Description : Designation of a curve is made by: (A) Angle subtended by a chord of any length (B) Angle subtended by an arc of specified length (C) Radius of the curve (D) Curvature of the curve
Last Answer : (C) Radius of the curve
Description : A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th
Last Answer : Given radius =2 cm Therefore AO=2 cm Let OD be the perpendicular from O on AB And AB =2cm Therefore AD=1cm (perpendicular from the centre bisects the chord) Now in triangle AOD, AO=2 cm ... by a chord at the centre is double of the angle made by the chord at any poin on the circumference)
Description : The lengths of two parallel chords of a circle are 6 cm and 8 cm. If the smaller chord is at a distance of 4 cm from the centre, what is the distance of other chord from the centre? -Maths 9th
Last Answer : There are two parallel chords of length 8 cm and 6 cm. The distance between center and shortest chord (6cm chord) is 4cm. So, the perpendicular distance from the center to the shortest chord is 4cm. The ... 32+42 =5. Since the radius is 5. The distance from center to largest chord is 52−42 =3.
Description : What is the solid angle subtended by the moon at any point of the Earth, given the diameter of the moon is 3474 km and its distance
Last Answer : What is the solid angle subtended by the moon at any point of the Earth, given the diameter of the moon ... its distance from the Earth 3.84 108 m?
Description : Degree of a road curve is defined as the angle in degrees subtended at the centre by an arc of (A) 10 metres (B) 20 metres (C) 25 metres (D) 30 metres
Last Answer : Answer: Option B
Description : If S, L and R are the arc length, long chord and radius of the sliding circle then the perpendicular distance of the line of the resultant cohesive force, is given by (A) a = S.R/L (B) a = L.S/R (C) a = L.R/S (D) None of these
Last Answer : (A) a = S.R/L
Description : A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th
Last Answer : Given, AB is a chord of a circle, which is equal to the radius of the circle, i.e., AB = BO …(i) Join OA, AC and BC. Since, OA = OB= Radius of circle OA = AS = BO
Description : Top chord of a truss is continuous over joints l apart. Effective lengths of the member in the plane perpendicular to the truss is (a) 0.7 l (b) 0.85 l (c ) l (d) 1.5 l
Last Answer : (c ) l
Description : If a circle is divided into eight equal parts, find the angle subtended by each arc at the centre. -Maths 9th
Last Answer : Total angle at centre = 360° When divided into eight part, Angle subtended by each arc = 360 / n8 = 45°
Description : The moon is at a distance of 3.84 × 10^8 m from the Earth. If viewed from two diametrically opposite points on the Earth, the angle subtended
Last Answer : The moon is at a distance of 3.84 108 m from the Earth. If viewed from two diametrically opposite ... is 1° 54′. What is the diameter of the Earth?
Description : The angle subtended by the surface of sewer water with partial flow, at sewer centre is 120°, the depth of sewerage is A. 20 cm B. 25 cm C. 40 cm D. 50 cm
Last Answer : ANS: D
Description : Solid angle subtended by the finite surface at the radiating element is (A) Called the view factor (B) Called the angle of vision (C) Proportional to the square of the distance between surfaces (D) Expressed in terms of radians
Last Answer : (B) Called the angle of vision
Description : Typically, repeaters are not required for fiber-optic cable lengths up to: a. 1000 miles b. 100 miles c. 100 km d. 10 km
Last Answer : c. 100 km
Description : The sum of the interior angles of a geometrical figure laid on the surface of the earth differs from that of the corresponding plane figure only to the extent of one second for every (A) 100 sq. km of area (B) 150 sq. km of area (C) 200 sq. km of area (D) None of these
Last Answer : (C) 200 sq. km of area
Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th
Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm
Description : The radius of a circle is 13 cm and the length of one of its chords is 24 cm. Find the distance of the chord from the centre. -Maths 9th
Last Answer : Let PQ be a chord of a circle with centre O and radius 13cm such that PQ = 24cm. From O, draw OM perpendicular PQ and join OP. As, the perpendicular from the centre of a circle to a chord bisects the chord. ∴ PM ... Hence, the distance of the chord from the centre is 5cm.
Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th
Last Answer : Let AB be a chord of a circle having centre at OPQ be the perpendicular bisector of the chord AB, which intersects at M and it always passes through O. To prove arc PXA ≅ arc PYB Construction Join AP and BP. Proof In ... ΔBPM, AM = MB ∠PMA = ∠PMB PM = PM ∴ ΔAPM s ΔBPM ∴PA = PB ⇒arc PXA ≅ arc PYB
Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, then prove that arc PXA ≅ arc PYB. -Maths 9th
Last Answer : Solution :- Let AB be a chord of a circle having centre at O. Let PQ be the perpendicular bisector of the chord AB intersect it say at M. Perpendicular bisector of the chord passes through the centre of the circle,i. ... = PM (Common) ∴ △APM ≅ △BPM (SAS) PA = PB (CPCT) Hence, arc PXA ≅ arc PYB
Description : The mathematical perception of the gradient is said to be a) Tangent b) Chord c) Slope d) Arc
Last Answer : c) Slope
Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, then find the distance of AB from the centre of the circle. -Maths 9th
Last Answer : ∵ The perpendicular drawn from the centre to the chord bisects it. ∴ AM = 1/2 AB = 1/2 × 30 cm = 15 cm Also, OA = 1/2 AD = 1/2 × 34 cm = 17 cm In rt. △OAM, we have OA2 = OM2 + AM2 172 = OM2 + 152 ⇒ 289 = OM2 + 225 ⇒ OM2 = 289 - 225 ⇒ OM2 = 64 ⇒ OM = √64 = 8 cm
Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is -Maths 9th
Last Answer : (d) Given, AD = 34 cm and AB = 30 cm In figure, draw OL ⊥ AB. Since, the perpendicular from the centre of a circle to a chord bisects the chord.
Description : Find the length of a chord which is at a distance of 12 cm from the centre of a circle of radius 13 cm. -Maths 9th
Last Answer : Let AB be a chord of circle with centre O and radius 13cm. Draw OM perpendicular AB and join OA. In the right triangle OMA, we have OA2 = OM2 + AM2 ⇒ 132 = 122 + AM2 ⇒ AM2 = 169 - 144 ... . As the perpendicular from the centre of a chord bisects the chord.Therefore, AB = 2AM = 2 x 5 = 10cm.
Description : The radius of a circle is 10cm. The length of a chord is 12 cm. Then the distance of the chord from the centre is `"__________________"`.
Last Answer : The radius of a circle is 10cm. The length of a chord is 12 cm. Then the distance of the chord from the centre is `"__________________"`.
Description : Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th
Last Answer : Join OA and OC. Let the radius of the circle be r cm and O be the centre Draw OP⊥AB and OQ⊥CD. We know, OQ⊥CD, OP⊥AB and AB∥CD. Therefore, points P,O and Q are collinear. So, PQ=6 cm. Let OP=x. Then, ... r2=52+(2.5)2=25+6.25=31.25 ⇒r2=31.25⇒r=5.6 Hence, the radius of the circle is 5.6 cm
Description : If a transmitting antenna is 100 meters high and a separate receiving antenna is 64 meters high, what is the maximum space wave communication distance possible between them? A. 18 km B. 72 km C. 164 km D. 656 km
Last Answer : B. 72 km
Description : The instruments which provide electromagnetic radiation of specified wave length or a band of wave lengths to illuminate the earth surface are called: (A) Sensors (B) Passive sensors (C) Active sensors (D) None of these
Last Answer : Answer: Option C
Description : For a curve of radius 100 m and normal chord 10 m, the Rankine's deflection angle, is (A) 0°25'.95 (B) 0°35'.95 (C) 1°25'.53 (D) 2°51'.53
Last Answer : (D) 2°51'.53
Description : While calculating the overtaking sight distance, the height of the object above road surface, is assumed (A) 50 cm (B) 75 cm (C) 100 cm (D) 120 cm
Last Answer : Answer: Option D
Description : The base of a right prism is a trapezium. The lengths of the parallel sides are 8 cm and 14 cm and the distance between the parallel -Maths 9th
Last Answer : Area of trapezium =12×h(AB+CD) =12×8×(8+14)=12×8×(8+14) =4×22=88cm2=4×22=88cm2 = Volume of prism = Height of prism ×× area of base ⇒height×88=1056 (given)⇒height×88=1056 (given) ⇒height×88=105688⇒height×88=105688 ⇒12cm =12×h(AB+CD)
