What is the sum of all the common factors of 45 and 63?

What is the sum of all the common factors of 45 and 63?
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13
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What is the greatest common factor of 45 63 and 99?

Description : What is the greatest common factor of 45 63 and 99?

Last Answer : The greatest common factor is 9

In the expression of `(x+y)^(123)` , the sum of the exponents of x and y in 63 rd term is __________

Description : In the expression of `(x+y)^(123)` , the sum of the exponents of x and y in 63 rd term is __________

Last Answer : In the expression of `(x+y)^(123)` , the sum of the exponents of x and y in 63 rd term is __________

What is the sum of -63-9?

Description : What is the sum of -63-9?

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A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : NEED ANSWER

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : (b) We arrange the given data into groups like 13-22,23-32 103-112. (since, our data is from 14 to 112). The class width in this case is 9. Now, the given data can be arranged in tabular form as follows. Hence, the number of classes in distribution will be 10.

What is the LCM of 45 81 and 63?

Description : What is the LCM of 45 81 and 63?

Last Answer : 2835

What goes in to 45 and 63?

Description : What goes in to 45 and 63?

Last Answer : Need answer

What is the LCM of 45 81 and 63?

Description : What is the LCM of 45 81 and 63?

Last Answer : 2835

A problem Drum ( 3 ft. diameter ; 6 ft. height ) is field with a fluid whose density is 50 lb/ft^3. Determine the total volume of the fluid.  A. 42.41 ft^3  B.44.35 ft^3  C.45.63 ft^3  D.41.23 ft^3 Formula: Vf = (pi d^2 h) / 4

Description : A problem Drum ( 3 ft. diameter ; 6 ft. height ) is field with a fluid whose density is 50 lb/ft^3. Determine the total volume of the fluid.  A. 42.41 ft^3  B.44.35 ft^3  C.45.63 ft^3  D.41.23 ft^3 Formula: Vf = (pi d^2 h) / 4

Last Answer : 42.41 ft^3

Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

Equivalent weight of crystalline oxalic acid is [MP PMT 1995] (A) 30 (B) 63 (C) 53 (D) 45

Description : Equivalent weight of crystalline oxalic acid is [MP PMT 1995] (A) 30 (B) 63 (C) 53 (D) 45

Last Answer : (B) 63

What is the sum of all the common factors of 25 and 80?

Description : What is the sum of all the common factors of 25 and 80?

Last Answer : The sum is 1 plus 5 = 6

What is the Greatest Common Factor of 21 63 and 14?

Description : What is the Greatest Common Factor of 21 63 and 14?

Last Answer : It is 7.

What are the first 3 common multiples of 36 and 63?

Description : What are the first 3 common multiples of 36 and 63?

Last Answer : 252, 504, 756

What is the greatest common factor for 35 63 and 84?

Description : What is the greatest common factor for 35 63 and 84?

Last Answer : 7

What is the greatest common factor of 105 84 and 63?

Description : What is the greatest common factor of 105 84 and 63?

Last Answer : The GCF of the given three numbers is 21

A 63 years old lady presents with abdominal mass and weight loss, was diagnosed as having an ovarian tumour. The most common ovarian tumour in this woman would be: a) Epithelial tumour. b) Germ cell tumour. c) Stromal tumour. d) Sex cord tumour. e) Trophoblastic tumour.

Description : A 63 years old lady presents with abdominal mass and weight loss, was diagnosed as having an ovarian tumour. The most common ovarian tumour in this woman would be: a) Epithelial tumour. b) Germ cell tumour. c) Stromal tumour. d) Sex cord tumour. e) Trophoblastic tumour.

Last Answer : a) Epithelial tumour.

Find four numbers, the sum of which is 45, so that if 2 is added to the first number, 2 is subtracted from the second number, the third number is multiplied by 2 and the fourth number is divided by 2, then the four numbers so produced are all the same. What are the four numbers? -Riddles

Description : Find four numbers, the sum of which is 45, so that if 2 is added to the first number, 2 is subtracted from the second number, the third number is multiplied by 2 and the fourth number is divided by 2, then the four numbers so produced are all the same. What are the four numbers? -Riddles

Last Answer : 8 + 2 = 10 12 - 2 = 10 5 x 2 = 10 20 ÷ 2 = 10 45

What three consecvtive odd numbers have the the sum of 45?

Description : What three consecvtive odd numbers have the the sum of 45?

Last Answer : They are: 13+15+17 = 45

The LCM of two numbers is 45 times their HCF. If one of the numbers is 125 and the sum of HCF and LCM is 1150, then the other number is? a) 100 b) 125 c) 250 d) 225 e) 180

Description : The LCM of two numbers is 45 times their HCF. If one of the numbers is 125 and the sum of HCF and LCM is 1150, then the other number is? a) 100 b) 125 c) 250 d) 225 e) 180

Last Answer : LCM = 45× HCF LCM + HCF = 46× HCF = 1150 HCF = 25, LCM =1125. product of 2 numbers = LCM×HCF required number = (25× 1125) / 125 = 225. Answer: d)

At present, a mother is 3 times older than her son. After 5 years, the sum of their ages will be 70 years. The age of the mother after 10 years will be (A) 40 (B) 55 (C) 45 (D) 60

Description : At present, a mother is 3 times older than her son. After 5 years, the sum of their ages will be 70 years. The age of the mother after 10 years will be (A) 40 (B) 55 (C) 45 (D) 60

Last Answer : 45

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 

Last Answer : Answer: D  Let the marks secured by them be x and (x + 18)  Then sum of their marks = x + (x + 18) = 2x + 18  Given that (x + 18) was 72% of the sum of their marks  =>(x+18) = 72/100(2x+18)  => ... 11x = 126 x = 11.45  Then (x + 18) = 11.45 + 18 = 29.45  Hence their marks are 11.45 and 29.45

Sum of factors problem (I think)

Description : Sum of factors problem (I think)

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Description : What 2 factors of 30 have a sum of 13?

Last Answer : They are 10 and 3

In moment distribution method, the sum of distribution factors of all the members meeting at any joint is always (A) Zero (B) Less than 1 (C) 1 (D) Greater than 1

Description : In moment distribution method, the sum of distribution factors of all the members meeting at any joint is always (A) Zero (B) Less than 1 (C) 1 (D) Greater than 1

Last Answer : (C) 1

The output of the sum point must contain information that controls what two factors of load movement in a position servo?

Description : The output of the sum point must contain information that controls what two factors of load movement in a position servo?

Last Answer : Amount and direction of rotation.

Factors of 45?

Description : Factors of 45?

Last Answer : 15