Are 56 cm bigger than 56000 km?

Are 56 cm bigger than 56000 km?
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56000 km is vastly greater than 56 cm
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Is 56 cm greater or 56000 km greater?

Description : Is 56 cm greater or 56000 km greater?

Last Answer : The second one.

Two people abi and krish invested in a business with 7 lakh and 8 lakh rupees respectively. They agree that 46% of the profit should be divided equally among them and rest is divided between them according to their investment. If krish got Rs. 2100 more than abi, Then the total profit is, A) 55000 B) 56000. C) 58333 D) None

Description : Two people abi and krish invested in a business with 7 lakh and 8 lakh rupees respectively. They agree that 46% of the profit should be divided equally among them and rest is divided between them according to their ... more than abi, Then the total profit is, A) 55000 B) 56000. C) 58333 D) None

Last Answer : Answer: C)  Ratio of profit abi and krish is,  =>7:8  46% of then profit should be divided equally among them, remaining share is 54% of x  Abi share =54/100 * x * 7/15  Krish share =54/100 * x* 8/15  54/100 * x * 8/15 - 54/100 * x* 7/15 =2100  X =58333

What would be the proper command to set a DCE clock rate of 56k for a serial interface? A. Router (config) # clockrate 56000 B. Router# clockrate 56000. C. Router (config-if) #clock rate 56000 D. Router (config-if) # clockrate 56k

Description : What would be the proper command to set a DCE clock rate of 56k for a serial interface? A. Router (config) # clockrate 56000 B. Router# clockrate 56000. C. Router (config-if) #clock rate 56000 D. Router (config-if) # clockrate 56k

Last Answer : Router (config-if) #clock rate 56000

In an election, candidate A got 40% of the total valid votes. If 55% of the total votes were declared invalid and the total numbers of votes is 280000, find the number of valid vote polled in favour of candidate. a) 32500 b) 56000 c) 35700 d) 50400 e) 29800

Description : In an election, candidate A got 40% of the total valid votes. If 55% of the total votes were declared invalid and the total numbers of votes is 280000, find the number of valid vote polled in favour of candidate. a) 32500 b) 56000 c) 35700 d) 50400 e) 29800

Last Answer : Answer: D Total number of invalid votes = 55 % of 280000  = 55/100 280000  = 15400000/100  = 154000 Total number of valid votes 280000 - 154000 = 126000 Percentage of votes polled in favour of candidate ... favour of candidate A = 40 % of 126000  = 40/100 126000  = 5040000/100  = 50400

What one is bigger 0.56 or 6 tenths?

Description : What one is bigger 0.56 or 6 tenths?

Last Answer : 0.6

What one is bigger 0.56 or 6 tenths?

Description : What one is bigger 0.56 or 6 tenths?

Last Answer : 0.6

A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the certain place. What is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Description : A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the ... is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Last Answer : B Let speed of the jeep =x kmph Then, speed of the bus =(100+25)x/100 =125x/100 =5x/4 kmph Time taken by the jeep to travel from P to Q =225/x hours Time taken by the bus to travel from p to Q =225/(5x/4) + ... 225/x=900/5x+37.5/60 225/x=180/x+37.5/60 45/x =37.5/60 37.5x=45*60 X=72 km/hr

Two cars A and B race each other. The Car A ran for 2 minute at a speed of 7.5 km/h, slept for 56 minute and again ran for 2 minute at a speed of 7.5 km/h. find the average speed of the car A in the race. -Science

Description : Two cars A and B race each other. The Car A ran for 2 minute at a speed of 7.5 km/h, slept for 56 minute and again ran for 2 minute at a speed of 7.5 km/h. find the average speed of the car A in the race. -Science

Last Answer : We know that Distance=speed×timeDistance=speed×time Distance travelled in first 2 minute = 7.5×2607.5×260 = 0.25 km Distance travelled in last 2 minute = 7.5×2607.5×260= 0.25 km Total distance = .25+.25 = 0.5 km Total time = 2+2+56 = 60 minute = 1 hr Average speed = 0.5/1 = 0.5 km/hr

A car is travelling at 15 m s-1, the distance it will travel in 1 hour is A. 54 km B. 55 km C. 56 km D. 57 km

Description : A car is travelling at 15 m s-1, the distance it will travel in 1 hour is A. 54 km B. 55 km C. 56 km D. 57 km

Last Answer : 54 km

The distance of mercury from sun is-----? A. 56 million km B. 57.9 million km (Answer) C. 58.9 million km D. 59.1 million

Description : The distance of mercury from sun is-----? A. 56 million km B. 57.9 million km (Answer) C. 58.9 million km D. 59.1 million

Last Answer : B. 57.9 million km

Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these

Description : Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these

Last Answer : Answer – C (48 sec) Explanation – Relative speed = all lengths/time [60+90] = [1.10 +0.9 ]/time [ PLUS when opposite direction] time=2/150 = 1/75 h 1 hour______3600 sec 1/75 hr______? ?= 3600/75=48 sec

kajal rides his scooter 14km at an average speed of 16 km/hr and again travels 16km at an average speed of 14 km/hr. What is her average speed for the entire trip approximately? a) 15.36 km/hr b) 17.46 km/hr c) 13.56 km/hr d) 14.86 km/hr