Description : Pick out the correct statement. (A) Higher is the temperature of the radiating body, higher is the wavelength of radiation (B) Logarithmic mean area is used for calculating the heat flow rate ... ) Solid angle subtended by the finite surface at the radiating element is called the angle of incidence
Last Answer : (B) Logarithmic mean area is used for calculating the heat flow rate through a thick walled cylinder
Description : The curvature of the earth's surface, is taken into account only if the extent of survey is more than (A) 100 sq km (B) 160 sq km (C) 200 sq km (D) 260 sq km
Last Answer : (D) 260 sq km
Description : Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these
Last Answer : Answer – C (48 sec) Explanation – Relative speed = all lengths/time [60+90] = [1.10 +0.9 ]/time [ PLUS when opposite direction] time=2/150 = 1/75 h 1 hour______3600 sec 1/75 hr______? ?= 3600/75=48 sec
Description : If a rectangular beam measuring 10 × 18 × 400 cm carries a uniformly distributed load such that the bending stress developed is 100 kg/cm2 . The intensity of the load per metre length, is (A) 240 kg (B) 250 kg (C) 260 kg (D) 270 kg
Last Answer : (B) 250 kg
Description : The ratio of the angles subtended at the eye, by the virtual image and the object, is known as telescopes (A) Resolving power (B) Brightness (C) Field of view (D) Magnification
Last Answer : (D) Magnification
Description : Which one of the following statements is correct? (A) (B) The cone subtended by an area on the sphere at the centre, is called the solid angle (C) The solid angle is equal to the ratio of the area on the sphere and the square of the radius of the sphere (D) All of these
Description : In case of Raymond pile (A) Lengths vary from 6 m to 12 m (B) Diameter of top of piles varies from 40 cm to 60 cm (C) Diameter of pile at bottom varies from 20 cm to 28 cm (D) All the above
Description : Minimum stopping distance for moving vehicles on road with a design speed of 80 km/hour, is (A) 80 m (B) 100 m (C) 120 m (D) 150 m
Description : An object on the top of a hill 100 m high is just visible above the horizon from a station at sea level. The distance between the station and the object is : (a) 38.53 km (b) 3.853 km (c) 3853 km (d) 385.3 km
Last Answer : (a) 38.53 km
Description : In the figure below, CD is a chord of the semi circle with centre O. OA is the radius of the circle. If `CD=10` cm, `AB=2` cm and `bar(OA)_|_bar(CD)`
Last Answer : In the figure below, CD is a chord of the semi circle with centre O. OA is the radius of the ... |_bar(CD)` the length of OB is `"_____________"`
Description : The radius of curvature of the arc of the bubble tube is generally kept (A) 10 m (B) 25 m (C) 50 m (D) 100 m
Last Answer : (D) 100 m
Description : If the maximum shear stress at the end of a simply supported R.C.C. beam of 6 m effective span is 10 kg/cm2 , the share stirrups are provided for a distance from either end where, is (A) 50 cm (B) 100 cm (C) 150 cm (D) 200 cm
Description : If depth of slab is 10 cm, width of web 30 cm, depth of web 50 cm, centre to centre distance of beams 3 m, effective span of beams 6 m, the effective flange width of the beam, is (A) 200 cm (B) 300 cm (C) 150 cm (D) 100 cm
Description : Non-passing sight distance along a road is the longest distance at which the driver of a moving vehicle, may see an obstacle on the pavement (A) 10 cm high (B) 25 cm high (C) 50 cm high (D) 100 cm high
Last Answer : Answer: Option A
Description : The altitudinal distance of a geostationary satellite from the earth is about: (A) 26,000 km (B) 30,000 km (C) 36,000 km (D) 44,000 km
Description : The wavelength used in radar is (a) 10 m (b) Less than 5 cm (c) 100 m (d) 1,000 km
Last Answer : Ans:(b)