Description : The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son a) 34,17 b) 14,40 c) 40,14 d) 50,17
Last Answer : C Let sons age = x years. Then mothers age = (54 - x)years. (x-8)(54-x-8) = 6(54- x - 8) hence (x-8) = 6 so x = 14 Their ages are 40 years and 14 years.
Description : The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10
Last Answer : Answer: A
Description : The mean of the ages of father and his son is 27 years. After 18 years, father will be twice as old as his son. Their present ages are (A) 42, 12 (B) 40, 14 (C) 30, 24 (D) 36, 18
Description : In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these
Last Answer : Let current age of Ram and his son be R,S (R + 10) = 3(S + 10) [2 times older = 3 times the age] R = 3S + 20 (R - 5) = 9(S - 5) 3S + 20 – 5= 9S – 45 3S + 15 = 9S – 45 or S = 10., R = 50 sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66. Answer: b)
Description : Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these
Last Answer : Sum of their present ages = 60 years sum of their ages, 5 years hence = 60 + (5 × 2) = 70 years. after 5 years, ratio of ages of A and B will be 3 : 4. A’s age after 5 years = (3/7) × 70 = 30 years A’s present age = 30 – 5 = 25 years Answer: a)
Description : Age of father 30 years ago was 9 times the age of her son. After 30 years, father’s age will be thrice that of his son. Find the ratio of their present ages. a) 21 : 5 b) 29 : 5 c) 27 : 4 d) 21 : 3
Last Answer : A At age of son be x and as father's age is 9 times the age of her son, let it be 9x, nine years ago. At present: father's age will be (9x + 30) and son's age will be (x + 30) After 30 years: father's age ... x = 20 We are asked to find the present ratio. (9x + 30) : (x + 30) = 210 : 50 = 21:5
Description : Madhan was 3 times as old as his daughter 10 years ago. After 10 years, Madhan will be twice as old as his daughter. Find out the present age of Madhan. a) 68 years b) 70 years c) 40 years d) 55 years e) 80 years
Last Answer : b Let age of the daughter before 10 years = x Then, age of Madhan before 10 years = 3x After 10 years, Madhan will be twice as old as his daughter. ⇒ 3x + 20 = 2( x+20) ⇒ x = 20 ⇒ Present age of Madhan = 3x + 10 = 3× 20+ 10 = 70 years.
Description : 15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years
Last Answer : C
Description : The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these
Last Answer : Difference in two sums = 80- 36 = 44 Age of both are increased by 44/2 = 22 years Difference in ages of father and son = 22 years sum of present ages of father and son = 36 years Son’s present age = 1/2 × (36 - 22) = 7 years Answer: b)
Description : The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years
Last Answer : A Son’s current age = x years. Then father’s age = (84 - x)years (84 - x) - 7 = 3(x - 7) 2x=56 x =28; after 7years it will be turn on 35
Description : When the average age of a father, mother and their son was 90 years, the son got married and a child was born just 6 year after the marriage when child turned 14 years the average age of the family is 80yrs. Find the age of daughter - in - law at present? A) 55 B) 56 C) 57 D) 58
Last Answer : B) total age of father, mother and son at the time of son's marriage = 90*3 =270 present age of family father, mother, son, daughter-in-law, child = (father, mother, son age at the time of marriage ... 60)+ daughter-in-law present age + 14 = 80*5 =400 daughter-in-law present age= 400-344 = 56yrs
Description : The mean marks obtained by a class of 40 students is 65. The mean marks of half of the students is found to be 45. The mean marks of the remaining students is (A) 85 (B) 60 (C) 70 (D) 65
Description : The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be ... present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these
Last Answer : Answer: B Let their ages 8 years ago be 2x, 3x, 7x, and 8x. Their ages now 2x+8, 3x+8, 7x+8, 8x+8. According to the question, =2x+8+3x+8+7x+8+8x+8=172 20x+32=172 =>x=140/20=7 Present age of Nishu=2×7+8=22 years Present age of mother=7×7+8=57 years Hence, required years (57-22)=35 years
Description : Keerthi's grandfather was 16 times older to her 32 years ago. He would be 6times of her age 16 years from now. What was ratio of ages of keerthi and her grandfather 16 years ago. a) 1:10 b) 11:10 c) 10:11 d) 10:1
Last Answer : A Let, keerthi’s age 32 years ago = x, Grandfather's age 32 years ago = 16x. 16 years from now, 6(x+32+16) = (16x+32+16) => x = 24 16 years ago ratio was: (x+16)/ (16x+16) = (24+16) / (16*24+16) 40 /400 = >1 / 10
Description : In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 ... (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg
Last Answer : (C) 105 days to 120 days and 18 kg to 21 kg
Description : The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after five years is 58. Find the ratio of their ages 3 years
Last Answer : The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after ... is 58. Find the ratio of their ages 3 years ago.
