Description : What is the value of the nine in 0.496?
Last Answer : 9 hundredths
Description : The value of a machine depreciates at the rate of 20% every year. It was purchased 6 years ago. If its present value is Rs. 17,496, its purchase price was : a) 25023.4 b) 67040.0 c) 34171.8 d) 27337.5
Last Answer : Answer: C Purchase price = 17,496 / (1 -20/ 100)³ = 17,496 × 10/8 × 10/8 ×10/8 = 17496 × 1.25 × 1.25 ×1.25 = 17496 ×1.953 = 34171.8
Description : what is 496 / 14 whole number and remainder?
Last Answer : 35.4286
Description : What is 0.496 to the nearest hundredth.?
Last Answer : 96
Description : Are codes 496 where is it from?
Last Answer : Need answer
Description : What is 13.496 rounded to the nearest tenth?
Last Answer : 13.5
Description : How many thousands are in 708,496?
Last Answer : 7556
Description : If the permissible compressive and tensile stresses in a singly reinforced beam are 50 kg/cm2 and 1400 kg/cm2 respectively and the modular ratio is 18, the percentage area At of the steel required for an economic section, is (A) 0.496 % (B) 0.596 % (C) 0.696 % (D) 0.796 %
Last Answer : Answer: Option C
Description : If the compound interest accrued on an amount of Rs.15,000/- in two years is Rs.2,496/-.What is the rate of interest p.c.p.a.? a) 8 b) 12 c) 7.5 d) Cannot be determined e) None of these
Last Answer : Let the rate of interest p.c.p.a. be x. 2496 =15000 * x /100 x = 16.64 16.64 is the rate of interest compounded for two year & for one year = 8% 8% C.I. table for two year. I year = 8% II year = 8.64 Total =16.64% Answer: a)
Description : Heating 235 g of water from 22.6 degrees C to 94.4 degrees C in a microwave oven requires 7.06x10^4 J of energy. If the microwave frequency is 2.88x10^10 Hz, how many quanta are required to supply the 7.06x10^4 J?
Last Answer : answer:Guidelines. I don’t mean to be the bearer of bad news…
Description : The temperature of O2 is changed from -48.03 °C to 235.59 °C. If its new volume is 29.164 L, what was its original volume in liters ______ L?
Last Answer : 12.90(Explanation): use charle's law for this one. V/T=V/T. we know the temperatures in both scenarios, and we're trying to solve for the volume in the beginning. Remember temperature in Kelvin! So, plug in ... Now, divide by 508.59 on both sides to get 12.90042093. Round to 4 sig figs, 12.90 DONE!
Description : what is 14.235 round to the nearest tenth?
Last Answer : It is: 14.2
Description : (A) Enrichement of `U^(235)` from a mixture containing more abundant `U^(238)` is based on diffusion of `UF_(6)`. `UF_(6) is a gaseous compound under
Last Answer : (A) Enrichement of `U^(235)` from a mixture containing more abundant `U^(238)` is based on diffusion of ` ... . D. If both (A) and (R ) are incorrect.
Description : The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` b)`Np^(237),Bi^(209)` c)`U^(235),Pb^
Last Answer : The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` ... )Pb` D. `.^(237)Np, .^(209)Bi`
Description : (A) The activity of 1 g pure uranium-235 will be greater than the same amount present in `U_(3) O_(6)` (R ) In the combined state, the activity of the
Last Answer : (A) The activity of 1 g pure uranium-235 will be greater than the same amount present in `U_(3) O_(6)` ... . D. If both (A) and (R ) are incorrect.
Description : Which among the following `"is"//"are"` fissible? a)`._(92)U^(235)` b)`._(92)U^(238)` c)`._(94)Pu^(239)` d)`._(94)Pu^(238)`
Last Answer : Which among the following `"is"//"are"` fissible? a)`._(92)U^(235)` b)`._(92)U^(238)` c)`._(94)Pu^(239)` ... ` C. `._(94)^(239)Pu` D. `._(94)^(238)Pu`
Description : `""_(92)U^(235)` nucleus absorbs a neutron and disintegrates into `""_(54)Xe^(139) .""_(38)Sr^(94)` and X. What will be the product X ?