Description : kajal rides his scooter 14km at an average speed of 16 km/hr and again travels 16km at an average speed of 14 km/hr. What is her average speed for the entire trip approximately? a) 15.36 km/hr b) 17.46 km/hr c) 13.56 km/hr d) 14.86 km/hr

Last Answer : D Total distance travelled =14+16=30Km Time taken to travel 14 km at an average speed of 16 km/hr =14/16=7/8 Hr Time taken to travel 16 km at an average speed of 14 km/hr =16/14=8/7 hr Total time taken = ... /Total time taken =30/(7/8+8/7) =30/(113/56) =30*56/113=1680/113 =14.86 km/hr

Is 4.8 km bigger than 4800 m?

Description : Is 4.8 km bigger than 4800 m?

Last Answer : Feel Free to Answer

How is 6200 m bigger than 5 km?

Description : How is 6200 m bigger than 5 km?

Last Answer : 5km = 5000m and 6200 is bigger than 5000

What is bigger a 5.1 km or a 5000 meters?

Description : What is bigger a 5.1 km or a 5000 meters?

Last Answer : 5.1 km is 100 metres bigger

Witch is bigger 6 km or 660 m?

Description : Witch is bigger 6 km or 660 m?

Last Answer : 6 km

A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Description : A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Description : A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then, the area of the triangle is -Maths 9th

Description : The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then, the area of the triangle is -Maths 9th

Last Answer : The area of the triangle is

The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then, the area of the triangle is -Maths 9th

Description : The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then, the area of the triangle is -Maths 9th

Last Answer : The area of the triangle is

How many inches 56 CM?

Description : How many inches 56 CM?

Last Answer : 56 inches is about 134.62 centimeters.

What is the circumference of a circle with 56 cm?

Description : What is the circumference of a circle with 56 cm?

Last Answer : Circumference of a circle: 2*pi*radius or pi*diameter

How do you convert 56 inches wide and 84 inches height to cm?

Description : How do you convert 56 inches wide and 84 inches height to cm?

Last Answer : Need answer

What is the impedance of a balance 4-wire with a diameter of 0.25 cm and spaced 2.5 cm apart using an insulator with a dielectric constant of 2.56? A. 100Ω B. 65Ω C. 75 Ω D. 50 Ω

Description : What is the impedance of a balance 4-wire with a diameter of 0.25 cm and spaced 2.5 cm apart using an insulator with a dielectric constant of 2.56? A. 100Ω B. 65Ω C. 75 Ω D. 50 Ω

Last Answer : A. 100Ω

A Pitot tube indicates 5 cm of water (manometer) when it is being used for measuring velocity of air. The velocity of air in m/sec is (A) 5 (B) 14.1 (C) 56.22 (D) 28.2

Description : A Pitot tube indicates 5 cm of water (manometer) when it is being used for measuring velocity of air. The velocity of air in m/sec is (A) 5 (B) 14.1 (C) 56.22 (D) 28.2

Last Answer : (D) 28.2

Find the pressure due to a column of mercury 74.0 cm high.  a. 91.80 x 10^3 N/m^2  b. 73.56 x 10^2 N/m^2  c. 9.86 x 10^4 N/m^2  d. 87.2 x 10^4 N/m^2

Description : Find the pressure due to a column of mercury 74.0 cm high.  a. 91.80 x 10^3 N/m^2  b. 73.56 x 10^2 N/m^2  c. 9.86 x 10^4 N/m^2  d. 87.2 x 10^4 N/m^2

Last Answer : 9.86 x 10^4 N/m^2

A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Description : A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Last Answer : Length of the wire = circumference of the circle 2 × (22/7) × 56 = 2 × 22 × 8 = 352 cm side of square = 352/4 = 88cm area of square = 88 × 88 = 7744 sq.cm Answer: c)

Is 6ft bigger than 300 cm?

Description : Is 6ft bigger than 300 cm?

Last Answer : 6 feet = 182.88 cm.

27 drops of water form a big drop of water. If the radius of each smaller drop is 0.2 cm, then what is the radius of the bigger drop ? -Maths 9th

Description : 27 drops of water form a big drop of water. If the radius of each smaller drop is 0.2 cm, then what is the radius of the bigger drop ? -Maths 9th

Last Answer : no of small drops of water =27 radius of per smaller drop of water =0.2cm therefore , radius of the big drop =(0.2 x 27) cm =5.4cm

What is bigger 1m or 990 cm For math?

Description : What is bigger 1m or 990 cm For math?

Last Answer : 990 cm equals 9.9 meters and so it is bigger than 1 meter

What is bigger yd or cm?

Description : What is bigger yd or cm?

Last Answer : A yard is bigger than a centimeter

Is 52800 cm smaller than 1 km?

Description : Is 52800 cm smaller than 1 km?

Last Answer : Yes

Is 7500000 cm greater than 750 km?

