr lesser to cover the distance. It would have taken further 45 mins lesser if the speed ... by 40km/hr. what is distance between the 2 cities. a) 1680 b) B1660 c) 1670 d) 1675

Last Answer : A Let distance = x km Usual rate = y km/hr Then x/y - x/(y+40) =1 X(y+40) / y(y+40) = 1 Xy+40x - xy = y(y+40) 40x = y(y+40) ---------->1 x/y - x/y+80 = 7/4 x(y+80) - xy / y(y+ ... (y+80) / y(y+40) 8(y+40) = 7y + 560 8y +320 = 7y+560 Y=240 Substitute y value in 1 40x = 240*280 X=1680 km

Description : Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77

Last Answer : D Total distance = (400+250+50+600)km =1300 km Total time taken = (400/70 + 600/80+250/60+50/40) hrs =(40/7 +60/8+25/6+5/4) =(24*40)+(21*60)+(28*25)+(42*5) / 168 =960+1260+700+210 / 168 =(3130 / 168) Average speed =(1300*168 / 3130) km/hr =218400/3130 =69.77 km/hr

Description : Robert travels from his home to anna park at a distance of 125 miles in 11/4 hrs. He returns to home in 2 hrs 15 mints. His average speed is. a) 50 b) 40 c) 30 d) 20 

Last Answer : A Speed from home to annapark: (125*4/11)mph = (500/11)mph Speed from annapark to home: (125*4/9)mph = (500/9) mph Average speed = 2xy / (x+y) mph =[(2*500/11 *500/9) / (500/11+500/9)]mph =(500000/99) / ((4500+5500)/99) =(500000/99) / 10000 /99 =50mph

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Last Answer : c. 4 sec

Description : A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance covered in two equal time intervals

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Description : 2. A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? -Physics-10

Last Answer : The position of the image should be at 2F since the image is the real and same size. It is given that the image of the needle is formed at a distance of 50 cm from the convex lens. Therefore, the needle is ... (u) = - 50 cm Image distance, (v) = 50 cm Focal length = f According to the lens formula,

Description : An object is placed at a distance equal to the focal length of convex mirror. If the focal length of the mirror be f, then the distance of the image from the pole of the mirror is (a) Less than f (b) Equal of f (c) More than f (d) Infinity

Last Answer : Ans:(a)

Description : Two objects A and B are moving with same momentum. Mass of object 'B' is greater then mass of object 'A'. Which of the two object will have higher kinetic energy? -Physics

Last Answer : Let m1​ and m2​ be the masses of the body Let m1​>m2​Given that m1​v1​=m2​v2​v2​v1​​=m1​m2​​∴ Ratio between their kinetic energies , =K2​K1​​=21​m2​v22​21​m1​v12​​⟹K2​K1​​=m2​m1​​×m12​

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Last Answer : a) increases

Description : A wavefront undergoes a phase change as it travels along the fiber. If the wavefront transverses the fiber twice and is reflected twice and the total phase change is equal to 1/2 p, will the wavefront disappear? If yes, why?

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Description : I'm moving from NC to Sacramento, CA in June. The distance is the same for I-80 or I-40. Which is better?

Last Answer : I-40 all the way in the summer

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Last Answer : It is the volume of the object.

Description : A man goes to work at the same time each day and travels part of his journey facing forwards and the remainder facing backwards. When he returns at the end of his working day, he only faces forwards.How can this be? -Riddles

Last Answer : He works in the engine room of a liner! To get to work, he walks along the decks from his cabin facing forwards, and down the ladders between decks facing backwards. However, when he finishes, he only needs to face forwards to climb the ladders again and walk along the deck back to his cabin.

Description : A train 200m in length, travels at 120 km/hr. In what time it will pass a boy who is walking at 12km an hour. a) against(opposite) it: b) in the same direction? A) 5.4,6.66 B) 7.2,5.2 C) 3.5,6 D) 12,16

Last Answer : ANSWER: A  Explanation: I) Speed of the train = 120 km/hr  Speed of the boy = 12 km/hr  Relative speed = (120 + 12) km/hr  Convert km/hr into m/s  132 km/hr = (132 * 5/ 18)m/s  = 36.66 m/s  Time = ... km/hr = (108 * 5 / 18)m/s  = 30 sec  Time = distance / speed  = 200 / 30  = 6.66 sec