Description : Percentage content of silica in window glass, is (A) 40 to 45 (B) 50 to 55 (C) 60 to 65 (D) 70 to 75
Last Answer : Answer: Option D
Description : Two numbers are in the ration 3:5. If 9 is subtracted from the numbers, the ratio becomes 12:23. The numbers are (A) 30, 50 (B) 36, 60 (C) 33, 55 (D) 42, 70
Last Answer : Answer: C
Description : 10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. ... 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above
Last Answer : Let current year be 2015 In 2005, sum of all ages = 25 45 = 1125 In 2015, sum of all ages = 1125 + (25 10) = 1375 Now 60 year old teacher was replaced by a 54 year old teacher. So we need ... all ages in 2015 considering the replacement teacher = 1375 - 6 = 1369 Average = 1369/25 = 54.76 Answer: c)
Description : A is 2 years older than B who is twice as old as C. If sum of ages of A, B and C is 37 years, find the age of A. a) 7 years b) 9 years c) 14 years d) 16 years e) None of these
Last Answer : Let the age of C be x years. Then age of B = 2x and age of A = 2x + 2 sum of ages of A, B and C = (2x + 2) + (2x) + x = 37 (5x + 2) = 37 x = 7 Age of A = 2x + 2 = 16 years Answer: d)
Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70
Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.
Description : At what time between 3 and 4 O’clock will the hands of a watch point in opposite directions? (A) 40 minutes past three (B) 45 minutes past three (C) 50 minutes past three (D) 55 minutes past three
Last Answer : Answer: C Require time of a watch point in opposite directions between 3 and 4 O'clock will the hands is = 50 minutes past three
Description : Ali buys a glass, a pencil box and a cup and pays Rs. 21 to the shopkeeper. Rakesh buys a cup, two pencil boxes and a glass and pays Rs. 28 to the shopkeeper. Preeti buys two glasses, a cup and two pencil boxes and pays Rs ... The cost of 10 cups will be (A) Rs. 40 (B) Rs. 60 (C) Rs. 80 (D) Rs. 70
Last Answer : Answer: D
Description : The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these
Last Answer : Sum of their ages, 3 years ago = 46 – (2 × 3) = 40 years sunil’s age, 3 years ago = 1/5 × 40 = 8 years sunil’s present age = 8 + 3 = 11 years Answer: c)
Description : Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these
Last Answer : Sum of present ages of A, B and C is 72 years. sum of their ages (4 years ago) = 72 – (3 × 4) = 60 years 4 years ago, ratio of ages of A, B and C was 1 : 2 :3. A’s age, 4 years ago = (1/6) ×60 = 10 years A’s present age = 10 + 4 = 14 years Answer: d)
Description : A party was held in which a grandmother, father, mother, four sons, their wives and one son and two daughters to each of the sons were present. The number of females present in the party is: (A) 12 (B) 14 (C) 18 (D) 24
Last Answer : Answer: B
Description : A man pointing to a lady said, “The son of her only brother is the brother of my wife”. The lady is related to the man as (A) Mother’s sister (B) Grand mother (C) Mother-in-law (D) Sister of Father-in-law
Last Answer : (D) Sister of Father-in-law
Description : Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25
Last Answer : Let the correct ages of Ramesh and Suresh be X in 2015 (since they are twins, they will have the same age) Given: 2x + 9 = 43 Or x = 17 years in 2015. Age in 2021 = 17 + 6 = 23 Note: year of birth = 2015 – 17 = 1998. Reversing, Suresh = 1989 or 9 year older. Answer: d)
Description : One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these
Last Answer : Answer - B (16) Explanation - Let one year ago Sam's age be 4X years And, Ash's age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam's age = (4X + 2) ... = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.
