Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 
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1 Answer

Answer :

Answer: D

 Let the marks secured by them be x and (x + 18)

 Then sum of their marks = x + (x + 18) = 2x + 18

 Given that (x + 18) was 72% of the sum of their marks

 =>(x+18) = 72/100(2x+18)

 =>(x+18) = 18/25(2x+18)

 => 25x + 450 = 36x + 324

 => 11x = 126  x = 11.45

 Then (x + 18) = 11.45 + 18 = 29.45

 Hence their marks are 11.45 and 29.45
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Last Answer : Answer: B Solution:. Let us find the day on 1st April, 1994. 2000 years have 0 odd day. We have to calculate day on 1st April, 1994. 2000-1994 = 6 Years. 1996 is leap year and have 4 odd days Ordinary years ... was Friday Thus, on 3 rd , 10 th , 17 th , 24 th will be Sunday fall on April 1994.

In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to the sum of the other two digits. The number will decreased by 297, if its digit are reversed. approximately what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Description : In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to ... what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Last Answer : A) Maximum mark consist of a three digit number let's consider Unit digit place is Z,ten's place digit is Y and hundred's place digit is X. According to the question, Y=x+z---------1 X+Y ... Total number of Mahi, Nitesh and Ritesh =164/100 451=739.61 Required average =739.64/3=246.54~247.

The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98

Description : The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98 

Last Answer : Answer: A Price of dhal before = $30 Price of dhal now = $ 37.5 Increase in dhal = current price - original price  = $37.5 - $ 30  = $ 7.5 Therefore, percentage increase in price = Increase in price/ ...  = 7.5 / 30 100 = 750/100 = 25 % Thus, increase in price= 25 %

A mixture of 90 kg of rava and sugar contains 90% of sugar. The new mixture is formed by adding 30 kg of sugar. What is the percentage of sugar in the new mixture? a) 45 1/2 b) 60 1/5 c) 45 1/2 d) 92 1/2 e) 98 1/2

Description : A mixture of 90 kg of rava and sugar contains 90% of sugar. The new mixture is formed by adding 30 kg of sugar. What is the percentage of sugar in the new mixture? a) 45 1/2 b) 60 1/5 c) 45 1/2 d) 92 1/2 e) 98 1/2

Last Answer : Answer: D 90 kg = 81 kg sugar 9 kg rava Adding = 30 kg sugar Total = 111kg sugar 9kg rava (new)  111/120 × 100 = 92.5 =92 1 /2

In an examination of a certain class, at least `70%` of the students failed in Physics, at least `72%` failed in Chemistry, at least `80%` failed in M

Description : In an examination of a certain class, at least `70%` of the students failed in Physics, at least `72%` failed in Chemistry, at least `80%` failed in M

Last Answer : In an examination of a certain class, at least `70%` of the students failed in Physics, at ... 15%` D. Cannot be determined due to insufficient data

Mithun went to a shop and bought things worth Rs. 75, out of which 90 Paise went on sales tax on taxable purchases. If the tax rate was 18%, then what was the cost of the tax free items? a) 12.5 b) 69.80 c) 19.7 d) 34.5 e) 69.1

Description : Mithun went to a shop and bought things worth Rs. 75, out of which 90 Paise went on sales tax on taxable purchases. If the tax rate was 18%, then what was the cost of the tax free items? a) 12.5 b) 69.80 c) 19.7 d) 34.5 e) 69.1

Last Answer : Answer: E  Total cost of the items he purchased = Rs.75  Given that out of this Rs.75, 90 Paise is given as tax  => Total tax incurred = 90 Paise  = Rs.90/100  Let the cost of the tax free items = x  Given that tax rate = ... −0.9 −x) = 90  ⇒ (75 − 0.9 − x) = 5  x = 75 − 0.9 - 5  X=69.1 

In final exam of class IX there are 130 students 20 % students failed. How many students passed to class X? a) 105 b) 112 c) 104 d) 117 e) 104.5

Description : In final exam of class IX there are 130 students 20 % students failed. How many students passed to class X? a) 105 b) 112 c) 104 d) 117 e) 104.5

Last Answer : Answer: C) Percentage of students passed to class X = (100 % - 20 %) of 130  = 80 % of 130 =>80 % of 130 => 80/100 × 130 =>10400/100 => 104 Therefore, 104 students passed to class X

A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98

Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98 

Last Answer : Answer: D Let the number be 100. Increase in the number = 70 % = 40 % of 100  = (40/100 100)  = 70 Therefore, increased number = 100 + 70 = 170 This number is decreased by 70 % Therefore, decrease ... = 100 - 51 = 49 Hence, net percentage decrease = (49/100 100)  = (4900/100)  = 49 %

The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98

Description : The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98

Last Answer : Answer: E  Original cost = $140  Decrease in it = 30% of $140  = 30/100 × 140  = 4200/100  = $42  Therefore, decrease cost = $140 - $42 = $98

In a plot of 18000 sq. m., only 13500 sq. m. is allowed for construction. What percent of the plot is to be left without construction? a) 25 b) 60 c) 45 d) 40 e) 98

Description : In a plot of 18000 sq. m., only 13500 sq. m. is allowed for construction. What percent of the plot is to be left without construction? a) 25 b) 60 c) 45 d) 40 e) 98

Last Answer : Answer: A Percentage of plot allowed for construction = (13500/18000 × 100) = 75 %. Thus, the percentage of plot to be left without construction = 100 % - 75 % = 25 %.

A foot ball team lost 75 % of the matches it played. If it won 45 matches, find the number of matches it played. a) 120 b) 145 c) 105 d) 140 e) 180

Description : A foot ball team lost 75 % of the matches it played. If it won 45 matches, find the number of matches it played. a) 120 b) 145 c) 105 d) 140 e) 180

Last Answer : Answer: E Percentage of matches lost = 75 % Therefore Percentage of matches won (100 - 75) % = 25 % Let the number of matches played be x. Then 25 % of x = 45 25/100 × x =45  x = (45 × 100)/25  x = (4500)/25  x = 180 Therefore, the total number of matches played is 180.

In an examination, Salim secured `52%` marks and got 114 marks more than the pass marks and A zam secured `39%` marks and got 36 marks more than the p

Description : In an examination, Salim secured `52%` marks and got 114 marks more than the pass marks and A zam secured `39%` marks and got 36 marks more than the p

Last Answer : In an examination, Salim secured `52%` marks and got 114 marks more than the pass marks and A zam ... (a) The pass mark. (b) The pass percentage.