Description : Is 7500000 cm greater than 750 km?

Last Answer : i dont know

The wavelength used in radar is (a) 10 m (b) Less than 5 cm (c) 100 m (d) 1,000 km

Description : The wavelength used in radar is (a) 10 m (b) Less than 5 cm (c) 100 m (d) 1,000 km

Last Answer : Ans:(b)

Water is following at the rate of 5 km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50 m long -Maths 9th

Description : Water is following at the rate of 5 km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50 m long -Maths 9th

Last Answer : Convert all to metres: 5 km = 5000 m 14 cm = 0.14 m 7 cm = 0.07 m Find the radius: Radius = Diameter 2 Radius = 0.14 2 = 0.07 m Find the amount of water that flowed out in an hour: Volume ... hours needed: Number of hours = 154 77 = 2 hours It takes 2 hours to fill up the tank to rise by 7 cm

If two locations are 1 km apart in actuality but only 1 cm apart on a map what is the map's scale?

Description : If two locations are 1 km apart in actuality but only 1 cm apart on a map what is the map's scale?

Last Answer : To find the scale:Convert the measurements to the same units (usually the smaller units)drop the unitssimplify1 m = 100 cm 1 km = 1,000 m = 1,000 100 cm = 100,000 cmMap scales are given with the map figure, then ... m in the real world, 1 cm on the map is 100,000 cm = 1 km in the real world, etc.)

For design purposes, the normal rate of infiltration of ground water into the sewer, is A. 500 litres/km/cm B. 1000 litres/km/cm C. 1500 litres/km/cm D. 2000 litres/km/cm

Description : For design purposes, the normal rate of infiltration of ground water into the sewer, is A. 500 litres/km/cm B. 1000 litres/km/cm C. 1500 litres/km/cm D. 2000 litres/km/cm

Last Answer : ANS: D

What is the diameter of a copper wire to be used in a 16 km loop with a dc loop resistance of 100 ohms/km? A. 0.108 cm B. 1.082 cm C. 0.017 cm D. 0.0465 cm

Description : What is the diameter of a copper wire to be used in a 16 km loop with a dc loop resistance of 100 ohms/km? A. 0.108 cm B. 1.082 cm C. 0.017 cm D. 0.0465 cm

Last Answer : D. 0.0465 cm

Speed of snail as compared to speed of a car will be in units A. cm s-1 B. m s-1 C. km s-1 D. km h-1

Description : Speed of snail as compared to speed of a car will be in units A. cm s-1 B. m s-1 C. km s-1 D. km h-1

Last Answer :  cm s-1

The difference in the lengths of an arc and its subtended chord on the earth surface for a distance of 18.2 km, is only (A) 1 cm (B) 5 cm (C) 10 cm (D) 100 cm

Description : The difference in the lengths of an arc and its subtended chord on the earth surface for a distance of 18.2 km, is only (A) 1 cm (B) 5 cm (C) 10 cm (D) 100 cm

Last Answer : (C) 10 cm

If a ‘vertical aerial photograph’, (20 cm x 20 cm) in size, on a R.F.I: 10,000, has 60% longitudinal overlap and 40% side overlap, the actual ground length covered by each photograph in the longitudinal direction of the flight will be : (a) 4 km (b) 6 km (c) 0.8 km (d) 0.4 km

Description : If a ‘vertical aerial photograph’, (20 cm x 20 cm) in size, on a R.F.I: 10,000, has 60% longitudinal overlap and 40% side overlap, the actual ground length covered by each photograph in the longitudinal direction of the flight will be : (a) 4 km (b) 6 km (c) 0.8 km (d) 0.4 km

Last Answer : .8

The index map of preliminary report should be to a scale of (a) 1 cm to 0.5 km (b) 1 cm to 1.0 km (c) 1 cm to 2.5 km* (d) 1 cm to 10.0 km

Description : The index map of preliminary report should be to a scale of (a) 1 cm to 0.5 km (b) 1 cm to 1.0 km (c) 1 cm to 2.5 km* (d) 1 cm to 10.0 km

Last Answer : (c) 1 cm to 2.5 km*

The project report of the reconnaissance survey should be accompanied by Index map area at a scale of 1 cm = ---- km. (a) 2.5 km* (b) 5.0 km (c) 10.0 km (d) 15.0 km (e) 20.0 km

Description : The project report of the reconnaissance survey should be accompanied by Index map area at a scale of 1 cm = ---- km. (a) 2.5 km* (b) 5.0 km (c) 10.0 km (d) 15.0 km (e) 20.0 km

Last Answer : (a) 2.5 km*

The project report of the reconnaissance survey should be accompanied by a map of the area at a scale of 1 cm= --- km. (a) 2.5 km (b) 5.0 km (c) 10.0 km (d) 15.0 km (e) 20.0 km*

Description : The project report of the reconnaissance survey should be accompanied by a map of the area at a scale of 1 cm= --- km. (a) 2.5 km (b) 5.0 km (c) 10.0 km (d) 15.0 km (e) 20.0 km*

Last Answer : (e) 20.0 km*