Description : Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6. What is the age of Q at present a) 44 b) 30 c) 45 d) 33
Last Answer : D Let their ages 8 years ago is4x, 5x and 6x years. 4x+8+5x + 8 + 6x + 8= 99 hence x= 5 Q’s present age = (5x + 8) =33 years
Description : The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)
Last Answer : The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)
Description : The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these
Last Answer : Sum of present ages = 35 years sum of their ages will be 85 years after (85-35) / 2 = 25 years from now. the father is 25 years older than his son. Present age of father = (35 + 25)/2 = 30 years. Answer: c)
Description : In practice, the compression ratio of compression-ignition (CI) engine ranges from (A) 15 to 25 (B) 5 to 10 (C) 40 to 55 (D) 60 to 70
Last Answer : Option A
Description : Fathima's father was 76 years of age when she was born while her mother was 72years old when her brother 8 years younger to her was born. What is the difference between the ages of her parents? a)12 years b)14 years c)16 years d)18 years
Last Answer : A Mother's age when Fathima 's brother was born = 72 years. Father's age when Fathima 's brother was born = (76+8) years = 84 years. Required difference = (84-72) years = 12 years
Description : At what angle must zig zag bracing be installed? a. 35-55 degree b. 35-60 degree c. 25-45 degree d. 35-70 degree
Last Answer : a. 35-55 degree
Description : Shyam is younger than Sharuk by 22 years. If the ratio of their ages is 5:7, find the age of Shyam a) 55 b) 77 c) 66 d) 88
Last Answer : A If sharuk age is x, then Shyam age is x-22, so (x-22)/x = 5/7 => 7x-154 = 5x => 2x = 154 => x = 77 So shyam age is 77 - 22 = 55
Description : The angle of V-welded joint in a pressure vessel 30 to 45 0 40 to 55 0 55 to 70 0 None
Last Answer : 55 to 70 0
Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these
Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)
Description : The ages of two sisters differ by 32 years. 12 years ago, the elder one was 7 times as old as the younger one. What are their present ages of the elder person a) 46.9 b) 49.3 c) 42.7 d) 45.4
Last Answer : B Let's take the present age of the elder person = x and the present age of the younger person = x – 32 (x – 12) = 7*(x-32-12) => x – 12 = 7x – 308 => 6x = 296 => x = 49years 3months
Description : Mani is 32years older than his son Dinesh. In 4 years, his age will be twice the age of his son. The present age of his son is a) 26 years b) 28years c) 22 years d) 24 years
Last Answer : B Let the son's present age be x years. Then, mani's present age = (x + 32) years => (x + 32) + 4 = 2(x + 4) => x + 36 = 2x + 8 So, x = 28
Description : Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36
Last Answer : C Let the present ages are 5x, 8x, 10x. => (5x-6) + (8x-6) + (10x-6) = 28 => 23x = 46 => x = 2 So their present ages are: 10,16,20
Description : Bobby is 2 year older than Samsung if the sum of their ages is 36 how old is Bobby?
Last Answer : 25
Description : The sum of ages of 4 puppies born at the intervals of 2 years each is 48 years. What is the age of the youngest puppy? a) 9years b) 8 years c) 10 years d) None of these
Last Answer : A Let the ages of puppies be x, (x + 2), (x + 4)and (x + 6) years. Then, x + (x + 2) + (x + 4) + (x + 6) = 48 4x = 36,x = 9 Age of the youngest puppy = x = 9 years
Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63
Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c
Description : The sum of two children is ‘a’. The age of the father is twice the ‘a’. After twenty years, his age will be equal to the addition of the ages of his children. Find the age of father. -Maths 10th
Last Answer : Let the sum of the ages of two children will be x and age of father will be y. A.T.Q. , y = 2x ----------(i) and , After 20 years, x+40=y+20 ==> ... i), x-2x = -20 ==> x = 20 Now, put x= 20 in (i), y = 2 x 20 = 40 Hence age of father will be 40 years.
Description : The ratio of the present ages of Rupa and her daughter is ` 7 : 3`. When Rupa was 26 years old, her daughter was 6 years old . Find the present age of
Last Answer : The ratio of the present ages of Rupa and her daughter is ` 7 : 3`. When Rupa was 26 years old, ... old . Find the present age of Rupa. (in years)
Description : Anil is twice as old as Sunita. Three years ago, he was three times as old as Sunita. The present age of Anil is (A) 6 years (B) 8 years (C) 12 years (D) 16 years
Description : The sum of the current ages of two persons M and N is 129. If the age of M is twice that of N, find the sum of their ages 8 years hence. a)125 b)145 c)137 d)149
Last Answer : B M+N=129 Given M=2N From Which N =43,M=86 8 years their age will be 51 and 94 ,so the sum of their ages is 145