Last Answer : `""_(92)U^(235)` nucleus absorbs a neutron and disintegrates into `""_(54)Xe^(139) .""_(38) ... B. 2-neutrons C. `alpha`-particles D. `beta`-particle
Description : The number of neutrons accompanying the formation of `._(54)Xe^(139)` and `._(38)Sr^(94)` from the absorption of a slow neutron by `._(92)U^(235)`, fo
Last Answer : The number of neutrons accompanying the formation of `._(54)Xe^(139)` and `._(38)Sr^(94)` from the ... `._(92)U^(235)`, followed by nuclear fission is
Description : Natural uranium consists of `.^(235)U`:
Last Answer : Natural uranium consists of `.^(235)U`: A. 0.99 B. 0.5 C. 0.1 D. 0.007
Description : Let us consider emission of `alpha`particle from uranium nucleus: `._(92)^(235)U - ._(2)He^(4) to ._(90)Th^(231)` `{:(e = 92, e = 0, e = 90),(p = 92,
Last Answer : Let us consider emission of `alpha`particle from uranium nucleus: `._(92)^(235)U - ._( ... evolve energy C. annihilation D. absorption in the nucleus
Description : In the neutron`-`induced fissioin reaction of `._(92)U^(235)` one of the products if `._(37)Rb^(95),` in this mode, another nuclide and three neutrons
Last Answer : In the neutron`-`induced fissioin reaction of `._(92)U^(235)` one of the products if `._(37)Rb^(95),` in this ... `._(55)^(145)Co` D. `._(54)^(143)Xe`
Description : The reaction `._(92)U^(235) + ._(0)n^(1) rarr ._(56)Ba^(140) + ._(36)Kr^(93) + 3 ._(0)n^(1)` represents a)Artificial radioactivity b)Nuclear fission c
Last Answer : The reaction `._(92)U^(235) + ._(0)n^(1) rarr ._(56)Ba^(140) + ._(36)Kr^( ... radioactivity B. nuclear fission C. nuclear fussion D. none of the above
Description : The isotope `._(92)^(235)U` decays in a number of steps to an isotope of `._(82)^(207)Pb`. The groups of particle emitted in this process will be:
Last Answer : The isotope `._(92)^(235)U` decays in a number of steps to an isotope of `._(82)^(207)Pb`. The groups ... C. `7 alpha, 4 beta` D. `10 alpha, 8 beta`
Description : The nucleus `._(92)^(235)U` decays according to `._(92)^(238)U rarr ._(92)^(234)Th + ._(2)^(4)He`. Calculate the kinetic energy of the emitted `alpha`
Last Answer : The nucleus `._(92)^(235)U` decays according to `._(92)^(238)U rarr ._(92)^(234)Th + ._(2)^(4)He`. ... kg " " ._(2)^(4)He = 6.64807 xx 10^(-27)`
Description : A uranium nucleus `.^(235)U` liberates 200 MeV per fission 1.5 kg of uranium reacts during explosion of a uranium bomb. What is the mass of an equival
Last Answer : A uranium nucleus `.^(235)U` liberates 200 MeV per fission 1.5 kg of uranium reacts during explosion of a uranium ... TNT is `4.1 xx 10^(6) J//kg` ?
Description : A reaction develop nuclear energy at the rate of `3 xx 10^(4) kW`. How many atoms of `.^(215)U` undergo fission per second? How much `.^(235)U` is bur
Last Answer : A reaction develop nuclear energy at the rate of `3 xx 10^(4) kW`. How many atoms of `.^(215)U` ... constant is `6.023 xx 10^(26)` per kg mole)
Description : Calculate the energy released by fission of 1 g of `._(92)^(235)U`, assuming that an energy of 200 MeV is released by fission of each atom of `.^(235)
Last Answer : Calculate the energy released by fission of 1 g of `._(92)^(235)U`, assuming that an energy of 200 MeV is ... `= 6.023 xx 10^(26) kg mol^(-1)`)
Description : Can you Describe the roman rulers from 235 to 284?
Description : How do you write 235 thousandths?
Last Answer : 0.235
Description : Is .235 a rational number?
Last Answer : Yes.
Description : What is 235 over 250 in decimal form?
Last Answer : 235/250 as a decimal is 0.94
Description : What is 14.235 rounded to the nearest tenth?
Description : How can you Write as a fraction or mixed number and write in simplest for 2.235?
Last Answer : 2.235 is a fraction. It is a fraction in decimal form rather than in the form of a ratio. However, that does not stop it being a fraction. And, being a decimal, there is no simpler form. Its rational equivalent is 2235/1000 which can be simplified to 447/200 or 247/200.
Description : How much faster does UF 235 effuse compared with UF 238?
Last Answer : What is the answer ?
Description : How many times can 3 go into 235?
Last Answer : 235 ÷ 3 = 78.33 or 78 times with a remainder of 1.
Description : Is 3 235 prime or composite?
Last Answer : If you mean 3235 then it is a composite number because it hasmore than two factors
Description : Is 9.24 greater than 9.235?
Last Answer : yes 0.005 greater
Description : Because uranium 235 isn't found naturally in large quantities, engineers increase its concentration in nuclear fuel so that a chain reaction is more likely to occur. What is the name of this process?
Last Answer : Enrichment
Description : Which type of Uranium is used in the fission process? A. Uranium – 234 B. Uranium - 235 C. Uranium - 236 D. Uranium - 237
Last Answer : ANSWER: B
Description : According to 1998 census the density of population in Khyber Pakhtunkhwa Province is: A. 187 Persons per Sq. Km B. 254 Persons per Sq. Km C. 235 Persons per Sq. Km D. 318 Persons per Sq. Km
Last Answer : ANSWER: C
Description : The isotope used for the production of atomic energy is - (1) U-235 (2) U-238 (3) U-234 (4) U-236
Last Answer : (1) U-235 Explanation: U235 is an isotope of uranium making up about 0.72% of natural uranium. Unlike the predominant isotope U238 it is fissile, i.e., it can sustain fission chain reaction. It ... critical, and the mass of U required to produce the critical condition is said to be a critical mass.
Description : The isotope of Uranium used in atomic reactors is – (1) U^235 (2) (2) U^236 (3) U^237 (4) U^232
Last Answer : (1) U^235 Explanation: A nuclear reactor is a device to initiate and control a sustained nuclear chain reaction. Most commonly they are used for generating electricity and for the propulsion of ships ... fissile atomic nucleus such as U235 or U239 absorbs a neutron, it may undergo nuclear fission.
Description : The isotope of Uranium capable of sustaining chain reaction is - (1) U-235 (2) U-238 (3) U-239 (4) N.O.T.
Last Answer : (1) U-235 Explanation: Uranium is a chemical element with symbol U and atomic number 92. It is a silvery-grey metal in the actinide series of the periodic table.
Description : Determine from the following radio frequency that falls under the very high frequency band of the radio spectrum. A. 345.00 MHz B. 144.50 MHz C. 235.50 MHz D. 450.00 MHz
Last Answer : C. 235.50 MHz
Description : A radio frequency in the ultra high frequency band of the radio spectrum band. A. 235.50 MHz B. 450.50 MHz C. 150.50 GHz D. 0.31250 GHz
Last Answer : D. 0.31250 GHz